I need a button-like control that has a checked property, so that when clicked it stays pressed. Something like the "Purge responses" button in the example image below.
How can I do this in CSS? I'm a CSS newbie. Can someone provide an example or point to one that is similar to this?
PS: I know that I need to use Javascript to update a boolean variable that holds the state of the button, and dynamically apply a style to the button. My problem is more like how to create a button that contains a checkbox , as I have only one image for background.
http://i.stack.imgur.com/vBV6F.png
As for CSS you can do the following:
<style type='text/css'>
/* this is the style of an unchecked "button" */
.input-check{
display:inline-block;
height:20px;
padding:5px 8px;
background:green;
width:70px;
color:white
}
/* This is the style for a checked "button" */
.input-check.checked{
background:red;
color:black;
font-weight:bold
}
/* Hide the checkbox */
.input-check input{
display:none
}
</style>
Next is the HTML. To reduce JavaScript coding, it's best to nest a checkbox inside a label. This will make it automatically handle the checking/unchecking of the checkbox when you click on the label.
<label class="input-check"><input onchange="change_state(this)" type="checkbox" value="something" name="test"/> click me </label>
Finally the JavaScript:
<script type="text/javascript">
/* If you have more experience in JavaScript, I recommend not binding the change event this way, I didn't bother much about this part, since I guess it isn't part of the question */
function change_state(obj){
if (obj.checked){
//if checkbox is being checked, add a "checked" class
obj.parentNode.classList.add("checked");
}
else{
//else remove it
obj.parentNode.classList.remove("checked");
}
}
</script>
This is a jsFiddle for you to test.
Why don't you just style a checkbox to look like a button?
Then you can use the :checked CSS psudeo selector to style it the way you want without adding classes through javascript.
Here's an elaborate example in CodePen: http://codepen.io/arjabbar/pen/csafj
See the section here titled checkbox button. If I'm understanding your question correctly, that seems to do what you're after, maybe with a little modification.
No CSS needed, if I understand what you want correctly
<button><input type="checkbox" /> Purge</button>
Then you'll likely need javascript to check and uncheck the box when the button is clicked, but the above is the basic idea.
Here's with a bit of quick js
<html>
<head>
<script type="text/javascript">
function check() {
var c = document.getElementById('check') ;
c.checked = (c.checked) ? false : true ;
}
</script>
</head>
<body>
<button onclick="check()"><input type="checkbox" id="check" /> Purge</button>
</body>
</html>
Related
i have this search bar in my application which i want to modify:
Right now the "X"-Icon is visible from the beginning even tho it does nothing before an input was done, so i want to make it appear AFTER the user starts entering text.
The icon is a SVG i added and styled seperatly.
I don't realy know how i can do this, i thought its easy and i can just use something like "::after" but it seems that this it not possible with input fields.
Ps.: im an absolute beginner in CSS so please have mercy.
Best way to achieve your requirement would be to have different classes which shows/hides the icon by checking when input is not empty in JS.
If you want to achieve without using JS you can target the adjacent button element when the input is focussed and add ::before pseudo element and style it.
input:focus+button:before {
content: "X";
position: absolute;
left: 0;
color: red;
}
It's not possible with CSS. You would have to use Javascript.
Javascript
// set the id of the x button to x-button
// set the id of the input field to input
var x_button = document.getElementById("x-button");
var input = document.getElementById("search-input");
input.oninput = function(){
if(this.value) x_button.classList.add("visible");
else x_button.classList.remove("visible");
}
CSS
.x-button { display:none;}
.visible {display:block;}
it is possible if you wanna do it using only css.
#Search{
font-size:22px;
color:green;
background-image:url('images/search.jpg');
background-repeat:no-repeat;
background-position:center;outline:0;
}
#Search::-webkit-search-cancel-button{
position:relative;
right:20px;
}
<input id="Search" name="Search" type="search" placeholder="Search" />
Is it possible to modify style of "Pay with Card" Stripe button? I've tried modifying by,
adding a new class defined in external style sheet
modifying its own class of stripe-button in external style sheet
and editing it inline with style=""
But I cannot get the button to change its style.
It looks like it might be possible with the custom integration instead of the simple integration (source: https://stripe.com/docs/checkout#integration-simple), but I was hoping there was something simpler.
