I want a job to be run on first 1-8 days of a month at different times in each day in CA Autosys.
Example:
Job A should run as per below example
DAY 1 & DAY 2 & DAY 3 & DAY 5: 3am, 7am, 11am, 8:30pm
DAY 4 & DAY 6 : 3am, 7am, 11am
Please help me with the above condition.
This can be done by creating two jobs with two different calenders.
First create Job A with calendar A:
Select the dates day1, day2, day3, day5 in calendar A and provide the timings .
Similarly create Job A1 with calendar A1 in calendar A1 and provide the timings .
Select the dates day4, day6.
Please find the below example jil:
insert_job: JobA
job_type: cmd or box
run_calendar: Calendar_A
start_times: "03:00, 07:00, 11:00, 20:30"
Similarly, for the second job:
insert_job: JobA1
job_type: cmd or box
run_calendar: Calendar_A1
start_times: "03:00, 07:00, 11:00"
Related
Looking assistance in PL/SQL query.
Business Case:
Extract 2 previous business days of data from DATE column excluding weekends.
(Business Days - Monday to Friday)
End users are going to provide only 1 date to extract data.
Example:
If Effective_date is on Monday, then need previous 2 working days data of Thursday and Friday.
If Effective_date is on Tuesday, then need previous 2 working days data of Friday and Monday.
If Effective_date is on Wednesday, then need previous 2 working days data of Monday and Tuesday. and so on.....
I have a table in Smartsheets that has bookings in it.
If the appointment is confirmed it changes the status to scheduled. It also has a date assigned to it. I'm trying to use countifs to see how many are scheduled for the next 7 days.
This is the formula i have.
=COUNTIFS([Shoot Setup]:[Shoot Setup], "Styleshoots", [Date start]:[Date
start], >=TODAY(7))
This does not give me the correct value.
If i dont have the 7 modifier then it gives me the correct value for items scheduled from today.
But i want to just see the total for today plus 6 days 7 days in total.
Any suggestions?
The formula you've posted will return the count of rows where:
Shoot Setup = "Styleshoots"
AND
Date start is greater than or equal to seven days from today
Try using this formula instead:
=COUNTIFS([Shoot Setup]:[Shoot Setup], "Styleshoots", [Date start]:[Date start], >=TODAY(), [Date start]:[Date start], <=TODAY(7))
This formula will return the count of rows where:
Shoot Setup = "Styleshoots"
AND
Date start is greater than or equal to Today
AND
Date start is less than or equal to 7 days from today
The date-time that i have now:
"schedule": "R/2017-10-05T17:21:00/PT15M"
for now the job is scheduled for every 15 minutes (in chron), but if i want to perform it three times a day at a certain time and only Monday - Friday?
Is it possible to define in this format?
It's not possible
ISO8601 is designed to define intervals but only static. There is no way to define weekdays or weekends. This means you can only define interval for 3 times a day but not every day from Monday to Friday because then you will have not equal intervals between Friday and Monday.
What you can do is to create 15 jobs scheduled weekly.
For work I have a report where I compile the number of calls, emails, and texts a person makes each day. Along with this I need to pick out the earliest (Min) and the latest (max) times for each of those actions. I'm wondering if there isn't an easier way to me to pull this data from the date column rather than scrolling down for each person and finding the information.
You are right, there is definitely an easier way. What we need to rely on is that Excel stores times as the number of days since 0th January 1900 (so 1st January 1900 is day 1). Therefore, finding the earliest and latest times is simple a matter of finding the min and max values within a specific day.
I'm assuming that your data is set out as in the following. If it isn't, you can just edit my formula as appropriate.
A B C D
1 Person Date Time
2 Steve Monday 14:00
3 Steve Monday 14:05
4 Sharon Monday 12:00
5 Steve Tuesday 09:00
6 Sharon Tuesday 15:00
What we need to do is find the minimum time for Steve, given that date = Monday. We need to use an array formula. Array formulas let us 'look up' against more than one cell at the same time. The formula I would use is:
=MIN(IF(A2:A6="Steve",IF(B2:B6="Monday",C2:C6)))
Instead of clicking 'Enter' when you use this formula, you need to click Ctrl+Shift+Enter i.e., you enter the formula above and click Ctrl+Shift+Enter and Excel will return:
={MIN(IF(A2:A6="Steve",IF(B2:B6="Monday",C2:C6)))}
Can you see how to add more constraints to the look up? I've included an example screenshot below, where I've made a bigger table and also made the 'Steve' and 'Monday' references refer out to a cell, rather than just being hardcoded into the formula.
I have the data frame as I have below. I want to examine all Intake frequencies with "03 Month". My mission is to remove any Intake that is far away from three months by comparing the dates. Intake stands for when a client first register with an agency. 03 Month is three months follow up.
I am running R version 3.3.2 in Window environment.
I have taking the difference between the current date and the previous date in days. However, it is not straight forward to eliminate the observation with less than 90 days and greater than say 100 days as some patient has only intake and no follow up which i will like to keep.
Any help please.
ID DATE FREQ
1 08/09/2014 Intake
1 27/03/2015 Intake
1 01/09/2015 Intake
1 07/12/2015 03 Months
1 18/03/2016 06 Months