Twitter bootstrap carousel with pictures that are not uniform - css

Let me start with i am sorry for the long post.
I'm attempting to use the bootstrap carousel and unfortunately the pictures i have been given are NOT uniform. for example some are 100x200, doe are 150x100, etc. The aspect ratios are different, letter vs landscape. Ive attempted a number of things, including the using the following helper function on load of each of my images in the Carousel:
function ScaleImage(srcwidth, srcheight, targetwidth, targetheight, fLetterBox) {
var result = { width: 0, height: 0, fScaleToTargetWidth: true };
if ((srcwidth <= 0) || (srcheight <= 0) || (targetwidth <= 0) || (targetheight <= 0)) {
return result;
}
// scale to the target width
var scaleX1 = targetwidth;
var scaleY1 = (srcheight * targetwidth) / srcwidth;
// scale to the target height
var scaleX2 = (srcwidth * targetheight) / srcheight;
var scaleY2 = targetheight;
// now figure out which one we should use
var fScaleOnWidth = (scaleX2 > targetwidth);
if (fScaleOnWidth) {
fScaleOnWidth = fLetterBox;
}
else {
fScaleOnWidth = !fLetterBox;
}
if (fScaleOnWidth) {
result.width = Math.floor(scaleX1);
result.height = Math.floor(scaleY1);
result.fScaleToTargetWidth = true;
}
else {
result.width = Math.floor(scaleX2);
result.height = Math.floor(scaleY2);
result.fScaleToTargetWidth = false;
}
result.targetleft = Math.floor((targetwidth - result.width) / 2);
result.targettop = Math.floor((targetheight - result.height) / 2);
return result;
}
function OnImageLoad(evt) {
var img = evt.currentTarget;
// what's the size of this image and it's parent
var w = $(img).prop('naturalWidth');
var h = $(img).prop('naturalHeight');
//var tw = $(img).parent().width();
//var th = $(img).parent().height();
var tw = $(img).parent().parent().parent().parent().width();
var th = $(img).parent().parent().parent().parent().height();
// compute the new size and offsets
var result = ScaleImage(w, h, tw, th, true);
// adjust the image coordinates and size
img.width = result.width;
img.height = result.height;
$(img).css("left", result.targetleft);
$(img).css("top", result.targettop);
}
and using the following for each of my images for the carousel
<img src="~/Images/Img1_Tall.jpg" alt="Tall" id="firstImage" onload="OnImageLoad(event);" />
and for the FIRST image in the carousel it works great, but each one after that they seem to just end up their natural size and are horizontally centered but are just against the top boarder of the carousel.
I've even changed the "onload" to pass the values of the length and width of the image but that didn't work either, in debug it seems only the first image kicks off the "onload" event.
the effect i am going for is if the ratio of the container is 3:4 and the ratio of the image is 1:2, the image stretch to meet the left and right edges and would center vertically and have letter box above and below, but the container does not change so that the navigation buttons of the carousel do not move. if the image is 2:1, the image would stretch to meet the top and bottom centered horizontally with letterboxes on the right and left, again keeping the navigation buttons unmoved.
any help would be appreciated... including:
what you are trying to do is crazy

do you want to do something like http://jsbin.com/zotelasa/1 . With that code I can get the active items w,h or any other variables you used in your code to run scale image. Because of parent.parent codes it applies to carousels main divs but you can set your own container.

The quick and dirty solution would be to resize the images using an image editor, and save the properly-sized images to a folder named eg carousel_images. Then whenever you get new content you simply run the image through your editor. With a carousel you're most likely dealing with a number of images in the several to dozens range and not hundreds or thousands.
A more complicated solution is explain to your image provider that you need everything one size. The images aren't going to look right if you're stretching and skewing them on the fly, and you can show them an image with the aspect ratios wrong to explain what you mean.
Finally, as a technical solution, I would try to find out why your image resizer is only being run on the first image. From the sound of it, other images just aren't being run through your function. I think that the technical solution should be a last resort in this case because, like I said, the end results are just not going to be as good. You should at a minimum, if possible, handle each image by hand to make sure the result is adequate.

