So I've got this small piece of example code in my View
#{
string MyValue = "val1;val2;val3";
}
And I am wondering how I can split it where there's a semi colon, and then I can run through each value and print it in an list
Remember that in a View when using the #{} most C# code can be used. You can use this line with a loop to get what you need done.
string sub = input.Substring(0, input.indexof(";"));
Related
I am working in C# with ASP.NET. I am familiar with this error but this time I can't solve it.
I have text in a drop-down list like this:
राम कुमार सिंह 8s2w8r
here राम कुमार सिंह is the name in HINDI while 8s2w8r is users' ID.
I need to separate these two values and need to pass them as session variables. The logic I am using is depicted in the code.
public string reverse(string s)
{
char []temp=s.ToCharArray();
Array.Reverse(temp);
return (temp.ToString());
}
string dropdowntextreversed=reverse(DropDownList1.Text);
char []delim=new char[]{' '};
string []parts=dropdowntextreversed.Split(delim,2);
string family_head_uid = reverse(parts[0]);
string family_head = reverse(parts[1]);
Session.Add("family_head", family_head);
Session.Add("family_head_uid", family_head_uid);
Response.Redirect("/WebForm1.aspx");
I always get an error as the index was outside the bounds of the array! I don't understand this because I am breaking the string into 2 parts so it should have parts[0] and parts[1]. Please suggest...
You are splitting the string into MAXIMUM 2 parts, but if there's only one you will get probably one part.
Read this documentation
Try to assert that parts.Length is == 2 or to access elemnts only there atre two elements
Try this link. As I think there is a problem in the temp.ToString() which will return System.Char[] rather than the value which are you looking for. Use string.join instead will work.
Use the following reverse method:
public string reverse(string s)
{
return String.Join(String.Empty, s.ToCharArray().Reverse());
}
I have a string that at any point may or may not contain one or more / characters. I'd like to be able to create a new string based on this string. The new string would include every character after the very last / in the original string.
Sounds like you're wanting the file name from a URL. In any case, it's the same function. The key is using the InStrRev function to find the first / char, but starting from the right. Here's the function:
Function GetFilename(URL)
Dim I
I = InStrRev(URL, "/")
If I > 0 Then
GetFilename = Mid(URL, I + 1)
Else
GetFilename = URL
End If
End Function
Split it up into parts and get the last part:
a = split("my/string/thing", "/")
wscript.echo a(ubound(a))
note: Not safe when the string is empty.
I'm having difficulty with the following.
In VB.Net, I have the following line:
Dim intWidgetID As Integer = CType(Replace(strWidget, "portlet_", ""), Integer)
where strWidget = portlet_n
where n can be any whole number, i.e.
portlet_5
I am trying to convert this code to C#, but I keep getting errors, I currently have this:
intTabID = Convert.ToInt32(Strings.Replace(strTabID, "tab_group_", ""));
which I got using an online converter
But it doesn't like Strings
So my question is, how to I replace part of a string, so intTabID becomes 5 based on this example?
I've done a search for this, and found this link:
C# Replace part of a string
Can this not be done without regular expressions in c#, so basically, I'm trying to produce code as similar as possible to the original vb.net example code.
It should be like this strTabID.Replace("tab_group_", string.Empty);
int intTabID = 0;
string value = strTabID.Replace("tab_group_", string.Empty);
int.TryParse(value, out intTabID);
if (intTabID > 0)
{
}
And in your code i think you need to replace "tab_group_" with "portlet_"
Instead of Strings.Replace(strTabID, "tab_group_", ""), use strTabID.Replace("tab_group_", "").
This should work
int intWidgetID = int.Parse(strTabID.Replace("tab_group_",""));//Can also use TryParse
Their is no Strings class in Vb.Net so please use the string class instead http://msdn.microsoft.com/en-us/library/aa903372(v=vs.71).aspx
you can achieve it by this way
string strWidget = "portlet_n";
int intWidgetID = Convert.ToInt32(strWidget.Split('_')[1]);
I've got a string like so
Jamie(123)
And I'm trying to just show Jamie without the brackets etc
All the names are different lengths so I was wondering if there was a simple way of replacing everything from the first bracket onwards?