Button with default style:
Does anyone have experience with this?
(I'm integrating into Ruby on Rails if that makes any difference.)
None of those worked for me. I ended up hiding the button in javascript and making a new one.
<form action="/your-server-side-code" method="POST">
<script src="https://checkout.stripe.com/checkout.js" class="stripe-button"
data-key="xxx"
data-amount="999"
data-name="zzz"
data-locale="auto">
</script>
<script>
// Hide default stripe button, be careful there if you
// have more than 1 button of that class
document.getElementsByClassName("stripe-button-el")[0].style.display = 'none';
</script>
<button type="submit" class="yourCustomClass">Buy my things</button>
</form>
Search for this class:
.stripe-button-el span
I think this is where you have to modify your own button's style.
You may overwrite it within your own external css file.
Although a little hacky, for anyone wanting a super quick and simple way of using a different button along with the "simple integration", especially if you don't have "solid JavaScript skills", you can just hide the Stripe button with;
.stripe-button-el { display: none }
This way, any submit button within the form will call the checkout so you can just use the button you already had before introducing Stripe.
The following will override the background color with the custom color #EB649C. Disabling the background-image is required, as well as styling both the button and it's inside span tag.
button.stripe-button-el,
button.stripe-button-el>span {
background-color: #EB649C !important;
background-image: none;
}
You should use data-label its part of the regular stripe Checkout API:
<script
src="https://checkout.stripe.com/checkout.js" class="stripe-button"
data-key="<%= ENV.fetch('STRIPE_PUBLISHABLE_KEY') %>"
data-amount="10000"
data-label="Proceed to Pay with Card"
...
...
data-locale="auto">
</script>
Using jQuery, you can also simply scale the button like this:
<script>
$(function() {
$(".stripe-button-el").css({'transform': 'scale(2)'});
});
</script>
Or replace it by a button with any image you want, like this:
<script>
$(function() {
$(".stripe-button-el").replaceWith('<button type="submit" class="pay"><img src="/assets/paywithcard.jpg"></button>');
});
</script>
You can remove the button styles with Jquery and add your own. Worked a charm for me:
<script type="text/javascript">
$(document).ready(function(){
$(".stripe-button-el span").remove();
$("button.stripe-button-el").removeAttr('style').css({
"display":"inline-block",
"width":"100%",
"padding":"15px",
"background":"#3fb0ac",
"color":"white",
"font-size":"1.3em" }).html("Sign Me Up!");
});
</script>
The .stripe-button-el span actually works.
But you need to add !important in CSS to overwrite the default CSS.
You can try this,
$(".stripe-button-el").find("span").remove();
$(".stripe-button-el").html("Proceed to pay");
Pay with card is inside a span.
For those of you who want to change the background color of the button, make sure you do something like
.stripe-button-el span {
background: #5e366a !important;
background-image:none !important;
background-color: #5e366a !important;
}
in your css file. this will change the actual background of the button fr you. If you wish to have the parent div changed, you can do the same thing without the span or do a direct inline style.
In my web app (c#/MVC3), I have a huge set of checkboxes in a table. Rather than a table of checkboxes, I'd like for it to look like a wall of toggle buttons. To the user I want it to look like a wall of buttons and when they click one it is 'checked' and the button changes color.
I wasn't sure if there was CSS that could make a checkbox do this (look like a button and change colors on check rather than show a check mark), or if I would have to use some combination of buttons and javascript/jquery and hidden checkboxes or what.
The jQuery UI Button widget can handle that:
http://jqueryui.com/button/#checkbox
Yes, it is definitely possible to do what you want with pure CSS.
I think you should check out the jsFiddle mentioned on this question.
Radio buttons are generated by the operating system and cannot be easily styled.
If you wany something different you need to generate it using CSS/images and JavaScript.
First of all, I'd actually avoid doing this for usability concerns but if you still want to then read on.
This is actually quite tricky to achieve but it is possible. My solution avoids the need to assign individual IDs to your check-boxes.
Essentially, you will need an image sprite for the "on" and "off" states which you will position with the CSS background-position property, using a toggle class. Then, the following jQuery will allow you to not only swap the image state, but also confirm the respective checkbox as checked or unchecked for use of the form. Do note, that the "actual" checkbox is hidden from view but the functionality remains.
