Is it real to make such border through css?
I thought about
border: 3px solid white;
border-top: none;
and pseudo-element with gradient, but its not exactly the same.
You can do this by adding a pseudo-element with a gradient. transparent -> white -> transparent.
FIDDLE
CSS
div
{
width: 600px;
height: 200px;
border: 5px solid black;
border-radius: 20px;
position: relative;
margin: 50px;
}
div:before
{
content: '';
position: absolute;
top:-5px;
left:0;right:0;
margin:auto;
height: 5px;
width: 80%;
background: -moz-linear-gradient(left, rgba(255,255,255,0) 0%, rgba(255,255,255,0) 1%, rgba(255,255,255,1) 17%, rgba(255,255,255,1) 85%, rgba(255,255,255,0) 100%); /* FF3.6+ */
background: -webkit-gradient(linear, left top, right top, color-stop(0%,rgba(255,255,255,0)), color-stop(1%,rgba(255,255,255,0)), color-stop(17%,rgba(255,255,255,1)), color-stop(85%,rgba(255,255,255,1)), color-stop(100%,rgba(255,255,255,0))); /* Chrome,Safari4+ */
background: -webkit-linear-gradient(left, rgba(255,255,255,0) 0%,rgba(255,255,255,0) 1%,rgba(255,255,255,1) 17%,rgba(255,255,255,1) 85%,rgba(255,255,255,0) 100%); /* Chrome10+,Safari5.1+ */
background: -o-linear-gradient(left, rgba(255,255,255,0) 0%,rgba(255,255,255,0) 1%,rgba(255,255,255,1) 17%,rgba(255,255,255,1) 85%,rgba(255,255,255,0) 100%); /* Opera 11.10+ */
background: -ms-linear-gradient(left, rgba(255,255,255,0) 0%,rgba(255,255,255,0) 1%,rgba(255,255,255,1) 17%,rgba(255,255,255,1) 85%,rgba(255,255,255,0) 100%); /* IE10+ */
background: linear-gradient(to right, rgba(255,255,255,0) 0%,rgba(255,255,255,0) 1%,rgba(255,255,255,1) 17%,rgba(255,255,255,1) 85%,rgba(255,255,255,0) 100%); /* W3C */
filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#00ffffff', endColorstr='#00ffffff',GradientType=1 ); /* IE6-9 */
}
[Update: this can be done with a radial gradient, but Im no longer in front of my computer.]
I'm not sure that there's a border gradient (yet anyway), but I built something with nested s for you. Just an idea. It's just missing the solid white across the bottom. Hope it's helpful.
jsfiddle: http://jsfiddle.net/itsmikem/HfCT3/
css:
div {
position:relative;
}
#outer {
background: #cccc00;
width:200px;
padding:10px;
}
#mid {
border-radius:10px;
background: #ffffff;
background: -webkit-linear-gradient(left, #ffffff 0%,#cccc00 50%,#ffffff 100%);
background: linear-gradient(to right, #ffffff 0%,#cccc00 50%,#ffffff 100%);
filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#ffffff', endColorstr='#ffffff',GradientType=1 );
padding:3px;
}
#inner {
/*width:100%;
height:100%;*/
background:#cccc00;
border-radius:10px;
padding:10px;
}
html:
<div id="outer">
<div id="mid">
<div id="inner">stuff
</div>
</div>
</div>
Related
I'm having a border transition on a focus. When I focus the input field, I want the border to change color. This works.
What I don't want is to let the border load when the page load, which it does now. Why is it doing this?
<input type="stad" name="stad" value=""/>
input {
border: 7px #227a7b solid;
height: 20px;
width: 200px;
background: #1a5a78;
/* Old browsers */
background: -moz-linear-gradient(-45deg, #1a5a78 0%, #11c7b8 100%);
/* FF3.6+ */
background: -webkit-gradient(linear, left top, right bottom, color-stop(0%, #1a5a78), color-stop(100%, #11c7b8));
/* Chrome,Safari4+ */
background: -webkit-linear-gradient(-45deg, #1a5a78 0%, #11c7b8 100%);
/* Chrome10+,Safari5.1+ */
background: -o-linear-gradient(-45deg, #1a5a78 0%, #11c7b8 100%);
/* Opera 11.10+ */
background: -ms-linear-gradient(-45deg, #1a5a78 0%, #11c7b8 100%);
/* IE10+ */
background: linear-gradient(135deg, #1a5a78 0%, #11c7b8 100%);
/* W3C */
filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#1a5a78', endColorstr='#11c7b8',GradientType=1 );
/* IE6-9 fallback on horizontal gradient */
padding: 5px;
margin-top: -50px;
transition: 1s border;
}
input:focus {
outline: none;
border: green 7px solid;
}
I'm trying to make a gradient overlay in my images, that makes this effect:
As you can see, gradient will be darker at the bottom, BUT, the top WONT be affected by the darkness.
