I'm trying to overlay this logo so it sits at the bottom of the page, and also so it is offset by its full width to the left (so that the right edge of the logo sits against the center line).
If I use position:absolute on #logo I have access to the top and left properties, which is good, but now centering won't work...
Here's the fiddle.
Also: making it a fixed distance from the left edge of the page won't work because the page is responsive. The right edge of the logo always has to sit perfectly on the center line.
In case the fiddle isn't working here's the code:
HTML:
<div id ="layer1">
<p>Hello</p>
</div>
<div id="layer2">
<div id="wrapper">
<img id="logo" src="http://i.stack.imgur.com/icxpG.png"/>
</div>
</div>
CSS:
body {
background: linear-gradient(to left, #1a1a1a 50%, #f15922 50%);
}
#layer1 {
position: absolute;
z-index: 100;
height: 100%;
width: 100%;
}
#layer2 {
position: absolute;
z-index: 5000;
height: 100%;
width: 100%;
}
#wrapper {
position: relative;
background-color: rgba(255, 255, 255, 0.3);
height: 100%;
}
#logo {
background-color: rgba(255, 0, 0, 0.3);
bottom: 0;
display: block;
margin-left: auto;
margin-right: auto
}
You could add position: absolute; and transform to center your #logo like this:
JSFiddle - DEMO
#logo {
background-color: rgba(255, 0, 0, 0.3);
display:block;
position: absolute;
bottom: 0;
left: 50%;
-webkit-transform: translateX(-100%);
-moz-transform: translateX(-100%);
-ms-transform: translateX(-100%);
-o-transform: translateX(-100%);
transform: translateX(-100%);
}
To get the image positioned offset perfectly at all widths, we need to get rid of the gradient and apply the second background to a pseudo element of the body.
In these 2 examples, body provides the orange background and body:before provides the dark background.
Example 1 - logo is a background image
calc(50% - 167px) offsets the logo.
html, body {
height: 100%;
width: 100%;
margin: 0;
}
body {
background: #f15922 url(http://i.stack.imgur.com/icxpG.png) calc(50% - 167px) bottom no-repeat;
}
body:before {
width: 50%;
height: 100%;
background: #1a1a1a;
content: '';
display: block;
position: absolute;
right: 0;
}
Example 2 - logo is <img>
right: 50% and bottom: 0 keep it at the bottom and offset by the natural width of the image.
html, body {
height: 100%;
width: 100%;
margin: 0;
}
body {
background: #f15922;
}
body:before {
width: 50%;
height: 100%;
background: #1a1a1a;
content: '';
display: block;
position: absolute;
right: 0;
}
#logo {
position: absolute;
bottom: 0;
right: 50%;
}
<img id="logo" src="http://i.stack.imgur.com/icxpG.png" />
Old Archived Examples (with gradient)
Limitation: There is a gap at certain viewport widths that is caused by the gradients 50% calculation. I'm not certain that this can be avoided.
Archived 1 - Keep it all in a background image / gradient
calc(50% - 167px) offsets the image from the center
html, body {
height: 100%;
width: 100%;
margin: 0;
}
body {
background: url(http://i.stack.imgur.com/icxpG.png) calc(50% - 167px) bottom no-repeat, linear-gradient(to left, #1a1a1a 50%, #f15922 50%);
}
Archived 2 - Using <img>
right: 50% and bottom: 0 keep it at the bottom and offset by the natural width of the image.
body {
background: linear-gradient(to left, #1a1a1a 50%, #f15922 50%);
}
#logo {
background-color: rgba(255, 0, 0, 0.3);
bottom: 0;
right: 50%;
position: absolute;
}
<img id="logo" src="http://i.stack.imgur.com/icxpG.png" />
Related
I have a simple div element that I wanna apply a background shape to it when the user hovers over it by using the ::before and ::after pseudo elements. I rotated these elements with rotateX(). How can I style it that the elements shouldn't overlap each other (or at least not ruin the background color) but it should look like a single shape?
Tried using % but didn't work.
Please help.
Thanks so much 🙏
div{
width:200px;
padding: 18px;
margin: 10px auto;
/* border: 1px solid black; */
text-align:center;
position: relative;
perspective: 100px;
z-index: 1;
}
div:hover{
color:#fff;
}
div:hover::before, div:hover::after{
content: "";
display: block;
background-color: #00000050;
width: 100%;
height: 50px;
position: absolute;
left: 0%;
z-index: -1;
}
div::before{
top:0;
transform: rotateX(-75deg);
}
div::after{
bottom:0;
transform: rotateX(75deg);
}
<div>Hello World</div>
If you make half of each pseudo element only have the color then when you rotate them the colors don't overlap.
