I know I can set
//RepositoryItemGridLookUpEdit riglue
eePozycje.gvView.Columns[KolNazwa].ColumnEdit = riglue;
but all I have is GridLookUpEdit.
How can I set GridLookUpEdit into column cel, or transform GridLookUpEdit into RepositoryItemGridLookUpEdit ?
//DONE
I found it in GridLookUpEdit.Properties.
Refer the documentation
The RepositoryItemLookUpEdit class contains settings specific to the
GridLookUpEdit control. You can access these settings via the editor's
GridLookUpEdit.Properties object. See the GridLookUpEdit topic for
details on the control.
You need to create repository items as standalone objects only to
specify inplace editors for container controls (such as the XtraGrid,
XtraTreeList, etc)
I think you that How to Assign Editors for In-Place Editing. Now If you want to set editors in particular cell then you have to handle the GridView.CustomRowCellEdit. The event occurs dynamically for each visible cell and allows you to supply an editor to individual cells, based on the position of the cell (its column and row).
Refer this - Assigning Editors to Individual Cells
example:
using DevExpress.XtraGrid.Views.Grid;
private void gridView1_CustomRowCellEdit(object sender, CustomRowCellEditEventArgs e) {
if (e.Column.FieldName == "FieldName") return;
GridView gv = sender as GridView;
string fieldName = gv.GetRowCellValue(e.RowHandle, gv.Columns["FieldName"]).ToString();
switch (fieldName) {
case "Population":
e.RepositoryItem = repositoryItemSpinEdit1;
break;
case "Country":
e.RepositoryItem = repositoryItemComboBox1;
break;
case "Capital":
e.RepositoryItem = repositoryItemCheckEdit1;
break;
}
}
Hope this help.
Related
I'm using a base class to modify the behavior of any Telerik RadGrid that appears on my ASP.Net pages. In the base class, I want to perform certain operations (set Css, tool tips, etc) on many common columns, but not every common column exists in every grid.
In the ItemDataBound event I'm getting an instance to the GridDataItem and in turn I want to get a reference to one or more of the contained cells of the GridDataItem:
var cell = gridDataItem["ColumnUniqueName"]
Problem is that this throws a GridException if the named column doesn't exist:
Cannot find a cell bound to column name 'ColumnUniqueName'
Is there a way to test for existence of a column by name before referencing it or am I
stuck using try catch?
Will sent me on the right path:
var tableView = gridDataItem.OwnerTableView;
var gridColumn = tableView.Columns.FindByUniqueNameSafe(uniqueName);
if (gridColumn != null)
{
var cell = gridDataItem[gridColumn];
...
Try using the RenderColumns collection:
protected void rgGrid_ItemDataBound(object sender, GridItemEventArgs e)
{
if (e.Item is GridDataItem)
{
bool found = (from d in rgGrid.MasterTableView.RenderColumns select d).Any(d => d.UniqueName == "ColumnUniqueName");
}
}
I have encountered a problem and I didn't manage to find any soultions yet. Let me simplify things a bit.
I have 2 forms, the first contains an ASP ListBox with multi select mode enabled. I submit the form and in the other form I use just for testing purposes this snippet of code:
protected void Page_Load(object sender, EventArgs e)
{
foreach (string formKey in Request.Form.AllKeys)
{
if (formKey != null)
{
if (formKey.Equals("ctl00$MainContent$ListBox1"))
Label1.Text = Request.Form[formKey];
}
}
}
The problems is that the values that come from the listbox (the values that i selected in the previous form) are separated by "," for ex. "test1,test2,test3". How can i change this separator to "$" for example? I need to change it because the actual values may contain "," and i don't manualy feed them to the listbox.
I can't use any other mode of transfering this values between the form because the entire application uses this model. The values that i get are then sent to a workflow where there will be manipulated and in the workflow i need to know where each listbox item starts and ends so it must be an unique separator.
Any help is apreciated! Thank you very much
Thank you MatteKarla but unfortunately this does not solve my problem. Yes, this is a good way of transfering the values from one form to another.
However i must use the method I described above with Request form keys because the listbox is one of many others "parameters" that are generated at runtime and have their values sent to a workflow method that takes this values. And i can't afford to change that in my application.
My problem is that coma (",") separator is used by default with a multiselect listbox.
I thought that there maybe is a method to change that separator from coma to another char because the coma can also be included in the value itself and this will create confusion.
As i said if i select three values test1, test2 and test3, the result with my method will be a string looking like "test1,test2,test3". However a "test1$test2$test3" would be much better.
