Symfony2 Console Output without OutputInterface - symfony

Question

I am trying to print some Information to the Console in a Symfony Console Command. Regularly you would do something like this:
protected function execute(InputInterface $input, OutputInterface $output)
{
$name = $input->getArgument('name');
if ($name) {
$text = 'Hello '.$name;
} else {
$text = 'Hello';
}
if ($input->getOption('yell')) {
$text = strtoupper($text);
}
$output->writeln($text);
}
For the full Code of the Example - Symfony Documentation
Unfortunately I can't access the OutputInterface. Is it possible to print a Message to the Console?
Unfortunately I can't pass the OutputInterface to the Class where I want to print some Output.

Answer 1

Understanding the matter of ponctual debugging, you can always print debug messages with echo or var_dump
If you plan to use a command without Symfony's application with global debug messages, here's a way to do this.
Symfony offers 3 different OutputInterfaces
NullOutput - Will result in no output at all and keep the command quiet
ConsoleOutput - Will result in console messages
StreamOutput - Will result in printing messages into a given stream
Debugging to a file
Doing such, whenever you call $output->writeln() in your command, it will write a new line in /path/to/debug/file.log
use Symfony\Component\Console\Output\StreamOutput;
use Symfony\Component\Console\Input\ArrayInput;
use Acme\FooBundle\Command\MyCommand;
$params = array();
$input = new ArrayInput($params);
$file = '/path/to/debug/file.log';
$handle = fopen($file, 'w+');
$output = new StreamOutput($handle);
$command = new MyCommand;
$command->run($input, $output);
fclose($handle);
Debugging in the console
It is quietly the same process, except that you use ConsoleOutput instead
use Symfony\Component\Console\Output\ConsoleOutput;
use Symfony\Component\Console\Input\ArrayInput;
use Acme\FooBundle\Command\MyCommand;
$params = array();
$input = new ArrayInput($params);
$output = new ConsoleOutput();
$command = new MyCommand;
$command->run($input, $output);
No debugging
No message will be printed
use Symfony\Component\Console\Output\NullOutput;
use Symfony\Component\Console\Input\ArrayInput;
use Acme\FooBundle\Command\MyCommand;
$params = array();
$input = new ArrayInput($params);
$output = new NullOutput();
$command = new MyCommand;
$command->run($input, $output);

Answer 2

Look at JMSAopBundle https://github.com/schmittjoh/JMSAopBundle and check out this great article http://php-and-symfony.matthiasnoback.nl/2013/07/symfony2-rich-console-command-output-using-aop/