Spring + Jackson + joda time: how to specify the serialization/deserialization format? - spring-mvc

I have the following class:
public static class ARestRequestParam
{
String name;
LocalDate date; // joda type
}
And I want it to be deserialized from the following JSON which is processed by jackson.
{ name:"abc", date:"20131217" }
Actually, I want to deserialize any LocalDate field in any class with "yyyyMMdd" format, without duplicating the format string, without adding any setter method, without any XML configuration. (That is, annotation and Java code is preferable)
How can it be done?
Also, I also want to know the serialization part. that is, LocalDate -> "yyyyMMdd".
I've seen followings:
jackson-datatype-joda (https://github.com/FasterXML/jackson-datatype-joda)
custom serializer (public class JodaDateTimeJsonSerializer extends JsonSerializer { ... } - Spring #ResponseBody Jackson JsonSerializer with JodaTime)
#JsonCreator
#DateTimeFormat
But I don't know which is applicable, and which is most up-to-date.
BTW, I use Spring Boot.
UPDATE
Ok, I have managed to write working code for the deserialization part.
It is as follows:
#Configuration
#EnableWebMvc
public class WebMvcConfiguration extends WebMvcConfigurerAdapter
{
#Override
public void configureMessageConverters(
List<HttpMessageConverter<?>> converters)
{
converters.add(jacksonConverter());
}
#Bean
public MappingJackson2HttpMessageConverter jacksonConverter()
{
MappingJackson2HttpMessageConverter converter =
new MappingJackson2HttpMessageConverter();
ObjectMapper mapper = new ObjectMapper();
mapper.registerModule(new ApiJodaModule());
converter.setObjectMapper(mapper);
return converter;
}
#SuppressWarnings("serial")
private class ApiJodaModule extends SimpleModule
{
public ApiJodaModule()
{
addDeserializer(LocalDate.class, new ApiLocalDateDeserializer());
}
}
#SuppressWarnings("serial")
private static class ApiLocalDateDeserializer
extends StdScalarDeserializer<LocalDate>
{
private static DateTimeFormatter formatter =
DateTimeFormat.forPattern("yyyyMMdd");
public ApiLocalDateDeserializer() { super(LocalDate.class); }
#Override
public LocalDate deserialize(JsonParser jp, DeserializationContext ctxt)
throws IOException, JsonProcessingException
{
if (jp.getCurrentToken() == JsonToken.VALUE_STRING)
{
String s = jp.getText().trim();
if (s.length() == 0)
return null;
return LocalDate.parse(s, formatter);
}
throw ctxt.wrongTokenException(jp, JsonToken.NOT_AVAILABLE,
"expected JSON Array, String or Number");
}
}
}
I had to implement the deserializer myself, since the datetime format for the deserializer in jackson-datatype-joda cannot be altered. So, since I've implemented the deserializer myself, jackson-datatype-joda is not needed. (although I've copied pieces of its code)
Is this code Ok?
Is this up-to-date solution?
Is there any other easier way?
Any suggestion would be greatly appreciated.
UPDATE
Following Dave Syer's suggestion, I modified the source above as follows:
Removed 2 methods: configureMessageConverters(), jacksonConverter()
Added following method into WebMvcConfiguration class:
#Bean
public Module apiJodaModule()
{
return new ApiJodaModule();
}
But now it does not work. It seems apiJodaModule() is ignored.
How can I make it work?
(It seems that I should not have a class that has #EnableWebMvc to use that feature.)
The version I use is org.springframework.boot:spring-boot-starter-web:0.5.0.M6.
UPDATE
Final working version is as follows: (with other configurations I've done previously in the class that had #EnableWebMvc)
As Dave Syer mentioned, this will only work on BUILD-SNAPSHOT version, at least for now.
#Configuration
public class WebMvcConfiguration
{
#Bean
public WebMvcConfigurerAdapter apiWebMvcConfiguration()
{
return new ApiWebMvcConfiguration();
}
#Bean
public UserInterceptor userInterceptor()
{
return new UserInterceptor();
}
public class ApiWebMvcConfiguration extends WebMvcConfigurerAdapter
{
#Override
public void addInterceptors(InterceptorRegistry registry)
{
registry.addInterceptor(userInterceptor())
.addPathPatterns("/api/user/**");
}
#Override
public void addResourceHandlers(ResourceHandlerRegistry registry)
{
registry.addResourceHandler("/**")
.addResourceLocations("/")
.setCachePeriod(0);
}
}
#Bean
public Module apiJodaModule()
{
return new ApiJodaModule();
}
#SuppressWarnings("serial")
private static class ApiJodaModule extends SimpleModule
{
public ApiJodaModule()
{
addDeserializer(LocalDate.class, new ApiLocalDateDeserializer());
}
private static final class ApiLocalDateDeserializer
extends StdScalarDeserializer<LocalDate>
{
public ApiLocalDateDeserializer() { super(LocalDate.class); }
#Override
public LocalDate deserialize(JsonParser jp,
DeserializationContext ctxt)
throws IOException, JsonProcessingException
{
if (jp.getCurrentToken() == JsonToken.VALUE_STRING)
{
String s = jp.getText().trim();
if (s.length() == 0)
return null;
return LocalDate.parse(s, localDateFormatter);
}
throw ctxt.mappingException(LocalDate.class);
}
}
private static DateTimeFormatter localDateFormatter =
DateTimeFormat.forPattern("yyyyMMdd");
}
}