A minor adjustment to the padding of the div was needed to get the two rotated 'halves' to meet correctly so this would have to be looked at if you ever went for a responsive rather than a fixed px unit solution.
This snippet removes the background-color from the pseudo elements, instead using a linear-gradient background-image going just half way up (or down) the pseudo element.
div {
width: 200px;
padding: 18px;
padding: 16px;
margin: 10px auto;
/* border: 1px solid black; */
text-align: center;
position: relative;
perspective: 100px;
z-index: 1;
}
div:hover {
color: #fff;
}
div:hover::before,
div:hover::after {
content: "";
display: block;
margin: 0;
padding: 0;
width: 100%;
height: 50px;
position: absolute;
left: 0%;
z-index: -1;
}
div::before {
top: 0;
transform: rotateX(-75deg);
background-image: linear-gradient(#00000050 0 50%, transparent 50% 100%);
}
div:hover::after {
bottom: 0;
transform: rotateX(75deg);
background-color: transparent;
background-image: linear-gradient(to top, #00000050 0 50%, transparent 50% 100%);
}
<div>Hello World</div>
A Haworth's answer covers using linear gradient stops to hide the color of half of each pseudo element.
Another approach you could take is to use only one of the pseudo elements with a polygon clip path to make your shape.
.container { display: flex; }
.hoverable { position: relative; margin: auto; padding: 10px 100px; }
.hoverable:hover::before {
content: "";
position: absolute;
inset: 0;
/* top: 0; left: 0; right: 0; bottom: 0; */
background-color: rgba(0, 0, 0, 0.25);
clip-path: polygon(0 0, 100% 0, 80% 50%, 100% 100%, 0 100%, 20% 50%);
}
<div class="container">
<div class="hoverable">Hello, World!</div>
</div>
My target is to implement a pure-CSS flag-shape container like this:
Requirements include:
background-color of parent container is unknown
works for different line-height and font-size settings
Option 1
Use clip-path, but check browser support for this property:
div {
clip-path: polygon(0% 0%, 100% 0%, 85% 50%, 100% 100%, 0% 100%);
background-color: #ff69b4;
/* styles for demo */
padding: 20px;
color: #fff;
}
<div>5 items</div>
Option 2
Use SVG:
<svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 100 100">
<polygon points="0 0, 100 0, 85 50, 100 100, 0 100" fill="#ff69b4" />
</svg>
Option 3
Use absolutely positioned pseudoelements with gradients (to simulate triangles)
div {
background-color: #ff69b4;
margin-right: 50px;
position: relative;
/* styles for demo */
padding: 20px;
color: #fff;
}
/* pseudoelement to simulate triangles */
div:before,
div:after {
content: "";
position: absolute;
top: 0;
left: 100%;
width: 50px;
height: 50%;
background-image: linear-gradient(to left top, transparent 50%, #ff69b4 50%);
}
/* Flip triangle */
div:after {
top: 50%;
transform: scaleY(-1);
}
<div>5 items</div>
Another possible variant would be to use transformed pseudo elements.
Create 2 layers using ::before ad ::after pseudo elements.
Add background-color and place them with position: absolute having 50% height of the parent.
Apply CSS3 skew() transformations to get the flag shape.
Output Image:
Working Demo:
* {box-sizing: border-box;}
body {
background: linear-gradient(green, yellow) no-repeat;
min-height: 100vh;
padding: 10px;
margin: 0;
}
.flag {
padding: 5px 40px 5px 10px;
display: inline-block;
vertical-align: top;
position: relative;
line-height: 40px;
overflow: hidden;
}
.flag:before,
.flag:after {
transform-origin: top right;
transform: skewX(-45deg);
position: absolute;
background: pink;
content: '';
left: -45px;
height: 50%;
z-index: -1;
right: 0;
top: 0;
}
.flag:after {
transform-origin: bottom right;
transform: skewX(45deg);
top: auto;
bottom: 0;
}
<div class="flag">5 Items</div>
I want to cut left top corner of a box using CSS like this.
keep in mind that background is transparent.
Nearly the same solution as OriDrori's answer but more flexible (if you need fixed-width cutted corner).
