I guess the title is kind of hard to understand, so I'll explain.
I am trying to achieve this effect:
(a box which has rounded corners and its border, which also has rounded borders).
I've managed to do this, by using the background-clip property:
(rounded corners for border but not for inner box)
The question is, how can I achieve rounded corners for the inner box?
Thank you!
EDIT
The HTML I am using:
<header class="body template-bg template-border radius-all">
<nav>
<ul>
<li>Link 1</li>
<li>Link 2</li>
<li>Link 3</li>
<li>Link 4</li>
</ul>
</nav>
</header>
And the CSS:
.radius-all {
border-radius: 10px;
-moz-border-radius: 10px;
-webkit-border-radius: 10px;
}
.template-bg {
background: #FFF;
-moz-background-clip: padding;
-webkit-background-clip: padding;
background-clip: padding-box;
}
.template-border {
border: 5px solid rgba(255, 255, 255, 0.2);
}
Inner border calculations
First, you'll need to remove -vendor-background-clip: padding-box or set them to border-box the default in order to achieve the inner border radius.
The inner border radius is calculated as the difference of the outer border radius (border-radius) and the border width (border-width) such that
inner border radius = outer border radius - border width
Whenever the border-width is greater than the border-radius, the inner border radius is negative and you get some awkward inverted corners. Currently, I don't believe there is a property for adjusting the inner-border-radius, so you'll need to calculate it manually.
In your case:
inner border radius = 6px - 5px = 1px
Your new CSS should be:
.radius-all { border-radius: 6px; -moz-border-radius: 6px; -webkit-border-radius: 6px; }
.template-bg { background: #FFF; }
.template-border { border: 5px solid rgba(255, 255, 255, 0.2); }
Simply subtract the border-radius (6px) values from the border-width value (5px) in order to achieve your desired inner-border-radius:
Code that works for me
Tested on Firefox 3.x, Google Chrome, and Safari 5.0
.radius-all { border-radius: 10px; -moz-border-radius: 10px; -webkit-border-radius: 10px; }
.template-bg { background: #FFF; }
.template-border { border: 5px solid rgba(0, 0, 0, 0.2); } /* Note that white on white does not distinguish a border */
Adding color overlays in JavaScript
<script type="text/javascript">
var bodyBgColor = document.getElementsByTagName('body')[0].style.backgroundColor;;
// insert opacity decreasing code here for hexadecimal
var header = document.getElementsByTagName('header')[0];
header.style.backgroundColor = bodyBgColor;
</script>
I'm not entirely sure how to do hexadecimal arithmetic in JavaScript but I'm sure you can find an algorithm in Google.
Applying General Borders
Are you using a separate box <div> for your border through its background property? If so, you'll need to apply border-radius and its vendor specific properties on both the border box and the inner box:
<div id="border-box" style="border-radius: 5px;">
<div id="inner-box" style="border-radius: 5px;">
</div>
</div>
A much more efficient way would simply have the inner-box manage its own border:
<div id="inner-box" style="border: 4px solid blue; border-radius: 5px">
<!-- Content -->
</div>
CSS-wise, you could just declare a .rounded-border class and apply it to every box that will have rounded borders:
.rounded-borders {
border-radius: 5px;
-moz-border-radius: 5px;
-webkit-border-radius: 5px;
-khtml-border-radius: 5px;
}
And apply the class to any boxes that will have rounded borders:
<div id="border-box" class="rounded-borders">
<div id="inner-box" class="rounded-borders">
</div>
</div>
For a single box element, you'll still be required to declare the border size in order to be shown:
<style type="text/css">
#inner-box { border: 4px solid blue; }
</style>
<div id="inner-box" class="rounded-borders">
</div>
Another solution is to have matching inner and outer borders combined with border-radius is to "fake" the border using the <spread-radius> value of the box-shadow property. This produces a solid shadow which can easily pass for a regular border.
