I'm trying to get box-shadow on all 4 sides of my element.
I've tried box-shadow: 4px 4px 4px 4px 5px grey but it doesn't work. There also doesn't seem to be a rule for specifically setting the blur of a box-shadow.
If you have googled this a bit more, you would have found the answer right away.
The box-shadow property syntax is the fallowing :
box-shadow : horizontal offset | vertical offset | blur | spread | color ;
So you want it on all sides means :
No offsets.
Blur as you like.
Spread here is key to this, setting 10px to the spread means 5px on all sides, basically, half the amount will be on each facing side.
* {
margin: 0;
padding: 0;
box-sizing: border-box;
}
div {
padding: 30px;
margin: 30px;
width: 300px;
height: 100px;
padding: 15px;
background-color: orange;
box-shadow: 0px 0px 10px 10px grey;
}
<div></div>
Also if you want to customize that you always define multiple shadows separated by a comma.
You have an extra value to box-shadow property. This works: box-shadow: 4px 4px 4px 5px grey
Try this instead 5px specify the blur distance of the shadow while 10px specify the horizontal and vertical shadow of the box-shadow. You can check this link for more info https://www.w3schools.com/css/css3_shadows.asp
div {
width: 300px;
height: 100px;
padding: 15px;
background-color: yellow;
box-shadow: 10px 10px 5px grey;
}
<body>
<div>This is a div element with a box-shadow</div>
</body>
or
you can modify yours like so
box-shadow: 4px 4px 5px grey
To get a box-shadow on all sides of your element, you'll need:
div {
width: 300px;
height: 100px;
padding: 15px;
background-color: lawngreen;
box-shadow: 0 0 20px black;
}
<div>All of my sides have a box-shadow!</div>
My code is as below
http://jsfiddle.net/gXN2u/219/
I am trying to add a border to each of the items with the class item-list. However it doesn't show.
My actual slider is a vertical slider.
What i want to achieve:
![enter image description here][1]
Please help
Just clear the float
<div class="item-list clearfix">
add clear fix style in your style sheet
or add float and width for the .item-list
.item-list {
border: 8px solid red;
box-shadow: 0px 0px 0px 10px #888888;
border-radius: 7px;
-moz-border-radius: 7px;
-webkit-border-radius: 7px;
float: left;/*added*/
width: 100%;/*added*/
}
Or, you can use overflow property
.item-list {
border-top: 1px solid red;
overflow: hidden;
}
.item-list:first-child {
border-top: 0;
}
http://jsfiddle.net/ewygux9t/
please refer to http://jsfiddle.net/3fTyt/806/
I need box 2 has the same box shadow style with box 1 but only top of box 2 must be shadowed.
I tried a lot but couldn't find a solution. Can you please help? regards.
Codes in jsfiddle
CSS
#box1 {
background: #fff;
box-shadow: 0 0 10px 1px rgba(0,0,0,.99);
font: bold 18px/1.2em sans-serif;
height: 100px;
margin: 15px auto;
padding: 75px 15px 25px;
text-align: center;
width: 200px; float:left; margin:50px;
}
#box2
{
background: #fff;
box-shadow: 0 0 10px 1px rgba(0,0,0,.1), 0 -1px 1px rgba(0,0,0,.99);
font: bold 18px/1.2em sans-serif;
height: 100px;
margin: 15px auto;
padding: 75px 15px 25px;
text-align: center;
width: 200px; float:left; margin:50px;
}
HTML
<div id="box1">box 1</div>
<div id="box2">box 2: only top shadow is required and should has same shadow style with box 1</div>
You might try something like this :
#box2 {
box-shadow: 0px -10px 10px -10px rgba(0,0,0,.99);
...
}
Why these settings ?
horizontal offset = 0px : no horizontal offset,
vertical offset = -10px : 10px to the top,
blur radius = 10px : just used the same value as #box1,
spread distance = -10px : as for spread distance, a positive value would expand the shadow, but a negative value make it "shrink" (see the box-shadow documentation here). As we're using a 10px blur radius, we need to use at least a -10px spread distance to avoid seeing any shadow on the left, right and bottom sides.
