I have a list of certain files that I see using the command below, but how can I copy those files listed into another folder, say ~/test?
find . -mtime 1 -exec du -hc {} +
Adding to Eric Jablow's answer, here is a possible solution (it worked for me - linux mint 14 /nadia)
find /path/to/search/ -type f -name "glob-to-find-files" | xargs cp -t /target/path/
You can refer to "How can I use xargs to copy files that have spaces and quotes in their names?" as well.
Actually, you can process the find command output in a copy command in two ways:
If the find command's output doesn't contain any space, i.e if the filename doesn't contain a space in it, then you can use:
Syntax:
find <Path> <Conditions> | xargs cp -t <copy file path>
Example:
find -mtime -1 -type f | xargs cp -t inner/
But our production data files might contain spaces, so most of time this command is effective:
Syntax:
find <path> <condition> -exec cp '{}' <copy path> \;
Example
find -mtime -1 -type f -exec cp '{}' inner/ \;
In the second example, the last part, the semi-colon is also considered as part of the find command, and should be escaped before pressing Enter. Otherwise you will get an error something like:
find: missing argument to `-exec'
find /PATH/TO/YOUR/FILES -name NAME.EXT -exec cp -rfp {} /DST_DIR \;
If you're using GNU find,
find . -mtime 1 -exec cp -t ~/test/ {} +
This works as well as piping the output into xargs while avoiding the pitfalls of doing so (it handles embedded spaces and newlines without having to use find ... -print0 | xargs -0 ...).
This is the best way for me:
cat filename.tsv |
while read FILENAME
do
sudo find /PATH_FROM/ -name "$FILENAME" -maxdepth 4 -exec cp '{}' /PATH_TO/ \; ;
done
Related
I have a script which has the following command. I am trying to edit this in such a way that it only searches the files in the directory of the path without going in the subdirectories. That is not recursive search
find {Path} -name "cor*" -type f -exec ls -l {} \;
Example: The command should give cor123.log only and not cor456.log. Currently it gives both
<Path>
..cor123.log
<directory>
..cor456.log
I tried using -maxdepth but it's not supported in AIX. -prune and -depth didn't help either.
Will appreciate any help. Thanks
You can use
find . -name . -o -prune
to find files and directories non-recursively.
So in your case this one will work:
find . -name . -o -prune -name 'cor*' -type f -exec ls -l {} \;
Do you need find for selecting files only?
When you know that all files starting with cor are regula files, you can use
ls -l ${Path}/cor*
or
ls -l ${Path}/cor*.log
When you need the -type f, you can try to filter the results.
The filename can not have a /, so remove everything with an / after the Path.
We do not know the last char of ${Path}. It can be /, which will make the grep -Ev "${Path}/.*/" filter useless. After the Path at least one character is needed before looking for the next /.
find "${Path}" -name "cor*" -type f 2>/dev/null| grep -Ev "${Path}..*/" | xargs -ls
Late answer but may save some. In aix
find /some/directory/* -prune -type f -name *.log
For instance make your path have the last forward slash with a wildcard then -prune
/*
find /some/directory/* -prune -name "cor*" -type f -exec ls -l {} \
Tested.
Am trying to delete files with below find command, few files are not deleting and all those file names are like: filname.123.log.
I can't rename or can't do any thing on file name just need to delete
command
$ find /BASE/CODE/LOGS_BACK -type f -mtime +60 | xargs rm -f
xargs: unmatched single quote; by default quotes are special to xargs unless you use the -0 option
I googled and try with the below command but it is giving different error.
$ find /BASE/CODE/LOGS_BACK -type f -mtime +60 | xargs -0 rm -f
xargs: argument line too long
Can you please help regarding this?
using -0 option in xargs means using -print0 option in find :
find /BASE/CODE/LOGS_BACK -type f -mtime +60 -print0 | xargs -0 rm -f
Then all results of find will be ended with '\0' NUL char and xargs will regenerate list correctly by parsing with same char.
find can directly execute a command for each result:
$ find /BASE/CODE/LOGS_BACK -type f -mtime +60 -exec rm -f {} \;
{} is replaced with each matching filename. \; end the command.
This is the fastest way to achieve what you want:
find /BASE/CODE/LOGS_BACK -type f -mtime +60 -exec rm -f {} +
Note the ending + which does the same job as xargs.
