aaaaa1bbbbb
ccccc2ddddd
eeeee3fffff
I want to remove all characters before numbers, after replacing file, it should look like
bbbbb
ddddd
fffff
In Find and Replace dialog box enter these values:
Find what : ^[a-z]+[0-9]
Replace with : Do not enter anything
Make sure to select Regular Expression checkbox.
Hit Replace All
Related
I am using Adobe Indesign. I want to replace all the column breaks (numberpad enter) with paragraph returns without having to do each and every one. Is there a simple way to do this? I've tried using the find/change feature, but I haven't found anywhere in there that I can easily search for a column break and paragraph return.
Just use GREP and appropiate metacharacters
(I am new with this) I see these weird black text-boxes and, as far as I know, they are ascii symbols, but I don't know how to see it in a "normal" view, if possible. Thanks in advance!
It was a bit hard to follow your link, I included the screenshot in your question. The ESC indicates a non-printable character. In this case it is the Escape character (ASCII 27), which from the screen shot appears to be part of escape sequences to change text color.
Unfortunately, Notepad++ does not have the means to render them as intended. One option is that you select one and find/replace with nothing. If you want to get rid of not only the ESC but also its associated "parameters" you can use this regular expression to find and replace them
\x1b[^m]*m
I am trying to figure out how I can put together a find and replace command with wildcards or figure out a way to find and replace the following example:
I would like to find terms that contain double quotes in front of them with a single quote at the end:
Example:
find "joe' and replace with 'joe'
Basically, I'm trying to find all terms with terms having "in front and at the end.'
Check the [x] Regular expression checkbox in textpad's replace dialog and enter the following values:
Find what:
"([^'"]*)'
Replace with:
'\1'
Explanation:
In a regular expression, square brackets are used to indicate character classes. A character class beginning with a caret will match anything not in the class.
Thus [^'"] will match any character except ' and ". The following * indicates that any number of these characters can follow. The ( and ) mark a group. And the group we're looking for starts with " and ends with '. Finally in the replace string we can refer to any group via \n where n is the nth group. In our case it is the first and only group and that is why we used \1.
I want to introduce a backspace character at the beginning of the line where a particular pattern is not found. Please advise.
Thanks,
Sagar
If you mean that you want to "remove the first character" then you can do this:
1) Write your regex pattern of what you want to find. For example, if you want to match Remove me at the start of the line, use:
^R\(emove me\)
Here we use ^ to assert the position to the start of the string. We also capture everything apart from the string we wish to keep in a backreference so it can be used later.
2) Replace the matches we find with whatever we grabbed in our backreference, in this case emove me, in effect backspacing the first character.
3) Make sure regular expression is checked and the cursor is at the start of the file, and hit Replace All.
Before
After:
I have a textbox and have to use the regular expressions in asp.net
My text should not allow the spaces in first and last place.
Output should be:
Valid:
[India Bangalore]
Not valid:
[ India Bangalore ]
i.e : user can enter the spaces in between the words but not in first position and last position.
If you have solution in JavaScript that is also fine.
Trim() should remove any trailing or leading spaces.
Try this please :
^[^\s].*[^\s]$
It simply match input which:
not to start with any white space ^[^\s] followed by any character even white spaces .* and not end with any white space [^\s]$.
Any way calling Trim() method on input string in server-side is much easy .