Setting a Dialplan for guests? - asterisk

I am trying to configure my asterisk to regsiter every user who tries to connect to it, and allow it to establish calls. I have read that I should set "allowguest = yes" in sip.conf.
What about the dialplan in extensions.conf ? What should I add so that all my users could make and recieve calls ? (this is my first questions).
I would go even more precise about the users : is it possible to allow only guests from one precise domain ? If yes please help find how to do it, I will be very thankful.

Guest calls will go to default context which is in general section of sip.conf
[general]
context=some_restricted_access
About dialplan for calls - you need read some book for beginner or install freepbx/other web which do dialplan for you.
No, you can't allow guests from domain. But you can try play with realm= setting or allow access from one ip by using ip-authentification.

Related

Pulling only Registration Contact information on Asterisk

I am not using real-time asterisk , But still astdb.sqlite3 contains entries of online peers with Reg.Contact information in SIP/registry/peer. key . I would like to store contact information of all peers as they come online in a separate persistent database. I need this for sending push notifications by fetching deviceID etc information in registration contact .
I tried to pull this information from astdb.sqlite3 but the entries are clearing off as soon as devices go offline .Though I am able to fetch the information with "sip show peer XXXX" in asterisk CLI , It is overburdened to fetch every time like this . Instead I want to save only Regcontact information for all the devices in a database ( without realtime) as the devices come online. The other way I tried to pull the information is using AMI event listener. But with AMI I don't see complete information like contact information It displays only below information
Event: PeerStatus
Privilege: system,all
SequenceNumber: 75
File: manager.c
Line: 1856
Func: manager_default_msg_cb
ChannelType: SIP
Peer: SIP/2030
PeerStatus: Reachable
Can someone suggest a better way to push Only Regcontact information to a database as the devices come online .
There are no mechanism like that in asterisk.
You can use kamailio or write patch similar to this one https://reviewboard.asterisk.org/r/4490/
It sounds like you have dynamic IPs for your endpoints, and you want a way to update a separate DB as soon as a device registers with an IP/port pair.
If you enable the security log, you will see all auth events, including the "SuccessfulAuth" event, which includes the RemoteAddress of the endpoint (including port and protocol).
Here is an example line:
[Jul 21 19:53:45] SECURITY[1342] res_security_log.c: SecurityEvent="SuccessfulAuth",EventTV="2020-07-21T19:53:45.182+0000",Severity="Informational",Service="SIP",EventVersion="1",AccountID="102",SessionID="0x7f41040132c0",LocalAddress="IPV4/UDP/10.0.0.200/5060",RemoteAddress="IPV4/UDP/10.0.0.75/5062",UsingPassword="1"
If all you're looking for is AccountID="102" and RemoteAddress="IPV4/UDP/10.0.0.75/5062", a very fast/cheap way to get it is to enable the security log, and use a script to tail it and update your DB as soon as the event occurs. I like to keep the security log on anyways for utilities like fail2ban. Just make sure your script is able to reopen the file each time it is rotated.
Edit:
By default the log is in /var/log/asterisk. To enable it, edit /etc/asterisk/logger.conf and un-comment (or create) the line under [logfiles] that says security => security.

Adding a prefix in outgoing calls in Asterisk

We have a many services in our company, each one must display a different number in his outgoing calls. We use a Asterisk SIP server.
Our SIP provider asks us to make our Asterisk server send a prefix before the outgoing number.
for exemple, for a normal call from the extension 1200, the SIP server send the number 0033123456789.
we want to make it adding a prefix for calls from each extension, for exemple :
add the prefix 400 before calls from the extension 1200 to send 40033123456789.
add the prefix 401 before calls from the extension 1201 to send 40133123456789.
... etc.
Can you help please ?
Many thanks.
Regards.
There might be several ways to achieve what you need, if calls from all extensions hit same context(context start with [some-context-name]), then you might achieve it in following way:
[some-context-name]
exten => _00X.,1,ExecIf($["${CALLERID(num)}" = "1200"]?Dial(SIP/mytrunk/400${EXTEN:2}))
exten => _00X.,1,ExecIf($["${CALLERID(num)}" = "1201"]?Dial(SIP/mytrunk/401${EXTEN:2}))
Additionally you might have separate context per extension or you might implement all of this inside AGI script.

