How to plot just one axis label in R? - r

A beginner question: I currently have some plots that look like this.
I'm keeping the plots free of other annotation because I have to fit a lot of them onto one page and specific values aren't important, just the general trend that the red line is to the right of the black one. However, I'd like to be able to indicate that the dashed line in my plot actually represents zero, like so:
Is there any way to tell R to only display that value on the x-axis labels? I don't think using text() would be a good idea because it relies on absolute coordinates, but I'm not really sure how to work with axis options to make it do what I want.

Try:
axis(side = 1, at = 0)
See ?axis for details.

Related

In Stata, how do I modify axes of dot chart?

I'm trying to create a dot chart in Stata, splitting it into two categories
Running a chunk of code:
sysuse nlsw88, clear
drop if race == 3
graph dot (mean) wage, over(occ) by(race)
Creates such output:
So far so good but I'd like to remove labels of Y axis from the right graph to give the data some more space.
The only way I've been able to do that was to manually edit graph and hide the axis label object:
Is there a way to do it programmatically? I do know I could use one more over() but in some graphs of mine that is already taken.
I believe the solution is buried in help bystyle and help by_option. However, I can't get it to work with your example (I'm on Stata 12). But the description is clear. For example:
A bystyle determines the overall look of the combined graphs,
including
whether the individual graphs have their own axes and labels or if instead the axes and labels are shared across graphs arrayed in the
same row and/or in the same column;
...
There are options that let you control each of the above attributes --
see [G-3] by_option --
And also
iyaxes and ixaxes (and noiyaxes and noixaxes) specify whether the y axes and x axes are
to be displayed with each graph. The default
with most styles and
schemes is to place y axes on the leftmost graph of each row and to place x axes on
the bottommost graph of each column. The y and
x axes include the
default ticks and labels but exclude the axes titles.
If for some reason that doesn't work out, something like
sysuse nlsw88, clear
drop if race == 3
graph dot (mean) wage, over(occ) by(race)
gr_edit .plotregion1.grpaxis[2].draw_view.setstyle, style(no)
does (but I don't really like the approach). You can mess with at least the axis number [#] to do a bit of customization. I guess recording changes in the graphical editor and then recycling the corresponding code, may be one way out of difficult situations.

Intelligent Y Axis Scaling BarPlot R

I want to plot some data with barplot. Rather, I want to make a bar graph and barplot seemed the logical choice. I am plotting just fine but I was wondering if there is a way to intelligently scale the y axis to round up from the highest count.
For example I set the yaxis in this case to be 30, because I knew that Strand.22 had 27 counts in it: barplot(unlist(d), ylim=c(0,30), xlab="Forward Reverse", ylab="Counts")
In the future, I want this script to run on its own, so it would be optimal for the the Y-axis to choose it's own ylim. Short of pulling the information out of my 'd' variable I can't think of a good way to do this. Is there an easy way to do this with barplot? Would some other plotter work better? I have seen things about ggplots but it seemed super complex and I wasn't sure that it would do anything better.
EDIT: If I do not choose a ylim it picks automatically and this is what it decided was best.
I disagree with it's choice.
If you don't specify ylim, R will come up with something based on the data. (Sounds like you don't like it's choice, which is fair.)
If you specify something based on the data like:
barplot(unlist(d), ylim=c(0,1.1*max(unlist(d)))
R will draw you a plot that reflects the maximum value of data. That example just takes the maximum of your values and multiplies that by 1.1 (this could be any number) to give it a little extra height. R does something similar to this when you make a scatterplot but it handles barplots slightly differently.

R plot axes don't meet and data extends beyond them

I have a VERY basic plot in R, and I'd like to solve two issues. Here is the code which produces the plot:
plot(o,n,bty="n",pch=21,cex=1.5,bg="gray",xlab="y",ylab="x",lwd=2)
And, here's the plot
There are two unwanted behaviors of this plot that I'm trying to fix. And I don't know how to do either one (nor do I understand why R doesn't do these things already...)
The X and Y axes do not meet. There is a gap near the origin in this plot. I want to remove that. The axes should touch, just like any other graph.
The data extends past the axis is both the X and Y direction. This clearly is unwanted. How can I fix this without having to manually make my own axis. Seems like there should be something more intuitive here.
bty="l".
You may also want to use something like:
xlim=c(0.02, 0.24), ylim=c(0.02, 0.24)
if you don't like the default limits of your two axes.
In general, check out ?par for guidance on both of these and many other options.
Try leaving out bty="n" or replacing it by bty="L" if you really do not want a box with edges above or on the right

R - Scatter plots, how to plot points in differnt lines to overlapping?

