Hover element - how Can I do something like this in attachment. This triangular as element after or is better way (simple)?
Width is diffrent of each element.
Main problem is in triangular, should I populate width of background? Position left?
Please see http://jsfiddle.net/jachu/AB3wx/
The only way you could do this (with just CSS) is by having a triangular image and when you hover you trigger it to show in CSS.
See this: http://jsfiddle.net/cranavvo/ze8GQ/
10x10 Triangle: http://i.imgur.com/3dxUiTX.png
ul#navigation>li:hover{
background: url('http://i.imgur.com/3dxUiTX.png') no-repeat 100% 100% black;
}
Related
I have a button with perfectly rounded corners; meaning, the button is 50px high and the border radius is 25px, making a perfect half-circle on either side of the button:
Achieving this with CSS is easy, provided you already know the height of the button (button height รท 2 = border radius).
But is it possible to maintain the perfectly-circular edges if the button's height increases dynamically (more text is added, for example)?:
Just set the border-radius to something high, like 360px.
div {
height:50px;
width:500px;
background:red;
border-radius:360px;
}
Look at this jsFiddle example to see what I mean.
I'm looking for a bit of brainstorming assistance.
I am coding a layout that was put together by a designer and am trying to think of a way to handle a horizontal navigation that has angled edges, and goes from a blue background, to a white background when a link is selected.
I'll actually just include a screenshot. This is actually the navigation for a Tabbed content area. The top half of the screenshot shows what it will look like when the first tab is selected. The bottom half of the screenshot shows the 2nd tab selected.
http://i.stack.imgur.com/P34yI.gif
So my problem comes from the fact that HTML elements are rectangles, not rectangles with angled edges. I saved the angled edge with the shadow as a CSS background, and that worked fine, until I realized that each link can turn white and the BG image has a bit of the next link embedded in it to give the illusion of the angle, and thus the left most link would need a different background then the middle link, and the right most link, etc...
I could assign a unique class / id (or use nth child) to each link, but I would like to keep the solution flexible so I can add another link/tab in the future.
I was curious if anyone had any ideas on how to create this appearance by possibly using CSS3 / HTML5 / or some transparent PNG and negative margins or relative positioning?
I'm not asking for code or for you to do my work for me :) I'm just looking for ideas - just a bit of community brainstorming. If anyone has any suggestions please let me know, it might lead me to a solution.
Thanks!!
Assuming you're using a 'ul > li > a' structure for the menu, I would use two angled backgrounds (right and left... the right one is about 27px with the shadow, the left about 22px). Apply the left corner to the <li>, and the right corner to the <a>. That will give you doubled backgrounds on each list item, so you should use negative margins on each side of the <li> to pull its siblings to overlap. Then use z-index to make sure on hover or highlight that the menu item shows up on top of the others. I've added an additional 30px of padding on both sides to create the extra space around the text:
li {
margin-right: -27px;
margin-left: -22px;
padding-left: 52px;
position: relative;
background: url(leftcorner.jpg) left top no-repeat;
background-color: #3aa1cc
}
li a {
padding-right: 57px;
background: url(rightcorner.jpg) right top
}
li:hover {z-index: 5; background: url(leftcorner-hover.jpg) left top no-repeat}
li:hover a {background: url(rightcorner-hover.jpg) left top no-repeat}
I haven't tested this but I think it should work... possibly with some additional tweaking.
This solution doesn't include the subtle inner shadow... to do that you would have to use a 1px repeating gradient background on the <li> then use :before and :after pseudo elements for the two corner background images.
Additionally in my code I put two seperate .jpgs (normal and hover) but really you should use a sprite and background-position so there is no flash while the hover state image is loading.
I have an image with and array 16x16 of multiple icons. e.g. "http://www.freepbx.org/v3/browser/trunk/assets/css/jquery/vader/images/ui-icons_cd0a0a_256x240.png?rev=1"
Any idea how to choose only one of those icons and set it as a background image using CSS?
