Apache Oltu Linkedin Integration example - spring-mvc

Question

I am looking forward to developed the Spring MVC + Apache Oltu + Linkedin integration example. In this example, you need to send Client ID and Client Secret to access the private resource from the Linked in Site.
First Step - we need to create App in Linkedin, follow the steps: http://codeboxr.com/how-to-create-linkedin-app.html
Once App is created, you need to make sure you've given value for the redirect URL.
In the java code I used
setScope("r_network w_share r_basicprofile")
setState("987654321")
When I used the following code:
request= new OAuthBearerClientRequest("https://api.linkedin.com/v1/people/").buildQueryMessage();
I get the following errror. Could anyone please?
Could not access resource: 401 <?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<error>
<status>401</status>
<timestamp>1429554559432</timestamp>
<request-id>QJWNLL5PWX</request-id>
<error-code>0</error-code>
<message>Unknown authentication scheme</message>
</error>
An important thing, I am getting correct details below, but seems accessing private resources:
{"access_token":"SQXZVmVM05AOzDB_DdBm5iaJkrEC8oK-FgE1m1snEZbMcKUODew9I0ZQ6NWc8JtGDxTtEd-yyPul0FtF3-hG4ah6LZ9P4oaSVuhhtybRFmjfsZcJwOs5Lm2IDUGQnjmq5EdT3PVR7Bocq31VBXg0JtkQdImab945oicO_w2j6CjlByp-bWw",
"expires_in":5108376}

Answer 1

It seems that you're successfully obtaining an OAuth 2.0 access token, you'll need to pass access_token in a query parameter when making API calls. That's how OAuth 2.0 authentication is handled (OAuth 1.0 required the access token to be in the header whereas OAuth 2.0 relies on a query parameter).
For example:
GET https://api.linkedin.com/v1/people/~?oauth2_access_token={your-access-token}
Please follow the link, if in case requires more details: https://developer-programs.linkedin.com/forum/unknown-authentication-scheme
If you send token along with the request to access protected resources, then you should be getting the following details.
The corrected code snippet:
request= new OAuthBearerClientRequest
("https://api.linkedin.com/v1/people/~?oauth2_access_token="+oAuthResponse.getAccessToken()).
buildQueryMessage();
In My Example, I am getting the following HTTP 200 OK response, just wanted to show you..
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<person>
<id>LLIyXMKhNI</id>
<first-name>FirstName</first-name>
<last-name>LastName</last-name>
<headline>Spring Developer at Amazon</headline>
<site-standard-profile-request>
<url>https://www.linkedin.com/profile/view?id=154416688&authType=name&authToken=ipNL&trk=api*a4360331*s4423501*</url>
</site-standard-profile-request>
</person>
Hope this will be help you.