Can anyone help me to find out a unix command that is used to upload/download a file on/from an URL?
Particular URL in which i'm trying to upload/download is protected with an user id and password.
I guess curl serves this purpose but not aware of how to use it? Could you please give me sugegstions on this?
curl has a command line argument named -d (for data) and you can use it like this to send a file(you need to add a # before a file-name to have curl treat it as a file and not a value:
curl -X POST -d #myfilename http://example.com/upload
You can add multiple -d arguments if you need to send a FORM value along with your file. Like so:
curl -X POST -d #myfilename -d name=MyFile http://example.com/upload
Related
I have the following method to post data to server :
curl --ipv4 http://localhost:3000/api/tests/1 -d #test.csv
I am trying to post a file with curl to a meter app
In meteor I am not able to read the data because I cant attach a key to the curl option data arrives as the key itself
example
contents of test.csv = > 1,1,1
at server
console.log('route to host' , this.request.body); yields {{1,1,1} : ''}
And yes I even tried -F data=#test.csv with no success as well
How can I add a key and make the contents of the file as value when posting through curl?
basically -d for curl means read the file and use its content as data
If you start the data with the letter #, the rest should be a file name to read the data from, or - if you want curl to read the data from stdin. Multiple files can also be specified. Posting data from a file named 'foobar' would thus be done with --data #foobar. When --data is told to read from a file like that, carriage returns and newlines will be stripped out. If you don't want the # character to have a special interpretation use --data-raw instead.
in order to send the file itself youll need something like -F
(HTTP) This lets curl emulate a filled-in form in which a user has pressed the submit button. This causes curl to POST data using the Content-Type multipart/form-data according to RFC 2388. This enables uploading of binary files etc. To force the 'content' part to be a file, prefix the file name with an # sign. To just get the content part from a file, prefix the file name with the symbol <. The difference between # and < is then that # makes a file get attached in the post as a file upload, while the < makes a text field and just get the contents for that text field from a file.
Example, to send your password file to the server, where 'password' is
the name of the form-field to which /etc/passwd will be the input:
curl -F password=#/etc/passwd www.mypasswords.com
in your case probably use -F
curl --ipv4 http://localhost:3000/api/tests/1 -F data=
if you want to file to be uploaded as a file use -F data=#test.csv
This works!!
curl --ipv4 --data-urlencode "csv#test.csv" http://localhost:3000/api/tests/1
Hope this helps someone :)
I know I can do this:
curl 'http://localhost:8080/myhandler' -F "myfile=#localfile"
so is it somehow possible to send a file that is on the web? Something like
curl 'http://localhost:8080/myhandler' -F "myfile=#SOMEURL"
I cannot find the right way to apply that (I am guessing it is possible?)
As per the curl documentation -F can read from stdin using -. So if you pipe output from the url as follows, I think it should work:
curl -vvv <url1> | curl -vvv 'http://localhost:8080/myhandler' -F "myfile=#-"
I am trying to send a DELETE request with a url parameter using CURL. I am doing:
curl -H application/x-www-form-urlencoded -X DELETE http://localhost:5000/locations` -d 'id=3'
However, the server is not seeing the parameter id = 3. I tried using some GUI application and when I pass the url as: http://localhost:5000/locations?id=3, it works. I really would rather use CURL rather than this GUI application. Can anyone please point out what I'm doing wrong?
The application/x-www-form-urlencoded Content-type header is not required (well, kinda depends). Unless the request handler expects parameters coming from the form body. Try it out:
curl -X DELETE "http://localhost:5000/locations?id=3"
or
curl -X GET "http://localhost:5000/locations?id=3"
#Felipsmartins is correct.
It is worth mentioning that it is because you cannot really use the -d/--data option if this is not a POST request. But this is still possible if you use the -G option.
Which means you can do this:
curl -X DELETE -G 'http://localhost:5000/locations' -d 'id=3'
Here it is a bit silly but when you are on the command line and you have a lot of parameters, it is a lot tidier.