What I want to achieve is have an x icon or tick icon to the right of an input text element in to notify the user if what he has given as input is valid or invalid.
Thanks,
Stavros
You would set the height of an element to the height of the icon in that image that you want, and then set the background of that element like so:
span {
background:url(path/to/image) 50px 10px;
height:10px;
width:10px;
}
Where the element used is a span, and the desired icon is at position (50px, 10px). To learn more about positioning backgrounds have a look at: http://www.w3schools.com/cssref/pr_background-position.asp
You can accomplish this with css, something like this:
div#myDiv {
background-image:url('url-to-image');
background-position:50px 50px; /* coordinates of the top left corner of the image portion you want to display */
width:20px; /* Width of image portion */
height:20px; /* Height of image portion */
}
I need to place an icon of 48x48 as background. I have this icon in my image sprite where of course there are many other images.
Is there a way to show as background only a porition of the image?
thanks
EDIT: Is there a way to do this without setting width-height of the backgrounded element? (I am not sure if acutally i can set a width-height)
Edit2: this is what i need: http://jsfiddle.net/pdxnj/
Thanks
Set the width and height of the element to 48px.
.element{
width: 48px;
height: 48px;
}
Set the background of the element to your image
.element{
background-image: url('image.png');
}
Move the background so that the top left corner of the icon is positioned correctly.
.element{
background-position: 20px 94px;
}
The two numbers in background-position are the X and Y coordinates (respectively) where the top left corner of your 48px by 48px is in your sprite image. So maybe it's actually 96px 0px or something.
EDIT
If you can't control the width and height of the element you are trying to put the background in, but you can add new DOM elements, you can try adding a span inside the element you really want to put the image as a background for.
It would look something like:
<div id="noControl">
<span id="justCreated">
</span>
</div>
and the CSS would look exactly the same as above, except you would need to treat the inline span as a block element:
#justCreated{
display: inline-block;
}
EDIT 2
If you have control over new DOM elements, and want to make your sprite the background without messing with a span, just add another div inside your original one.
Would wind up looking like:
<div id="noControl">
<div id="justCreated">
ALL of the content that used to be inside #noControl
</div>
</div>
and the CSS for it would be
#justCreated{
width: 48px;
height: 48px;
background-image: url('image.png');
background-position: 96px 0px;
z-index: -200;
/* z-index of all the contents needs to be not set, or set to larger than -200 */
}
This is all theoretical, but it SHOULD work.
This way, you can apply the sprite sizing to a block element without messing with the inline stuff. This may affect CSS if it addresses elements by child status (like #noControl > a), because you are inserting a div between the parent and the child.
I am still researching whether you can do this at all if you have no control over the DOM at all.
simple answer no, but by using html elements you can. Html element hight and width should match the background portion of image.
You can if you're not going to be setting a repeating background. Otherwise no.
To do this, you need to play around with the background offset, and width/height of the actual element that you're setting the background on.
it will depend on how much whitespace is around it in the sprite whether it will fit where you need it to without showing parts of other images.. however you could e.g. put a span where you want the image and crop the span to 48x48 so that it only shows the icon itself. it kind of depends what you want to use it for and how the sprite is built
It's better using ::before or ::after so you can easily define your image size without having overflow problems!
This is possible. You need to display that in a 48x48 div then set position: absolute style for the div and define left and top too for it. Also set z-index: 0 for the div so that it appears under everything.
Is it possible to hide lower div background fully?
I have two fixed position divs with shadow - semi transparent background so they overlap and become darker.
Is there a way - in Adobe Air - to make the lower div's background fully hidden?
Not sure if this helps or what you mean by "in adobe air" but can you not position the background of the second div to start further down with css eg
.div2 {
background-position: 0 50%;
}
Or you can move it down a set number of pixels maybe.
read more about bg positioning: w3c schools
If you want to hide the seconde div why not use jquery to hide it?
$("div1.class").hide()