Some others are displayed like this
Tom(Test(123))
Jack ((4u72))
I've got a simple replace of the bracket at the moment like this
mystring.Replace("(", "").Replace(")","")
Any help would be appreciated
Thanks
VB.NET
mystring.Substring(0, mystring.IndexOf("("C)).Trim()
C#
mystring.Substring(0, mystring.IndexOf('(')).Trim();
One logic; get the index of the ( and you can trim the later part from that position.
public static string Remove(string value)
{
int pos = value.IndexOf("(");
if (pos >= 0)
{
return value.Remove(pos, remove.Length);
}
return value;
}
aneal's will work. The alternative I generally use because it's a bit more flexible is .substring.
string newstring = oldstring.substring(0,oldstring.indexof("("));
If you aren't sure that oldstring will have a "(" you will have to do the test first just as aneal shows in their answer.
String.Remove(Int32) will do what you need:
Deletes all the characters from this string beginning at a
specified position and continuing through the last position.
You will also have to .Trim() as well given the data with padding:
mystring = mystring.Remove(mystring.IndexOf("("C))).Trim()
I'm trying to add comma separators to a number. I've tried the advice here: add commas using String.Format for number and and here: .NET String.Format() to add commas in thousands place for a number but I can't get it to work - they just return the number without commas. The code I'm using is here:
public static string addCommas(string cash) {
return string.Format("{0:n0}", cash).ToString();
}
Where am I going wrong?
Thanks.
Update: Hi all, thanks for your help, but all of those methods are returning the same error: "error CS1502: The best overloaded method match for 'BishopFlemingFunctions.addCommas(int)' has some invalid arguments" (or variations therof depending on what number type I'm using.) Any ideas?
Well, you are sending in a string. it looks like you want a currency back
Why are you passing in a string to the method if it is a numeric value?
String.Format will return a string so there is not need to .ToString() it again.
{0:c} = Currency format if you do not want the $ then use {0:n}
Not sure you have to but you may need to do an explicit conversion if you pass it in as a string to (decimal)cash
return String.Format("{0:c}", (decimal)cash);
or
return String.Format("{0:n}", (decimal)cash);
but i think it should be something like:
public static string addCommas(decimal cash)
{
return String.Format("{0:c}", cash);
}
but this is such a simple statement i do not see the logic in making it a method, if you method is one line, in most cases, its not a method.
In order to apply number formatting you have to pass cash as a number type (int, double, float etc)
Note the cash parameter is of type double and the .## at the end of the formatted string for cents.
EDIT
Here is the code in its entirety:
static class Program {
static void Main() {
double d = 123456789.7845;
string s = addCommas(d);
System.Console.WriteLine(s);
}
public static string addCommas(double cash) {
return string.Format("${0:#,###0.##}", cash);
}
}
This prints "$123,456,789.78" to console. If you're getting
error CS1502: The best overloaded
method match for 'addCommas(double)'
has some invalid arguments
check to make sure that you're calling the function properly and that you're actually passing in the correct data type. I encourage you to copy/paste the code I have above and run it - BY ITSELF.
i have a method on my custom class to convert any numbers
public static string ConvertToThosandSepratedNumber(object number)
{
string retValue = "";
retValue = string.Format("{0:N0}", Convert.ToDecimal(number));
return retValue;
}
Here is a fairly efficient way to Add commas for thousands place, etc.
It is written in VB.net.
It does not work for negative numbers.
Public Function AddCommas(number As Integer) As String
Dim s As String = number.ToString()
Dim sb As New StringBuilder(16)
Dim countHead As Integer = s.Length Mod 3
If countHead = 0 Then countHead = 3
sb.Append(s.Substring(0, countHead))
For I As Integer = countHead To s.Length - 1 Step 3
sb.Append(","c)
sb.Append(s.Substring(I, 3))
Next
Return sb.ToString()
End Function