I am saying this because cURL commands are usually quite long, so it is worth making it on more than one line escaping the line breaks.
curl -X DELETE -G \
'http://localhost:5000/locations' \
-d id=3 \
-d name=Mario \
-d surname=Bros
This is obviously a lot more comfortable if you use zsh. I mean when you need to re-edit the previous command because zsh lets you go line by line. (just saying)
I need to make a POST request via cURL from the command line. Data for this request is located in a file. I know that via PUT this could be done with the --upload-file option.
curl host:port/post-file -H "Content-Type: text/xml" --data "contents_of_file"
You're looking for the --data-binary argument:
curl -i -X POST host:port/post-file \
-H "Content-Type: text/xml" \
--data-binary "#path/to/file"
In the example above, -i prints out all the headers so that you can see what's going on, and -X POST makes it explicit that this is a post. Both of these can be safely omitted without changing the behaviour on the wire. The path to the file needs to be preceded by an # symbol, so curl knows to read from a file.
I need to make a POST request via Curl from the command line. Data for this request is located in a file...
All you need to do is have the --data argument start with a #:
curl -H "Content-Type: text/xml" --data "#path_of_file" host:port/post-file-path
For example, if you have the data in a file called stuff.xml then you would do something like:
curl -H "Content-Type: text/xml" --data "#stuff.xml" host:port/post-file-path
The stuff.xml filename can be replaced with a relative or full path to the file: #../xml/stuff.xml, #/var/tmp/stuff.xml, ...
If you are using form data to upload file,in which a parameter name must be specified , you can use:
curl -X POST -i -F "parametername=#filename" -F "additional_parm=param2" host:port/xxx
Most of answers are perfect here, but when I landed here for my particular problem, I have to upload binary file (XLSX spread sheet) using POST method, I see one thing missing, i.e. usually its not just file you load, you may have more form data elements, like comment to file or tags to file etc as was my case. Hence, I would like to add it here as it was my use case, so that it could help others.
curl -POST -F comment=mycomment -F file_type=XLSX -F file_data=#/your/path/to/file.XLSX http://yourhost.example.com/api/example_url
I was having a similar issue in passing the file as a param. Using -F allowed the file to be passed as form data, but the content type of the file was application/octet-stream. My endpoint was expecting text/csv.
You are able to set the MIME type of the file with the following syntax:
-F 'file=#path/to/file;type=<MIME_TYPE>
So the full cURL command would look like this for a CSV file:
curl -X POST -F 'file=#path/to/file.csv;type=text/csv' https://test.com
There is good documentation on this and other options here: https://catonmat.net/cookbooks/curl/make-post-request#post-form-data
I had to use a HTTP connection, because on HTTPS there is default file size limit.
https://techcommunity.microsoft.com/t5/IIS-Support-Blog/Solution-for-Request-Entity-Too-Large-error/ba-p/501134
curl -i -X 'POST' -F 'file=#/home/testeincremental.xlsx' 'http://example.com/upload.aspx?user=example&password=example123&type=XLSX'
Using REST Server 6.x-2.0-beta3, I'm trying to understand how to post to user.save.
curl -d 'XX' -v http://localhost/services/rest/service_user/save
I've tried to replace XX with:
account{'name':'myname','pass':'mypassword','mail':'my#email.org'}
account = {'name':'myname','pass':'mypassword','mail':'my#email.org'}
account="name=myname,pass=mypassword,mail=myemail.org"
account=name=myname,pass=mypassword,mail=myemail.org
account=myname,mypassword,myemail.org
But none of these seems to be right and finding any documention regarding this is next to impossible.
I've also tried the following:
curl -H "Content-Type: application/json" -d 'account={"name":"myname","pass":"mypassword","email":"123"}' -v http://localhost/services/rest/service_user/save
The error I get in this case is:
HTTP/1.0 406 Not Acceptable: Missing required argument account
Hi I also just started working with this module and wondering how to create content using JSON.
Just been able to create a simple node using this:
Post URL: http://path-to-site/services/rest/node
Request Header: Content-Type: application/json
Request Body: {"type":"story","title":"REST Test","body":"REST using JSON"}
I think you're using the wrong URL
I figured it out:
curl -H “application/x-www-form-urlencoded” -d "sessid=xxxx" -d "account[name]=MyName&account[pass]=mypass&account[mail]=myemail#gmail.com&account[conf_mail]=myemail#gmail.com" -v http://path-to-site/services/rest/service_user/save
You only have to add -d "sessid=xxxx" if you have configured Services to require a session. Make sure in that case to replace xxxx with your actual session id (from system.connect).