Angular2 recursive tree expand all - recursion

I have recursive tree component and I would like to expand all nodes on click from parent component, how can I do this? More details in plunker.
Plunker
I talking about this method:
expandAll(){
console.log("expanded all");
}

Just add an expandAll() method to the TreeComponent that expands all nodes and calls expandAll() on all nested TreeComponent components.
You can get all nested TreeComponent components by adding
#ViewChildren(TreeComponent) subTrees:QueryList<TreeComponent>;
and call the method on the childs like
expandAll() {
for(var subTree of this.subTrees.toArray()) {
subTree.expandAll();
}
}

After a while I guess I figure it out. I just added one more #Input() in TreeComponent:
#Input() expandAll: boolean;
and replaced *ngIf recursive condition to:
[hidden]="(!expanded[i] && !expandAll) || (expanded[i] && expandedAll)"
Its need a bit more work (collapsing all doesnt work that how it should), but it works that how I wanted.
Plnker

Related

How would I apply Material-UI managed styles to non-material-ui, non-react elements?

I have an application where I'm using Material UI and its theme provider (using JSS).
I'm now incorporating fullcalendar-react, which isn't really a fully fledged React library - it's just a thin React component wrapper around the original fullcalendar code.
That is to say, that I don't have access to things like render props to control how it styles its elements.
It does however, give you access to the DOM elements directly, via a callback that is called when it renders them (eg. the eventRender method).
Here's a basic demo sandbox.
Now what I'm wanting to do is make Full Calendar components (eg, the buttons) share the same look and feel as the rest of my application.
One way to do this, is that I could manually override all of the styles by looking at the class names it's using and implementing the style accordingly.
Or - I could implement a Bootstrap theme - as suggested in their documentation.
But the problem with either of these solutions, is that that:
It would be a lot of work
I would have synchronisation problems, if I made changes to my MUI theme and forgot to update the calendar theme they would look different.
What I would like to do is either:
Magically convert the MUI theme to a Bootstrap theme.
Or create a mapping between MUI class names and the calendar class names, something like:
.fc-button = .MuiButtonBase-root.MuiButton-root.MuiButton-contained
.fc-button-primary= .MuiButton-containedPrimary
I wouldn't mind having to massage the selectors etc to make it work (ie. For example - MUI Buttons have two internal spans, whereas Full Calendar have just one). It's mostly about when I change the theme - don't want to have to change it in two places.
Using something like Sass with its #extend syntax would is what I have in mind. I could create the full-calendar CSS with Sass easily enough - but how would Sass get access to the MuiTheme?
Perhaps I could take the opposite approach - tell MUI 'Hey these class names here should be styled like these MUI classes'.
Any concrete suggestions on how I would solve this?
Here is my suggestion (obviously, it's not straight forward). Take the styles from the MUI theme and generate style tag based on it using react-helmet. To do it event nicely, I created a "wrapper" component that do the map. I implemented only the primary rule but it can be extended to all the others.
This way, any change you will do in the theme will affect the mapped selectors too.
import React from "react";
import { Helmet } from "react-helmet";
export function MuiAdapter({ theme }) {
if (!theme.palette) {
return <></>;
}
return (
<Helmet>
<style type="text/css">{`
.fc-button-primary {
background: ${theme.palette.primary.main}
}
/* more styles go here */
`}</style>
</Helmet>
);
}
And the use of the adapter
<MuiAdapter theme={theme} />
Working demo: https://codesandbox.io/s/reverent-mccarthy-3o856
You could create a mapping between MUI class names and the calendar class names by going through ref's. It's possible that this is not what some would call "best practice"...but it's a solution :). Note that I updated your component from a functional component to a class component, but you could accomplish this with hooks in a functional component.
Add refs
Add a ref to the MUI element you want to set as a reference, in your case the Button.
<Button
color="primary"
variant="contained"
ref={x => {
this.primaryBtn = x;
}}
>
And a ref to a wrapping div around the component you want to map to. You can't add it directly to the component since that wouldn't give us access to children.
<div
ref={x => {
this.fullCal = x;
}}
>
<FullCalendar
...
/>
</div>
Map classes
From componentDidMount() add whatever logic you need to target the correct DOM node (for your case, I added logic for type and matchingClass). Then run that logic on all FullCalendar DOM nodes and replace the classList on any that match.
componentDidMount() {
this.updatePrimaryBtns();
}
updatePrimaryBtns = () => {
const children = Array.from(this.fullCal.children);
// Options
const type = "BUTTON";
const matchingClass = "fc-button-primary";
this.mapClassToElem(children, type, matchingClass);
};
mapClassToElem = (arr, type, matchingClass) => {
arr.forEach(elem => {
const { tagName, classList } = elem;
// Check for match
if (tagName === type && Array.from(classList).includes(matchingClass)) {
elem.classList = this.primaryBtn.classList.value;
}
// Run on any children
const next = elem.children;
if (next.length > 0) {
this.mapClassToElem(Array.from(next), type, matchingClass);
}
});
};
This is maybe a little heavy handed, but it meets your future proof requirement for when you updated update Material UI. It would also allow you to alter the classList as you pass it to an element, which has obvious benefits.
Caveats
If the 'mapped-to' component (FullCalendar) updated classes on the elements you target (like if it added .is-selected to a current button) or adds new buttons after mounting then you'd have to figure out a way to track the relevant changes and rerun the logic.
I should also mention that (obviously) altering classes might have unintended consequences like a breaking UI and you'll have to figure out how to fix them.
Here's the working sandbox: https://codesandbox.io/s/determined-frog-3loyf

Which CSS selector is used when a DragOver event is detected?

