I am using Microsoft-Cognitive service (Form-Recognizer) to analyze the document and read its content for further operations. I wanted to analyze the pdf file which is uploaded at the blob.
I am able to get the content using local file path but once I am providing the blob URL then it is not able to open the file.
file-path looks like: https:\blob\SupplierformUpdate1.pdf
curl: (26) couldn't open file: the File path
I have trained it properly and got the model id.
I tried an analyze service.
curl -X POST "https://<Endpoint>/formrecognizer/v1.0-preview/custom/models/<modelID>/analyze" -H "Content-Type: multipart/form-data" -F "form=#\"<path to your form>\";type=<file type>" -H "Ocp-Apim-Subscription-Key: <subscription key>"
https://learn.microsoft.com/en-us/azure/cognitive-services/form-recognizer/quickstarts/curl-train-extract#train-a-form-recognizer-model
I want to get the content by providing the blob URL of the pdf file.
To analyze a form and extract data with Form Recognizer you can send the file as a multipart/form.
I am unable to get my cURL command to work in Postman. I am lost on how the Expect header works. My cURL command breaks when I remove the expect header. I am not even supplying a value for that header? I figured out the cURL command from here
This works and successfully uploads the jar to Apache Flink:
curl -X POST -H "Expect:" -F "jarfile=#/home/myUserName/goDev/src/myProject.dev/flink-init/bin/target/flink-java-project-1.jar" http://localhost:9081/jars/upload
When I import as raw text into POSTMAN I get:
{
"error": "Failed to upload the file."
}
The HTTP Header "Expect" indicates to the server to expect a large amount of data. Something on the server side is requiring that header. Populate it with "100-continue".
Regarding the file upload, in PostMan on the Body tab change the parameter type to "File" instead of "Text". Then you should able to select your file. If you hover your mouse over the key "jarfile" you should see the option appear.
I think what is happening is your request is sending the value of the file path instead of the contents of the file.
I have a mini program/server built on one of my computers (Machine1) and I am trying to create or overwrite a file through cURL on another computer (Machine2). So Machine2 is connected to Machine1. Ive been looking through cURL's documentation for command that will do this but have had no luck and as well on stack overflow.
https://curl.haxx.se/docs/manpage.html
I have also tried the examples on this SO post:
HTTP POST and GET using cURL in Linux
Any idea as to what the command might be through command prompt? (equivalent of a POST command). I have tried so far using -O, -K, -C and a multitude of others which have not worked.
In command line, all you need to do is using curl --form to simulate a multipart/form-data POST request:
curl --form "testfile=#thefilename.jpg" http://<Machine2>/<Path>
testfile is the field name used for form, if you don't care, just use any english word.
# is used here to make file thefilename.jpg get attached in the post as a file upload. Refer to curl man doc.
In server side, URL http://<Machine2>/<Path> should be listened. When curl send the previous POST request, server side program should get it, extract the attached file (thefilename.jpg), and save to disk.
Can anyone help me to find out a unix command that is used to upload/download a file on/from an URL?
Particular URL in which i'm trying to upload/download is protected with an user id and password.
I guess curl serves this purpose but not aware of how to use it? Could you please give me sugegstions on this?
curl has a command line argument named -d (for data) and you can use it like this to send a file(you need to add a # before a file-name to have curl treat it as a file and not a value:
curl -X POST -d #myfilename http://example.com/upload
You can add multiple -d arguments if you need to send a FORM value along with your file. Like so:
curl -X POST -d #myfilename -d name=MyFile http://example.com/upload
I need to make a POST request via cURL from the command line. Data for this request is located in a file. I know that via PUT this could be done with the --upload-file option.
curl host:port/post-file -H "Content-Type: text/xml" --data "contents_of_file"
You're looking for the --data-binary argument:
curl -i -X POST host:port/post-file \
-H "Content-Type: text/xml" \
--data-binary "#path/to/file"
In the example above, -i prints out all the headers so that you can see what's going on, and -X POST makes it explicit that this is a post. Both of these can be safely omitted without changing the behaviour on the wire. The path to the file needs to be preceded by an # symbol, so curl knows to read from a file.
I need to make a POST request via Curl from the command line. Data for this request is located in a file...
All you need to do is have the --data argument start with a #:
curl -H "Content-Type: text/xml" --data "#path_of_file" host:port/post-file-path
For example, if you have the data in a file called stuff.xml then you would do something like:
curl -H "Content-Type: text/xml" --data "#stuff.xml" host:port/post-file-path
The stuff.xml filename can be replaced with a relative or full path to the file: #../xml/stuff.xml, #/var/tmp/stuff.xml, ...
If you are using form data to upload file,in which a parameter name must be specified , you can use:
curl -X POST -i -F "parametername=#filename" -F "additional_parm=param2" host:port/xxx
Most of answers are perfect here, but when I landed here for my particular problem, I have to upload binary file (XLSX spread sheet) using POST method, I see one thing missing, i.e. usually its not just file you load, you may have more form data elements, like comment to file or tags to file etc as was my case. Hence, I would like to add it here as it was my use case, so that it could help others.
curl -POST -F comment=mycomment -F file_type=XLSX -F file_data=#/your/path/to/file.XLSX http://yourhost.example.com/api/example_url
I was having a similar issue in passing the file as a param. Using -F allowed the file to be passed as form data, but the content type of the file was application/octet-stream. My endpoint was expecting text/csv.
You are able to set the MIME type of the file with the following syntax:
-F 'file=#path/to/file;type=<MIME_TYPE>
So the full cURL command would look like this for a CSV file:
curl -X POST -F 'file=#path/to/file.csv;type=text/csv' https://test.com
There is good documentation on this and other options here: https://catonmat.net/cookbooks/curl/make-post-request#post-form-data
I had to use a HTTP connection, because on HTTPS there is default file size limit.
https://techcommunity.microsoft.com/t5/IIS-Support-Blog/Solution-for-Request-Entity-Too-Large-error/ba-p/501134
curl -i -X 'POST' -F 'file=#/home/testeincremental.xlsx' 'http://example.com/upload.aspx?user=example&password=example123&type=XLSX'