Is it possible to modify style of "Pay with Card" Stripe button? I've tried modifying by,
adding a new class defined in external style sheet
modifying its own class of stripe-button in external style sheet
and editing it inline with style=""
But I cannot get the button to change its style.
It looks like it might be possible with the custom integration instead of the simple integration (source: https://stripe.com/docs/checkout#integration-simple), but I was hoping there was something simpler.
Button with default style:
Does anyone have experience with this?
(I'm integrating into Ruby on Rails if that makes any difference.)
None of those worked for me. I ended up hiding the button in javascript and making a new one.
<form action="/your-server-side-code" method="POST">
<script src="https://checkout.stripe.com/checkout.js" class="stripe-button"
data-key="xxx"
data-amount="999"
data-name="zzz"
data-locale="auto">
</script>
<script>
// Hide default stripe button, be careful there if you
// have more than 1 button of that class
document.getElementsByClassName("stripe-button-el")[0].style.display = 'none';
</script>
<button type="submit" class="yourCustomClass">Buy my things</button>
</form>
Search for this class:
.stripe-button-el span
I think this is where you have to modify your own button's style.
You may overwrite it within your own external css file.
Although a little hacky, for anyone wanting a super quick and simple way of using a different button along with the "simple integration", especially if you don't have "solid JavaScript skills", you can just hide the Stripe button with;
.stripe-button-el { display: none }
This way, any submit button within the form will call the checkout so you can just use the button you already had before introducing Stripe.
The following will override the background color with the custom color #EB649C. Disabling the background-image is required, as well as styling both the button and it's inside span tag.
button.stripe-button-el,
button.stripe-button-el>span {
background-color: #EB649C !important;
background-image: none;
}
You should use data-label its part of the regular stripe Checkout API:
<script
src="https://checkout.stripe.com/checkout.js" class="stripe-button"
data-key="<%= ENV.fetch('STRIPE_PUBLISHABLE_KEY') %>"
data-amount="10000"
data-label="Proceed to Pay with Card"
...
...
data-locale="auto">
</script>
Using jQuery, you can also simply scale the button like this:
<script>
$(function() {
$(".stripe-button-el").css({'transform': 'scale(2)'});
});
</script>
Or replace it by a button with any image you want, like this:
<script>
$(function() {
$(".stripe-button-el").replaceWith('<button type="submit" class="pay"><img src="/assets/paywithcard.jpg"></button>');
});
</script>
You can remove the button styles with Jquery and add your own. Worked a charm for me:
<script type="text/javascript">
$(document).ready(function(){
$(".stripe-button-el span").remove();
$("button.stripe-button-el").removeAttr('style').css({
"display":"inline-block",
"width":"100%",
"padding":"15px",
"background":"#3fb0ac",
"color":"white",
"font-size":"1.3em" }).html("Sign Me Up!");
});
</script>
The .stripe-button-el span actually works.
But you need to add !important in CSS to overwrite the default CSS.
You can try this,
$(".stripe-button-el").find("span").remove();
$(".stripe-button-el").html("Proceed to pay");
Pay with card is inside a span.
For those of you who want to change the background color of the button, make sure you do something like
.stripe-button-el span {
background: #5e366a !important;
background-image:none !important;
background-color: #5e366a !important;
}
in your css file. this will change the actual background of the button fr you. If you wish to have the parent div changed, you can do the same thing without the span or do a direct inline style.
Related
I need to turn the products listed in http://srougi.biz/gb/portfolio_listing/ into non-clickable items, but without loose its overlay effect. And since its a wordpress site, that I can't change the code, my only option is do it with CSS. I've tried to put pointer-events:none and cursor:default in the image, but it lost its overlay effect. I will appreciate your help.
we don't have a option to handle the events in css. use this jquery snippet to fix
$('.isotope-item .thumbnail a').click(function(e) e.preventDefault();
});
To deactivate the links in this case, you need to add some javascript code.
JS: Add this before </body> in the theme file: footer.php
<script>
var thumbnails = document.getElementsByClassName('thumbnail');
for(i = 0; i < thumbnails.length; i++){
thumbnails[i].getElementsByTagName("a")[0].setAttribute("onclick", "return false;");
}
</script>
CSS: Style to remove pointer from link.
.thumbnail a {
cursor: default !important;
}
In my web application I've set the CSS style for all the buttons like,
input[type=button], button
{
//
}
If I want to use some other CSS class for a particular button, If its a ASP button I can simply use the property EnableTheming="false".
but I've a html button, for this I need to disable theming. I tried EnableTheming, but its not working. How can I do this, can anyone help me here.
I tried to setting the removeClass using jQuery like,
<script type="text/javascript">
$(document).ready(function () {
$(":button").removeClass("marked");
});
</script>
but, its not working
you can remove the css class using jquery
$(":button").removeClass("marked");
if you want to add class
$(":button").addClass("marked");
If your class has something like this
input[type=button], button
{
border:1px solid #fco;
padding : 0;
margin:0;
}
Do this to make the style default
$(document).ready(function () {
$(":button").css({"border":"", "padding":"", "margin":""});
});
I need a button-like control that has a checked property, so that when clicked it stays pressed. Something like the "Purge responses" button in the example image below.