Your code is OK, but if you use #EnableWebMvc in a Spring Boot app you switch off the default settings in the framework, so maybe you should avoid that. Also, you now have only one HttpMessageConverter in your MVC handler adapter. If you use a snapshot of Spring Boot you ought to be able to simply define a #Bean of type Module and everything else would be automatic, so I would recommend doing it that way.

Related

Spring redis unable to autowire repository

I'm using custom crudrespository to persist data in redis. However, I'm unable to autowire custom repository.
All the configuration seems correct and redis is running on my local.
import org.springframework.data.repository.CrudRepository;
import org.springframework.stereotype.Repository;
#Repository
public interface CustomRepository extends CrudRepository<String,
Long> {
String get(String key);
void put(String key, String value);
}
//////////
public class StorageServiceImpl implements IStorageService {
#Autowired
private CustomRepository respository;
#Override
public void saveParameter() {
this.respository.put("key1","value1");
}
#Override
public String getParameter() {
return this.respository.get("key1");
}
/////
#Service
public interface IStorageService {
void saveParameter();
String getParameter();
}
///////
#SpringBootApplication(scanBasePackages = {"com.example.cache"})
#EnableRedisRepositories(basePackages = {"com.example.cache.repository"})
public class ApplicationConfiguration {
public static void main(String[] args){
SpringApplication.run(ApplicationConfiguration.class, args);
new StorageServiceImpl().saveParameter();
System.out.println(new StorageServiceImpl().getParameter());
}
}
When I try running this application using gradle bootRun, I get
Exception in thread "main" java.lang.NullPointerException
at com.example.cache.impl.StorageServiceImpl.saveParameter(StorageServiceImpl.java:16)
at com.example.cache.ApplicationConfiguration.main(ApplicationConfiguration.java:17)
Not sure what's wrong?
You can't use new on any bean, you need to #Autowire it. The annotations only work with spring managed beans at every level.
Add a new bean with a a storage service and a method that makes your call after it is created.
Also, I can't remember if the spring-boot creates the bean if there is only one implementation but I believe your StorageServiceImpl needs the #Service annotation, not the interface.
Delete this from your ApplicationConfiguration class.
new StorageServiceImpl().saveParameter();
System.out.println(new StorageServiceImpl().getParameter());
Then add this new class.
#Service
public class Startup {
#Autowired
IStorageService storageService;
#PostConstruct
public void init(){
storageService.saveParameter();
System.out.println(storageService().getParameter());
}
}
And you need a config
#Configuration
#EnableRedisRepositories
public class ApplicationConfig {
#Bean
public RedisConnectionFactory connectionFactory() {
return new JedisConnectionFactory();
}
#Bean
public RedisTemplate<?, ?> redisTemplate() {
RedisTemplate<byte[], byte[]> template = new RedisTemplate<byte[], byte[]>();
return template;
}
}