Which gives us a pretty cool result, I think. Pretty close from what you were looking for :
<div class="row">
some content
<div class="info-box">
some other content
</div>
</div>
.row {
float: left;
margin-bottom: 1.5%;
border: 1px solid #e3e3e3;
-webkit-border-radius: 4px;
-moz-border-radius: 4px;
-ms-border-radius: 4px;
-o-border-radius: 4px;
border-radius: 4px;
background-color: rgb(250, 250, 250);
width: 685px;
-webkit-box-shadow:rgb(153,153,153) 0px 1px 2px 0px;
-moz-box-shadow:rgb(153,153,153) 0px 1px 2px 0px;
-ms-box-shadow:rgb(153,153,153) 0px 1px 2px 0px;
-o-border-box-shadow:rgb(153,153,153) 0px 1px 2px 0px;
box-shadow:rgb(153,153,153) 0px 1px 2px 0px;
}
.row:hover {
background-color: rgb(240, 245, 245);
-moz-box-shadow: inset 0 0 5px #4d4d4d;
-webkit-box-shadow: inset 0 0 5px #4d4d4d;
box-shadow: inset 0 0 5px #4d4d4d;
}
.info-box {
position: relative;
border-left: 1px solid #e3e3e3;
padding: 15px;
width: 170px;
font-size: 0.93em;
color: #363636;
float: left;
}
Alright, I have this info box inside row. Since at .row:hover, I'm creating an inner shadow. The border-left of the info-box seems to show on top of the shadow when you hover on row.
My question is if you can make the shadow on top of the border. Thanks in advance.
Note: z-index doesn't work for me.
Of course it's on top: the child has to appear above the parent, otherwise it'd be hidden by it. To achieve the desired effect, you would have to apply the shadow to an element that came above, ie after, the .info-box. You can achieve this with no additional markup by using the :after pseudo-element.
If you take a look at this fiddle, I've achieved the basic proposition — although you may want to shift the border to the pseudo element or adjust dimensions to get it positioned just right.
Basic guide to what I did:
Gave .row the CSS position: relative so we can place children in relation to it.
Moved everything apart from the background property in the .row:hover rule to a new .row:hover:after rule.
Added content: ' ' to force the pseudo element to display.
Added positioning, height and width, top and left to make the pseudo element cover available width.
EDIT: Felipe points out in the comments that any attempt to click in through to object within .row will be intercepted by the :after element, but suggests you can use pointer events set to pointer-events: none to mitigate the problem (in everything other than IE and Opera). I've updated my example to show this in action.
I guess the title is kind of hard to understand, so I'll explain.
I am trying to achieve this effect:
(a box which has rounded corners and its border, which also has rounded borders).
I've managed to do this, by using the background-clip property:
(rounded corners for border but not for inner box)
The question is, how can I achieve rounded corners for the inner box?
Thank you!
EDIT
The HTML I am using:
<header class="body template-bg template-border radius-all">
<nav>
<ul>
<li>Link 1</li>
<li>Link 2</li>
<li>Link 3</li>
<li>Link 4</li>
</ul>
</nav>
</header>
And the CSS:
.radius-all {
border-radius: 10px;
-moz-border-radius: 10px;
-webkit-border-radius: 10px;
}
.template-bg {
background: #FFF;
-moz-background-clip: padding;
-webkit-background-clip: padding;
background-clip: padding-box;
}
.template-border {
border: 5px solid rgba(255, 255, 255, 0.2);
}
Inner border calculations
First, you'll need to remove -vendor-background-clip: padding-box or set them to border-box the default in order to achieve the inner border radius.
The inner border radius is calculated as the difference of the outer border radius (border-radius) and the border width (border-width) such that
inner border radius = outer border radius - border width
Whenever the border-width is greater than the border-radius, the inner border radius is negative and you get some awkward inverted corners. Currently, I don't believe there is a property for adjusting the inner-border-radius, so you'll need to calculate it manually.
In your case:
inner border radius = 6px - 5px = 1px
Your new CSS should be:
.radius-all { border-radius: 6px; -moz-border-radius: 6px; -webkit-border-radius: 6px; }
.template-bg { background: #FFF; }
.template-border { border: 5px solid rgba(255, 255, 255, 0.2); }
Simply subtract the border-radius (6px) values from the border-width value (5px) in order to achieve your desired inner-border-radius:
Code that works for me
Tested on Firefox 3.x, Google Chrome, and Safari 5.0
.radius-all { border-radius: 10px; -moz-border-radius: 10px; -webkit-border-radius: 10px; }
.template-bg { background: #FFF; }
.template-border { border: 5px solid rgba(0, 0, 0, 0.2); } /* Note that white on white does not distinguish a border */
Adding color overlays in JavaScript
<script type="text/javascript">
var bodyBgColor = document.getElementsByTagName('body')[0].style.backgroundColor;;
// insert opacity decreasing code here for hexadecimal
var header = document.getElementsByTagName('header')[0];
header.style.backgroundColor = bodyBgColor;
</script>
I'm not entirely sure how to do hexadecimal arithmetic in JavaScript but I'm sure you can find an algorithm in Google.