...And the answer is a little long too...
• I assume that the width’s image’s parent is a constant, and while you don’t change the width’s viewport that must remain.
A-. Get the width’s image’s parent…
(Because the id attribute I took the grand parent’s parameter, that is (must be) the same than the parent’s one).
B-. With the below value deduce the height’s image’s parent, including the preferred ratio (in this case 16x9…
C-. … And with this, set the images’ parents height collection (all the elements with class=”item”).
D-. In order to conserve your carousel’s responsive characteristic, you must add the $F_getAdjustImagesParents function to the window resize event.
E-. Set the slide’s images position to absolute (Note: That must be via JQuery because if you do it in Css the bootstrap carousel will not display correctly. I did it with a new class for the images ('myCarouselImgs').
• Bootstrap carousel’s event 'slide.bs.carousel' and 'slid.bs.carousel'.
As you know, after the ‘click’ event, the slide.bs.carousel event is one of the firsts events that imply the change from the present slide to the next one; while the 'slid.bs.carousel' one is the end of the process.
F-. In the first one (slide.bs.carousel event), using the ‘relatedTarget’ variable of the Bootstrap’s plugin, the item’s id attribute and a item’s data attribute, get the number of the next item (ensure that these last ones -id attribute and data attribute- be present).
G-. In the second one, 'slid.bs.carousel', get the image’s size. For that you need to identify the implied image. I gave an id to each one. With this and the value obtained in previus step, it can do it.
H-. Well, now you already have the four values required for the ScaleImage function. You can call it…
I-. … And apply the result with some effect
var $parentImgW = ' '
var $parentImgH = ' ';
var $myCarousel = $('#myCarousel')
var $carouseItems = $('.item');
function $F_getAdjustImagesParents(){
$parentImgW = $myCarousel.width(); // A
$parentImgH = ($parentImgW*9)/16; // B
$carouseItems.height($parentImgH+'px').css('max-height',$parentImgH+'px'); //C
console.log('$parentImgW ====> '+$parentImgW);
console.log('$parentImgH ====> '+$parentImgH)
};
$F_getAdjustImagesParents();
$(window).on('resize',function(){ // D
$F_getAdjustImagesParents();
});
$('.myCarouselImgs').css('position','absolute'); // E
$myCarousel.on('slide.bs.carousel', function(event) {// The slide’s change process starts
var $slideNum = $("#"+event.relatedTarget.id).data('slide_num'); // F
console.log('$lideNum ====> '+$slideNum)
$myCarousel.on('slid.bs.carousel', function(event) {//The slide’s change process ends
var $imgW = $('#myCarouselSlideImage'+$slideNum).width(); //G
var $imgH = $('#myCarouselSlideImage'+$slideNum).height(); //G
console.log('$imgW ====> '+$imgW);
console.log('$imgH ====> '+$imgH);
var $result = '';
$result = ScaleImage($imgW, $imgH, $parentImgW, $parentImgH, true); //H
console.log('$result.width ====> '+$result.width);
console.log('$result.height ====> '+$result.height);
console.log('$result.targetleft ====> '+$result.targetleft);
console.log('$result.targettop ====> '+$result.targettop);
$('#myCarouselSlideImage'+$slideNum).animate({ // I
width:$result.width+'px',
height:$result.height+'px',
left:$result.targetleft+'px',
top:$result.targettop+'px' },
300);
});
});
See it runnig at https://jsfiddle.net/nd90r1ht/57/ or at https://jsfiddle.net/omarlin25/nd90r1ht/59/

Related

Matter.js i need always same movement ( on any canvas size)

I need help. I have a player and I want jump the player in same diametric order. I wanted to fix this with getHeight with return ( innerHeight/100 * per ), but there's no improvement. Even worse, if the canvas size becomes bigger the player doesn't jump as high and if the window becomes smaller the player jumps higher! I dont want to callibrate in hard code way. I need responsive function!
"leave a comment before vote negative"
r.player.force = {
x: 0,
y: -(getHeight(0.03)),
};
Matter.Body.applyForce(r.player, { x: r.player.position.x, y: r.player.position.y }, r.player.force);
public getHeight(percente: number): number {
return this.reperH() / 100 * percente;
}
this.reperH = function () {
if ((window as any).innerHeight > (window as any).innerWidth / this.aspectRatio) {
return (window as any).innerWidth / this.aspectRatio;
} else {
return (window as any).innerHeight;
}
};
Full source : link
I don't know about a single function to do everything, but you can multiply the force by window.innerHeight or window.innerWidth:
var windowWidth = window.innerWidth;
var windowHeight = window.innerHeight;
var vw = windowWidth/100;
var vh = windowHeight/100;
var jumpForce = vh*-5;
var pushX = vw*0.1;
After that, you just apply jumpForce to the player when they jump and pushX to the player when they move (You will have to multiply it by -1 when the player is moving to the left). If you want it to look even more consistent, you can have jumpForce use vw instead of vh and make sure all of the objects created in the game use vw for positioning and scaling.
Whether you do use only vw or not, you will have to convert all your pixel values into vw or vh (depending on whether you're changing the x or y of the object), so it looks like this:
var object = Bodies.rectangle(vw*60, vw*40, vw*8, vw*5);
I figure that matter.js already have diametric scale with simple number inputs.
When i remove all getHeight and getWidth and put numbers everything start works fine again.
It is my solution for any platform to get percent always no matter for screen size.
My opinion : Matter.js looks like good solution.