I want to plot several lists of points, each list has distance (decimal) and error_no (1-8). So far I am using the following:
plot(b1$dist1, b1$e1, col="blue",type="p", pch=20, cex=.5)
points(b1$dist2, b1$e2, col="blue", pch=22)
to add them both to the same plot. (I will add legends, etc later on).
The problem I have is that points overlap, and even when changing the character using for plotting, it covers up previous points. Since I am planning on plotting a lot more than just 2 this will be a big problem.
I found some ways in:
http://www.rensenieuwenhuis.nl/r-sessions-13-overlapping-data-points/
But I would rather do something that would space the points along the y axis, one way would be to add .1, then .2, and so on, but I was wondering if there was any package to do that for me.
Cheers
M
ps: if I missed something, please let me know.
As noted in the very first point in the link you posted, jitter will slightly move all your points. If you just want to move the points on the y-axis:
plot(b1$dist1, b1$e1, col="blue",type="p", pch=20, cex=.5)
points(b1$dist2, jitter(b1$e2), col="blue", pch=22)
Depends a lot on what information you wish to impart to the reader of your chart. A common solution is to use the transparency quality of R's color specification. Instead of calling a color "blue" for example, set the color to #0000FF44 (Apologies if I just set it to red or green) The final two bytes define the transparency, from 00 to FF, so overlapping data points will appear darker than standalone points.
Look at the spread.labs function in the TeachingDemos package, particularly the example. It may be that you can use that function to create your plot (the examples deal with labels, but could just as easily be applied to the points themselves). The key is that you will need to find the new locations based on the combined data, then plot. If the function as is does not do what you want, you could still look at the code and use the ideas to spread out your points.
Another approach would be to restructure your data and use the ggplot2 package with "dodging". Other approaches rather than using points several times would be the matplot function, using the col argument to plot with a vector, or lattice or ggplot2 plots. You will probably need to restructure the data for any of these.

R/Zoo: show a tick every year on x-axis

I've a zoo object, with a yearqtr index, covering about 50 years. When plotted the x-axis shows labels every 10 years, which feels a bit barren:
b=zoo(1:200,as.yearqtr(1900+seq(1,200)/4))
plot(b)
Some study got me this:
plot(b,xaxt="n");axis(1,time(b))
Which feels like swinging from one extreme to the other, as the x-axis is a blur of ticks, with ugly fractional labels. Is there an easy way to have it just show years? (What I was looking for initially was a way to say: "lower the x-axis label spacing a bit", but there seems nothing like that? cex.axis just alters the font-size.)
Did you read help(axis)?
Here is one way, just creating a simple index every four quarters:
R> ind <- seq(1, length(b), by=4)
and using it to index the axis placement and labels:
R> plot(b,xaxt="n")
R> axis(1,time(b)[ind], format(time(b)[ind]), las=2, cex.axis=0.5)
I used las=2 and the lower cex value to make this fit. Once every year may still be too plenty.
Computing "good" axis labels is really hard.
This is probably one of those (rare) situations when you want to use grid rather then ticks to better show your data. As #dirk-eddelbuettel pointed out - tweaking good axis labels is hard, especially with such density. You also might want your labels inside plot, so the grid will slightly hide their density. The easiest grid to get is with abline, unless you want to play with ggplot2, but it's uglier then standard plots in R (personal opinion). Also - make the plot wider. In fact, it's better to get rid of box around plot too ;) Below is mod of Dirk's approach:
png("strangeplot.png",width=800)
#extend y-axis to fit inside labels and remove box
plot(b,type="n",xaxt="n",yaxt="n",ylab="",xlab="",ylim=c(min(b)-30,max(b)),bty="n"))
#use 'mpg' to get labels inside
axis(1,time(b)[ind], format(time(b)[ind]), las=2, cex.axis=0.6,tick=F,mgp=c(0,-2.5,0))
axis(2,tick=F,las=1)
#you locate lines slightly to the left of label...
abline(h=seq(0,200,by=50),v=time(b)[ind]-0.5,col=gray(0.9))
#...so you need to add extra single line in the end
abline(v=max(time(b)[ind])+0.5,col=gray(0.9))
#plot at the end to get it above grid
points(b,type="l")
dev.off()

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