Return 404 for every null response

I'd like to return 404 when the response object is null for every response automatically in spring boot.
I need suggestions.
I don't want to check object in controller that it is null or not.
You need more than one Spring module to accomplish this. The basic steps are:
Declare an exception class that can be used to throw an exception when a repository method does not return an expected value.
Add a #ControllerAdvice that catches the custom exception and translates it into an HTTP 404 status code.
Add an AOP advice that intercepts return values of repository methods and raises the custom exception when it finds the values not matching expectations.
Step 1: Exception class
public class ResourceNotFoundException extends RuntimeException {}
Step 2: Controller advice
#ControllerAdvice
public class ResourceNotFoundExceptionHandler
{
#ExceptionHandler(ResourceNotFoundException.class)
#ResponseStatus(HttpStatus.NOT_FOUND)
public void handleResourceNotFound() {}
}
Step 3: AspectJ advice
#Aspect
#Component
public class InvalidRepositoryReturnValueAspect
{
#AfterReturning(pointcut = "execution(* org.example.data.*Repository+.findOne(..))", returning = "result")
public void intercept(final Object result)
{
if (result == null)
{
throw new ResourceNotFoundException();
}
}
}
A sample application is available on Github to demonstrate all of this in action. Use a REST client like Postman for Google Chrome to add some records. Then, attempting to fetch an existing record by its identifier will return the record correctly but attempting to fetch one by a non-existent identifier will return 404.
Simplest way to do this in Spring is write your own exception class like below
#ResponseStatus(value = HttpStatus.NOT_FOUND)
class ResourceNotFoundException extends RuntimeException{
}
Then just throw the ResourceNotFoundException from anywhere.
if (something == null) throw new ResourceNotFoundException();
For more -> Read
Similar to #manish's answer (https://stackoverflow.com/a/43891952/986160) but without the AspectJ pointcut and using another #ControllerAdvice instead:
Step 1: NotFoundException class:
public class NotFoundException extends RuntimeException {
public NotFoundException(String msg) {
super(msg);
}
public NotFoundException() {}
}
Step 2: Check if body returned in endpoint is null and throw NotFoundException:
#ControllerAdvice
public class NotFoundAdvice implements ResponseBodyAdvice {
#Override
public boolean supports(MethodParameter returnType, Class converterType) {
return true;
}
#Override
#SuppressWarnings("unchecked")
public Object beforeBodyWrite(Object body, MethodParameter returnType, MediaType selectedContentType, Class selectedConverterType, ServerHttpRequest request, ServerHttpResponse response) {
if (body == null) {
throw new NotFoundException("resource not found");
}
return body;
}
}
Step 3: handle NotFoundException and make the response have a status of 404
#ControllerAdvice
public class GlobalExceptionAdvice {
#Data
public class ErrorDetails {
private Date timestamp;
private String message;
private String details;
public ErrorDetails(Date timestamp, String message, String details) {
super();
this.timestamp = timestamp;
this.message = message;
this.details = details;
}
}
#ExceptionHandler(NotFoundException.class)
public final ResponseEntity<ErrorDetails> notFoundHandler(Exception ex, WebRequest request) {
ErrorDetails errorDetails = new ErrorDetails(new Date(), ex.getMessage(),
request.getDescription(false));
return new ResponseEntity<>(errorDetails, HttpStatus.NOT_FOUND);
}
}
Alternative to Step 3:
You can just annotate your NotFoundException with #ResponseStatus and override fillInStackTrace() (from https://stackoverflow.com/a/31263942/986160) so that it has similar effect to GlobalExceptionAdvice and doesn't show stacktrace like this:
#ResponseStatus(value = HttpStatus.NOT_FOUND,reason = "resource not found")
public class NotFoundException extends RuntimeException {
public NotFoundException(String msg) {
super(msg);
}
public NotFoundException() {}
#Override
public synchronized Throwable fillInStackTrace() {
return this;
}
}
There is no need to throw exceptions, now ResponseBodyAdvice does the trick:
#ControllerAdvice
public class NullTo404 implements ResponseBodyAdvice<Object> {
#Override
public boolean supports(MethodParameter returnType, Class<? extends HttpMessageConverter<?>> converterType) {
return true;
}
#Override
public Object beforeBodyWrite(Object body, MethodParameter returnType, MediaType selectedContentType,
Class<? extends HttpMessageConverter<?>> selectedConverterType, ServerHttpRequest request,
ServerHttpResponse response) {
if (body == null) {
response.setStatusCode(HttpStatus.NOT_FOUND);
}
return body;
}
}
Similarly, you can implement ResponseBodyAdvice<Optional<?>>, and check for Optional.isEmpty() before setting the response status. It has the added benefit of working nicely with CrudRepository. Most controller methods eventually ends like this:
public Optional<Product> getProductBySku(#PathVariable String sku) {
// logic goes here...
return productRepository.findBySku(sku);
}

Spring MVC - How to create a proper Service layer?