This gradient will look the same regardless of .card width and height.
body {
background: purple;
}
.card {
width: 200px;
height: 200px;
background: linear-gradient(135deg, transparent 20px, white 20px);
}
<div class="card"></div>
You can use a simple linear gradient for that:
body {
background: purple;
}
.card {
width: 200px;
height: 200px;
background: linear-gradient(to bottom right, transparent 5%, white 5%);
}
<div class="card"></div>
You can use clip-path
https://developer.mozilla.org/en/docs/Web/CSS/clip-path
and use something like this:
div#test{
background:red;
width:200px;
height: 200px;
-webkit-clip-path: polygon(22% 0, 100% 0, 100% 100%, 0 100%, 0 20%);
clip-path: polygon(22% 0, 100% 0, 100% 100%, 0 100%, 0 20%);
}
<div id="test"></div>
With a pseudo and transform you can do that, and it has good browser support (from IE9)
body {
background: url(https://picsum.photos/400/300) center / cover;
}
div {
position: relative;
width: 200px;
height: 200px;
overflow: hidden;
}
div::before {
content: '';
position: absolute;
left: calc(50% + 25px); /* 25px is height/width of the cut */
top: calc(50% + 25px);
width: 141.5%;
height: 141.5%;
transform: translate(-50%,-50%) rotate(45deg);
background: #eee;
opacity: 0.8;
}
<div></div>
As pointed out, if you need it to scale on different aspect ratio's, use this
body {
background: url(https://picsum.photos/400/300) center / cover;
}
div {
position: relative;
width: 80vw;
height: 80vh;
overflow: hidden;
}
div::before {
content: '';
position: absolute;
left: 0;
top: 0;
width: 1000%;
height: 5000%;
transform: rotate(45deg) translate(25px,-50%); /* 25px for the cut height/width */
transform-origin: left top;
background: #eee;
opacity: 0.8;
}
<div></div>
I'm trying to create a partial shadow on a skewed div, as close as I can get to this creative.
Right now I've been trying to do this with pseudo elements (before specifically) but I found that those elements behave strangely whenever I skew the element they are applied to. The pseudo element keeps appearing on top of my div, even though the z-index is set to -1. No matter what I do with z-index, it will stay on top of it. I want it to be behind the div it's applied to, and in front of the div below, like in the creative.
Here's my ::before code and a link to the codepen
CSS
/*! Shadows */
#test-title {
position: relative;
}
#test-title:before {
z-index: -1;
position: absolute;
content: "";
bottom: 15px;
left: 10px;
width: 50%;
top: 80%;
max-width:300px;
box-shadow: 0 15px 10px #777;
-webkit-transform: rotate(-3deg);
-moz-transform: rotate(-3deg);
-o-transform: rotate(-3deg);
-ms-transform: rotate(-3deg);
transform: rotate(-3deg);
}
http://codepen.io/kathryncrawford/pen/WwWEma
Skew the parent then unskew the child at the same degree.
* {
box-sizing: border-box
}
body {
padding: 40px 0
}
section {
width: 60vw;
clear: both;
overflow: hidden;
min-height: 100px;
margin: 0 auto;
position: relative;
background: #035076
}
section article {
width: 60%;
padding: 20px;
color: white;
margin: 0 auto
}
section:nth-child(even) {
transform: skew(-45deg) translate(5vw);
box-shadow: inset 0 0 2px 0 black;
}
section:nth-child(odd) {
transform: skew(45deg);
}
section:nth-child(even) article {
transform: skew(45deg) translate(5vw);
}
section:nth-child(odd) article {
transform: skew(-45deg);
}
section:before,
section:after {
content: '';
position: absolute;
}
section:nth-child(even):before {
width: 100%;
height: 0;
bottom: 100%;
left: 0;
z-index: 6;
opacity: 1;
transform: rotate(-10deg) translateY(-30px);
box-shadow: 0px 0px 64px 30px rgba(0, 0, 0, 0.8);
}
section:nth-child(odd):not(:first-child):before {
width: 100%;
height: 0;
bottom: 100%;
right: 0;
z-index: 6;
opacity: 1;
transform: rotate(10deg) translateY(-30px);
box-shadow: 0px 0px 64px 30px rgba(0, 0, 0, 0.8);
}
<section>
<article>What our clients say About Us</article>
</section>
<section>
<article>Read More!</article>
</section>
<section>
<article>Read More!</article>
</section>
<section>
<article>Read More!</article>
</section>
The easier approach would be to put the drop shadow at the top of each box after the first. This will solve all sorts of z-index issues, since each box sits 1 level higher than the box above it.. and it allows the shadow to sit inside the container instead of outside of it.
