bulk insert using insert...select in sqlite? - sqlite

I have a list of users who should receive the message. They are in the table subscribe. Now I'd like to insert a message for every one of these users. My query is
insert into message(user, type, theId)
select (select user from subscribe_message), #type, #id
At the moment it is empty. I get the error message.user may not be NULL. Shouldn't it not insert any rows? When I have more than one row it inserts the first row only. How do I write this so it will insert 0 to many rows?

Try this
INSERT INTO message ( user, type, theId )
SELECT subscribe_message.user, #type, #id
FROM subscribe_message

Related

Oracle 11g Triggers

I have create a table person(id, name ,samenamecount).The samenamecount attribute can be null but for each row can store the row count for same names.I am achieving this by calling a stored procedure inside a after insert trigger.Below is my code.
create or replace procedure automatic(s in person.name%type)
AS
BEGIN
update person set samenamecount=(select count(*) from person where name=s) where name=s;
END;
create or replace trigger inserttrigger
after insert
on person
for each row
declare
begin
automatic(:new.name);
end;
On inserting a row it is giving error like
table ABCD.PERSON is mutating, trigger/function may not see it.
Can somebody help me to figure out this?
If you have the table:
CREATE TABLE person (
id NUMBER
GENERATED ALWAYS AS IDENTITY
CONSTRAINT person__id__pk PRIMARY KEY,
name VARCHAR2(20)
NOT NULL
);
Then rather than creating a trigger, instead, you could use a view:
CREATE VIEW person_view (
id,
name,
samenamecount
) AS
SELECT id,
name,
COUNT(*) OVER (PARTITION BY name)
FROM person;
You can use the trigger:
CREATE TRIGGER inserttrigger
AFTER INSERT ON person
BEGIN
MERGE INTO person dst
USING (
SELECT ROWID AS rid,
COUNT(*) OVER (PARTITION BY name) AS cnt
FROM person
) src
ON (src.rid = dst.ROWID)
WHEN MATCHED THEN
UPDATE SET samenamecount = src.cnt;
END;
/
fiddle
If you want to make it more efficient then you could use a compound trigger and collate the names that are being inserted and only update the matching rows.

Inserting rows from table2 to end of table1 with unique ids

I'm trying to add a test user to my website that employers can look at to see my work. I want to use some of the data I have entered into my profile so that it is faster.
I have a workouts table:
CREATE TABLE workouts(
id INTEGER NOT NULL,
userID INTEGER NOT NULL,
DateAndTime smalldatetime NOT NULL,
PRIMARY KEY (id),
FOREIGN KEY (UserID) REFERENCES users(id)
);
I have taken 25 of the first results and put it into a temporary workouts2 table:
CREATE TABLE workouts2 (
userid integer,
dateandtime smalldatetime);
Now I want to take those rows from workouts2 and put them into workouts. I have tried to add them by inserting workouts2 into workouts like this:
insert into workouts (id , userID, DateandTime) values (select * from workouts2);
This gives me an Error: in prepare, near "select": syntax error (1)
I can do it one at a time like this:
insert into workouts (userid, dateandtime) values (2, "2022-01-02T06:00");
Doing it one at a time is not ideal.
What am I missing here? I know I have a syntax error but I don't know how to fix it.
I have looked at this question which inserts one at a time:
How to insert a unique ID into each SQLite row?
The problem is it only inserts one at a time.
You should use SELECT instead of VALUES and not include the column id, which is auto-incremented, in the list of columns of workouts which will receive the values (such a column does not exist in workouts2):
INSERT INTO workouts (userID, DateandTime)
SELECT *
FROM workouts2;

ORA-01427: single-row subquery returns more than one row when inserting multiple rows