But I'm affraid that changing this default separator is not possbile. I must think at a method to overcome this problem like replacing before feeding the listbox all the intended coma from the values with some other char not to create confusion. But this is not a great way of doing it.
On your first page/form (First.aspx.cs) create a public property with the listbox:
public ListBox PostedListBox { get { return ListBox1; } }
Set the postback-url for the button to Second.aspx
Second page in the aspx-file after the #Page-directive add:
<%# PreviousPageType VirtualPath="~/First.aspx" %>
Then in Form_Load on Second.aspx.cs you can extract the values:
if (PreviousPage != null)
{
ListBox postedListbox = PreviousPage.PostedListBox;
foreach (var index in postedListbox.GetSelectedIndices())
{
var itemText = postedListbox.Items[index].Text;
}
}
Or you could just try to locate the control by using:
if (PreviousPage != null)
{
var control = PreviousPage.FindControl("ListBox1") as ListBox;
}
Third Edit:
You could use GetValues:
Request.Form.GetValues("ctl00$MainContent$ListBox1");
returns a string array containing each of the selected items.
I will be starting a project soon at my company and the client would like to have the option in the portal to add textboxes or checkboxes as an administrator,,, so for instance initially I may have something like
Name [textBox]
Phone [textBox]
So the client would like to log in as an admin and be able to add
Name [textBox]
Phone [textBox]
Receive Brochure [checkBox] //added by client.
Forget about the portal and the admin part.. what I would like to know is what would be the best way to design this (the user to be able to add elements)
Any ideas would be much appreciated
Regards
You could create an additional aspx-form in which the User (or the Admin) is able to define and create his/her own forms, you supply the Variable names and they choose to add the controls, save it in a specific scheme in the Database, e.g.
UserForm:
UserID FormID
Form:
FormID FormName
FormElement:
FormID VariableName ControlType Index
Of course this could also be done by an administrator and be visible by everyone.
To view the specific forms you could add yet another aspx-page containing the following code:
protected void Page_Load(object sender, EventArgs e)
{
//you saved the FormName or ID to Session when you accessed it
string formName = Session["FormName"].ToString();
//this handles getting the elements for this Form from DB
List<FormElement> elementList = FormElement.GetForForm(formName);
this.renderForm(elementList);
}
private void renderForm(List<FormElement> eList)
{
foreach(FormElement fe in eList)
{
//Labels left, Controls right, of course this is just a design decision
if(fe.Index%2==1)
{
Label lbl = new Label();
lbl.Text = fe.Variable;
lbl.ID = fe.ControlType + fe.Variable;
divLeft.Controls.Add(lbl);
}
else
{
dynamic ctrl = null;
switch (fe.ControlType)
{
case "TextBox":
ctrl = new TextBox();
break;
case "CheckBox":
ctrl = new CheckBox();
break;
default:
break;
}
ctrl.ID = fe.ControlType + fe.Variable;
divRight.Controls.Add(ctrl);
}
}
}
Later on after the User hitting submit you'd be able to receive the values entered into those Controls by accessing divRight.FindControl(fe.ControlType + fe.Variable) since that should be unique per Form.
This approach assumes you're using .NET 4.0 (because of dynamic), but of course you can do this just fine without it, it'll just be more code.
Please let me know if this is what you searched for or if it was helpful.
Thanks,
Dennis
From what I have done in the past where I had to create a dynamic survey based on a client needs. I had a database that contained the following tables:
Survey - stores list of client surveys.
Controls - listed the type of controls that would be needed. For example, textbox, checkbox etc.
Survey Controls - links all the controls required for a survey.
User values - stores the values entered in a controll based on the survey used.
I then added some logic to dynamically create the controls based on a survey selected by reading the values from my database.
I am using DevExpress Xtragrid control in my C#.net windows application.
I enter some value into the first cell of the grid and if i go to second cell , the value entered in the first cell disappears.
How to retain the value entered in the cell ?
I am assuming that you are using this for an unbound column in a gridView (Xtragrid), first step is make sure to go to the column properties, and change the UnboundType property value to the datatype that you will be entering into that column, example below uses double.