I've tried this:
#include linear-gradient(to top, rgba(0,0,0,0.4) 0%, rgba(255,255,255,1));
But this will make a whitish effect at the top. I want the gradient to darken only the bottom part of the image, and DON'T do anything to the upper part of the image.
Has anyone know how to do this?
Thanks
You can use the following CSS, http://jsfiddle.net/3sxd82nf/5/
<div id="test">x</div>
<div id="gradient"></div>
#test {
position:absolute;
top: 10px;
left: 0px;
width: 200px;
height: 200px;
background-image: url('http://images2.layoutsparks.com/1/198321/50s-diner-chick-squares.jpg');
}
#gradient {
position:absolute;
top: 10px;
left: 0px;
width: 200px;
height: 200px;
background: -moz-linear-gradient(top, rgba(0,0,0,0) 50%, rgba(0,0,0,1) 100%); /* FF3.6+ */
background: -webkit-gradient(linear, left top, left bottom, color-stop(50%,rgba(0,0,0,0)), color-stop(100%,rgba(0,0,0,1))); /* Chrome,Safari4+ */
background: -webkit-linear-gradient(top, rgba(0,0,0,0) 50%,rgba(0,0,0,1) 100%); /* Chrome10+,Safari5.1+ */
background: -o-linear-gradient(top, rgba(0,0,0,0) 50%,rgba(0,0,0,1) 100%); /* Opera 11.10+ */
background: -ms-linear-gradient(top, rgba(0,0,0,0) 50%,rgba(0,0,0,1) 100%); /* IE10+ */
background: linear-gradient(to bottom, rgba(0,0,0,0) 50%,rgba(0,0,0,1) 100%); /* W3C */
filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#00000000', endColorstr='#000000',GradientType=0 ); /* IE6-9 */
}
I was stupid and built a web widget in jsFiddle using absolute positioning because it was just a quick prototype to show someone how the functionality would work.
Well we decided that we're gonna use it now and I'm having a hell of a time converting the elements to utilize relative positioning. Also, I'm in the middle of trying to convert this to a jQuery UI widget, so I want everything set up so that it just dumps onto the page without issue.
The widget can be seen HERE. Basically it's a search box of sorts that will allow some filtering with the left-most button.
The components are as such:
#refine: The left-most button.
#refineDropdown: The drop down menu that appears when you click on the refine button
#search: The input box
#dropdown: The live-type search filtering box
#submit: The right-most search button
Question: When creating a widget, should positioning be done relatively or absolutely? If I have multiple instances of this on a page, the position of the dropdowns should be independent of their position on the page, but I don't fully understand positioning and HTML arrangement to get this to work.
