How to stop text from overlapping CSS? - css

Im creating a website for college and Im not sure how to stop text from overlapping when I make the web browser smaller. This is what I mean:
(not overlapping)
(overlapping)
Here is my jsfiddle: (http://jsfiddle.net/RC4Ar/)
.words {
font-family:apple;
font-size:20px;
max-width:800px;
height:190px;
margin-top:10px;
margin-left:42%;
}
Thanks in advance!

Assuming you are adding the words class to the paragraph tags (without your html, we can only guess), you simply need to remove the height declaration.
.words {
font-family: apple;
font-size: 20px;
max-width: 800px;
margin-top: 10px;
margin-left: 42%; }

For your fiddle example, I would change the title_bar to have a min height instead of a fixed height. This will allow it to be responsive instead of overlapping over the following text.
#title_bar {
margin-top:78px;
left:-17px;
width:101.5%;
min-height:30px;
background:blue;
position:relative;
top:-70px;
z-index:3;
border: 3px rgba(255, 105, 180, 1) solid;
background-image: -webkit-gradient(linear, right bottom, right top, color-stop(0, #5977FF), color-stop(1, #59C5FF));
background-image: -o-linear-gradient(top, #5977FF 0%, #59C5FF 100%);
background-image: -moz-linear-gradient(top, #5977FF 0%, #59C5FF 100%);
background-image: -webkit-linear-gradient(top, #5977FF 0%, #59C5FF 100%);
background-image: -ms-linear-gradient(top, #5977FF 0%, #59C5FF 100%);
background-image: linear-gradient(to top, #5977FF 0%, #59C5FF 100%);
}
Fiddle

Related

How to make css background-blend-mode work with gradients?

I have a page with multiple backgrounds: one with gradient and one with texture pattern. But background-blend-mode doesn't work. Chrome appears to show only gradient layer. When I try to blend two background-images or background-image with solid background-color it works well. But not with gradient. Is something wrong?
body {
width: 100%;
height: 100%;
background: url('../images/noisy.png');
background-color: rgba(29, 84, 140, 1);
background: -webkit-radial-gradient(center, ellipse cover, rgba(36,138,166,1) 0%,rgba(21,112,145,1) 42%,rgba(5,58,103,1) 100%);
background: radial-gradient(ellipse at center, rgba(36,138,166,1) 0%,rgba(21,112,145,1) 42%,rgba(5,58,103,1) 100%);
background-blend-mode: multiply;}
And my goal is something like that:
It does work with gradients you just need to use multiple backgrounds.
The problem with your current code is that you are only setting one background.
First you set background to an image:
background: url('../images/noisy.png');
Then you override the image and set background to a gradient:
background: radial-gradient(ellipse at center, rgba(36,138,166,1) 0%,rgba(21,112,145,1) 42%,rgba(5,58,103,1) 100%);
To assign multiple backgrounds you need to comma seperate them:
background: background1, background2, ..., backgroundN;
Using your gradient:
body {
width: 100%;
height: 100%;
background: url('http://i.stack.imgur.com/PEnJm.png');
background-color: rgba(29, 84, 140, 1);
/* ^ fallbacks for crappy IE ^ */
background: url('http://i.stack.imgur.com/PEnJm.png'), -webkit-radial-gradient(center, ellipse cover, rgba(36,138,166,1) 0%,rgba(21,112,145,1) 42%,rgba(5,58,103,1) 100%);
background: url('http://i.stack.imgur.com/PEnJm.png'), radial-gradient(ellipse at center, rgba(36,138,166,1) 0%,rgba(21,112,145,1) 42%,rgba(5,58,103,1) 100%);
background-blend-mode: multiply;
}
A gradient similar to your image example:
body {
width: 100%;
height: 100%;
background: url('http://i.stack.imgur.com/PEnJm.png'), -moz-linear-gradient(left, rgba(21,112,145,1) 0%, rgba(36,138,166,1) 100%);
background: url('http://i.stack.imgur.com/PEnJm.png'), -webkit-gradient(linear, left top, right top, color-stop(0%,rgba(21,112,145,1)), color-stop(100%,rgba(36,138,166,1)));
background: url('http://i.stack.imgur.com/PEnJm.png'), -webkit-linear-gradient(left, rgba(21,112,145,1) 0%,rgba(36,138,166,1) 100%);
background: url('http://i.stack.imgur.com/PEnJm.png'), -o-linear-gradient(left, rgba(21,112,145,1) 0%,rgba(36,138,166,1) 100%);
background: url('http://i.stack.imgur.com/PEnJm.png'), -ms-linear-gradient(left, rgba(21,112,145,1) 0%,rgba(36,138,166,1) 100%);
background: url('http://i.stack.imgur.com/PEnJm.png'), linear-gradient(to right, rgba(21,112,145,1) 0%,rgba(36,138,166,1) 100%);
background-blend-mode: multiply;
}