For instance, to achieve a 4px border and a 4px white border radius, try this:
/* rounded corners */
-webkit-border-radius: 4px;
-moz-border-radius: 4px;
border-radius: 4px;
/* drop shadow */
-webkit-box-shadow: 0px 0px 0px 4px #fff;
-moz-box-shadow: 0px 0px 0px 4px #fff;
box-shadow: 0px 0px 0px 4px #fff;
If you want to add a "real" drop shadow to the entire container, you can simply chain your shadow statements like so:
/* drop shadow */
-webkit-box-shadow: 0px 0px 0px 4px rgba(255,255,255,1.0),
1px 1px 8px 0 rgba(0,0,0,0.4);
-moz-box-shadow: 0px 0px 0px 4px rgba(255,255,255,1.0),
1px 1px 8px 0 rgba(0,0,0,0.4);
box-shadow: 0px 0px 0px 4px rgba(255,255,255,1.0),
1px 1px 8px 0 rgba(0,0,0,0.4);
Note: Keep in mind here that the order of the statements is the order in which it will be rendered.
The only thing to beware of is that the initial "faux border" will overlap the first X pixels (where X is the width of the border) of any shadow you want beneath it (and combine, if you're using RGBa opacity on it below 100%.)
So it won't work in all situations, but it'll get the majority. I use this pretty frequently when regular borders are not ideal.
Since there is no such thing as inner-border-radius for CSS, the browsers default it to border-radius - border-width. If you don't like that, the typical solution is to create two divs with borders to mimic the inner border radius but this solution brings in more design into the html. It is also a pain if it's a common border template used through out the site.
I managed to figure a way to keep it all in css by producing the inner div using :after and content: "". So for your case it would be:
.template-border {
position: relative;
border-radius: 5px;
background-color: #000;
border: 10px solid #000;
z-index: -2;
}
.template-border:after {
content: "";
display: block;
position: absolute;
width: 100%;
height: 100%;
border-radius: 5px;
background-color: #FFF;
z-index: -1;
}
Most of the solutions on this page are from the web stone ages (before 2013 - i.e. even before IE11).
Since IE11, the way to do this is easy...
Just in case someone is Googling for this answer after 2013 (it's almost 2020 today) and got sent here, here is the most simple, compatible, and easy way to do this, even if you need to support IE11...
(Feel free to change the px values for the look you want, or better yet, use variables and transpile with Stylus or SASS)
Example HTML...
<div class="wrapper">
<div class="content">
your content goes here
</div>
</div>
Example CSS...
.wrapper {
border-radius: 25px;
border: solid 25px blue;
background-color: blue;
}
.content {
border-radius: 10px;
background-color: white;
}
...Presto.
The problem is not the coding of the CSS but the mathematics of a circle.
Essentially your border-inner-radius (I know this property does not exist) is equal to the border-radius - border-width.
Quite simply work out what you want your inner radius to be and then add the width of the border to achieve the desired effect.
border-inner-radius + border-width = border-radius
Based on Leo Wu's idea, here it is my solution:
.my-div
{
background-color: white;
border: solid 20px black;
border-radius: 10px;
box-shadow: 0 0 10px black;
height: 100px;
left: 30px;
position: relative;
top: 20px;
width: 200px;
}
.my-div:before
{
background-color: white;
border-radius: 5px;
content: "";
display: block;
height: calc(100% + 20px);
left: -10px;
position: absolute;
top: -10px;
width: calc(100% + 20px);
z-index: 1;
}
.some-content
{
height: calc(100% + 20px);
left: -10px;
position: relative;
top: -10px;
width: calc(100% + 20px);
z-index: 3;
}
.some-header
{
background-color: green;
border-radius: 5px 5px 0 0;
height: 30px;
}
<html>
<body>
<div class="my-div">
<div class="some-content">
<div class="some-header">my title</div>
<div>some other content</div>
</div>
</div>
</body>
</html>
You need to have two div elements, one inside the other, and use a cross browser rounded corner css, like this:
.small-rounded {
border: 1px solid ##000;
-moz-border-radius-topleft: 5px; -webkit-border-top-left-radius: 5px;
-moz-border-radius-topright: 5px; -webkit-border-top-right-radius: 5px;
-moz-border-radius-bottomleft: 5px; -webkit-border-bottom-left-radius: 5px;
-moz-border-radius-bottomright: 5px; -webkit-border-bottom-right-radius: 5px;
border-radius: 5px;
}
Today I run into this "problem". My solution uses two divs and overlaps the inner div on the outer one.
