If i send ARP request sent to a find the MAC address of a machine in a LAN. But among the group of hosts in the LAN, two hosts having the same IP address, then how the ARP reply works.
The same situation with the RARP, if the two machines inside the LAN with same MAC address. If i send RARP request to find IP address, then how the RARP reply works.
If it receives 2 different ARP or RARP responses, it knows something wrong.
Further reading: gratuitous ARP.
Primarily IP address is unique within a network and MAC is unique globally and so there should not be any confusion.
But incase if multiple devices have same IP or MAC then (probably) the first ARP or RARP will be accepted as valid response. Because once a request is obtained the information is written in to kernels ARP cache and so for subsequent needs the cache will be used (till the cache expires).
Related
Why broadcast is happening in RARP request , we already know the sender and destination Mac address . Just send unicast request and get the Ip address..! What is the reason for using broadcasting...?
The original reason is for a computer to discover its own IP address, and at the point of booting, the computer would not know the MAC address of any servers to help.
I'm writting a simple network sniffer that should be able to reconstruct network structure.
When an interface has set up a DHCP, I can easily read interface settings such as client IP address, subnet mask, DNS server etc. by catching a DHCP packet and analysing it.
When an interface has a static IP, I'm catching ARP Announcement packet to get static IP address and then ARP request from the gateway, to get geteway IP address. I'm also saving MAC addresses.
My problem is: how to get subnet mask from one or more static IPs in the network and the gateway address. Or by caching some packets. I didn't see packets that could have such informations.
I also need DNS address, but it's less important.
The program should work in OpenWRT (C++).
My problem is: how to get subnet mask from one or more static IPs in the network and the gateway address.
Possibly, you can't.
If the sniffed network uses DHCP then you can monitor the DHCP requests (which should be broadcast) for their subnet mask and router fields which mirror the server's offer.
Without DHCP, all you can do is take an educated guess. If your passive sniffer registers broadcasts from addresses 192.168.1.1 through 192.168.1.29, you know that the prefix length is at most /27. It could also be anything shorter, down to /16, with potential addresses being (currently) absent or silent. The prefix could be even short than /16 if the network admin is ignoring RFC 1918. With public addresses you're mostly on your own.
If you can scan actively you could send ARP requests and see which ones get answered - you'd also see nodes that don't originate any traffic/broadcasts.
The gateway is also just a guess. In a network with mostly Internet-bound traffic, the default gateway is most likely the one being ARPed most often. If the network traffic is mostly server-centric, ARP requests for their addresses outnumber the ones for any gateway.
Your sniffer is severely limited when it is just attached to a switch and listening to broadcast packets only. If the sniffer manages to listen to all traffic on the network (via a monitoring/mirroring switch port) then you can easily identify the gateway by its MAC address that packets for arbitrary IP addresses is sent to and vice versa.
As above, if you can actively send probe packets you could test the gateway(s) with packets that they accept (and hopefully forward) and which ones they reject.
I recently found that packets are encapsulated within ethernet frames. Packets use IP addresses, frames use MAC addresses.
Why aren't IP addresses used in ethernet frames for routing? I understand that when trying to access a basic website, the computer goes to a DNS to find the IP address relevant to the user-entered domain name. How do computers find the correct MAC address?
Really, how are MAC addresses used in routing internet traffic?
Thanks
IP packets aren't always encapsulated in Ethernet frames. There are other physical media such as ISDN, etc. When packets are routed, IP addresses are used to determine the next hop and the physical address is used to physically identify the interface serving as the next hop. Only the former (determining next-hop) is usually called routing.
To answer your second part, MAC addresses are discovered through ARP (Address Resolution Protocol) in IPv4 & ND6 (Neighbor Discovery) in IPv6.
Update:
The destination IP address in the IP header is the final destination. In the process of routing (at each hop), you get the next hop's IP address to (eventually) reach the final destination from the routing table (this could be a default gateway's IP address). To send the packet to the next hop, you need its MAC address. While hopping through intermediate links, the IP address in the IP header don't change - only the MAC addresses change.
Bit late but still here is my answer :) ...
To send data you need two address, the MAC address and the IP address.
Basically the sending host will ARP for a MAC address, this occurs when the local host doesn't know the MAC address of the host it has an IP address for or it will ARP for the default gateway MAC address (if it doesn't already know it) if the IP address in on a different subnet/ network. Once it obtains a MAC address the IP packet is encapsulated in a L2 frame and sent across the media. If the IP packet is meant for a host on a different subnet/ network, it will be sent to the default gateway, this router will de-encapsulate the L2 frame (remove and discard it) check the IP address and will forward it. For the router to do this it needs a MAC address to send it over the media, It will look up the next hop in it's routing table, encapsulate the IP packet with the same source and destination IP address that was sent from the original host into a new L2 frame. This time the MAC address for the source address will be that of the forwarding interface of the router, and the receiving interface of the next hop will be the destination MAC address. This will continue from hop to hop until it reaches the final host, each time the MAC addresses will change, but the original IP address will remain the same.
