If I make a div that has 50x50px dimension, and I make an image (sprite) that has 50x100px dimension. Then one image is on top of the other.
Now, if I make a hover effect on the div, where the image should change, I would just change the background position from top to bottom as an example. Then when I hover the image changes and so on. Easy...
But, if I use a transition timer, then I will see the image move from the top, to the bottom.
My question is: Is it possible via sprites to make fades instead ? I mean, lets say I have an image that changes color. Then I don't want it to like like the image is going up and down, but just fade in the color of the other image and so on.
Is that possible via sprites, or do I really have to just onclick-change-image events etc. ?
Thanks in advance.
Related
For clarification: I'm not asking how to darken an image when you hover over it. I'm wondering how to make other images surrounding the image your cursor is over darken.
Here is an example: http://www.b-reel.com/
When you hover over the big category images, the surrounding images darken, but the hovered image remains the same.
Any input would be appreciated. Thank you!
You don't make surrounding images darker. Instead, what you do is you put a div around all images, and when the cursor is over this div, all images are darker. But you also add div elements around each image, and you make an image less dark when the cursor is over it. The combination of both is what gives you the desired effect.
In the example you posted they are using JavaScript to apply a .fadeOut class on the other divs. That .fadeOut class sets the opactiy of the other divs to 50%.
Is the background-position css property used to indicated where in the element should the image be displayed (like this) or what part of the image should be displayed (like when using sprites) ?
In my instance i have a div of let's say 300px width, i want the image to be shown in the right part of that element so normally i just added a center right to my background declaration, though now my image is a spirit so how can i control the coordinate of the image that i want to display ?
Seems to me that this background property act in 2 different way.. Am i missing something ?
If the place where you want to put element of the sprite is larger then the element then you need to put white space (trasnparent) around it. And you can't use keywords like center, you need to use pixels, because you will center whole sprite and not your element.
Using sprites is like using window where background is larger then background image so you need to position the window (actually you position the background).
If your container is larger than the background sprite image part you want to display then the other part of image will also be displayed. Better use Sprite cow to generate sprite it will give you the css for different parts of sprite image
http://www.spritecow.com/
Good day, I have a DIV of fixed width and height on my HTML page. In normal state it should show image A on the background and in hover state it should show image B. I know how to do it using CSS and two image files A and B. Somewhere I saw those two images (A and B) put into a single image file and then they somehow wrote CSS so that in normal state the DIV showed upper half of the image on the background and in a hover state it showed the bottom half of the image. Could you please advise CSS code to achieve this? The DIV has no position set but it is a child of a DIV with relative position. Thank you in advance.
Vojtech
This is called CSS spriting and is an awesome technique that everyone should use.
See this answer for a good overview. What it comes down to is having a DOM element with a defined height and width and using a background image that is larger than that area. Then you can selectively show only portions of that background image using background-position
I need to create this layout and I'd like to do as much of it as possible with CSS, rather than using images and whatever.
As such, how can I do this in CSS? (if at all?)
As you can see, there is the image behind, with the button overlaid with padding. The bit that I'm struggling with is creating the curves on the IMAGE above and to the left of the button and bottom to the right of the button (I've pointed them out on the pic below).
Any help would be great.
Thanks
I know just enough CSS to be dangerous so I can't detail every step, but I think you can approach it like this:
Split the background image into two separate images both at a z-index of 0 at the height of the top of the grey box. I think you can use two div's that reference the same original image with different offsets (similar to CSS Sprites) but I don't know the details of how to do that. The left edge of the lower div would start where the grey box ends. Round the lower-left corner of each "image" div.
Add the grey box at a z-index of 1 with appropriate rounding, and then the blue box at a z-index of 2, again with appropriate rounding.
The background of the block element containing all of this would also have to be grey to match the grey border and properly fill in grey where your right-most arrow is pointing.
You don't have to split your image at all, only the container divs.
Let me detail a bit:
You can have your image set as a background image instead of putting it in a src attribute of an img tag. This technique is most commonly used when working with CSS sprites.
So, if you have you uppermost div at a constant width and height, if you try to apply the background image in it, you'll see it fits very nice.
On the bottom, you have two divs or whatever block element you'll like, just be sure to put fixed width and height, so the background will be applied and you will be able to actually see it.
Then all you have to do is fiddle with css background-position to adjust the SE chunk of image.
I'll be putting a small demo together to better illustrate the idea.
After you have a big div at the top, and two smaller at the bottom, where two of them share the same background-image, but with different background-position, you can safely add some css3 border-radius to fit your roundness needs. You can also use some tool like http://css3generator.com/ to add a compatibility layer on all browsers with ease.
That is very easy to realize with pure css. The page you have shown is divided into 3 divs without any margin. You only need to set the right border radius for each div.
This is a function of the background image, which is a css element if that's what you mean, but it is not a seperate attribute for a selector, at least not in standard CSS. Wait until CSS3 becomes more prevelant, then it's corner-radius or some such thing.
Well it's 3 probably 3 seperate divs, a hole "burned" into the background image, or a div being overlayed for the button.
The best way to figure out how it's done is to read the source of the page you found it on.
For convenience:
If you have a webkit based browser like chrome or safari then enable developper mode mouse over the button "right click" and choose inspect element. Otherwise you can pour over the page source until you find what you want.
I'm setting up a design that uses some gradients, and of course that causes issues. What I want is for my one background image with the vertical gradient to be the main background, but then if the content extends and pushes the div out, I want a different sliver image to repeat on the bottom. Is it possible to do something like this?
The closest you can get is using a background color with your background image. Then set the image to non repeating. Then the color will be the background for the parts of the div where the backgound image is not.