I have a gallery (responsiveslides.js) that is launched within a jquery mobile popup that overlays the window. The desired look is to have the gallery scale based on the browser window.
Here is a stripped down working example of my setup and issue: https://jsfiddle.net/02ds2trp/
What I'm trying to accomplish is to have the popup div height match the scaled image. The blue background is ok on the sides of the image but I don't want it on the bottom/top. ie. the orange border should be tight to the image. Also the popup div shouldn't grow more then 70% of the screen.
Right now I have .popupGalleryBannerDIV with height:70% but that is growing it too big, removing that makes the image gallery have no height.
.popupGalleryBannerDIV {
position: fixed;
width: 100%;
background: #2795EE;
top: 15%;
left: 0px;
height: 70%; /* how to I make this dynamic? */
max-height: 70%;
}
Note: I've been playing with this for a week so some css markup on fiddle might be from failed attempts.
I'm having trouble figuring out how to make this work any help would be appreciated.
Edit:
Add some picture to help understand what I'm trying to do.
View post on imgur.com
Part of the problem, is that your slide is using a background image which has no default height/width on it's own. It's the content that dictates how much space should be filled up.
My suggestion is to use an tag instead or have some js function that will appropriately size the viewport height to match the image's ratio based on the viewport width.
This is how I ended up coding the size change:
function gallerySize() {
//set height of content to 70%
$('.popupGalleryBannerDIV').css("height", "70%");
//check img size compaired to it, of large set image height to height of content
var imgHeight = $('.popupGalleryBannerDIV').find('img').height();
//else if height is smaller set conect to height of img
if (imgHeight < $('.popupGalleryBannerDIV').height()){
$('.popupGalleryBannerDIV').css("height", imgHeight);
}
}
Related
i have portrait image (width: 869px; height: 2853px) which i wanna use as the background image for my website. the image should be responsive and always fill the entire width of the browser window. the image should keep its proportions and should never be cropped. therefor the height needs to adjust to the given width. since the image height is always bigger than the viewport height, you should be able to scroll to the bottom of the image, which should be the bottom of the website as well.
i'd really appreciate if someone would tell me how to do this.
I think the other commenters are ignoring your request for help in not "cropping" the image, when they keep suggesting use of background-size: cover.
Here's what I've gathered are your requirements:
An image to be a background, behind the content of your site.
The background image has a specific aspect ratio and should not be cropped
If the browser window doesn't match the images aspect ratio, it should allow scrolling vertically, but should always fit to the windows width.
A css only solution...
body {
position: relative;
margin: 0;
}
body::before {
content: '';
display: block;
position: absolute;
top: 0;
left: 0;
right: 0;
z-index: -1;
height: 0;
/* height / width = ratio% */
/* 2853px / 869px = 328.3084% */
padding-bottom: 328.3084%;
padding-bottom: calc(2853 / 869 * 100%);
background: url('//placekitten.com/869/2853') center top / 100% auto no-repeat;
}
Replace the url with the url of your image, and if the image pixel dimensions change, update those in the way I have commented out how padding-bottom should be calculated.
This creates a separate background element inside the body of the website and still allows you to have whatever content you want inside your site. But keep in mind, if you're on a very small screen, say 320px/480px, and the websites content becomes very tall because of the narrow width of the screen, this background image could be scrolled passed to account for the content. That won't break this code, but I would just suggest adding a background color or texture to your html element, which would show below the image in this case. Good luck.
So, I have a popup that opens for a gallery. The width of the image in the popup is set to 100%, stretching to fit it's containing div. And, the height is set to auto, so the height will resize, depending on the width (same ratio). This is great for wide images ... but for tall images, the tall images get cutoff at the bottom of the page. If the height is too tall (and the image is cutoff), then I want the height to shrink to a different size, and the width to adjust. I tried max-height, but that skews the image ratio (shrinking the height, but not affecting the width). Anyone have a better solution?
You can see the problem here:
Webpage
Click the image of the outside white door, with the flower bushes (the 8th image). You will see that the image is too tall for the page, and gets cut off at the fold.
Here is an image of the issue
Any ideas?
Do you want to have a CSS-only solution? Are you able to use Javascript?
If you can use Javascript you could add a condition to see if the height of the image is bigger than the window height and in this case add a class to change the behavior of the image.
var img = document.querySelector("img"); // Add correct selector here
if ( img.height > window.innerHeight ) {
img.classList.add("maxHeight");
}
img {
width: 100%;
height: auto;
}
.maxHeight {
height: 100%;
width: auto;
}
I am assuming I will need Javascript for this, but perhaps there is a CSS trick I'm not aware of.
I have a web page based on a square background image. Ideally, the user would always set the browser as a square, but I know that won't happen.
Because the image is square, if the image is set to fill the browser at 100%, the width is always the same as where the "bottom" of the page should be.