How would I make a color relative to images in the background?

For example, if you go to Twitter and click on an image, you can see they have a nice color that is close to what you see on the image. I tried looking up ways to achieve this as well as trying to figure it out on my own but no luck. I'm not sure if there's a color: relative property or not.
if you want to use the a colour that exists in your image and set it as a background colour you need to use the canvas element in the following manner:
HTML (this is your image)
<img src="multicolour.jpg" id="mainImage">
JS
window.onload = function() {
// get the body element to set background (this can change dependending of your needs)
let body = document.getElementsByTagName("body")
// get references to the image element that contains the picture you want to match with background
let referenceImage = document.getElementById("mainImage");
// create a canvas element (but don't add it to the page)
let canvas = document.createElement("canvas");
// make the canvas size the same as your image
canvas.width = referenceImage.offsetWidth
canvas.height = referenceImage.offsetHeight
// create the canvas context
let context = canvas.getContext('2d')
// usage your image reference to draw the image in the canvas
context.drawImage(referenceImage,0,0);
// select a random X and Y coordinates inside the drawn image in the canvas
// (you don't have to do this one, but I did to demonstrate the code)
let randomX = Math.floor(Math.random() * (referenceImage.offsetWidth - 1) + 1)
let randomY = Math.floor(Math.random() * (referenceImage.offsetHeight - 1) + 1)
// THIS IS THE MOST IMPORTANT LINE
// getImageData takes 4 arguments: coord x, coord y, sample size w, and sample size h.
// in our case the sample size is going to be of 1 pixel so it retrieves only 1 color
// the method gives you the data object which constains and array with the r, b, g colour data from the selected pixel
let color = context.getImageData(randomX, randomY, 1, 1).data
// use the data to dynamically add a background color extracted from your image
body[0].style.backgroundColor = `rgb(${color[0]},${color[1]},${color[2]})`
}
here is a gif of the code working... hopefully this helps
UPDATE
Here is the code to select two random points and create a css3 background gradient
window.onload = function() {
// get the body element to set background (this can change dependending of your needs)
let body = document.getElementsByTagName("body")
// get references to the image element that contains the picture you want to match with background
let referenceImage = document.getElementById("mainImage");
// create a canvas element (but don't add it to the page)
let canvas = document.createElement("canvas");
// make the canvas size the same as your image
canvas.width = referenceImage.offsetWidth
canvas.height = referenceImage.offsetHeight
// create the canvas context
let context = canvas.getContext('2d')
// usage your image reference to draw the image in the canvas
context.drawImage(referenceImage,0,0);
// select a random X and Y coordinates inside the drawn image in the canvas
// (you don't have to do this one, but I did to demonstrate the code)
let randomX = Math.floor(Math.random() * (referenceImage.offsetWidth - 1) + 1)
let randomY = Math.floor(Math.random() * (referenceImage.offsetHeight - 1) + 1)
// THIS IS THE MOST IMPORTANT LINE
// getImageData takes 4 arguments: coord x, coord y, sample size w, and sample size h.
// in our case the sample size is going to be of 1 pixel so it retrieves only 1 color
// the method gives you the data object which constains and array with the r, b, g colour data from the selected pixel
let colorOne = context.getImageData(randomX, randomY, 1, 1).data
// THE SAME TO OBTAIN ANOTHER pixel data
let randomX2 = Math.floor(Math.random() * (referenceImage.offsetWidth - 1) + 1)
let randomY2 = Math.floor(Math.random() * (referenceImage.offsetHeight - 1) + 1)
let colorTwo = context.getImageData(randomX2, randomY2, 1, 1).data
// use the data to dynamically add a background color extracted from your image
//body[0].style.backgroundColor = `rgb(${allColors[0]},${allColors[1]},${allColors[2]})`
body[0].style.backgroundImage = `linear-gradient(to right, rgb(${colorOne[0]},${colorOne[1]},${colorOne[2]}),rgb(${colorTwo[0]},${colorTwo[1]},${colorTwo[2]}))`;
}
The following are your options.
1. Use an svg.
As far as I know there's no way to have javascript figure out what color is being used in a png and set it as a background color. But you can work the other way around. You can have javascript set the background color and an svg image to be the same color.
See this stackoverflow answer to learn more about modifying svgs with javascript.
2. Use a custom font.
There are fonts out there that provide a bunch of icons instead of letters, you can also create your own font if you feel so inclined to do so. With css you just have to set the font-color of that icon to be the same as the background-color of your other element.
Font Awesome provides a bunch of useful custom icons. If the image you need to use happens to be similar to one of theirs, you can just go with them.
3. Use canvas
If you really want to spend the time to code it up you can use a html <canvas/> element and put the image into it. From there you can inspect certain details about the image like its color, then apply that color to other elements. I won't go into too much detail about using this method as it seems like it's probably overkill for what you're trying to do, but you can read up more about from this stackoverflow answer.
4. Just live with it.
Not a fun solution, but this is usually the option I go with. You simply have to hard-code the color of the image into your css and live with it. If you ever need to modify the color of the image, you have to remember to update your css also.