I am trying to assign or give all permissions of a user to another given user, 13053 but facing this Oracle error, ORA-01427: single-row subquery returns more than one row and i know exactly which part of my SQL statement shown below is returning this error but failed to handle it because what i want to achieve is to give those multiple rows returned to the given user with an id of 13053.
My attempt
INSERT INTO userpermissions (
userid,permissionid
) VALUES (
13053,( SELECT permissionid
FROM userpermissions
WHERE userid = ( SELECT userid
FROM users
WHERE username = '200376'
)
)
);
Any help ?
Thanks in advance.
A rewrite ought to do the trick:
INSERT INTO USERPERMISSIONS(
USERID,
PERMISSIONID
)
SELECT 13053 AS USERID,
p.PERMISSIONID
FROM USERPERMISSIONS p
WHERE p.userid = (SELECT userid FROM users WHERE username = '200376');
The problem with the original insert is that you are using single-row insert syntax when you are really trying to insert a set of rows.
Including the target userid as a literal is one way to make the set of rows look the way I am assuming you intend.

"Insert if not exists" statement in SQLite

I have an SQLite database. I am trying to insert values (users_id, lessoninfo_id) in table bookmarks, only if both do not exist before in a row.
INSERT INTO bookmarks(users_id,lessoninfo_id)
VALUES(
(SELECT _id FROM Users WHERE User='"+$('#user_lesson').html()+"'),
(SELECT _id FROM lessoninfo
WHERE Lesson="+lesson_no+" AND cast(starttime AS int)="+Math.floor(result_set.rows.item(markerCount-1).starttime)+")
WHERE NOT EXISTS (
SELECT users_id,lessoninfo_id from bookmarks
WHERE users_id=(SELECT _id FROM Users
WHERE User='"+$('#user_lesson').html()+"') AND lessoninfo_id=(
SELECT _id FROM lessoninfo
WHERE Lesson="+lesson_no+")))
This gives an error saying:
db error near where syntax.
If you never want to have duplicates, you should declare this as a table constraint:
CREATE TABLE bookmarks(
users_id INTEGER,
lessoninfo_id INTEGER,
UNIQUE(users_id, lessoninfo_id)
);
(A primary key over both columns would have the same effect.)
It is then possible to tell the database that you want to silently ignore records that would violate such a constraint:
INSERT OR IGNORE INTO bookmarks(users_id, lessoninfo_id) VALUES(123, 456)
If you have a table called memos that has two columns id and text you should be able to do like this:
INSERT INTO memos(id,text)
SELECT 5, 'text to insert'
WHERE NOT EXISTS(SELECT 1 FROM memos WHERE id = 5 AND text = 'text to insert');
If a record already contains a row where text is equal to 'text to insert' and id is equal to 5, then the insert operation will be ignored.
I don't know if this will work for your particular query, but perhaps it give you a hint on how to proceed.
I would advice that you instead design your table so that no duplicates are allowed as explained in #CLs answer below.
For a unique column, use this:
INSERT OR REPLACE INTO tableName (...) values(...);
For more information, see: sqlite.org/lang_insert
insert into bookmarks (users_id, lessoninfo_id)
select 1, 167
EXCEPT
select user_id, lessoninfo_id
from bookmarks
where user_id=1
and lessoninfo_id=167;
This is the fastest way.
For some other SQL engines, you can use a Dummy table containing 1 record.
e.g:
select 1, 167 from ONE_RECORD_DUMMY_TABLE

Inserting data from one table to the next in sql

I have two tables with fields as shown below :-
tbl_emp --> id(auto generate, auto increment, primary key),name, dob
tbl_login --> id(refers to id in tbl_emp, primary key), password
I have a web form which reads the name, password and date of birth(dob), and a submit button. On pressing the submit button, the data is inserted into the first table, and also to the second table. It would be easy to insert data to the second column if I had a way to access the "id" field from the first table.
The query I have is :-
insert into tbl_emp (name,dob) values(#name, #dob);
insert into tbl_login (id,password) values((select id from tbl_emp where id=(select id from tbl_emp where id=id)), #password)
The problem that I encounter with the above coeds is :
Subquery returned more than 1 value. This is not permitted when the subquery follows =, !=, <, <= , >, >= or when the subquery is used as an expression.
The statement has been terminated.
You could use the SCOPE_IDENTIY function:
insert into tbl_emp (name,dob) values(#name, #dob);
insert into tbl_login (id,password)
select id, #password
from tbl_emp
where id = SCOPE_IDENTITY();

Resources