I have a custom DateTimePicker control that prepared for Persian calendar. Is there any way to add it to the DevExpress GridControl column?
Please help me.
From: Creating a custom (RepositoryItem) ImageComboBox
If you wish to use your custom control in GridControl, it is necessary
to create an editor and its RepositoryItem descendants.
Please refer to the Custom Editors and How to register a custom
editor for use in the XtraGrid articles for complete information
on how to create custom controls. You can find some custom editor
descendants in our examples: editor descendants.
The RepositoryItem class contains editor settings and is used as
a template for cells in the grid. In the display mode, GridControl
only draws cells content via RepositoryItem's methods. In the edit
mode, GridControl creates a corresponding editor via the
RepositoryItem.CreateEditor method. Thus, if you wish to add items to
the editor used in the grid on its initialization, implement this at
the RepositoryItem level.
You can set an editor for the auto filter row if you handle GridView.CustomRowCellEdit event with following code
RepositoryItemDateEdit rd = new RepositoryItemDateEdit();
void gridView1_CustomRowCellEdit(object sender, DevExpress.XtraGrid.Views.Grid.CustomRowCellEditEventArgs e) {
GridView view = sender as GridView;
if(e.Column.FieldName == "DOB" && view.IsFilterRow(e.RowHandle)) {
e.RepositoryItem = rd;
}
}
Review the Assigning Editors to Columns and Card Fields help article to learn how to assign a specific editor to a particular GridView's column.
I hope you will find this information useful.
Related
I seem to be struggling with this. I am working on a project management app in Google App Maker. I am using SQL data models. The portion of the app I am having trouble with is several project detail pages linked with a project list page. I have no trouble going from the project list page to the first project detail page.
I have a table widget in the project list page, and the onClick code for a table row is:
app.datasources.Projects.selectKey(widget.datasource.item._key);
app.showPage(app.pages.ProjectPage);
This filters the first detail page with the primary key of the record in focus. No problem here. When I want to navigate the next detail page that has a different datasource (but I still need to filter using the same primary key) I am struggling.
If someone can guide me in making a button in the first detail page that when clicked gets the _key of the project loaded in that current page and filters another detail page for the same project in focus, (using another data model, let's call it ProjectBudgetPage for example) I would really appreciate the help.
This was one my latest attempts at navigation to other detail pages within a project, this was for an onClick event:
var widgets = widget.parent.descendants;
var projectID = widgets.HiddenProjectID.text;
var projectDataSource = app.datasources.ProjectBudgetView.item;
projectDataSource = projectID;
app.showPage(app.pages.ProjectInfoPage);
which results in: (TypeError) : Cannot read property '__gwt_instance' of undefined
at HeaderProjectTabs.HeaderContainer.InfoTabButton.onClick:5:5
I am not sure if I understood properly but I suggest that you start by checking this official App Maker template available here https://developers.google.com/appmaker/templates/partner-management/ which provides a ready-to-run app you can use to manage an internal list of partners, but you can also customize it with your own needs. I recently used most of the UI and logic of this template and I was able to integrate it with SQL data models and it works really great.
I noticed that for this template they are saving the (widget.datasource.item._key) to a Page custom property which you can access afterwards. Custom properties are page-level properties that store data for a single user session. Custom properties are useful when you need to bind properties of multiple widgets to a single value. More info available here https://developers.google.com/appmaker/ui/binding#custom_properties
In your scenario, you can create a new custom property (string) inside your ProjectInfoPage and then you can add a script to the button onClick event in your ProjectPage to save the _key or any other item to a page property. For example:
app.pages.ProjectInfoPage.properties.ProjectKey = widget.datasource.item._key;
app.showDialog(app.pages.ProjectInfoPage);
Then you can get the “ProjectKey” property by adding this to the onAttach event in your ProjectInfoPage:
var key = app.pages.ProjectInfoPage.properties.ProjectKey;
…
In the onAttach event you can filter the new model or pass the property values to a server script. I believe there are other approaches but I hope this helps!
My page generates a list of check boxes at run time. I set the Id of each of these boxes manually by assigning to each the string.Format("checkbox_{0}, n} where n is a running number.
How to I find out the list of checkbox controls from codebehind? I couldn't find them in Page.Form.Controls. Where are they placed?
(I can see the checked checkboxes in Request.Form but that contains client side names of each control.)
Thanks.
-
---More info----
My iterative loop Adds CheckBoxes to a Panel control (created in the mark-up page) as follows:
CheckBox checkbox = new CheckBox();
checkbox.Text = "Add to list";
checkbox.ID = string.Format("checkbox_{0}", n.ToString("0"));
Panel1.Controls.Add(checkbox);
The checkboxes show up nicely on the page. I can tick. When I submit the Http POST stream contains all those ticked ones.
On post back, Panel1.Controls.Count is 0. When the page was first generated, Panel1.Controls.Count was 200, as it contained lots of LieteralControls for layout.
You can use the findcontrol method on page object or parent control object to find that checkbox object. like:
CheckBox chx=(CheckBox)Page.FindControl("Checkbox1");
if(chx!=null)
chx.Checked = false;
you can put this insode the loop also like:
for(int i=0;i<n;i++)
{
CheckBox chx=(CheckBox)Page.FindControl("Checkbox"+n);
if(chx!=null)
chx.Checked = false;
}
On post back, Panel1.Controls.Count is 0. When the page was first generated, Panel1.Controls.Count was 200, as it contained lots of LieteralControls for layout.