I am creating a custom RowFactory for my TableView to accept drag-and-drop files. I want to update the style of the specific Row when an acceptable DragOver event is detected.
Using :hover obviously won't work because that would apply even if the user is not dragging anything.
The end goal is simply to make it visually clear which row the user is about to drop the items onto.
Is there a selector I can use in my stylesheet to handle this? I could not find anything in the JavaFX CSS Reference Guide.
I can currently work around this by defining my own StyleClass and adding it in the setOnDragOver() method:
setOnDragOver(event -> {
// Determine if the dragged items are files
if (!this.isEmpty() && event.getDragboard().hasFiles()) {
event.acceptTransferModes(TransferMode.LINK);
this.getStyleClass().add("dragging");
}
});
However, attempting to remove the class when exiting does not seem to work:
setOnDragExited(event -> this.getStyleClass().remove("dragging"));
Edit: I should also clarify that each row may have other styles applied to them (based on several factors) and would want to ADD a style to the row when being dragged over, not replace all the rest)
As mentioned by #kleopatra, working with custom PseudoClass can work for you.
/**
* Interface to keep all custom pseudo classes.
*/
public interface Styles{
/** Dragged pseudo class. */
public static final PseudoClass DRAGGED_PSEUDOCLASS = PseudoClass.getPseudoClass("dragged");
}
In your code:
setOnDragOver(event -> {
if (!this.isEmpty() && event.getDragboard().hasFiles()) {
event.acceptTransferModes(TransferMode.LINK);
this.pseudoClassStateChanged(Styles.DRAGGED_PSEUDOCLASS,true);
}
});
setOnDragExited(event -> this.pseudoClassStateChanged(Styles.DRAGGED_PSEUDOCLASS,false));
In CSS:
.table-row-cell:dragged{
-fx-background-color:$custom-color;
}

How to set style for an element in typescript?(Angular)

How can I set the background colour for an item within an if statement in typescript? I used querySelector but the answer can use anything to achieve the result.
The selector is (.mat-step:nth-child(2) .mat-step-header .mat-step-icon-selected).
Here is the code in a stackblitz.
I would appreciate any help!
The stackblitz example can be helpful but there is a lot in there to summarise what you are askign for, this answer is a generic way of doing so, meaning you can apply it to your code as and where you see fit.
Declare you boolean.
public value = true;
Now declare the CSS class you would like to use.
.exmaple-class {
background: red;
}
Then on the selected HTML element you want to apply the class.
<div [class.example-class]="value === true"></div>
or just
<div [class.example-class]="value"></div>
As this still equates to true. If value were set to false then the class would not be applied.
If you want to start building more classes and options for a specific element you can look into Angular's ngStyle.
Add in this, think this is what you are also asking for, little different. It only runs after the view is loaded, not working in you example because the HTML has not yet been drawn.
public ngAfterViewInit(): void
{
this.changeColour();
}
public changeColour() {
document.querySelector<HTMLInputElement>(".mat-step-icon-selected").style.backgroundColor = 'red';
}
}
Then add a click event to ensure that each time you select something the selector is updated.
<div class="center-contrainer" (click)=changeColour()>

Calling a Stylus {block} with a variable in an iteration

I'm trying to generate classes with Stylus {block} insertions while on an iteration with that code:
// Blocks
flexbox =
display flex
inline-flexbox =
display inline-flex
// Properties collection
props = {
'flexbox': 'flex',
'inline-flexbox': 'inline-flex'
}
// Generating classes
for kProp, vProp in props
.u-{vProp}
{kProp}
{kProp} is supposed to output {flexbox} and {inline-flexbox} but I guess there's some kind of syntax conflict between calling a Stylus {block} and calling the iteration variable.
So basically with this code, I got no output at all.
I also tried to escape the { } but no luck.
Does anyone know a workaround?
No proper solution but some workarounds I found:
You can replace {blocks} by extending $placeholders but be aware that with Stylus you can't extend inside a Media Query (it just ignore the MQ part)
You can simply replace {blocks} by mixins() (and it works inside Media Queries) which is the one I chose.
So basically now my code looks like this:
// Blocks
flexbox()
display flex
inline-flexbox()
display inline-flex
// Properties collection
props = {
'flexbox': 'flex',
'inline-flexbox': 'inline-flex'
}
// Generating classes
for kProp, vProp in props
.u-{vProp}
{kProp}()

CSS: What does "input[type="search"]::-webkit-search-decoration" do?

I wonder what the the part ::-webkit-search-decoration do in the CSS selector for input[type="search"]::-webkit-search-decoration?
And why is this causing en DOM Exception error?
function is(selector, element) {
var div = document.createElement("div"),
matchesSelector = div.webkitMatchesSelector;
return typeof selector == "string" ? matchesSelector.call(element, selector) : selector === element;
}
is('input[type="search"]::-webkit-search-decoration', document.body);
It allows you to make search boxes look uniform across multiple browsers. Chrome for instance has default styling for search boxes that does not fit into some designs.
here is a good link on the topic.
http://geek.michaelgrace.org/2011/06/webkit-search-input-styling/
It just makes your search box little bit styled.As it is one of the property for css3 then it will not work on every browser.
Have a look in this link
http://css-tricks.com/webkit-html5-search-inputs/

Resources