I've also changed your shadow styling to use a radial gradient* instead of a box shadow, as it is a bit easier to control in this situation, and is also closer to your design. I also did a bit of positioning to make it look a bit better too, and get the separate sides for skew1 and skew2
I've changed your last ruleset to this:
.test-info:before {
position: absolute;
content: "";
width: 100%;
left: 0;
top: 0;
height: 30px;
}
.test-info.skew1:before {
background: radial-gradient(ellipse farthest-side at 30% top, rgba(0,0,0,0.5) 0%, rgba(0,0,0,0) 100%);
}
.test-info.skew2:before {
background: radial-gradient(ellipse farthest-side at 70% top, rgba(0,0,0,0.5) 0%, rgba(0,0,0,0) 100%);
}
See Demo
* note: You may want to check/add additional browser support on the gradient that I put in before using it.
I have tried, it's not perfect, but, it is closer to desired look, imho:
<div id="test-title">
<h3>What our clients say about us</h3>
</div>
<div id="shadow1"></div>
So, i've added new html element(shadow), rather than using pseudo-elements... Now, i've set z-indexes and positions properly, to hide rotated shadow div behind first div, and added this css:
#shadow1 {
position:absolute;
width:50%;
height:150px;
background:black;
top:50px;
left:11%;
z-index:6;
opacity:1;
transform: rotate(-5deg);
box-shadow: 15px 56px 50px -12px rgba(0,0,0,0.80);
}
Demo: http://codepen.io/anon/pen/vGwNqY
You can play with rotation, box-shadow, position, height... but, this could be a good start (maybe). P.S. Similar logic could be applied to second div.
try to make box shadow for the second element using :before pseudo https://jsfiddle.net/0andpzsp/
.cont {
width: 1000px;
height: 500px;
}
div[class^="d"] {
width: 70%;
height: 50%;
position: relative;
margin-left: 40px;
margin-top: 50px;
}
.d0 {
background: linear-gradient(to right, #005f8a 0%,#00486c 50%,#003a59 100%);;
transform: skew(20deg)
}
.d1 {
background: linear-gradient(to right, #005f8a 0%,#00486c 50%,#003a59 100%);;
overflow: hidden;
top: -50px;
left: 20%;
transform: skewX(-20deg);
z-index: -1
}
.d1:before {
content: '';
border-radius: 30%;
position: absolute;
display: block;
width: 600px;
height: 70px;
z-index: 9999;
top: -100px;
left: -70px;
box-shadow: -50px 60px 90px 0px #000;
transform: rotate(-5deg)
}
<div class="cont">
<div class="d0"></div>
<div class="d1">
</div>
</div>
I'm trying to make the bottom of an image pointed. I've tried to get this effect by producing two triangles at the bottom. They must be responsive. and after searching all over the internet with a lot of examples that don't work for my requirement this is the best so far I've managed to produce.
body,
html {
height: 100%
}
.image {
width: 1410px;
margin-right: auto;
margin-left: auto;
height: 500px;
overflow: hidden;
position: relative;
}
.pointer {
height: 50px;
position: absolute;
bottom: 0;
left: 0;
width: 100%;
}
.triangleWrapper {
width: 50%;
height: 50px;
float: left;
}
.lefttriangle {
width: 100%;
height: 10px;
left: 0px;
top: 0px;
background-image: linear-gradient(to right top, #ffffff 50%, transparent 50%);
}
.righttriangle {
width: 100%;
height: 10px;
right: 0px;
top: 0px;
background: linear-gradient(to left top, #ffffff 50%, transparent 50%)
}
<div class="image">
<img src="http://placekitten.com/1410/500">
<div class="pointer">
<div class="triangleWrapper">
<div style="height: 100%;" class="lefttriangle"></div>
</div>
<div class="triangleWrapper">
<div style="height: 100%;" class="righttriangle"></div>
</div>
</div>
</div>
CodePen Demo
It works exactly how I want it to as it is responsive without the need for media queries. BUT it has a jagged edge on the triangle line that isn't 90deg.
How do I get this to produce a smooth line in most if not all modern browsers? I'm not asking for backward compatibility.
Any help is greatly appreciated!
Unfortunately, this always happens when we use angled linear-gradient images and currently the only way to overcome this behavior seems to be to avoid hard-stopping of the colors (that is, don't make the stop point of one color as the start point of the next). Making the second color start a little farther away from the stop point of the first color would kind of create a blurred area and make it look more smoother. This is still not 100% perfect but is better than having jagged edges.