Insert a page break if the height of a div does not fit in print media?

I am dynamically creating elements on a web page which I want to print. I want a page break if the element can't fit in the rest of the A4 size paper.
Example is this question: Force an element to take exactly half of available height in print media
In the picture, A broken element is appearing on first page, which should actually go on the second page.
How can I force a page break if the element does not fit in this page.
**What I tried: **
I tried to use css page-breakafter` property, with the following code:
$(document).ready(function(){
$(".row").each(function(){
if($(this).height()>$(document).height()/2){
$(this).after('<div style="page-break-after:always"></div>');
}
});
});
But it does not work.
Here is a JsFiddle
I noticed in your fiddle that you have applied page breaks only after a few rows. The problem with your jQuery code is that, the $(document).height() will return a huge value compared to each row. In your case, document height = 3861 while each row is only 537. Hence 537 is never greater than 3861/2. Revisit the exact condition you need to apply the page break. I tried window.height instead and it works.
Note: You can only see the difference in print preview
EDIT:
Could you remove all the page break div's you manually added and try the below script.
What I tried is to capture the previous element height and then calculate if he page break is necessary.
For this purpose, I have kept a maxHeight of the document to be 1024 considering how much an A4 sheet can take up. Feel free to adjust the maxHeight according to your paper size.
$(document).ready(function(){
var prevRowHeight = 0;
$(".row").each(function(){
// console.log($(this).height());
var maxHeight = 1024;
var eachRowHeight = $(this).height();
if((prevRowHeight + eachRowHeight) > maxHeight){
$(this).before('<div style="page-break-after:always"></div>');
console.log("add page break before");
}
prevRowHeight = $(this).height();
});
});
Previous answer was good but there is a bug. You must need total_height. Please Check this I think this code help you. I use this code for a hospital management project for printing system. Thank you.
jQuery(document).ready(function(){
var prevRowHeight = 0;
var total_height = 0;
jQuery(".row").each(function(){
// console.log($(this).height());
var maxHeight = 1000;
var eachRowHeight = jQuery(this).height();
total_height += prevRowHeight + eachRowHeight;
alert('now : '+total_height +' , Was: '+ prevRowHeight);
if(total_height > maxHeight){
jQuery(this).before('<div style="page-break-after:always"></div>');
console.log("add page break before");
now_height = 0;
}
prevRowHeight = jQuery(this).height();
});
});

Rotate background-image in a rotated div?