CSS:
.inline { float:left; }
.clearBoth { clear:both; }
#refine {
position: relative;
margin-right: -3px;
overflow:hidden;
white-space:nowrap;
background: rgb(238,238,238); /* Old browsers */
background: -moz-linear-gradient(top, rgba(238,238,238,1) 0%, rgba(204,204,204,1) 100%); /* FF3.6+ */
background: -webkit-gradient(linear, left top, left bottom, color-stop(0%,rgba(238,238,238,1)), color-stop(100%,rgba(204,204,204,1))); /* Chrome,Safari4+ */
background: -webkit-linear-gradient(top, rgba(238,238,238,1) 0%,rgba(204,204,204,1) 100%); /* Chrome10+,Safari5.1+ */
background: -o-linear-gradient(top, rgba(238,238,238,1) 0%,rgba(204,204,204,1) 100%); /* Opera 11.10+ */
background: -ms-linear-gradient(top, rgba(238,238,238,1) 0%,rgba(204,204,204,1) 100%); /* IE10+ */
background: linear-gradient(to bottom, rgba(238,238,238,1) 0%,rgba(204,204,204,1) 100%); /* W3C */
filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#eeeeee', endColorstr='#cccccc',GradientType=0 ); /* IE6-9 */
border-top-left-radius:4px;
border-bottom-left-radius:4px;
border:1px solid #AAA;
height:12px;
padding:6px 25px 6px 6px;
text-align:center;
font-size:11px;
font-family:Helvetica, sans-serif;
color:#666;
text-shadow:0px 1px 0px #e8eae5;
}
#refine:hover {
background: rgb(238,238,238); /* Old browsers */
background: -moz-linear-gradient(top, rgba(238,238,238,1) 0%, rgba(221,221,221,1) 100%); /* FF3.6+ */
background: -webkit-gradient(linear, left top, left bottom, color-stop(0%,rgba(238,238,238,1)), color-stop(100%,rgba(221,221,221,1))); /* Chrome,Safari4+ */
background: -webkit-linear-gradient(top, rgba(238,238,238,1) 0%,rgba(221,221,221,1) 100%); /* Chrome10+,Safari5.1+ */
background: -o-linear-gradient(top, rgba(238,238,238,1) 0%,rgba(221,221,221,1) 100%); /* Opera 11.10+ */
background: -ms-linear-gradient(top, rgba(238,238,238,1) 0%,rgba(221,221,221,1) 100%); /* IE10+ */
background: linear-gradient(to bottom, rgba(238,238,238,1) 0%,rgba(221,221,221,1) 100%); /* W3C */
filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#eeeeee', endColorstr='#dddddd',GradientType=0 ); /* IE6-9 */
cursor:pointer;
}
#submit {
float: left;
margin-right:-1px;
overflow:hidden;
white-space:nowrap;
background: rgb(238,238,238); /* Old browsers */
background: -moz-linear-gradient(top, rgba(238,238,238,1) 0%, rgba(204,204,204,1) 100%); /* FF3.6+ */
background: -webkit-gradient(linear, left top, left bottom, color-stop(0%,rgba(238,238,238,1)), color-stop(100%,rgba(204,204,204,1))); /* Chrome,Safari4+ */
background: -webkit-linear-gradient(top, rgba(238,238,238,1) 0%,rgba(204,204,204,1) 100%); /* Chrome10+,Safari5.1+ */
background: -o-linear-gradient(top, rgba(238,238,238,1) 0%,rgba(204,204,204,1) 100%); /* Opera 11.10+ */
background: -ms-linear-gradient(top, rgba(238,238,238,1) 0%,rgba(204,204,204,1) 100%); /* IE10+ */
background: linear-gradient(to bottom, rgba(238,238,238,1) 0%,rgba(204,204,204,1) 100%); /* W3C */
filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#eeeeee', endColorstr='#cccccc',GradientType=0 ); /* IE6-9 */
border-top-right-radius:4px;
border-bottom-right-radius:4px;
border:1px solid #AAA;
height:12px;
padding:6px 6px 6px 6px;
text-align:center;
font-size:11px;
font-family:Helvetica, sans-serif;
color:#666;
text-shadow:0px 1px 0px #e8eae5;
}
#submit:hover {
background: rgb(238,238,238); /* Old browsers */
background: -moz-linear-gradient(top, rgba(238,238,238,1) 0%, rgba(221,221,221,1) 100%); /* FF3.6+ */
background: -webkit-gradient(linear, left top, left bottom, color-stop(0%,rgba(238,238,238,1)), color-stop(100%,rgba(221,221,221,1))); /* Chrome,Safari4+ */
background: -webkit-linear-gradient(top, rgba(238,238,238,1) 0%,rgba(221,221,221,1) 100%); /* Chrome10+,Safari5.1+ */
background: -o-linear-gradient(top, rgba(238,238,238,1) 0%,rgba(221,221,221,1) 100%); /* Opera 11.10+ */
background: -ms-linear-gradient(top, rgba(238,238,238,1) 0%,rgba(221,221,221,1) 100%); /* IE10+ */
background: linear-gradient(to bottom, rgba(238,238,238,1) 0%,rgba(221,221,221,1) 100%); /* W3C */
filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#eeeeee', endColorstr='#dddddd',GradientType=0 ); /* IE6-9 */
cursor:pointer;
}
.refineClicked {
background:white !important;
