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Find the day of a week
(7 answers)
Closed 7 years ago.
Is there one function returning the weekday's date? For example, today is 3/25/2015. If input the parameter is current week(0) and weekday is Monday(1), it will return '3/23/2015'. If input is last week(-1) and weekday is Monday(1), it will return '3/16/2015'.
I believe as.posix allows you to request $wday
Related
This question already has answers here:
How to subtract/add days from/to a date?
(3 answers)
Closed 2 years ago.
I started working in R and need to change a date. On my search I only found how to change the format or setting the day/month/year to a specific number.
I have for example:
my_date = as.Date("2020-03-01")
in my algorithm I need to change this by one day. For this special case I am looking for
2020-02-29
Thanks for your answers.
Best
Felix
I would propose to use lubridate library.
Then:
library(lubridate)
date <- ymd("2020-03-01")
date - days(1)
gives you "2020-02-29".
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Add hours minutes with the format hh:mm using moment
(5 answers)
How to convert time (hh:mm) to decimal form with momentjs
(1 answer)
Closed 3 years ago.
I have a duration in the format 'HH:mm'
for instance: 14:45 means 14hours and 45 seconds.
Does moment has a built function to parse duration based on a specific format ?
This question already has answers here:
C# DateTime to "YYYYMMDDHHMMSS" format
(18 answers)
Closed 5 years ago.
DateTime.Now.ToString("DD.MMM.YYYY.HH.MM.SS")
Using the above formatting to get the current date and time as per the above format. But it's resulting
DD.Sep.YYYY.15.09.SS
Use This it will definetly work as per your expecting output
string h = DateTime.Now.ToString("dd.MMM.yyyy.HH.MM.ss");
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How can I paste 100000 without it being shortened to 1e+05? [duplicate]
(3 answers)
Closed 9 years ago.
The result of function was displayed in scientific notation, I want to change it back to normal, but only for that function, I don't want to change the global setting. Can anyone help?
You can do:
format(functionResult, scientific=FALSE);
or:
as.integer(functionResult);
This question already has answers here:
What is the expression on RegularExpressionValidator to check if the Textbox text is 6 or more characters long?
(2 answers)
Closed 8 years ago.
I want to use an ASP:RegularExpressionValidator to enforce a minimum character count (6) but only if the field is NOT empty.
Could anyone help me with the regex for this?
Try this regular expression:
^(?:.{6,}|)$