I had a directory with many files and sub-directories. To move only the sub-directories, I just learned you can use:
ls -d BASEDIR/*/ | xargs -n1 -I% mv % TARGETDIR/
I use the following:
$ mv ./*/ DirToMoveTo
For example:
Say I wanted to move all directories with "Old" in the name to a folder called "Old_Dirs" on /data.
The command would look like this:
mv ./*Old*/ /data/
Why not use find?
find . -maxdepth 1 -type d -exec mv '{}' /tmp \;
-maxdepth 1 makes sure find won't go deeper than current directory
-type d tells find to only find directories
-exec execute a command with the result of the find referenced by {}
In my opinion a cleaner solution and it also works better then using xargs when you have files with white space or tabs in them.
With a file structure like this:
/dir2move2
/dir
/subdir1
/subdir2
index.js
To move only the sub directories and not the files you could just do:
mv ./dir/*/ ./dir2move2
Possible solution:
find BASEDIR/ -maxdepth 1 -mindepth 1 -type d -exec mv '{}' TARGETDIR \;
you can simply use the same command for moving a file but put a slash after the name of the subdirectory
sudo mv */ path/to/destination
sudo mv subdir/ path/to/subdirectory
I need a Unix command to find all the text files older than 3 days and move them to some other location in single command.
In that case you want find and use its -exec and -mtime flags.
It should be something like:
find . -mtime -3 -type f -print0 | xargs -0 -I file mv file /new/dir/.
man find
man xargs
I'm trying to remove all the .svn directories from a working directory.
I thought I would just use find and rm like this:
find . -iname .svn -exec 'rm -rf {}' \;
But the result is:
find: rm -rf ./src/.svn: No such file or directory
Obviously the file exists, or find wouldn't find it... What am I missing?
You shouldn't put the rm -rf {} in single quotes.
As you've quoted it the shell is treating all of the arguments to -exec it as a command rather than a command plus arguments, so it's looking for a file called "rm -rf ./src/.svn" and not finding it.
Try:
find . -iname .svn -exec rm -rf {} \;
Just by-the-bye, you should probably get out of the habit of using -exec for things that can be done to multiple files at once. For instance, I would write that out of habit as
find . -iname .svn -print | xargs rm -rf
or, since I'm now using a Macintosh and more likely to encounter file or directory names with spaces in them
find . -iname .svn -print0 | xargs -0 rm -rf
"xargs" makes sure that "rm" is invoked only once every "N" files, where "N" is usually 20. That's not a huge win in this case, because rm is small, but if the program you wanted to execute on every file was large or did a lot of processing on start up, it could make things a lot faster.
maybe its just me, but the old find & rm script does not work on my current config, a la:
find /data/bin/test -type d -mtime +10 -name "[0-9]*" -exec rm -rf {} \;
whereas the xargs solution does, a la:
find /data/bin/test -type d -mtime +10 -name '[0-9]*' -print | xargs rm -rf ;
no idea why, but i've updated my scriptLib so i dont spend another couple hours beating
my head on something so simple....
(running RHEL under kernel-2.6.18-194.11.3.el5)
EDIT: found out why - my RHEL distro defaults vi to insert the dreaded cr into line breaks (whch breaks the command) - following suggestions from nx5000 & jliagre at linuxquestions.org, added the following to ~/.vimrc:
:set fileformat=unix
map <F4> :set fileformat=unix<CR>
map <F5> :set fileformat=dos<CR>
which allows the behavior to pivot on the F4/F5.
to check whether CR's are embedded in your file:
head -1 scriptFile.sh | od -c | head -1
http://www.linuxquestions.org/questions/linux-general-1/bad-interpreter-no-such-file-or-directory-213617/
You can also use the svn command as follows:
svn export <url-to-repo> <dest-path>
Look here for more info.
Try
find . -iname .svn -exec rm -rf {} \;
and that probably ought to work IIRC.
You can pass anything you want in quotes, with the following trick.
find . -iname .svn -exec bash -c 'rm -rf {}' \;
The exec option will be happy to see that you're simply calling an executable with an argument, but your argument will be able to contain a script of basically any size and shape.
find . -iname .svn -exec bash -c '
ls -l "{}" | wc -l
' \;