border-bottom-left-radius:0px !important;
border-bottom:none !important;
}
.arrow-down {
position: absolute;
width: 0;
height: 0;
border-left: 5px solid transparent;
border-right: 5px solid transparent;
border-top: 5px solid #666;
right: 7px;
top: 10px;
}
#search {
float: left;
height: 24px;
margin-right:-5px;
padding: 0px 7px 0px 7px;
border:1px solid #AAA;
color:#444;
}
#search:focus { outline:none }
#refineDropdown {
position:relative;
top:40px;
left:30px;
width:150px;
max-height:200px;
background:#fff;
border-left:1px solid #AAA;
border-right:1px solid #AAA;
border-bottom:1px solid #AAA;
word-wrap:normal;
overflow:auto;
}
#dropdown {
top: 76px;
padding:3px;
width:200px;
max-height:200px;
background:#fff;
border-left:1px solid #CCC;
border-right:1px solid #CCC;
border-bottom:1px solid #CCC;
word-wrap:normal;
overflow:auto;
left: 59px;
position: absolute;
}
ul {
list-type:none;
margin:0;
padding:0;
}
li {
padding:5px 10px 5px 10px;
}
li:hover {
margin:-1px;
background:#E5F3FF;
border:1px solid #3366FF;
cursor:pointer;
}
.selected {
margin:-1px;
background: #E5F3FF;
border:1px solid #3366FF;
}
.hidden { display:none }
I believe the reason you want this to be done with relative positioning is that you believe absolute positioning is always absolute in relation to the page. Surprise: it isn't.
In fact, what it is absolute to is the first parent that has its position attribute set. As such, the simple solution could be to wrap your entire widget into a div and declare the position of that div as relative.
For example:
<p>adsadds
<div class='container'>
<div class='absolutelyPositioned'>BlaBla</div>
</div>
sddasda</p>
With this css:
.container
{
position: relative;
}
.absolutelyPositioned
{
position: absolute;
top: 100px;
left: 100px;
}
will have the inner div with "BlaBla" in it position not at (100, 100) of the web page, but of the container div. In other words if I turn <p>adsadds into <p>adsadds <br /> the "BlaBla" will be pushed down as well.
I would like to create this shape using just css. I am pretty sure this can be done. But i am having trouble with gradients involved.
This shape will contain some text inside. Suggested html markup is:
<div class="container">
... more html contents...
</div>
A jsFiddle would be highly appreciated.
Thanks in advance.
Try this, http://jsfiddle.net/HshfF/1/
CSS: (From the fiddle in this comment)
.main {
background: -moz-linear-gradient(top, #ffffff 0%, #e8e8e8 100%); /* FF3.6+ */
background: -webkit-gradient(linear, left top, left bottom, color-stop(0%,#ffffff), color-stop(100%,#e8e8e8)); /* Chrome,Safari4+ */
background: -webkit-linear-gradient(top, #ffffff 0%,#e8e8e8 100%); /* Chrome10+,Safari5.1+ */
background: -o-linear-gradient(top, #ffffff 0%,#e8e8e8 100%); /* Opera 11.10+ */
background: -ms-linear-gradient(top, #ffffff 0%,#e8e8e8 100%); /* IE10+ */
background: linear-gradient(to bottom, #ffffff 0%,#e8e8e8 100%); /* W3C */
position: relative;
width: 150px;
height: 100px;
margin: 10px;
border: 1px solid #d0d0d0;
border-radius: 10px;
padding: 20px;
}
.main:before {
content: '';
display: block;
top: -1px;
right: -1px;
width: 20px;
height: 20px;
background: -moz-linear-gradient(top, #ffffff 0%, #e8e8e8 100%); /* FF3.6+ */
background: -webkit-gradient(linear, left top, left bottom, color-stop(0%,#ffffff), color-stop(100%,#e8e8e8)); /* Chrome,Safari4+ */
background: -webkit-linear-gradient(top, #ffffff 0%,#e8e8e8 100%); /* Chrome10+,Safari5.1+ */
background: -o-linear-gradient(top, #ffffff 0%,#e8e8e8 100%); /* Opera 11.10+ */
background: -ms-linear-gradient(top, #ffffff 0%,#e8e8e8 100%); /* IE10+ */
background: linear-gradient(to bottom, #ffffff 0%,#e8e8e8 100%); /* W3C */
position: absolute;
border-radius: 0 0 0 5px;
border-left: 1px solid #d0d0d0;
border-bottom: 1px solid #d0d0d0;
}
.main:after {
content: '';
display: block;
position: absolute;
top: -1px;
right: -1px;
border-top: 20px solid #fff;
border-left: 20px solid transparent;
}
Please Learn CSS3, Try Nicholas Gallagher tutorials, he has some of the best css3 tutorials:
one you looking for http://nicolasgallagher.com/pure-css-folded-corner-effect/demo/
The drop shadow and colors you looking for i think you need to do it yourself.