How can I do this in CSS? I'm a CSS newbie. Can someone provide an example or point to one that is similar to this?
PS: I know that I need to use Javascript to update a boolean variable that holds the state of the button, and dynamically apply a style to the button. My problem is more like how to create a button that contains a checkbox , as I have only one image for background.
http://i.stack.imgur.com/vBV6F.png
As for CSS you can do the following:
<style type='text/css'>
/* this is the style of an unchecked "button" */
.input-check{
display:inline-block;
height:20px;
padding:5px 8px;
background:green;
width:70px;
color:white
}
/* This is the style for a checked "button" */
.input-check.checked{
background:red;
color:black;
font-weight:bold
}
/* Hide the checkbox */
.input-check input{
display:none
}
</style>
Next is the HTML. To reduce JavaScript coding, it's best to nest a checkbox inside a label. This will make it automatically handle the checking/unchecking of the checkbox when you click on the label.
<label class="input-check"><input onchange="change_state(this)" type="checkbox" value="something" name="test"/> click me </label>
Finally the JavaScript:
<script type="text/javascript">
/* If you have more experience in JavaScript, I recommend not binding the change event this way, I didn't bother much about this part, since I guess it isn't part of the question */
function change_state(obj){
if (obj.checked){
//if checkbox is being checked, add a "checked" class
obj.parentNode.classList.add("checked");
}
else{
//else remove it
obj.parentNode.classList.remove("checked");
}
}
</script>
This is a jsFiddle for you to test.
Why don't you just style a checkbox to look like a button?
Then you can use the :checked CSS psudeo selector to style it the way you want without adding classes through javascript.
Here's an elaborate example in CodePen: http://codepen.io/arjabbar/pen/csafj
See the section here titled checkbox button. If I'm understanding your question correctly, that seems to do what you're after, maybe with a little modification.
No CSS needed, if I understand what you want correctly
<button><input type="checkbox" /> Purge</button>
Then you'll likely need javascript to check and uncheck the box when the button is clicked, but the above is the basic idea.
Here's with a bit of quick js
<html>
<head>
<script type="text/javascript">
function check() {
var c = document.getElementById('check') ;
c.checked = (c.checked) ? false : true ;
}
</script>
</head>
<body>
<button onclick="check()"><input type="checkbox" id="check" /> Purge</button>
</body>
</html>
I would like to style my selected button.
I would like to display a light-blue border around the image of my selected button to show which page the user is on. (or just use the same hover image as the selected button image when the button is pushed.)
I didn't have success with the css link selectors :visited, :focus, or :selected.
Does this require a javascript solution?
thanks for any pointers!
i usually just a extra class name called selected
<div class="button selected">Button 1</div>
<div class="button">Button 2</div>
.selected {
border: 1px solid #0000ff;
}
It depends on how you display your page (using ajax or refresh on every click). If you are using javascript to load the page content than you just put an extra classname using javascript when the button is clicked.
you should use :active pseudo class in css to achieve what you want.
jQuery Solution with your CSS
You would probably want to check first if it is selected, that way this solution works with things like Twitter Bootstrap, where you can make any element act like a button:
$(function () {
$('div.button').click(function(){
if ($(this).hasClass('selected') {
$(this).removeClass('selected');
//Insert logic if you want a type of optional click/off click code
}
else
{
$(this).addClass('selected');
//Insert event handling logic
}
})
});
You will, in fact, need to use javascript. I did this in a project a while back, by iterating through the links in the navbar, and setting a class called "selected" on the one the user is currently visiting.
If you use jQuery, you can accomplish it like this:
$(function() {
$('#navbar li').each(function() {
if ($(this).children('a').attr('href') == window.location.pathname)
{
$(this).addClass('active');
}
});
})
The CSS Pseudo-selector :active won't still be active after a pagereload.
I currently have an asp form that uses jquery for two elements: an image upload and a datapicker.
The code that implements the image upload is
$(function() {
$("#wcpImage").makeAsyncUploader({
upload_url: "/Business/ImageUpload",
flash_url: '../../Scripts/swfupload.swf',
button_image_url: '../../Content/images/blankButton.png',
disableDuringUpload: 'INPUT[type="submit"]'
});
});
With an input element <input type="file" id="wcpImage" name="wcpImage" />.
The code that implements the Datepicker using the JQueryUI DatePicker widget is
$().ready(function() {
$('#Business_Work_Cover_Expiry_Date').datepicker({ dateFormat: 'dd/mm/yy' });
});
With an input element generated by <%= Html.TextBoxFor(m => Model.Business.Liability_Expiry_Date) %>
The datepicker pops up when users enter the text box for the expiry date. The issue I'm having is that the buttons for the image upload are appearing over the top of the datepicker.
Can I use CSS z-index to fix this and how?
The use of the CSS z-index is most likely the only way to hand these types of issues.
This might do it:
<style type="text/css">
#ui-datepicker-div {
z-index: 9999999;
}
</style>
Turns out that it was because the buttons were flash objects being drawn with a wmode of Window, which means that z-index will have no effect as the button is rendered over the top of everything. Set the wmode to Transparent in the javascript and now it works.
Found the answer here.