CSS Styled Span Class

I was looking on website an found a rather cool style for a span class, but I couldn't figure out how it was created. I looked at the css files, which is where I thought the code would be. Has anyone seen this style before or used it? I would really like to know how to re-create this effect.
the code that I was looking at was the following
<p>
<span class="new">New</span>
</p>
Any help would be greatly appreciated
I could produce the css code you need:
span.new {
padding-right:5px;
padding-left: 25px;
-webkit-border-radius: 5px;
-moz-border-radius: 5px;
border-radius: 5px;
/* Next 6 lines do the same thing but they are used to prevent compatibility issiues in different browsers */
background-image: -ms-linear-gradient(left, #FFFFFF 0%, #EFA718 100%);
background-image: -moz-linear-gradient(left, #FFFFFF 0%, #EFA718 100%);
background-image: -o-linear-gradient(left, #FFFFFF 0%, #EFA718 100%);
background-image: -webkit-gradient(linear, left top, right top, color-stop(0, #FFFFFF), color-stop(1, #EFA718));
background-image: -webkit-linear-gradient(left, #FFFFFF 0%, #EFA718 100%);
background-image: linear-gradient(to right, #FFFFFF 0%, #EFA718 100%);
}
you can get help from http://ie.microsoft.com/testdrive/graphics/cssgradientbackgroundmaker/
and play with it.
They are using an image that they probably created using Photoshop and just setting that image as the background to the span.
span{
background: url('path to image') repeat-none left;
}
Either that or they are using css3 gradients

colozilla gradient generator

I generated gradient background in colorzilla and i put inside css file as u can see in this code and it keeps repeating me the background. I want this background to be from where it starts to the end of page.
body{
background: #1d6fa4;
background: -moz-linear-gradient(-45deg, #1d6fa4 1%, #499bc8 26%, #51abc9 52%, #3e94c1 74%, #277cad 100%);
background: -webkit-gradient(linear, left top, right bottom, color-stop(1%,#1d6fa4), color-stop(26%,#499bc8), color-stop(52%,#51abc9), color-stop(74%,#3e94c1), color-stop(100%,#277cad));
background: -webkit-linear-gradient(-45deg, #1d6fa4 1%,#499bc8 26%,#51abc9 52%,#3e94c1 74%,#277cad 100%);
background: -o-linear-gradient(-45deg, #1d6fa4 1%,#499bc8 26%,#51abc9 52%,#3e94c1 74%,#277cad 100%);
background: -ms-linear-gradient(-45deg, #1d6fa4 1%,#499bc8 26%,#51abc9 52%,#3e94c1 74%,#277cad 100%);
background: linear-gradient(135deg, #1d6fa4 1%,#499bc8 26%,#51abc9 52%,#3e94c1 74%,#277cad 100%);
filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#1d6fa4', endColorstr='#277cad',GradientType=1 );
}
You need this
html, body {
height: 100%;
}
body {
background-position: fixed;
/* Gradient dump goes here */
}

CSS gradient on two-parted image

I have to accomplish following image by using CSS:
It's one image which will contain the main-navigation. So I wrote some CSS in order to do so (not the correct color-codes, I know):
#menu-block {
background: #730868;
background: -webkit-gradient(linear, 0 0, 0 bottom, from(#730868), to(#0a9f9d));
background: -webkit-linear-gradient(top, #730868 0%, #0e70a2 76%,#0a9f9d 100%);
background: -moz-linear-gradient(top, #730868 0%, #0e70a2 76%,#0a9f9d 100%);
background: -ms-linear-gradient(top, #730868 0%, #0e70a2 76%,#0a9f9d 100%);
background: -o-linear-gradient(top, #730868 0%, #0e70a2 76%,#0a9f9d 100%);
background: linear-gradient(top, #730868 0%, #0e70a2 76%,#0a9f9d 100%);
-pie-background: linear-gradient(top, #730868 0%, #0e70a2 76%,#0a9f9d 100%);
behavior: url(/pie/PIE.htc);
}
And this code works great! It does what it has to do except for the arrow on the end... I honestly have no idea on how to tacle this issue.
Should I create a second div in the shape of an arrow and guess the closest color?
It should support IE8...
This gets you close
It actually ends up with a solid colored "point" (equal to the end color of the gradient). It might be possible to actually get a continuation of the gradient into the triangle if it absolutely needs to (I don't have time at present to figure that out).
Here's the example (note: the example uses code generated from colorzilla for IE9 support). You need to have a fixed width for this to work (to set the left/right border of the psuedo-element), but the height can be flexible. In my example, IE8 loses the red center. Perhaps with your PIE solution, it does not.
HTML (with IE9 condition as the example has)
<!--[if gte IE 9]>
<style type="text/css">
#menu-block {
filter: none;
}
</style>
<![endif]-->
<div id="menu-block" ></div>
CSS
#menu-block {
width: 100px;
position: relative;
background: rgb(0,0,255);
background: url(data:image/svg+xml;base64,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);
background: -moz-linear-gradient(top, rgba(0,0,255,1) 0%, rgba(255,0,0,1) 50%, rgba(255,255,0,1) 100%);
background: -webkit-gradient(linear, left top, left bottom, color-stop(0%,rgba(0,0,255,1)), color-stop(50%,rgba(255,0,0,1)), color-stop(100%,rgba(255,255,0,1)));
background: -webkit-linear-gradient(top, rgba(0,0,255,1) 0%,rgba(255,0,0,1) 50%,rgba(255,255,0,1) 100%);
background: -o-linear-gradient(top, rgba(0,0,255,1) 0%,rgba(255,0,0,1) 50%,rgba(255,255,0,1) 100%);
background: -ms-linear-gradient(top, rgba(0,0,255,1) 0%,rgba(255,0,0,1) 50%,rgba(255,255,0,1) 100%);
background: linear-gradient(to bottom, rgba(0,0,255,1) 0%,rgba(255,0,0,1) 50%,rgba(255,255,0,1) 100%);
filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#0000ff', endColorstr='#ffff00',GradientType=0 );
}
#menu-block:after {
content: '';
width: 0;
height: 0;
position: absolute;
left: 0;
top: 100%;
border-right: 50px transparent solid;
border-left: 50px transparent solid;
border-bottom: 0 transparent solid;
border-top: 30px #ffff00 solid;
}
Why not create the full rectangle and then position and overlay triangle images at the bottom that blend with your background to give the look of a down-pointing arrow?