I have a div shape with before: and after: so it looks like a cross shape (Rotated).
But now my problem is, that the background is logically also rotated. I'd like that the background image isn't rotated and the image should be the size of the div.
I already tried to add a transform rotate to the place where I added the background but it didnt rotate back. Also for the size I tried background-size to adjust it, didnt work either.
Here is my jsbin: http://jsbin.com/iYogaCE/29/edit
thanks in advance!
nick
Well, I tried for a while to get a version working with pure CSS and HTML, but I was unable to do so. I believe that double pseudo selectors, aka ::after and ::before, would allow it to be possible, but I don't think that you can do it in pure CSS in one object currently.
With that being said, the way I accomplished it using one element is the much more common way - by using a canvas. With canvas it becomes pretty simple. Hopefully the comments make it easy to understand
Live demo here
// Gets a list of all the canvases to create an X for
var canvases = document.getElementsByClassName('profile');
// Allows the X to be drawn on multiple canvases without being redrawn
var tempCanvas = drawX();
// Gives the canvases a background image (the person's profile)
// If you wanted different images for each you could easily create an array
// and iterate through it for each canvas
var background = new Image();
background.src = "http://asta-design.ch/gameotion/wp-content/uploads/2013/03/placeholder.jpg";
// Once the image has loaded, apply the Xs
background.onload = function() {
// Do it for each canvas
for(var i = 0, j = canvases.length; i < j; i ++)
{
// Gets the current canvas and context
var canvas = canvases[i];
var context = canvas.getContext('2d');
// Allows the portrait only to be shown through the generated X
context.globalCompositeOperation = "destination-atop";
// Draws the profile picture
context.drawImage(background, 0,0, canvas.width, canvas.height)
// Cuts out everything that is not within the X
context.drawImage(tempCanvas, 0, 0);
}
}
// Creates the X to use as the cut out
function drawX() {
// Creates a hidden canvas to draw the X on
var offscreenCanvas = document.createElement('canvas');
var offscreenCtx = offscreenCanvas.getContext('2d');
// The width/height of the original canvas, not sure why "canvas.width" doesn't work here...
var size = 200;
offscreenCanvas.width = size;
offscreenCanvas.height = size;
// Creates the rectangles sloped positively
offscreenCtx.save();
offscreenCtx.translate(3 * size / 4, 3 * size / 4);
offscreenCtx.rotate(Math.PI/4);
offscreenCtx.fillRect(-size/2, -size/2, size * .3, size);
// Loads the state before the first rectangle was created
offscreenCtx.restore();
// Creates the rectangles sloped positively
offscreenCtx.translate(3 * size / 4, 1 * size / 4);
offscreenCtx.rotate(-Math.PI/4);
offscreenCtx.fillRect(-size/2, -size/2, size * .3, size);
// Returns the canvas with the X
return offscreenCanvas;
}
You can't rotate a CSS background independently of the element it is attached to.
The only way you're going to be able to do this is to have the rotated content in an additional element inside your existing one, and only rotate the inner element.
eg:
<div> <-- background applied to this element
<div>....</div> <-- but this one is rotated
</div>
Now your background will remain static while the content inside it rotates.
If you can't have any extra markup, you could still achieve this without changing the HTML, by using CSS the :before selector to create an additional pseudo-element behind the main element. Apply the background to that instead of the main element; after that it's similar to what I described above with the extra markup.
Hope that helps.

How can I have a sliding menu div that doesn't move unless the page is scrolled down past a certain point

I have a menu div that I want to slide down so it's always visible, but I want it to be positioned under my title div. I don't want it to move until the top of the menu hits the top of the screen and then stay in place. Basically I want a sliding menu with a maximum height it can slide to.
I think I understand what you're talking about—we used a similar technique on The King with jQuery. Here's how:
///// CONFIGURATION VARIABLES:
var name = "#rightsidebar";
var menu_top_limit = 241;
var menu_top_margin = 20;
var menu_shift_duration = 500;
var menuYloc = null;
///////////////////////////////////
$(window).scroll(function()
{
// Calculate the top offset, adding a limit
offset = menuYloc + $(document).scrollTop() + menu_top_margin;
// Limit the offset to 241 pixels...
// This keeps the menu out of our header area:
if(offset < menu_top_limit)
offset = menu_top_limit;
// Give it the PX for pixels:
offset += "px";
// Animate:
$(name).animate({top:offset},{duration:menu_shift_duration,queue:false});
});
(Hat tip to #soyrex who wrote this code.)
Slashdot does this. Check it out at, for example, http://tech.slashdot.org/tech/08/10/22/1246200.shtml
You may be able to lift the technique from their site.

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