FreePBX add a new SIP extension

I've successfully built VoIP server with FreePBX Asterisk. It works fine when I register a user on FreePBX. However, I would like to register a SIP account from mobile device directly. I found out that I can add custom information into FreePBX MySQL database.
However, it doesn't work either, and I couldn't find a place to insert SIP password.. Someone said that I need to do something with /var/www/html/admin/functions.inc.php file. Is there better way to create a new SIP extension from outside of FreePBX GUI? Thank you.
Freepbx not use database way(asterisk realtime).
Instead it use text file method.
After adding new info into mysql database, you have apply changes on web to write new config files. You can do same from command line interface (see amp_engine), but can't do that using db query.
Other option is use freepbx framework.php correctly.
Also you can use asterisk realtime architecture and not use freepbx dialplan.
WARNING Freepbx is designed for low number of extensions and low load(branch office pbx). As result using it for support mobile device application will be great fail. Check other projects, for example a2billing.org or hire expert to build core server with HA/failover for your need.

Answer an incoming call by a sip account programatically using AMI

I use asterisk in my project and users login with softphones. I want to grant a person to forward an incoming call to another user's sip account by clicking on a button and answer the call immediately so that the user will be able to start talking with caller.
You need read documentation for you softphones/hardphones. Usualy need add sip header Call-Info: answer-after=0.
So you plan can be
Check if auto-answer/intercom posible with your softphone or hardphone.
Create dialplan which will add header and call
Transfer call to that dialplan using AMI Transfer command
For more info check this:
http://icesupport.ingeniussoftware.com/customer/portal/articles/990030-asterisk-auto-answer-on-originate
http://www.voip-info.org/wiki/view/Asterisk+manager+Example:+Transfer