Trouble getting a CSS vertical linear background gradient to display properly in all major browsers

I got it to display exactly how I want it in Firefox, but with every other browser there seems to be some problems. This website isn't exactly public (as in, no one knows of it) yet as I'm still trying to get things to display properly, but the URL is: http://www.mixbin.net (just view:source for the code - there's nothing server side interfering)
Firefox: Perfect.
Chrome: Perfect except the bottom margin is being ignored in the .content class.
Opera: Perfect except the bottom margin is being ignored in the .content class.
Safari: Displays gradient properly but forces a refresh as soon as you scroll halfway down the page.
Internet Explorer: Displays gradient properly but .content div is cut off where the gradient stops.
background:linear-gradient(top, #000000 0%, #353535 100%); /*W3C*/
background:-moz-linear-gradient(top, #000000 0%, #353535 100%); /*FF3.6+*/
background:-ms-linear-gradient(top, #000000 0%, #353535 100%); /*IE10+*/
background:-o-linear-gradient(top, #000000 0%, #353535 100%); /*Opera 11.10+*/
background:-webkit-gradient(linear, left top, left bottom, color-stop(0%, #000000), color-stop(100%, #353535)); /*Chrome,Safari4+*/
background:-webkit-linear-gradient(top, #000000 0%, #353535 100%); /*Chrome10+,Safari5.1+*/
filter:progid:DXImageTransform.Microsoft.gradient( startColorstr='#000000', endColorstr='#353535',GradientType=0 ); /*IE6-9*/
No images wanted. So please don't reply with, "just make a background image".
Update 2: Everything (including IE), is now working. I switched these two lines from:
background:-webkit-linear-gradient(top,#000000 0,#353535 100%);
background:-webkit-gradient(linear,left top,left bottom,color-stop(0,#000),color-stop(100%,#353535));
To:
background:-webkit-linear-gradient(top, #000000, #353535);
background:-webkit-gradient(linear, left top, left bottom, from(#000000), to(#353535));
If your CSS for the gradient is:
background: linear-gradient(top, #000000 0%, #353535 512px);
there will be no need for a <div> with height 512px. Unfortunately, this solution works for every browser except IE.
Back to your extra background <div> approach. I copied and modified your code a little. This works for all browsers.
body {
background: #353535;
}
.content {
background-color: white;
height: 1000px;
margin: 20px auto;
width: 300px;
z-index: 2;
position: relative;
}
#background {
position: absolute;
top: 0;
height: 512px;
width: 100%;
background: linear-gradient(top, #000000 0%, #353535 100%); /*W3C*/
background: -moz-linear-gradient(top, #000000 0%, #353535 100%); /*FF3.6+*/
background: -ms-linear-gradient(top, #000000 0%, #353535 100%); /*IE10+*/
background: -o-linear-gradient(top, #000000 0%, #353535 100%); /*Opera 11.10+*/
background: -webkit-gradient(linear, left top, left bottom, color-stop(0%, #000000), color-stop(100%, #353535)); /*Chrome,Safari4+*/
background: -webkit-linear-gradient(top, #000000 0%, #353535 100%); /*Chrome10+,Safari5.1+*/
filter: progid: DXImageTransform.Microsoft.gradient(startColorstr='#000000', endColorstr='#353535', GradientType=0); /*IE6-9*/
}
<body>
<div id="background"></div>
<div class="content"></div>
</body>
This might not be the solution you are looking for but, since you will have to use hacks to make it looks the same on different browsers, why wont you use an image of the gradient and repeat it in the background.
If your background gradient is 300px, make the image with 300px height and 1px width (image size wont be over 1KB), and repeat it in your background
background: url('bg_gradient.jpg') repeat-x 0px 0px;
It will work on all the browsers without any hassle;

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