CSS gradient on two-parted image - css

Question

I have to accomplish following image by using CSS:
It's one image which will contain the main-navigation. So I wrote some CSS in order to do so (not the correct color-codes, I know):
#menu-block {
background: #730868;
background: -webkit-gradient(linear, 0 0, 0 bottom, from(#730868), to(#0a9f9d));
background: -webkit-linear-gradient(top, #730868 0%, #0e70a2 76%,#0a9f9d 100%);
background: -moz-linear-gradient(top, #730868 0%, #0e70a2 76%,#0a9f9d 100%);
background: -ms-linear-gradient(top, #730868 0%, #0e70a2 76%,#0a9f9d 100%);
background: -o-linear-gradient(top, #730868 0%, #0e70a2 76%,#0a9f9d 100%);
background: linear-gradient(top, #730868 0%, #0e70a2 76%,#0a9f9d 100%);
-pie-background: linear-gradient(top, #730868 0%, #0e70a2 76%,#0a9f9d 100%);
behavior: url(/pie/PIE.htc);
}
And this code works great! It does what it has to do except for the arrow on the end... I honestly have no idea on how to tacle this issue.
Should I create a second div in the shape of an arrow and guess the closest color?
It should support IE8...

Answer 1

This gets you close
It actually ends up with a solid colored "point" (equal to the end color of the gradient). It might be possible to actually get a continuation of the gradient into the triangle if it absolutely needs to (I don't have time at present to figure that out).
Here's the example (note: the example uses code generated from colorzilla for IE9 support). You need to have a fixed width for this to work (to set the left/right border of the psuedo-element), but the height can be flexible. In my example, IE8 loses the red center. Perhaps with your PIE solution, it does not.
HTML (with IE9 condition as the example has)
<!--[if gte IE 9]>
<style type="text/css">
#menu-block {
filter: none;
}
</style>
<![endif]-->
<div id="menu-block" ></div>
CSS
#menu-block {
width: 100px;
position: relative;
background: rgb(0,0,255);
background: url(data:image/svg+xml;base64,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);
background: -moz-linear-gradient(top, rgba(0,0,255,1) 0%, rgba(255,0,0,1) 50%, rgba(255,255,0,1) 100%);
background: -webkit-gradient(linear, left top, left bottom, color-stop(0%,rgba(0,0,255,1)), color-stop(50%,rgba(255,0,0,1)), color-stop(100%,rgba(255,255,0,1)));
background: -webkit-linear-gradient(top, rgba(0,0,255,1) 0%,rgba(255,0,0,1) 50%,rgba(255,255,0,1) 100%);
background: -o-linear-gradient(top, rgba(0,0,255,1) 0%,rgba(255,0,0,1) 50%,rgba(255,255,0,1) 100%);
background: -ms-linear-gradient(top, rgba(0,0,255,1) 0%,rgba(255,0,0,1) 50%,rgba(255,255,0,1) 100%);
background: linear-gradient(to bottom, rgba(0,0,255,1) 0%,rgba(255,0,0,1) 50%,rgba(255,255,0,1) 100%);
filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#0000ff', endColorstr='#ffff00',GradientType=0 );
}
#menu-block:after {
content: '';
width: 0;
height: 0;
position: absolute;
left: 0;
top: 100%;
border-right: 50px transparent solid;
border-left: 50px transparent solid;
border-bottom: 0 transparent solid;
border-top: 30px #ffff00 solid;
}

Answer 2

Why not create the full rectangle and then position and overlay triangle images at the bottom that blend with your background to give the look of a down-pointing arrow?