.lefttriangle {
width: 100%;
height: 10px;
left: 0px;
top: 0px;
background-image: linear-gradient(to right top, #ffffff 48%, transparent 50%); /* note the change of stop and start points */
}
.righttriangle {
width: 100%;
height: 10px;
right: 0px;
top: 0px;
background: linear-gradient(to left top, #ffffff 48%, transparent 50%); /* note the change of stop and start points */
}
body,
html {
height: 100%
}
.image {
width: 1410px;
margin-right: auto;
margin-left: auto;
height: 500px;
overflow: hidden;
position: relative;
}
.pointer {
height: 50px;
position: absolute;
bottom: 0;
left: 0;
width: 100%;
}
.triangleWrapper {
width: 50%;
height: 50px;
float: left;
}
.lefttriangle {
width: 100%;
height: 10px;
left: 0px;
top: 0px;
background-image: linear-gradient(to right top, #ffffff 48%, transparent 50%);
}
.righttriangle {
width: 100%;
height: 10px;
right: 0px;
top: 0px;
background: linear-gradient(to left top, #ffffff 48%, transparent 50%);
}
<div class="image">
<img src="http://placekitten.com/1410/500">
<div class="pointer">
<div class="triangleWrapper">
<div style="height: 100%;" class="lefttriangle"></div>
</div>
<div class="triangleWrapper">
<div style="height: 100%;" class="righttriangle"></div>
</div>
</div>
</div>
Alternate Implementations:
Clip Paths: You can use clip-path feature also to produce a similar effect. The advantage of using clip-path is that it is both responsive and also produces a transparent cut. The SVG based clip-path has better browser support than the CSS version. This is not yet supported in IE though.
body,
html {
height: 100%
}
.image {
width: 1410px;
margin-right: auto;
margin-left: auto;
height: 500px;
overflow: hidden;
position: relative;
}
.css-clip {
-webkit-clip-path: polygon(0% 0%, 0% 90%, 50% 100%, 100% 90%, 100% 0%);
clip-path: polygon(0% 0%, 0% 90%, 50% 100%, 100% 90%, 100% 0%);
}
.svg-clip {
-webkit-clip-path: url(#clipper);
-moz-clip-path: url(#clipper);
clip-path: url(#clipper);
}
<!-- CSS Clip-path - Lower browser support -->
<div class="image css-clip">
<img src="http://placekitten.com/1410/500">
</div>
<!-- SVG Clip-path - Better browser support -->
<svg width="0" height="0">
<defs>
<clipPath clipPathUnits="objectBoundingBox" id="clipper">
<path d="M0,0 0,0.9 0.5,1 1,0.9 1,0z" />
</clipPath>
</defs>
</svg>
<div class="image svg-clip">
<img src="http://placekitten.com/1410/500">
</div>
Using CSS Transform: You could also try using the approach mentioned in this answer. It achieves a pointed effect on the left side but it should be easy to adapt it to create a pointed effect on the bottom side.
body,
html {
height: 100%
}
.image {
width: 1410px;
margin-right: auto;
margin-left: auto;
height: 500px;
overflow: hidden;
position: relative;
}
.top-container,
.bottom-container {
position: absolute;
bottom: 0px;
height: 100%;
width: 50%;
overflow: hidden;
backface-visibility: hidden;
}
.top-container {
left: 0px;
transform-origin: right bottom;
transform: skewY(10deg);
}
.bottom-container {
right: 0px;
transform-origin: left bottom;
transform: skewY(-10deg);
background-position: 0% 100%;
}
.top-container:after,
.bottom-container:after {
position: absolute;
content: '';
height: 100%;
width: 100%;
bottom: -62px; /* tan(10) * (width/2) / 2 */
background: url(http://placekitten.com/1410/500);
background-size: 200% 100%;
}
.top-container:after {
left: 0px;
transform: skewY(-10deg);
}
.bottom-container:after {
right: 0px;
transform: skewY(10deg);
background-position: 100% 0%;
}
<div class="image">
<div class='top-container'></div>
<div class='bottom-container'></div>
</div>
Just found an insanely good solution on codepen using calc(50% - 1px)
https://codepen.io/hellonico/pen/xEYXmL
background: linear-gradient(7deg, currentColor calc(50% - 1px), transparent 50%);
No blur whatsoever, just a smooth edge
EDIT: .. apparently not in Safari?..