I'm using SpringBoot and I am trying to create a service layer for my web application but i cant make it work.
My classes look like this
ServiceFactory
#Service
public class ServiceFactory {
#Autowired
public static EncuestaService getEncuestaService()
{
return new EncuestaServiceImpl();
}
}
EncuestaService
public interface EncuestaService {
void crearEncuesta(Encuesta encuesta, Map<String,String> parametros);
}
EncuestaServiceImpl
#Service
public class EncuestaServiceImpl implements EncuestaService {
#Override
public void crearEncuesta(Encuesta encuesta, Map<String, String> parametros) {
CrearEncuesta nueva = new CrearEncuesta(encuesta,parametros);
nueva.execute();
}
}
CrearEncuesta
#Service
public class CrearEncuesta {
private Encuesta encuesta;
private Map<String,String> parametros;
#Autowired
private RespuestasRepository respuestasRepository;
#Autowired
private EncuestasRepository encuestasRepository;
public CrearEncuesta(Encuesta encuesta, Map<String,String> parametros) {
super();
this.encuesta = encuesta;
this.parametros = parametros;
}
public void execute()
{
encuestasRepository.save(encuesta);
}
}
Everytime I call ServiceFactory.getEncuestasService().crearEncuesta() from any Controller it returns me a NullPointerException.
From what I have been reading I should not be creating a new EncuestsaServiceImpl() in my ServiceFactory but I don't really know the correct way to do so. I would appreciate if anyone could help me out :P.
Edit:
#SpringBootApplication
public class Application {
public static void main(String[] args) {
SpringApplication.run(Application.class, args);
}
Controller
#Controller
public class EncuestaController {
#RequestMapping(value ="registrarEncuesta", method = RequestMethod.POST)
private String formularioEncuesta(#Valid #ModelAttribute("formEncuesta") EncuestaForm formEncuesta, BindingResult bindingResult,#RequestParam Map<String,String> allRequestParams)
{
if (bindingResult.hasErrors()) {
return "nuevaEncuesta";
}
try {
Encuesta nueva = formEncuesta.toEncuesta();
ServiceFactory.getEncuestaService().crearEncuesta(nueva,allRequestParams);
} catch (DataIntegrityViolationException e) {
return "nuevaEncuesta";
}
return "redirect:/encuestas";
}
}
You will have to read a little bit more about dependency injection. The central principle in Spring Framework is dependency injection which should be used to avoid referencing beans (service implementations, repository implementations etc...) statically. Spring container also servers as a bean factory that will instantiate and inject (autowire) implementations to beans that need them.
Because Spring will instantiate service interface implementations for you, you don't need ServiceFactory. In your controller you need to add a reference (a field) to EncuestaService and annotate it as Autowired and Spring will wire in the implementation. And then you can just use it in your controller.
#Controller
public class EncuestaController {
#Autowired
EncuestaService encuestaService;
#RequestMapping(value ="registrarEncuesta", method = RequestMethod.POST)
private String formularioEncuesta(#Valid #ModelAttribute("formEncuesta") EncuestaForm formEncuesta, BindingResult bindingResult,#RequestParam Map<String,String> allRequestParams)
{
if (bindingResult.hasErrors()) {
return "nuevaEncuesta";
}
try {
Encuesta nueva = formEncuesta.toEncuesta();
encuestaService.crearEncuesta(nueva,allRequestParams);
} catch (DataIntegrityViolationException e) {
return "nuevaEncuesta";
}
return "redirect:/encuestas";
}
}

BeanPostProcessor not being called in spring mvc web app

I have a spring mvc 3.0 web application and am trying to implement a generic solution for my initBinder methods. Rather than speciyfying the same initBinder code in all my contorllers for my date picker I am trying to do this (I do not have #Controller advice to help me in this version of spring)
#Component
public class MyPostProcessor implements BeanPostProcessor {
public Object postProcessBeforeInitialization(Object bean, String name) throws BeansException {
if (bean instanceof RequestMappingHandlerAdapter) {
WebBindingInitializer wbi = ((RequestMappingHandlerAdapter) bean).getWebBindingInitializer();
if (wbi == null) {
wbi = new ConfigurableWebBindingInitializer();
((RequestMappingHandlerAdapter) bean).setWebBindingInitializer(wbi);
}
if (wbi instanceof ConfigurableWebBindingInitializer) {
((ConfigurableWebBindingInitializer) wbi).setPropertyEditorRegistrar(new MyPropertyEditorRegistrar());
}
}
return bean;
}
public class MyPropertyEditorRegistrar implements PropertyEditorRegistrar {
#Value("#{appProperties['date.format']}")
public String dateFormat = null;
/* (non-Javadoc)
* #see org.springframework.beans.PropertyEditorRegistrar#registerCustomEditors(org.springframework.beans.PropertyEditorRegistry)
*/
public void registerCustomEditors(PropertyEditorRegistry registry) {
SimpleDateFormat df = new SimpleDateFormat(dateFormat);
df.setLenient(false);
registry.registerCustomEditor(Date.class, new CustomDateEditor(df, true));
}
}
But my BeanPostProcessor doesn't seem to be getting called. Can someone help me understand how and when the BeanPostProcessor gets called?
p.s. I am using mvc:annotationdriven
thanks

