Dynamic button in gridview ASP.NET c# - asp.net

Question

i have a grid view in Asp.net. i want to generate button for specific rows.
Like i have a column named as "Status". If status is "Accept" a button should be generated in that particular row.
column

Answer 1

You can use a TemplateField in ASP.NET GridView and conditionally set the Button visibility, like shown below:
<asp:GridView runat="server" AutoGenerateColumns="false">
<Columns>
<asp:BoundField DataField="Status" HeaderText="Status" />
<asp:TemplateField>
<ItemTemplate>
<asp:Button runat="server" Text="Accept"
Visible='<%# Eval("Status")=="Accept" %>' />
</ItemTemplate>
</asp:TemplateField>
</Columns>
</asp:GridView>
Hope this will help.

Answer 2

first add template field button like this
<asp:TemplateField HeaderText="status" ShowHeader="False">
<ItemTemplate>
<asp:Button ID="btn" runat="server" CausesValidation="false"
CommandName="Select" Text="button" />
</ItemTemplate>
</asp:TemplateField>
and codebehind
protected void grid_RowDataBound(object sender, GridViewRowEventArgs e)
{
if (e.Row.RowType == DataControlRowType.DataRow)
{
Button btn = (Button)e.Row.FindControl("btn");
if (e.Row.Cells[1].Text == "Accept")//replace 1 by your column(status) index in gridview
{
btn.Visible = true;
}
else
{
btn.Visible = false;
}
}
}
and to add code to this button so add it on
protected void grid_SelectedIndexChanging(object sender, GridViewSelectEventArgs e)
{
//code
}