Assign the CustomUnboundColumnData event to your gridView. Make sure that you declare a class level variable (named _userEnteredData in code sample below) to hold the value that you are entering into your gridView, then add the following piece of code, but make sure that you change the names to match your gridView and variable names:
Class level variable declaration:
private double _userEnteredData = 0;
Now the event:
private void gridView1_CustomUnboundColumnData(object sender, DevExpress.XtraGrid.Views.Base.CustomColumnDataEventArgs e)
{
if (e.Column == gridColumn_YourColumn && e.IsSetData)
{
_userEnteredData = Convert.ToDouble(e.Value);
}
else if (e.Column == gridColumn_YourColumn && e.IsGetData)
{
e.Value = _userEnteredData;
}
}
I hope this helps.
You can get further details from here:
http://documentation.devexpress.com/#WindowsForms/CustomDocument1477
Few possibilities:
check FieldName property of edited column. Maybe there is a typo, so grid does not pass your entered value to underlying datasource
property that is bound to column must have public setter. If there is only getter, grid also won't be capable to store entered value
check ColumnOptions.ReadOnly property in grid column - must be set to false
Hope this helps
I want to bind a List to a GridView on a web page, but override the way the property names display via annotation. I thought System.ComponentModel would work, but this doesn't seem to work. Is this only meant for Windows Forms?:
using System.ComponentModel;
namespace MyWebApp
{
public class MyCustomClass
{
[DisplayName("My Column")]
public string MyFirstProperty
{
get { return "value"; }
}
public MyCustomClass() {}
}
Then on the page:
protected void Page_Load(object sender, EventArgs e)
{
IList<MyCustomClass> myCustomClasses = new List<MyCustomClass>
{
new MyCustomClass(),
new MyCustomClass()
};
TestGrid.DataSource = myCustomClasses;
TestGrid.DataBind();
}
This renders with "MyFirstProperty" as the column header rather than "My Column." Isn't this supposed to work?
When using .net 4 or later you can use gridview1.enabledynamicdata(typeof(mytype)). I haven't looked at all the types you can use there but I know the [displayname("somename")] works well but the [browsable(false)] doesn't omit the column from the grid. It looks like a knit one slip one from MS. at least you can easily rename column names and to omit a column I just declare a variable instead of using a property. It has the same effect...
Just by the way, using the designer to create columns is the easy way out but to just show a different column name takes way to much time especially with classes with many fields.
What SirDemon said...
The answer appears to be no, you can't. At least not out of the box.
The System.Web.UI.WebControls.GridView uses reflected property's name:
protected virtual AutoGeneratedField CreateAutoGeneratedColumn(AutoGeneratedFieldProperties fieldProperties)
{
AutoGeneratedField field = new AutoGeneratedField(fieldProperties.DataField);
string name = fieldProperties.Name; //the name comes from a PropertyDescriptor
((IStateManager) field).TrackViewState();
field.HeaderText = name; //<- here's reflected property name
field.SortExpression = name;
field.ReadOnly = fieldProperties.IsReadOnly;
field.DataType = fieldProperties.Type;
return field;
}
While System.Windows.Forms.DataGridView uses DisplayName if available:
public DataGridViewColumn[] GetCollectionOfBoundDataGridViewColumns()
{
...
ArrayList list = new ArrayList();
//props is a collection of PropertyDescriptors
for (int i = 0; i < this.props.Count; i++)
{
if (...)
{
DataGridViewColumn dataGridViewColumnFromType = GetDataGridViewColumnFromType(this.props[i].PropertyType);
...
dataGridViewColumnFromType.Name = this.props[i].Name;
dataGridViewColumnFromType.HeaderText = !string.IsNullOrEmpty(this.props[i].DisplayName) ? this.props[i].DisplayName : this.props[i].Name;
}
}
DataGridViewColumn[] array = new DataGridViewColumn[list.Count];
list.CopyTo(array);
return array;
}
Unfortunately, while you can override the CreateAutoGeneratedColumn, neither the missing DisplayName nor underlying property descriptor gets passed, and you can't override CreateAutoGeneratedColumns (although you could CreateColumns).
This means you'd have to iterate over reflected properties yourself and in some other place.
If all you care about is the header text in GridView, just use the HeaderText property of each field you bind. If you're autogenerating the columns, you just set the HeaderText after you've bound the GridView.
If you want a GridView that takes into account some attribute you placed on the properties of your bound class, I believe you'll need to create your own GridView.
I may be wrong, but I've not seen any ASP.NET Grid from control vendors (at least Telerik , Janus Systems and Infragistics) do that. If you do it, maybe sell the idea to them.
Are you using .net4, what you need to do is to set enabledynamicdata on the grid view to true.
You can do it now on asp.net mvc2. It works just like that