A good thing about my solution is that it does not alter the background color (it can be transparent).
You can control the outer border radius by modifying the outer-border class and the inner border with the inner-border class.
.outer-border {
border: 10px solid #20b2aa;
border-radius: 5px;
display: flex;
flex-direction: column;
min-height: 100px;
}
.inner-border, .inner-border-evidence {
flex: 1;
border: 10px solid #20b2aa;
border-radius: 30px;
margin: -9px;
}
.inner-border-evidence {
border-color: #0a3b8a;
}
<div class="outer-border">
<div class="inner-border">
</div>
</div>
<br />
<p>Here you can see how the inner div overlaps the outer div.</p>
<div class="outer-border">
<div class="inner-border-evidence">
</div>
</div>
Another idea is to consider multiple radial-gradient to simulate the inner radius and you can control the outer and inner radius like you want without the need of any extra element:
.box {
width:150px;
height:150px;
margin:10px;
border:10px solid red;
border-radius:10px; /* Outer Radius*/
background:
radial-gradient(farthest-side at bottom right,#0000 98%,red) top left,
radial-gradient(farthest-side at top right,#0000 98%,red) bottom left,
radial-gradient(farthest-side at bottom left ,#0000 98%,red) top right,
radial-gradient(farthest-side at top left ,#0000 98%,red) bottom right,
blue;
background-size:25px 25px; /* inner Radius*/
background-repeat:no-repeat;
background-origin:padding-box;
}
<div class="box">
</div>
You can also have different values for each side:
.box {
width:150px;
height:150px;
margin:10px;
border:10px solid red;
border-radius:10px; /* Outer Radius*/
background:
radial-gradient(farthest-side at bottom right,#0000 98%,red) top left / 30px 30px,
radial-gradient(farthest-side at top right,#0000 98%,red) bottom left / 20px 20px,
radial-gradient(farthest-side at bottom left ,#0000 98%,red) top right / 50px 50px,
radial-gradient(farthest-side at top left ,#0000 98%,red) bottom right/ 10px 10px,
blue;
background-repeat:no-repeat;
background-origin:padding-box;
}
<div class="box">
</div>
You need to make the border-radius to a value greater than the border-width until you start to see a curve. It's not a set formula to set the border-radius of +1px greater than border-width. However, it's going to be a positive value, definitely. You need to experiment in the different browsers where you need this until you see the smallest possible border-radius value that works good enough for you in most browsers. (Some browsers may not support this.) For instance, in Google Chrome, I set a border-width to 10px, but had to set the border-radius to 13px before I started to see a semblance of an inner border curve, while 15px worked even better.
The best and fastest way is to do this
.curve {
width : 300px;
height: 100px;
border: 4px solid black;
border-bottom-left-radius: 20px;
border-bottom-right-radius: 20px;
border-top-right-radius: 20px;
border-top-left-radius: 20px;
}
<div class='curve'></div>
If you can't add an extra div you can accomplish this with a background images in each corner.
#nice-corners {
border: 5px solid green;
border-radius: 5px;
background-image: url(top-left.svg), url(top-right.svg), url(bottom-left.svg), url(bottom-right.svg);
background-position: left top, right top, left bottom, right bottom;
background-repeat: no-repeat;
background-size: 16px
}
Related
I need to create a button like the one below, but it's proving exceedingly difficult to get that border effect without the use of images:
.
Specifically, the border effects I've seen never have a bevel effect - it's almost as though I need two borders. The colors, shape, and other aspects of the button are not the problem here.
Here's what I have so far, which is pretty close:
button {
border: 1px solid gray;
border-radius: 4px;
text-align: center;
display: inline-block;
padding: 5px 10px;
background: linear-gradient(to bottom, #f9fcff 0%,#93a0c6 100%);
}
<button>OK</button>
You can achieve this effect with one element, using a background: linear-gradient, double border and border-radius.
