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I have a csv file with quoted numeric column such as "'0001',a\n'0002',b\n'0003',c", for fread(), the first column will be character but for read.csv() the 1st column will be numeric type.
How can I make it work same as read.csv()?
You need to specify the type of the column through argument colClasses, e.g.
fread(..., colClasses = c("character", "character"))`.
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In R, I have a variable column of numbers which are being counted as variables. When I do as.numeric() on it I get the "NA caused by coercion" and nothing works.
This is what the code looks like
Volume.x has no NA in it, every single value is a number but it's read as a character and doing the as.numeric() prints a bunch of NA's
We can remove the , and convert to numeric
df1$Volume.x <- as.numeric(gsub(",", "", df1$Volume.x))
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I am trying to replace parenthesis with "." in the string "abc(def)ghi".
The code used is following:
str_replace_all("abc(def)ghi", "\\)|\\)", ".")
The output is "abc(def.ghi".
.
The desire output should be "abc.def.ghi" .
Any easy way to achieve this in R?
You can use this snippet:
str_replace_all("abc(def)ghi", "[()]", ".")
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(USING R)
So I imported a data set by using
xcars <- read.csv(file.choose())
and then I chose my data set which was originally an excel file.
So, I have a column named dist (short for displacement) and I want to choose the first 25 entries underneath that column and then plot it on a histogram, so I attempted the following.
carsUpTo25 <- xcars(1:25,)
hist(carsUpTo25$dist)
Of course this didn't work. However, any help on how I would do this would be helpful.
Try this-
hist(xcars[,dist[1:10]])
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Suppose I have a very simple data frame:
symbol <- c("A", "A^","B","C","C^")
df = data.frame(symbol)
Now imagine this is a very large dataframe so that I cannot easily list the rows in which the character "^" appears.
How can I subset the rows with (or without) that character?
Notice that things like:
df[grep("^", df$symbol)
or regular subsetting will not work since the carat "^" is usually used to represent the beggining of a string.
Many thanks
Add fixed to the grep function, as follows:
df[grep("^", df$symbol, fixed=T),]
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I am getting error on following lines of code...plz help.
Index (zero based) must be greater than or equal to zero and less than the size of the argument list.
string order1= string.Format ("exec a_add_user '{0}','{1}','{2}','{3}','{4}','{5}','{6}','{7}','{8}','{9}','{10}'",TextBox_first_name.Text ,TextBox_last_name.Text ,TextBox_user_name.Text ,TextBox_password.Text ,DropDownList_telephone_code.SelectedValue +TextBox_telephone_no.Text ,DropDownList_mobile_code.SelectedValue +TextBox_mobile_no.Text ,RadioButtonList_gender.SelectedValue ,DropDownList_country.SelectedValue ,DropDownList_city.SelectedValue ,TextBox_address.Text);
You're specifying 11 format items but have 10 strings you're trying to append.