Applying General Borders
Are you using a separate box <div> for your border through its background property? If so, you'll need to apply border-radius and its vendor specific properties on both the border box and the inner box:
<div id="border-box" style="border-radius: 5px;">
<div id="inner-box" style="border-radius: 5px;">
</div>
</div>
A much more efficient way would simply have the inner-box manage its own border:
<div id="inner-box" style="border: 4px solid blue; border-radius: 5px">
<!-- Content -->
</div>
CSS-wise, you could just declare a .rounded-border class and apply it to every box that will have rounded borders:
.rounded-borders {
border-radius: 5px;
-moz-border-radius: 5px;
-webkit-border-radius: 5px;
-khtml-border-radius: 5px;
}
And apply the class to any boxes that will have rounded borders:
<div id="border-box" class="rounded-borders">
<div id="inner-box" class="rounded-borders">
</div>
</div>
For a single box element, you'll still be required to declare the border size in order to be shown:
<style type="text/css">
#inner-box { border: 4px solid blue; }
</style>
<div id="inner-box" class="rounded-borders">
</div>
Another solution is to have matching inner and outer borders combined with border-radius is to "fake" the border using the <spread-radius> value of the box-shadow property. This produces a solid shadow which can easily pass for a regular border.
For instance, to achieve a 4px border and a 4px white border radius, try this:
/* rounded corners */
-webkit-border-radius: 4px;
-moz-border-radius: 4px;
border-radius: 4px;
/* drop shadow */
-webkit-box-shadow: 0px 0px 0px 4px #fff;
-moz-box-shadow: 0px 0px 0px 4px #fff;
box-shadow: 0px 0px 0px 4px #fff;
If you want to add a "real" drop shadow to the entire container, you can simply chain your shadow statements like so:
/* drop shadow */
-webkit-box-shadow: 0px 0px 0px 4px rgba(255,255,255,1.0),
1px 1px 8px 0 rgba(0,0,0,0.4);
-moz-box-shadow: 0px 0px 0px 4px rgba(255,255,255,1.0),
1px 1px 8px 0 rgba(0,0,0,0.4);
box-shadow: 0px 0px 0px 4px rgba(255,255,255,1.0),
1px 1px 8px 0 rgba(0,0,0,0.4);
Note: Keep in mind here that the order of the statements is the order in which it will be rendered.
The only thing to beware of is that the initial "faux border" will overlap the first X pixels (where X is the width of the border) of any shadow you want beneath it (and combine, if you're using RGBa opacity on it below 100%.)
So it won't work in all situations, but it'll get the majority. I use this pretty frequently when regular borders are not ideal.
Since there is no such thing as inner-border-radius for CSS, the browsers default it to border-radius - border-width. If you don't like that, the typical solution is to create two divs with borders to mimic the inner border radius but this solution brings in more design into the html. It is also a pain if it's a common border template used through out the site.
I managed to figure a way to keep it all in css by producing the inner div using :after and content: "". So for your case it would be:
.template-border {
position: relative;
border-radius: 5px;
background-color: #000;
border: 10px solid #000;
z-index: -2;
}
.template-border:after {
content: "";
display: block;
position: absolute;
width: 100%;
height: 100%;
border-radius: 5px;
background-color: #FFF;
z-index: -1;
}
Most of the solutions on this page are from the web stone ages (before 2013 - i.e. even before IE11).
Since IE11, the way to do this is easy...
Just in case someone is Googling for this answer after 2013 (it's almost 2020 today) and got sent here, here is the most simple, compatible, and easy way to do this, even if you need to support IE11...
(Feel free to change the px values for the look you want, or better yet, use variables and transpile with Stylus or SASS)
Example HTML...
<div class="wrapper">
<div class="content">
your content goes here
</div>
</div>
Example CSS...
.wrapper {
border-radius: 25px;
border: solid 25px blue;
background-color: blue;
}
.content {
border-radius: 10px;
background-color: white;
}
...Presto.
The problem is not the coding of the CSS but the mathematics of a circle.
Essentially your border-inner-radius (I know this property does not exist) is equal to the border-radius - border-width.