Here's the key point -- there can be more types of packets than INTERNET traffic. You could be using IPX, which is non-routable. How do clients identify each other? By the MAC address.
Routing != Addressing, which is really where the MAC comes into play.
In order to be routed, the OSI model adds a layer to allow for path discovery to the next gateway. This layer is responsible for routing, but knows nothing about the MAC address.
As a side note, at the hardware level, MAC addresses ARE used by switches, but not for routing. From How Stuff Works:
The switch gets the first packet of data from Node A. It reads the MAC
address and saves it to the lookup table for Segment A. The switch now
knows where to find Node A anytime a packet is addressed to it. This
process is called learning.
In this way, a switch can make sure that traffic is only outputted to the correct port. This isn't accomplishing routing so much as reducing network congestion. Only broadcasts and traffic destined specifically for that MAC address should be sent out the port.
Recently I have been thinking about the same and came upon this question. Here is my answer to this question. Actually MAC address is needed for correctly sending the packet to right destination. This is specially true when packet is needed to sent over a VLAN. There can be multiple switches/routes connected on that VLAN over multiple physical interfaces. However IP Routing is unaware of these physical interface. It only knows about the logical connectivity. For example, route 10.10.10.0/24 is reachable via VE/VIF0.10(logical VLAN interface) and/or nexthop neighbor is 20.20.20.1. There could be multiple interfaces under VLAN 10. Then to which interface packet is sent out? This is where ARP comes in the picture. ARP helps to discover the MAC address associated with the next-hop IP address. When switch/router learns the nexthop MAC. along with that it learns the physical interface also via which that MAC is reachable. Hence while routing packet, firstly MAC corresponding to the destination IP is searched and then the physical interface associated with that MAC is searched. Finally packet is sent out via that physical interface. The MAC corresponding to that destination IP is used as destination MAC. In absence of this, routed packets will always be flooded in the outgoing VLAN.
Hope this helps.
Thanks.
Answer: MAC addresses are not used in the process of routing of a packet.
segment -> transport layer (TCP ports)
packets -> network layer (IP addresses)
frame -> data link layer (MAC addresses)
bits -> physical layer (electric/optical signals)
Create your own packet/segment visit http://wirefloss.com/wireit/
There are 2 models (TCP/IP and ISO/OSI)
In detail:
Your app has some data. This is encapsulated by mentioned layers. Encapsulation means that a header with fields is added at each layer. If your data never leave the local network the MAC address will be the same. Once your data needs to be delivered outside your network the frame header is stripped by router and is replaced by router fields.
UPDATE 2021: Some people seems never heard of ISO OSI model and put this answer as incorrect.
I connected two machines via a network cable. I need to get an ARP request data via Wireshark. When I pinged the IP of the other machine, I get the ARP request on Wireshark. But, it is not broadcasting a message. It targets pinged IP address directly. I think a LAN with only two machines does not need to do a broadcast. Am I right? Can any one explain this to me?
Always in ARP packet, MAC address will be broadcast not IP. As it is used to learn MAC address of other host whose IP address is known, ARP packet needs to have valid IP address rather than broadcast IP. You can check ARP packet example at below path:
http://wiki.wireshark.org/AddressResolutionProtocol
Hope this clears your doubt.
I'm looking for some Linux code to find an IP address from an Ethernet address. I suppose I have to do some inverse ARP trickery but I don't find any example...
http://compnetworking.about.com/od/networkprotocolsip/f/convertipmacadd.htm
Try sending an IP broadcast (e.g. ping 192.168.1.255 if your subnet is 192.168.1.0/24) to prime your ARP cache, followed by arp -a to spit it all out.
For computers that you have communicated with, you can look at their arp entry. This is available in text format in /proc/net/arp for example. Finding an IP address for a MAC that you know but haven't communicated with is significantly more difficult. The closest match, protocol-wise, would be RARP but that's hardly ever in use so your are not likely to get a response.
You can always scan your local subnet to make sure you get a full view in your arp table. See for example fping for an efficient way to do this. Note that hosts don't actually need to respond to the pings in question to appear in the ARP table, so this is useful even in the presence of local firewalls etc.
Take a look at Thomas Habet's Arping. I've not tried it, but the basic idea is to send an ICMP Ping network packet to the MAC address in question using a broadcast destination IP address in the IP header. Only the host with the specified MAC address will reply and the reply will (usually) contain its IP address. It won't always work but it might be good enough for you. See the project readme for limitations.