Can two Unix processes simultaneous write to different positions in a single file? - unix

Question

This is an unresolved exam question of mine.
Can two Unix processes simultaneous write to different positions
in a single file?
Yes, the two processes will have their own file table entries
no, the shared i-node contains a single offset pointer
only one process will have write privilege
yes, but only if we operate using NFS

Answer 1

There is no file offset recorded in an inode so answer 2. is incorrect.
There is no documented reason for a process to have its access rights modified so 3. is incorrect.
NFS allows simultaneous access by processes on different hosts, the question here is for processes on the same host so NFS shouldn't make a difference.
Here is a shell script demonstrating the remaining answer 1. is correct:
# create a 10m file
dd if=/dev/zero of=/var/tmp/file bs=1024k count=10
# create two 1 MB files
cd /tmp
printf "aaaaaaaa" > aa
printf "bbbbbbbb" > bb
i=0
while [ $i -lt 17 ]; do
cat aa aa > aa.new && mv aa.new aa
cat bb bb > bb.new && mv bb.new bb
i=$((i+1))
done
ls -lG /var/tmp/file /tmp/aa /tmp/bb
# launch 10 processes that will write at different locations in the same file.
# Uses dd notrunc option for the file not to be truncated
# Uses GNU dd fdatasync option for unbuffered writes
i=0
while [ $i -lt 5 ]; do
(
dd if=/tmp/aa of=/var/tmp/file conv=notrunc,fdatasync bs=1024k count=1 seek=$((i*2)) 2>/dev/null &
dd if=/tmp/bb of=/var/tmp/file conv=notrunc,fdatasync bs=1024k count=1 seek=$((i*2+1)) 2>/dev/null &
) &
i=$((i+1))
done
# Check concurrency
printf "\n%d processes are currently writing to /var/tmp/file\n" "$(fuser /var/tmp/file 2>/dev/null | wc -w)"
# Wait for write completion and check file contents
wait
printf "/var/tmp/file contains:\n"
od -c /var/tmp/file
Its output shows ten processes successfully and simultaneously write to the very same file:
-rw-r--r-- 1 jlliagre 1048576 oct. 30 08:25 /tmp/aa
-rw-r--r-- 1 jlliagre 1048576 oct. 30 08:25 /tmp/bb
-rw-r--r-- 1 jlliagre 10485760 oct. 30 08:25 /var/tmp/file
10 processes are currently writing to /var/tmp/file
/var/tmp/file contains:
0000000 a a a a a a a a a a a a a a a a
*
4000000 b b b b b b b b b b b b b b b b
*
10000000 a a a a a a a a a a a a a a a a
*
14000000 b b b b b b b b b b b b b b b b
*
20000000 a a a a a a a a a a a a a a a a
*
24000000 b b b b b b b b b b b b b b b b
*
30000000 a a a a a a a a a a a a a a a a
*
34000000 b b b b b b b b b b b b b b b b
*
40000000 a a a a a a a a a a a a a a a a
*
44000000 b b b b b b b b b b b b b b b b
*
50000000

Answer 2

Definition:
Yes, the two processes will have their own file table entries.
If the file is opened twice with the open function the two file descriptor is created.
Each file descriptor have seperate file status flags.
So the two file descriptor have a write permission file descriptor1 and file descriptor2 have initial position of point to first character to file.
If we specify some position to both descriptor and write in file it can be tested easily.
The content of file.txt
My name is Chandru. This is an empty file.
Coding for testing:
#include<stdio.h>
#include<fcntl.h>
#include<stdlib.h>
main()
{
int fd1, fd2;
if((fd1=open("file.txt", O_WRONLY)) <0){
perror("Error");
exit(0);
}
if((fd2=open("file.txt", O_WRONLY)) < 0) {
perror("Error");
exit(0);
}
if(lseek(fd1,20,SEEK_SET) != 20)
{
printf("Cannot seek\n");
exit(0);
}
if(write(fd1,"testing",7) != 7)
{
printf("Error write\n");
exit(0);
}
if(lseek(fd2,10,SEEK_SET) != 10)
{
printf("Cannot seek\n");
exit(0);
}
if(write(fd2,"condition",9) != 9)
{
printf("Error write\n");
exit(0);
}
}
Output:
After that my output is
My name isconditionitesting empty file.

Answer 3

Yes, they can of course, with the following caveats:
Depending on open() mode, one process can easily wipe the file contents
Depending on scheduling, the order of write operations is not deterministic
There is no mandatory locking (in general) - careful design calls for advisory locking.
If they write in the same area using buffered I/O results can be non-deterministic.