Say I have a string of date like "3/23/2016" and just want to change the format to 3/23/2016. I try:
as.Date("3/23/2016, "%m%d%Y") but keeps giving me NA, as well as trying other methods. Anyone know a easy/fast way to do this? 03/23/2016 is ok too.
Try this:
b=as.Date(a, "%m/%d/%Y"),
It will give you the result then
Try:
Class(b)
to find the format.
Hope this helps :)
Another option is lubridate
library(lubridate)
mdy("3/23/2016")
#[1] "2016-03-23"
Related
I required date as mentioned below in if condition.
if day('2019-12-23') <=15 then '2019-11-16' else '2019-12-01'.
I have tried writing codes in R, but output is not correct.
Codes
ifelse(day(Sys.Date()) <=15,
(ymd(Sys.Date()-day(Sys.Date()-1)) %m-% months(1))+15,
ymd(Sys.Date()-day(Sys.Date()-1)))
Output
18231
Required Output
2019-12-01
Please help me with the solution.
Got the solutions thanks. forgot to convert into character.
updated query
ifelse(day(Sys.Date()) <=15,
as.character((ymd(Sys.Date()-(day(Sys.Date()-1))) %m-% months(1))+15),
as.character(ymd(Sys.Date()-(day(Sys.Date()-1)))))
Based on the structure of the data, I could not import the data by defining the types prior to upload/import.
So, doing that won't work. Anyway, it comes out as a number, below for examples:
43683
43686
43689
I did try some methods. Below is the code I did use and it did sort of end up turning it into a date but the year is wrong (comes out 2089 instead of 2019). I did do trimws prior to the below.
Transactions_Combined$Trans_Date <- as.numeric(Transactions_Comvined$Trans_Date)
Transaction_Combined <- as.Date(Transactions_Combined$Trans_Date)
Comes out as:
'2089-08-07'
'2089-08-10'
'2089-08-13'
Just want an accurate date and make sure I'm doing it right too. Thanks for your help!
Use the function readxl::read_excel() from the readxl-package to read in your excel-data.
Set the col_types-argument to "Date", and it will read the excel-dates to POSIXct-timestamp.
If this is not an option, you can try
as.POSIXct( colum_with_excel_times * 24 * 3600 + as.POSIXct( "1899-12-30 00:00" ) )
Another option could be janitor::excel_numeric_to_date()
I have dataset with column Date such
1-Apr-08
18-Sep-09
And I want to transform them to
01/04/08
18/09/09
I try
format(as.Date(d, "%d-%b-%y"), "%d/%m/%y")
but it doesn't work
UPD I found that my code doesn't work because system language of my PC is russian. When I try to transform 1-Апр-08, it works (Апрель = April).
When your d is a character, you can use:
format(as.Date(d, "%d-%b-%y"), "%d/%m/%y")
If not, then use
format(as.Date(as.character(d), "%d-%b-%y"), "%d/%m/%y")
My code was correct. It didn't work because system language of my PC was russian. For example, When I tried to transform 1-Апр-08, it worked routinely (Апрель is April in russian)
How to show date and time in one label?
lbldatetime.Text = DateTime.Now.ToString("hh:mm:ss");
I want it in 05-10-2013 9:47am format.
Use "tt" for the AM/PM designator:
lbldatetime.Text = DateTime.Now.ToString("MM-dd-yyyy h:mmtt");
See here for the complete reference.
You can format the date and time with the ToString() Method:
lbldatetime.Text = DateTime.Now.ToString("MM-dd-yyyy h:mmtt");
You can do that by using format provider to convert date time value in particular format
for more learn about format please review this link
http://msdn.microsoft.com/en-us/library/8kb3ddd4.aspx
Thank you.
i have date showing like the following
01-Nov-2012 12:00:00 AM
and i want to show the if the date is like above than
01-Nov-2012
this comes for few data only not for all,
How to do this in Xquery.
Please help
Regards
This will work:
fn:replace("01-Nov-2012 12:00:00 AM", "\s.*", "")
It replaces the space and everything after with the empty string.
You could use either:
tokenize(/test,' ')[1]
or
substring-before(/test,' ')
With /test being replaced with the appropriate path to the date.
It is so simple.
convert(VARCHAR(10),datetoformate,106)
thats it