Error '2035' ('MQRC_NOT_AUTHORIZED') While Connecting to MQ

I am getting this error while connecting to IBM MQ. I know that this is because of privileges, but is there any way just to check the connection with IBM MQ?
Please suggest.
The 2035 suggests that your connection is getting to the QMgr. If you had the wrong channel name, host or port you would get back a 2059. The 2035 means that the connection made it to the listener, found a channel of the name that was requested and attempted a connection.
If you want to test past this point it will be necessary to either authorize the ID that you are using to connect or to put an authorized ID in the MCAUSER attribute of the channel.
For a detailed explanation of how the WMQ security works on client channels, see the WMQ Base Hardening presentation at http://t-rob.net/links.
If you enable authorization messages then the 2035 will show up in the event queue. Then you can look at the message and see what ID was used to connect and what options were used too. The 2035 might be because you asked for set authority on the queue manager or something else you aren't supposed to have. The authorization messages wil show you that.
You can also resolve this By setting mcauser('mqm') .. i was able to overcome 2035 error.
Define channel (channel1) chltype (svrconn) trptype (tcp) mcauser(‘mqm’)
Esp thanx to my SENIOR Bilal Ahmad (PSE)
You have to check the privileges with an MQ administrator.
You can use dspmqaut to check the grant.
Below is the sample to give user poc access to Queue Manager QM1 and Queue LQ1
# check the access right of user POC to QM1
dspmqaut -m QM1 -n LQ1 -t q -p poc
# if you want to give access, you should use
setmqaut -m QM1 -n LQ1 -t q -p poc <access Types>
# eg (put everything - in the real live scenario, choose only what you want to grant) :
setmqaut -m QM1 -n LQ1 -t q -p poc +put +get +browse +inq +set +crt +dlt +chg +dsp +passid +setid +setall +clr
Then dont forget to restart QM1 with
endmqm -i QM1
strmqm QM1
Finally, you should be able to proceed without error 2035.
I have been struggling with this for ages too. Eventually I found this solution. (If you can call turning off authentication a solution.)
I am using version
- IBM Websphere 9.1.0.201807091223
From IBM's website they advise turning connection authentication off!!!
Resolving the problem Disable channel authentication
You will need to disable connection authentication, at least
temporarily. There are known issues in FTM for Check with regard to
using MQ connection authorization. These problems are actively being
addressed and fixes will appear in a future fix pack. The target is
fixpack 3.0.0.8.
Steps to disable connection authentication: Open MQ command console
and type runmqsc ALTER
AUTHINFO(SYSTEM.DEFAULT.AUTHINFO.IDPWOS) AUTHTYPE(IDPWOS)
CHCKCLNT(NONE) CHCKLOCL(NONE) Restart the queue manager for this
change to take effect.
Source http://www-01.ibm.com/support/docview.wss?uid=swg21962081
On this topic if you are using MQSeries 9.1 in a test or development environment you can disable channel authentication with the following approach :
. Launch MQ command line utility with the following :
runmqsc (for example runmqsc QM1)
. Disable authentication for all channels with the following command
ALTER QMGR CHLAUTH (DISABLED)
For a Q/Q-manager running on Windows, you may have to create the user on the Q/Q-manager machine [i.e. create a user on the Q-machine to match the user on the Q-client machine], and then add that user to the 'mqm' group on that machine.
Steps:
Ensure that the domain user that is being used to create the Q CLIENT [i.e. the user that the Q-client app is running under] also exists on the box with the Q/Q-manager. You may be able to just create a local user on the Q/Q-manager box [, or you may have to do some more complicated creation of an Active Directory user - I can't help you there].
On the Q/Q-manager box, add the user you have just created [or the existing one, if it already exists] to the mqm group. [On a Windows server box you will need to use the Microsoft Management Console (1. 'mmc' from the command line, 2. File > Add/Remove SnapOn > Local Users & Groups, 3. add user to group)]. The 'mqm' group should already exist on the Q/Q-manager machine.
Error MQRC 2035 basically means that your application has been able to connect to the queue manager, however due to certain absence of permissions/authorizations, it was unable to put/get/publish/subscribe messages.
To resolve this, at first, try these steps in order to disable the authorizations from queue manager and channel. Use this only if it isn't a production queue manager.
Always check the queue manager logs. It tells you exactly where you need to look into, and resolve the issue.
In this case, generally, you can issue the following commands after doing a runmqsc on the queue manager :
ALTER QMGR CHLAUTH(DISABLED)
Then set the chckclnt object(under authinfo) to optional
DISPLAY QMGR CONNAUTH
DISPLAY AUTHINFO(name-from-above) ALL //name from the first commands
ALTER AUTHINFO(name-from-above) AUTHTYPE(IDPWOS) ADOPTCTX(YES)
ALTER AUTHINFO(name-from-above) AUTHTYPE(IDPWOS) CHCKCLNT(OPTIONAL)
REFRESH SECURITY TYPE(CONNAUTH)
SET CHLAUTH('*') TYPE(BLOCKUSER) ACTION(REMOVEALL)
This helps remove any blocks that the channel is creating against any user.
SET CHLAUTH(your channel name) TYPE(ADDRESSMAP) ADDRESS('*') USERSRC(CHANNEL)
This should resolve your issue, since we have disabled every authorization that an application has to pass in order to do anything on a queue manager.
Now, in case you are using a production queue manager, NEVER remove authorizations.
Go, and right click on any QM that you have configured in your MQ explorer. Go to the QM authority, and authority records. Click on create new user, and give the same name as the username your application is using. Select all the checkboxes, then copy from the space below all the commands that are given. Namely, setmqaut. Edit with your queue manager name, and issue them!
----Never give up, the answer is where you have not looked yet--------

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