To apply the background even to the transparent middle part of the border, increase the size of the background (i.e. 140%) and adjust its position.
button {
background: linear-gradient(to bottom, #fff 0%, #8ab 100%);
background-size: 140%;
background-position: 0 50%;
border: 4px double #23538a;
border-radius: 6px;
padding: 5px 8px;
color: #23538a;
}
<button>OK</button>
This will get you close. Use a combination of box-shadow, padding, and 'border-radius`:
.btn-container {
display:inline-block;
border: solid 1px #224488;
border-radius: 4px;
padding: 2px;
background:#acd;
box-shadow:0px 4px 6px #cde inset;
}
.btn {
display:inline-block;
border: solid 1px #224488;
border-radius: 4px;
padding: 2px;
background:#acd;
box-shadow:0px 5px 10px #e0f0ff inset;
}
<div>
<span class='btn-container'>
<span class='btn'>Click here!</span>
</span>
</div>
Fiddle: https://jsfiddle.net/oqqpccmf/
I am having an unexpected 1px margin under a div residing in a fixed container. This issue only occurs in Edge (possibly in IE as well). After some testing, I was able to reproduce the bug with a bare bones example.
This picture, which you can reproduce running the snippet below, is composed of 3 square divs inside a fixed div. Firefox
In Edge, you can "fix" this issue by either disabling the property top: 50% in the container div, or by disabling border-*-right-radius: 6px in the divs inside it. Naturally, this isn't a fix, because I need both these properties to effectively implement this design.
How can I fix this? I tried adding borders the same color as the background, but the background is not opaque.
Edit: If you can't see it right away in IE/Edge, try to select the container div and slowly increase the value of the top property. In IE11, changing it from 5% to 6% already made the problem obvious again.
.box {
background-color: rgba(0,0,0,0.15);
height: 70px;
line-height: 70px;
text-align: center;
border-right: 1px solid rgba(0,0,0,0.2);
}
.box:hover {
background-color: rgba(50,50,100,0.15);
}
.box:first-child {
border-top-right-radius: 6px;
border-top: 1px solid rgba(0,0,0,0.2);
}
.box:last-child {
border-bottom-right-radius: 6px;
border-bottom:1px solid rgba(0,0,0,0.2);
}
.main {
width: 70px;
position: fixed;
left: 0;
top: 5%;
}
<div class="main">
<div class="box"></div>
<div class="box"></div>
<div class="box"></div>
</div>
Try to use border on parent div: http://jsfiddle.net/gtf0fa8n/1/
Border radius on parent does not brake inner divs rendering in IE
.main {
border: 1px solid rgba(0, 0, 0, 0.5);
border-left: 0;
border-radius: 0 6px 6px 0;
overflow: hidden;
}
.box {
background-color: rgba(0, 0, 0, 0.3);
height: 70px;
line-height: 70px;
text-align: center;
}
.box:hover {
background-color: rgba(50,50,100,0.15);
}
Just give boxshadow of 1px with same color on bottom.
box-shadow: #2a2e37 0px 1px 0px;
I want to trim my CSS border statement. I know there is a possibility, but I found always that one in the internet e.g. :
You would better do it through classes like this:
.box{
width: 100px;
height: 100px;
margin: 20px;
float: left;
}
.border{
border-width: 5px;
border-style: solid;
border-color: #98bf21;
}
.b1{ border-width: 5px 10px 15px 2px; }
.b2{ border-width: 5px 7px 10px 7px; }
.b3{ border-width: 15px 2px 10px 5px; }
<div class="box border b1"></div>
<div class="box border b2"></div>
<div class="box border b3"></div>
For for instance padding, you can write: padding: 5px 10px to set a five pixel top and bottom padding and a 10 pixel left and right padding.
But for border, that is not the case. You have to set the same value to all sides, or set the property for one side at a time.