<form>
<input type="checkbox" class="custom" />
</form>
<style type="text/css">
.checkbox {
clear:left;
float:left;
background:url('your_image');
background-position:top;
width:20px;
height:20px;
display:block;
}
.toggled {
background-position:bottom !important;
}
</style>
$(document).ready(function () {
var checkboxes = $('form .custom'),
custom = $('<span></span>').addClass('checkbox');
checkboxes.before(custom);
checkboxes.css('visibility', 'hidden');
$('.checkbox').click(function () {
$(this).toggleClass('toggled');
var isChecked = $(this).next(':checkbox');
var value = isChecked.prop('checked') ? 'true' : 'false';
if (value == 'false') {
isChecked.prop('checked', true);
} else {
isChecked.prop('checked', false);
}
});
});
You will, of course, have to edit the CSS to suit your exact needs. I hope this helps as this task was deceptively non-trivial.
I have a Submit Button like this:
<input type="submit" data-corners="false" id="code_check_button" tabindex="5" data-rel="external" value="GO">
which - with a custom css theme - outputs this: http://sht.tl/59y3m
Now I would like to use the id (#code_check_button) to style the button with more specificity.
Unfortunately jquerymobile automagically transforms the input type submit in a snippet of code I cannot control: http://sht.tl/cQq
As you can note, the original button ID is useless...
Can you tell me how may I custom style that button (of course, without wrapping it in an extra tag...)?
Thank you!
Numerous ways this can be achieved..
Here are a few examples:
submit {
styles:styles;
}
Not the most compatible in older browsers:
input[type="submit"] {
styles:styles;
}
Then you can target the ID:
#code_check_button {
styles:styles;
}
In your stylesheet add the ID #code_check_button and provide the desired style you want.. see example below :-
#code_check_button {
your desired style properties here...
}
EDIT:
You can use the class of the generated div and style the button accordingly. In this generated snippet you have two elements to style. please find below :-
.ui-btn {
style properties here...
}
.ui-btn .ui-btn-text {
style properties here...
}
CSS
#code_check_button {
color:#000 !important;
width:200px !important;
}
You can see I have added !important tag in all the css properties. This is because of overwritten the jQ mobile default styles.
If something keeps changing your intended css into useless code, this may be a situation where you would resort to simple text (eg. nano for mac or notepad for windows) Web design programs are double edged swords, most of the time the bells and whistles on these programs help make things easier, but sometimes they can make things more complicated. To custom style a button all you have to do is put your id or class selector name in the input tag and then enter the css for it. For example
CSS
#code_check_button { background-image: url(/*desired image url*/);
background-color: /*desired background color*/;
color: /*desired font color*/; }
HTML
<input id="code_check_button" type="submit" name="submit">
Just try it in notepad this time.
I would like to style my selected button.
I would like to display a light-blue border around the image of my selected button to show which page the user is on. (or just use the same hover image as the selected button image when the button is pushed.)
I didn't have success with the css link selectors :visited, :focus, or :selected.
Does this require a javascript solution?
thanks for any pointers!
i usually just a extra class name called selected
<div class="button selected">Button 1</div>
<div class="button">Button 2</div>
.selected {
border: 1px solid #0000ff;
}
It depends on how you display your page (using ajax or refresh on every click). If you are using javascript to load the page content than you just put an extra classname using javascript when the button is clicked.
you should use :active pseudo class in css to achieve what you want.
jQuery Solution with your CSS
You would probably want to check first if it is selected, that way this solution works with things like Twitter Bootstrap, where you can make any element act like a button:
$(function () {
$('div.button').click(function(){
if ($(this).hasClass('selected') {
$(this).removeClass('selected');
//Insert logic if you want a type of optional click/off click code
}
else
{
$(this).addClass('selected');
//Insert event handling logic
}
})
});
You will, in fact, need to use javascript. I did this in a project a while back, by iterating through the links in the navbar, and setting a class called "selected" on the one the user is currently visiting.
If you use jQuery, you can accomplish it like this:
$(function() {
$('#navbar li').each(function() {
if ($(this).children('a').attr('href') == window.location.pathname)
{
$(this).addClass('active');
}
});
})
The CSS Pseudo-selector :active won't still be active after a pagereload.