Nearly there with this: http://jsfiddle.net/Grezzo/52zG7/
You only need one div (thanks to pseudo element), but I haven't "cut" the corner yet.
I'm trying to style my HTML buttons using CSS, so that they have the reflected shine like the icons on iOS devices' home page. Apple does this to icons automatically as shown here. I need something similar to the shine in CSS.
Take a look at this fiddle.
Here's the code:
HTML:
<div class="icon">
<div class="shine"></div>
</div>
And CSS:
.icon {
width: 150px;
height: 150px;
border-radius: 30px;
background: red;
float: left;
margin: 50px;
box-shadow: 0px 4px 6px rgba(0, 0, 0, 0.5);
}
.shine {
background: -moz-linear-gradient(top, rgba(255,255,255,0.7) 0%, rgba(255,255,255,0.2) 100%); /* FF3.6+ */
background: -webkit-gradient(linear, left top, left bottom, color-stop(0%,rgba(255,255,255,0.7)), color-stop(100%,rgba(255,255,255,0.2))); /* Chrome,Safari4+ */
background: -webkit-linear-gradient(top, rgba(255,255,255,0.7) 0%,rgba(255,255,255,0.2) 100%); /* Chrome10+,Safari5.1+ */
background: -o-linear-gradient(top, rgba(255,255,255,0.7) 0%,rgba(255,255,255,0.2) 100%); /* Opera 11.10+ */
background: -ms-linear-gradient(top, rgba(255,255,255,0.7) 0%,rgba(255,255,255,0.2) 100%); /* IE10+ */
background: linear-gradient(top, rgba(255,255,255,0.7) 0%,rgba(255,255,255,0.2) 100%); /* W3C */
filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#b3ffffff', endColorstr='#33ffffff',GradientType=0 ); /* IE6-9 */
height: 90px;
width: 150px;
box-shadow: inset 0px 2px 1px rgba(255, 255, 255, 0.7);
border-top-right-radius: 30px;
border-top-left-radius: 30px;
border-bottom-right-radius: 100px 40px;
border-bottom-left-radius: 100px 40px;
}
my example uses a background-color:red instead of an image, but just put any image as background in the #icon div and it should also work.
(btw I used this awesome site: http://www.colorzilla.com/gradient-editor/ for the gradients)
HTML:
<div class="icon">
<div class="shine">
</div>
</div>
CSS:
.icon {
width:50px;
height:50px;
background-color: red;
overflow: hidden;
position: relative;
}
.shine {
position: absolute;
top: -70px;
left: -25px;
width:100px;
height:100px;
border-radius: 50px;
background: -webkit-radial-gradient(center, ellipse cover, rgba(255,255,255,1) 0%,rgba(255,255,255,0) 150%); /* Chrome10+,Safari5.1+ */
background: -moz-radial-gradient(center, ellipse cover, rgba(255,255,255,1) 0%, rgba(255,255,255,0) 150%); /* FF3.6+ */
background: -webkit-gradient(radial, center center, 0px, center center, 100%, color-stop(0%,rgba(255,255,255,1.5)), color-stop(100%,rgba(255,255,255,0))); /* Chrome,Safari4+ */
background: -o-radial-gradient(center, ellipse cover, rgba(255,255,255,1) 0%,rgba(255,255,255,0) 150%); /* Opera 12+ */
background: -ms-radial-gradient(center, ellipse cover, rgba(255,255,255,1) 0%,rgba(255,255,255,0) 150%); /* IE10+ */
background: radial-gradient(center, ellipse cover, rgba(255,255,255,1) 0%,rgba(255,255,255,0) 150%); /* W3C */
filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#ffffff', endColorstr='#00ffffff',GradientType=1 ); /* IE6-9 fallback on horizontal gradient */
}
Hope it works for you!