Thus, to position an element dynamically horizontally (so the page can be resized but still hold it's structure), the top position of said element is a percentage of the width.
In other words, if I have a horizontal bar that should ALWAYS be positioned 85% from the top of the image, the top position can be defined as 85% of width (top:85% [of browser width]). If you simply define the top of the horizontal bar as 85% (top:85%;), the horizontal bar's position will vary with the height of the browser window (whereas if you set it as 85% of the width it would be exactly where I want it).
As mentioned before, this is likely an easy thing to do with Javascript, but I don't know Javascript. I assume there isn't a function in CSS that will allow positioning by calculating a percentage of width, but that would be ideal.
Any help is greatly appreciated! Thanks in advance.
======================================
(source: renboy.com)
Unfortunately I'm a new user and the interface won't allow me to post a photo.
The page is square (a large, square image). There is a horizontal navbar who's top should be positioned 85% from the top of the image (it would be defined as (top:85%;) if the browser were opened to the exact same size and dimension (square) of the image).
However, if someone drags the bottom of their browser down (to make a tall rectangle), 85% will not be where I want it over the image. HOWEVER, 85% of the width will ALWAYS be in the exact right spot (because the image always fills 100% of the width). So, if I could define the horizontal position as 85% of the browser width (instead of height), the navbar would be exactly where I want it, no matter what dimensions the browser is open to. Thanks in advance for any possible solutions.
==================
Doing more research, it would seem that the answer might lie in Jquery (using position or maybe outerWidth or possibly something like var winWidth = $(window).width();), but I have no experience with Java/Javascript. Any help out there? Again, I want to set the position of the div holding the horizontal navigation bar to 85% of the width of the browser window. Thanks!
http://jsfiddle.net/f7RMA/
<div class="box">
<img src="http://renboy.com/images/squareWeb.jpg">
<div class="bar"></div>
</div>
CSS:
.box {
position: absolute;
z-index: -1;
top: 0;
left: 0;
width: 100%;
}
.box img {
display: block;
width: 100%;
}
.box .bar {
position: absolute;
width: 100%;
height: 10%;
top: 85%;
}
WTF happens: .box is set to 100% width. The image inside is also set to 100%. Images in non-crappy browsers keep their aspect ratio when they are resized by only one side. .box wants contain the image entirely, so its height will be set to image's height. Because .box is positioned absolute, you can put the .bar inside the .box and position it vertically as you wish, because .box now has a well-defined height.
Check out this picture to see what I am trying to accomplish. Basically I want to use a full screen background image and then overlay a div (in the linked picture, this is the gray area in the middle with the red lines around it) after the logo and nav on the left that will always have a 100% height regardless of scrolling.
The only way I think I can pull this off is to use a background image for the gray area that is repeated vertically, and then make a div for the full screen background image and change the z-indexes around to get the desired layering.
The css I was using for the overlay div was:
#overlay
{
position: absolute;
left: 360px;
top: 0;
bottom: 0;
width: 600px;
height: 100%;
}
But when you have to scroll for larger content, the div always ends at the "fold" and then the background image takes over for the rest of the content.
Are there any tricks I can take advantage of to do this in purely CSS? Also, I don't want to use CSS3 multiple backgrounds because of cross-browser concerns.
Try deleting the height: 100% and changing the position to relative.
You may need to add some padding and margins to get it exactly how you want but this should just about fix it.
I have an image in the header of my website. I'd like to use a CSS property to make it stretch across the width of the browser, so that it reacts to the user adjusting the browser window size, and so that the vertical axis of the image is scaled accordingly. Is this actually something that can be done?
Percentages will keep an image the whole width, and will update the image on browser resizing.
If you want the image to always be stretch, you can use:
img {
width:100%;
}
However, that can easily make the image look like total crap. A safer way might be:
img {
max-width:100%;
}
Either way will get the image changing sizes with browser resizing. However, the second won't stretch the image past it's natural size, so it doesn't look deformed.
You can set the width and height properties to percentages (for example, a width of 100% would cause the image to stretch across your page). This can be done using CSS.
CSS can certainly stretch an image (or, at least, I've used it to do so in Firefox at the folowing url: http://www.davidrhysthomas.co.uk/mindez/borked.html):
img {height: 100%;
width: 100%;
min-height: 600px;
min-width: 800px;
}
for example.
But...I think for it to react to the viewport resizing that JS would be probably your better-friend.
Here, give this a go, just apply this CSS style to the element that contains the image. In this example the image is on the background of the page body:
body
{
margin: 0;
padding: 0;
width: 100%;
background: url(images/YOUR-IMAGE.JPG) no-repeat left top;
background-size: 100%;
}
This will maximise your image across the element. Resizing the window will scale the image to fit the browsers new window size