Spring MVC jackson auto serialize?

I would like to serialize an object with jackson in spring MVC.
I have a controller which returns an ObjectTest1 which has a property ObjectTest2.
public class ObjectTest1{
private ObjectTest2;
// setters getters...
}
public class ObjectTest2{
private String value;
// setters getters...
}
public #ResponseBody ObjectTest1 test() throws IOException ...
I have a mapper and I have a serializer for ObjectTest2 and I've annotated the ObjectTest1.getObjectTest2 method with #JsonSerialize(using = ObjectTest2.class).
It works correctly!
But I want to use this serializer in a lot of Object, not just in ObjectTest1.
What should I do to avoid put annotation every getter method? Can use spring this serializer automatically for all properites which is ObjectTest2?
UPDATED:
I've already use this in my code:
<mvc:annotation-driven>
In ajax response Objects generated correctly as json.
Maybe I should try to explain another way.
So.
I have these objects:
public class DTO{
private InnerThing innerThing;
#JsonSerialize(using=ThingSerializer.class)
public InnerThing getThing(){...}
}
public class InnerThing{
private String value;
}
Generated json looks like:
{"innerThing":{"value":"something"}}
Afther when I've written a serializer, json is:
{"innerThing":"something"}
It is OK, but to get the second version of json I must annotate the getInnerThing method in DTO class with #JsonSerialize...
I don't want to annotate all methods where I use InnerThing as a property.
So my question is, can spring auto serialize every property which type is InnerThing?
By default, Spring will handle serialization and de-serialization of JSON automatically if you add Jackson to the classpath and you use either <mvc:annotation-driven> or #EnableWebMvc.
Links to the Spring Reference Docs:
Spring 3.0: <mvc:annotation-driven>
Spring 3.1: <mvc:annotation-driven> and #EnableWebMvc
You want Jackson to always use your custom JsonSerializer or JsonDeserializer to serialize/deserialize a specific type?
I ended up writing a custom Jackson module to let Jackson find serializers and deserializers that are Spring beans.
I am using Spring 3.1.2 and Jackson 2.0.6
Simplified version:
public class MyObjectMapper extends ObjectMapper {
#Autowired
public MyObjectMapper(ApplicationContext applicationContext) {
SpringComponentModule sm = new SpringComponentModule(applicationContext);
registerModule(sm);
}
}
Module:
public class SpringComponentModule extends Module {
private ApplicationContext applicationContext;
public SpringComponentModule(ApplicationContext applicationContext) {
this.applicationContext = applicationContext;
}
#Override public String getModuleName() {
return "jackson-spring-component";
}
#Override public Version version() {
return SpringComponentModuleVersion.instance.version();
}
#Override
public void setupModule(SetupContext context) {
context.addSerializers(new SpringComponentSerializers(this.applicationContext));
context.addDeserializers(new SpringComponentDeserializers(this.applicationContext));
}
}
ComponentSerializer class:
public class SpringComponentSerializers extends Serializers.Base {
private ApplicationContext applicationContext;
public SpringComponentSerializers(ApplicationContext applicationContext) {
this.applicationContext = applicationContext;
}
#Override
public JsonSerializer<?> findSerializer(SerializationConfig config, JavaType type, BeanDescription beanDesc) {
Class<?> raw = type.getRawClass();
Map<String,JsonSerializer> beanSet = applicationContext.getBeansOfType(JsonSerializer.class);
for(String beanName : beanSet.keySet()) {
JsonSerializer<?> serializer = beanSet.get(beanName);
if(serializer.handledType().isAssignableFrom(raw)) {
return serializer;
}
}
return null;
}
}

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