You can however set just the width using border-left-width, so you could set a default border and override just the width for specific sides:
border: 5px solid #666;
border-left-width: 10px;
border-right-width: 10px;
Or use border-width, which lets you set multiple values for the width alone, in the same way as you can set padding.
i'm trying to add shadow effect only for single border while other borders have sharp borders. Does CSS has this power or are there other techniques i don't know?
#panel {
-moz-box-shadow:0 1px 10px #00c6ff;
-webkit-box-shadow: 0 1px 10px #00c6ff;
box-shadow:0 1px 10px #00c6ff;
width:25%;
height: 50px;
background-color:#161616;
color: #fff;
margin: 20px auto;
text-align: center;
}
HTML
<div id="panel">
<p>Panel Content</p>
</div>
i'm trying to do something like this
Instead of a box-shadow, you could use a :pseudo-element with linear-gradient.
#panel {
position: relative;
width: 25%;
height: 50px;
background-color: #161616;
color: #fff;
margin: 20px auto;
text-align: center;
}
#panel:after {
position: absolute;
content: '';
width: 100%;
height: 100%;
top : -10px;
left: 0;
background: linear-gradient(0deg, #00c6ff, #00c6ff calc(100% - 20px), rgba(0, 198, 255, 0));
z-index: -1;
}
<div id="panel">
<p>Panel Content</p>
</div>
Like this:
box-shadow: 0px -8px 5px -5px #00c6ff;
The fourth value is the spread radius. Positive values will cause the shadow to expand and grow bigger, negative values will cause the shadow to shrink. If not specified, it will be 0 (the shadow will be the same size as the element).
So basically you make the shadow smaller than your box, and make sure it sticks out on one side only.
shadows are not related to borders. They are independent of each other. There's no such thing as a "border shadow".
<div class="row">
some content
<div class="info-box">
some other content
</div>
</div>
.row {
float: left;
margin-bottom: 1.5%;
border: 1px solid #e3e3e3;
-webkit-border-radius: 4px;
-moz-border-radius: 4px;
-ms-border-radius: 4px;
-o-border-radius: 4px;
border-radius: 4px;
background-color: rgb(250, 250, 250);
width: 685px;
-webkit-box-shadow:rgb(153,153,153) 0px 1px 2px 0px;
-moz-box-shadow:rgb(153,153,153) 0px 1px 2px 0px;
-ms-box-shadow:rgb(153,153,153) 0px 1px 2px 0px;
-o-border-box-shadow:rgb(153,153,153) 0px 1px 2px 0px;
box-shadow:rgb(153,153,153) 0px 1px 2px 0px;
}
.row:hover {
background-color: rgb(240, 245, 245);
-moz-box-shadow: inset 0 0 5px #4d4d4d;
-webkit-box-shadow: inset 0 0 5px #4d4d4d;
box-shadow: inset 0 0 5px #4d4d4d;
}
.info-box {
position: relative;
border-left: 1px solid #e3e3e3;
padding: 15px;
width: 170px;
font-size: 0.93em;
color: #363636;
float: left;
}
Alright, I have this info box inside row. Since at .row:hover, I'm creating an inner shadow. The border-left of the info-box seems to show on top of the shadow when you hover on row.
My question is if you can make the shadow on top of the border. Thanks in advance.
Note: z-index doesn't work for me.
Of course it's on top: the child has to appear above the parent, otherwise it'd be hidden by it. To achieve the desired effect, you would have to apply the shadow to an element that came above, ie after, the .info-box. You can achieve this with no additional markup by using the :after pseudo-element.
If you take a look at this fiddle, I've achieved the basic proposition — although you may want to shift the border to the pseudo element or adjust dimensions to get it positioned just right.
Basic guide to what I did:
Gave .row the CSS position: relative so we can place children in relation to it.
Moved everything apart from the background property in the .row:hover rule to a new .row:hover:after rule.
Added content: ' ' to force the pseudo element to display.
Added positioning, height and width, top and left to make the pseudo element cover available width.
EDIT: Felipe points out in the comments that any attempt to click in through to object within .row will be intercepted by the :after element, but suggests you can use pointer events set to pointer-events: none to mitigate the problem (in everything other than IE and Opera). I've updated my example to show this in action.