Quite simply work out what you want your inner radius to be and then add the width of the border to achieve the desired effect.
border-inner-radius + border-width = border-radius
Based on Leo Wu's idea, here it is my solution:
.my-div
{
background-color: white;
border: solid 20px black;
border-radius: 10px;
box-shadow: 0 0 10px black;
height: 100px;
left: 30px;
position: relative;
top: 20px;
width: 200px;
}
.my-div:before
{
background-color: white;
border-radius: 5px;
content: "";
display: block;
height: calc(100% + 20px);
left: -10px;
position: absolute;
top: -10px;
width: calc(100% + 20px);
z-index: 1;
}
.some-content
{
height: calc(100% + 20px);
left: -10px;
position: relative;
top: -10px;
width: calc(100% + 20px);
z-index: 3;
}
.some-header
{
background-color: green;
border-radius: 5px 5px 0 0;
height: 30px;
}
<html>
<body>
<div class="my-div">
<div class="some-content">
<div class="some-header">my title</div>
<div>some other content</div>
</div>
</div>
</body>
</html>
You need to have two div elements, one inside the other, and use a cross browser rounded corner css, like this:
.small-rounded {
border: 1px solid ##000;
-moz-border-radius-topleft: 5px; -webkit-border-top-left-radius: 5px;
-moz-border-radius-topright: 5px; -webkit-border-top-right-radius: 5px;
-moz-border-radius-bottomleft: 5px; -webkit-border-bottom-left-radius: 5px;
-moz-border-radius-bottomright: 5px; -webkit-border-bottom-right-radius: 5px;
border-radius: 5px;
}
Today I run into this "problem". My solution uses two divs and overlaps the inner div on the outer one.
A good thing about my solution is that it does not alter the background color (it can be transparent).
You can control the outer border radius by modifying the outer-border class and the inner border with the inner-border class.
.outer-border {
border: 10px solid #20b2aa;
border-radius: 5px;
display: flex;
flex-direction: column;
min-height: 100px;
}
.inner-border, .inner-border-evidence {
flex: 1;
border: 10px solid #20b2aa;
border-radius: 30px;
margin: -9px;
}
.inner-border-evidence {
border-color: #0a3b8a;
}
<div class="outer-border">
<div class="inner-border">
</div>
</div>
<br />
<p>Here you can see how the inner div overlaps the outer div.</p>
<div class="outer-border">
<div class="inner-border-evidence">
</div>
</div>
Another idea is to consider multiple radial-gradient to simulate the inner radius and you can control the outer and inner radius like you want without the need of any extra element:
.box {
width:150px;
height:150px;
margin:10px;
border:10px solid red;
border-radius:10px; /* Outer Radius*/
background:
radial-gradient(farthest-side at bottom right,#0000 98%,red) top left,
radial-gradient(farthest-side at top right,#0000 98%,red) bottom left,
radial-gradient(farthest-side at bottom left ,#0000 98%,red) top right,
radial-gradient(farthest-side at top left ,#0000 98%,red) bottom right,
blue;
background-size:25px 25px; /* inner Radius*/
background-repeat:no-repeat;
background-origin:padding-box;
}
<div class="box">
</div>
You can also have different values for each side:
.box {
width:150px;
height:150px;
margin:10px;
border:10px solid red;
border-radius:10px; /* Outer Radius*/
background:
radial-gradient(farthest-side at bottom right,#0000 98%,red) top left / 30px 30px,
radial-gradient(farthest-side at top right,#0000 98%,red) bottom left / 20px 20px,
radial-gradient(farthest-side at bottom left ,#0000 98%,red) top right / 50px 50px,
radial-gradient(farthest-side at top left ,#0000 98%,red) bottom right/ 10px 10px,
blue;
background-repeat:no-repeat;
background-origin:padding-box;
}
<div class="box">
</div>
You need to make the border-radius to a value greater than the border-width until you start to see a curve. It's not a set formula to set the border-radius of +1px greater than border-width. However, it's going to be a positive value, definitely. You need to experiment in the different browsers where you need this until you see the smallest possible border-radius value that works good enough for you in most browsers. (Some browsers may not support this.) For instance, in Google Chrome, I set a border-width to 10px, but had to set the border-radius to 13px before I started to see a semblance of an inner border curve, while 15px worked even better.
The best and fastest way is to do this
.curve {
width : 300px;
height: 100px;
border: 4px solid black;
border-bottom-left-radius: 20px;
border-bottom-right-radius: 20px;
border-top-right-radius: 20px;
border-top-left-radius: 20px;
}
<div class='curve'></div>
If you can't add an extra div you can accomplish this with a background images in each corner.
#nice-corners {
border: 5px solid green;
border-radius: 5px;
background-image: url(top-left.svg), url(top-right.svg), url(bottom-left.svg), url(bottom-right.svg);
background-position: left top, right top, left bottom, right bottom;
background-repeat: no-repeat;
background-size: 16px
}