In javafx BorderPane the tab traversal order is defined by the order of the children.
The problem is I have some Stage inheritance with a BorderPane on the base class, and BorderPane.setBottom() is called first.
This screws the tab order, since the bottom child is the first item on the children list.
I want to make the tab traversal on the BorderPane to be:
top
left
center
right
bottom
How could I archieve this?
This makes more sense than the set (setTop, setCenter, ...) order.
It seems it can't be done.
The solution was to add AnchorPanes inside the BorderPane areas and calling setTop, setCenter, ... in the desired tab traversal order.
Related
I am looking for a way to draw a node on top of the neighbouring ones in a HBox. Default behaviour means it is drawn on top of the previous one, but that also means the next one is drawn on top of it. For other containers, one could use the Node.toFront(), but changing the position of the node in the list containing a HBox's children also changes the actual position in the HBox, which is unwanted behaviour in my case. I appreciate any help, thank you.
EDIT:
The overlapping occurs when applying a DropShadow effect on an Ellipse and wrapping them in a StackPane along with a Text. It looks like the effect has a weird interaction with the HBox, as it works as intended without it. After adding the effect, it allocates more horizontal space for the ellipse, but not enough to cover the margins of the effect. Also, when clicking anywhere in the whole right half of the black rectangle, the mouse click is dispatched to the stackPane event handler, not to the rectangle's.
This happens
In VBox and HBox, the Node.toFront() and Node.toBack() functions will change the layout, so they are not usable. If you are using JavaFX 9+,you can use the viewOrder commands to change the rendering order of the Node in its Parent:
Node.getViewOrder()
Node.setViewOrder()
The default value of viewOrder is 0, so setting it to -1 will render it above all others. You can customize this to get specific orders. It also has a CSS property -fx-view-order.
I have created a Hbox with several Buttons inside as children. I want to increase one button size and be on top of others. Not as appreciated in the figure... I Have tried with children_button.toFront() but it changes the layout order.
Any help would be appreciated.
i am not sure if this works in an Hbox as I think toFront puts the Child on the first position of the ChildList in the parent Node. But this would mean that HBox would layout it on the very left on first place. So maybe they are overriding the default behavior in this Case? Just my guess
I got the task to draw some points on a map. Wrote some code but currently every point I create via shapes will be added to the wrong position inside of my gridpane. Oh and I'm using JavaFX.
I added an imageView to the index 0,0 of my GridPane and every point is created through x and y position of the MouseEvent on the imageView.
After that I added the created point as a child of the GridPane and it's displayed at the center of the y-axis of the first grid.
Tried different things like anchorPanes and canvas but can't seem to get it working.
Code of my View:
http://pastebin.com/dCb7EN4d
Code of my Main:
http://pastebin.com/vp5tzxkG
I hope that's enough ^^'
pls help!
Greetings,
Ben
GridPane is a managed layout: it will position nodes that are added to it via the properties you set (using defaults if you don't set them). So when you add your circles to the grid pane, since you don't set any properties, it will place it in cell (0,0) and align it within that cell using default settings; i.e. it ignores the centerX and centerY properties.
What you should really do here is use a layout that does not manage the positioning of the nodes for you, such as a Pane (or possibly a Group). You can put the ImageView and the Circles in the pane, and then place the pane in the rest of your layout (in the scroll pane, I think).
The other option you have is to call setManaged(false) on the nodes you add to the GridPane in order to instruct the GridPane not to position them, though this feels like more of a workaround.
I have created TreeTableView by coding. Then I created 2 fxml files. one(overview.fxml) has splitpane(left side is label andand button and right side nothing) and the other(RootLayout.fxml) one with a menu bar which wraps the first one. How can i set bind my treetable view which is in main class to the right side of splitpane?
try this sorry for the earlier blunder
SplitPane sp = FXMLLoader.load(getClass().getResource("/overview.fxml"));
StackPane container = new StackPane();
container.getChildren().add(YourCreatedTreeViewNode);
sp.getItems().add(container);
sp.setDividerPositions(0.3f, 0.6f, 0.9f); // you can tweak it any how
SplitPane two or more sides, each separated by a divider, which can be dragged by the user to give more space to one of the sides, resulting in the other side shrinking by an equal amount. Nodes needs to be placed inside a layout container before they are added into the SplitPane. If the node is not inside a layout container the maximum and minimum position of the divider will be the maximum and minimum size of the content.
Safe to say you just add your nodes to the SplitPane and it will do the positioning..
hope it helps
I'm using StackPanel as container for my figures, panels, etc. What I discovered, that coordinates X,Y (0,0) are placed right in center of my panel.
Is it possible to move it to left top od Pane ?
Calculating all dimensions from center is much more difficult.
You can set the layout of Nodes added to the StackPane to a position within the Stackpane using the StackPane.setAlignment(node, position) method:
Label topLeftLabel = new Label("Top Left");
StackPane stack = new StackPane();
stack.getChildren().add(topLeftLabel);
StackPane.setAlignment(topLeftLabel, Pos.TOP_LEFT);
Even though this is possible, from your brief description of how you are trying to use the StackPane, it sounds like you would be better off using a regular Pane, or a Group or an AnchorPane for the kind of absolute positioning you appear to be wanting to achieve.
Possibly look into using a visual tool such as SceneBuilder as well. Even if you don't end up using the FXML it outputs, SceneBuilder should give you a much better idea of how JavaFX layout mechanisms work. SceneBuilder makes use of AnchorPane as its default layout pane used to provide absolute positioning for elements (which seems to be what you want to achieve).
The previous answer is of course the best in this situation, but it is also wise to know that you can move Nodes on the StackPane using Translation.
Ex.
Label topLeftLabel = new Label("Top Left");
StackPane stack = new StackPane();
stack.getChildren().add(topLeftLabel);
topLeftLabel.setTranslateX(stack.getWidth()/2);
topLeftLabel.setTranslateY(stack.getHeight()/2);
It would do the same thing (but may look a bit worse)