If you add controls dynamically in this way, you need to add them again (same ids, same order) on each postback.
Which means you need to persist whatever info you need to add them again. For example, you could store the number of checkboxes in ViewState, then regenerate that number of checkboxes on each post back.
I am using devexpress for windows application. I am having a devxgrid which populates the data and at the last column, I have a hyperlink button named cancel. When I click the cancel button it will do some functionalities that is working great. After that the corresponding cancel button should be disabled. How to make it disabled? Any help is greatly appreciated.
There are two ways to implement this task:
Create two ButtonEdit repository items. One with the enabled button and another with the disabled button. Then handle the GridView.CustomRowCellEdit event and pass the necessary repository item to the e.RepositoryItem parameter according to a specific condition. Please see the Assigning Editors to Individual Cells help topic for additional information.
If the button editor has several buttons and their Enabled state must be changed dynamically, you can implement this functionality by handling the GridView.CustomDrawCell event as shown in the following DevExpress Forum thread:
How to display disabled buttons for particular cells within a ButtonEdit column
.
But you should follow the first approach, In case of hyperlinkEdit., for your implementation logic add a custom column with bool values, that will give you condition that whether you will show enabled or disabled hyperlinkEdit repository edit.
If you just want to set this readonly then you do in following way:
you can make the editor read only by handling CustomRowCellEdit:
private void gridView1_CustomRowCellEdit(object sender, CustomRowCellEditEventArgs e)
{
if(code goes here)
e.RepositoryItem.ReadOnly = true;
}
you can also prevent the editor from being show by handling ShowingEditor:
private void gridView1_ShowingEditor(object sender, CancelEventArgs e)
{
if (code goes here)
e.Cancel = true;
}
Hope this help you to solve your task..
I have created a class inherit from StateManagedCollection.
It has got a few class as Columns like GridView.
But I can not select which filed I want to select from.
It should look like the picture below in design.
But mine is the one below:
I have written the property as below:
[Description("A collection of ToolBarItem's ")]
[DesignerSerializationVisibility(DesignerSerializationVisibility.Content)]
[Editor(typeof(System.ComponentModel.Design.CollectionEditor), typeof(System.Drawing.Design.UITypeEditor)), PersistenceMode(PersistenceMode.InnerProperty)]
public virtual Items Items
{
}
Can anyone help me out?
GridView columns collection uses a custom UI Type editor to show this interface. The in-built ASP.NET CollectionEditor will not show the required UI. Further in your case, CollectionEditor may not work if the collection's item type is a abstract class.
Solution is to build your own custom UI Type editor - basic steps are
Inherit from System.Drawing.Design.UITypeEditor.
Override GetEditStyle method to inform the property browser that you will launch modal form.
Override the EditValue method to launch your custom UI form.
Build the custom UI Form.
See a couple examples here (see sample for TagTypeEditor) and here.
It is known that the ListView control can't display both an EmptyDataTemplate and a InsertItemTemplate at the same time.
For my design style I need to be able to show both. I want to be able to show that no data exist and at the same time show a form to add new data.
I've already implemented various solutions, such as putting a PlaceHolder in my LayoutTemplate and then manually showing or hiding this PlaceHolder in the code-behind, depending on if there is data or not.
However, I would like a control that has this built-in capability in order to keep my code-behind light.
I believe there are only two ways to achieve what I want:
First way (preferred) is to write that custom control myself. I was thinking of deriving from ListView and overriding the function responsible for disabling the EmptyDataTemplate, but I have no experience with custom controls. And I'm not even sure it will work in the end.
Second way is to use a custom control found or purchased somewhere. I have not been able to find such control that has the same base capabilities as the ListView.
Has anybody any idea how to solve #1 and maybe #2?
Thank you.
Here is what I ended up doing:
public class MyListView : ListView
{
protected override int CreateChildControls(IEnumerable dataSource, bool dataBinding)
{
int itemCount = base.CreateChildControls(dataSource, dataBinding);
if (this.InsertItemPosition != InsertItemPosition.None && itemCount == 0)
{
CreateEmptyDataItem();
}
return itemCount;
}
}
Works great!
I would go for your option 1: Create a custom control
Because you haven't specified a programming language I made one in VB.NET:
Public Class CustomListView
Inherits ListView
Public Sub CheckEmptyData() Handles Me.PreRender
If Me.Items.Count = 0 Then
Dim label As New Label
label.Text = "No data found <br/>"
Me.Controls.AddAt(0, label)
End If
End Sub
End Class
Just tested it and works perfectly, it can just replace an existing ListView.
As you can see it checks if there is any data and if not it inserts a label with the text "No data found". I haven't found an easy way to use the EmptyDataTemplate for this, that would be a better option but this might already work for you.
Another option is to hide the InsertItem (InsertItemPosition.None) if there is no data, and add a Button "Insert" to the EmptyDataTemplate that enables the InsertItemTemplate and therefore hides the EmptyDataTemplate.
I don't understand much of your requirement without a screen shot of what you are actually trying to achieve. Anyway, you may be able to achieve this interface with a combination of ListView+FormView or ListView+ a User Control. If you can provide any more info I may help further.