find . -name '{fileNamePattern}*.bz2' | xargs -n 1 -P 3 bzgrep -H "{patternToSearch}"
I am using the command above to find out a .bz2 file from set of files that have a pattern that I am looking for. It does go through the files because I can see the pattern that I am trying to find being printed on the console but I don't see the file name.
If you look at the bzgrep script (for example this version for OS X) you will see that it pipes the output from bzip2 through grep. That process loses the original filenames. grep never sees them so it cannot print them out (despite your -H flag).
Something like this should do, not exactly what you want but something similar. (You could get the prefix you were expecting by piping the output from bzgrep into sed/awk but that's a bit less simple of a command to write out.)
find . -name '{fileNamePattern}*.bz2' -printf '### %p\n' -exec bzgrep "{patternToSearch}" {} \;
I printed the file name through echo command and xargs.
find . -name "*bz2" | parallel -j 128 echo -n {}\" \" | xargs bzgrep {pattern}
Etan is very close with his answer: grep indeed does not show the filename when only dealing with one file, so you can make grep believe he's looking into multiple files, just by adding the NULL file, so the command becomes:
find . -name '{fileNamePattern}*.bz2' -printf '### %p\n'
-exec bzgrep "{patternToSearch}" {} /dev/null \;
(It's a dirty trick but it's helping me already for more than 15 years :-) )
I`m going to delete all files from directory that contains "2" in their name.
this command work well
ls | grep [*2*]
but when i try to pipe the output from that command to command rm
ls | grep [*2*] | rm
there is error "Try `rm --help' for more information."
please help
Why not use the wildcarding in the shell directly ?
e.g.
$ rm *2*
I don't think you need the ls or the grep. Your above problem stems from the fact that you're piping output into the stdin of rm, whereas you want to supply command line arguments to rm. rm doesn't read from stdin.
To pipe output from another command to rm you must use xargs commant for rm
Try this
ls | grep [*2*] | xargs rm
the output will send like arguments of rm command
you need to feed every line to rm command as an input. For this you need xargs along with pipe.
so modify the command like ls -1 | grep [*2*] | xargs rm -rf
just complementing on other answers, instead of running ls then grep, you could use find.
find . -name "*2*" | xargs rm
Using find I create a file that contains all the files that use a specific key word:
find . -type f | xargs grep -l 'foo' > foo.txt
I want to take that list in foo.txt and maybe run some commands using that list, i.e. run an ls command on the list contained within the file.
You don't need xargs to create foo.txt. Just execute the command with -exec like this:
find . -type f -exec grep -l 'foo' {} \; > foo.txt
Then you can run ls against the file by looping through the file:
while IFS= read -r read file
do
ls "$file"
done < foo.txt
Maybe it is a little ugly, but this can also make it:
ls $(cat foo.txt)
You can use xargs like this:
xargs ls < foo.txt
The advantage of xargs is that it will execute the command with multiple arguments which is more efficient than executing the command once per argument using a loop, for example.
I'm looking for the string foo= in text files in a directory tree. It's on a common Linux machine, I have bash shell:
grep -ircl "foo=" *
In the directories are also many binary files which match "foo=". As these results are not relevant and slow down the search, I want grep to skip searching these files (mostly JPEG and PNG images). How would I do that?
I know there are the --exclude=PATTERN and --include=PATTERN options, but what is the pattern format? The man page of grep says:
--include=PATTERN Recurse in directories only searching file matching PATTERN.
--exclude=PATTERN Recurse in directories skip file matching PATTERN.
Searching on grep include, grep include exclude, grep exclude and variants did not find anything relevant
If there's a better way of grepping only in certain files, I'm all for it; moving the offending files is not an option. I can't search only certain directories (the directory structure is a big mess, with everything everywhere). Also, I can't install anything, so I have to do with common tools (like grep or the suggested find).
Use the shell globbing syntax:
grep pattern -r --include=\*.cpp --include=\*.h rootdir
The syntax for --exclude is identical.
Note that the star is escaped with a backslash to prevent it from being expanded by the shell (quoting it, such as --include="*.cpp", would work just as well). Otherwise, if you had any files in the current working directory that matched the pattern, the command line would expand to something like grep pattern -r --include=foo.cpp --include=bar.cpp rootdir, which would only search files named foo.cpp and bar.cpp, which is quite likely not what you wanted.
Update 2021-03-04
I've edited the original answer to remove the use of brace expansion, which is a feature provided by several shells such as Bash and zsh to simplify patterns like this; but note that brace expansion is not POSIX shell-compliant.
The original example was:
grep pattern -r --include=\*.{cpp,h} rootdir
to search through all .cpp and .h files rooted in the directory rootdir.
If you just want to skip binary files, I suggest you look at the -I (upper case i) option. It ignores binary files. I regularly use the following command:
grep -rI --exclude-dir="\.svn" "pattern" *
It searches recursively, ignores binary files, and doesn't look inside Subversion hidden folders, for whatever pattern I want. I have it aliased as "grepsvn" on my box at work.
Please take a look at ack, which is designed for exactly these situations. Your example of
grep -ircl --exclude=*.{png,jpg} "foo=" *
is done with ack as
ack -icl "foo="
because ack never looks in binary files by default, and -r is on by default. And if you want only CPP and H files, then just do
ack -icl --cpp "foo="
grep 2.5.3 introduced the --exclude-dir parameter which will work the way you want.
grep -rI --exclude-dir=\.svn PATTERN .
You can also set an environment variable: GREP_OPTIONS="--exclude-dir=\.svn"
I'll second Andy's vote for ack though, it's the best.
I found this after a long time, you can add multiple includes and excludes like:
grep "z-index" . --include=*.js --exclude=*js/lib/* --exclude=*.min.js
The suggested command:
grep -Ir --exclude="*\.svn*" "pattern" *
is conceptually wrong, because --exclude works on the basename. Put in other words, it will skip only the .svn in the current directory.
In grep 2.5.1 you have to add this line to ~/.bashrc or ~/.bash profile
export GREP_OPTIONS="--exclude=\*.svn\*"
I find grepping grep's output to be very helpful sometimes:
grep -rn "foo=" . | grep -v "Binary file"
Though, that doesn't actually stop it from searching the binary files.
If you are not averse to using find, I like its -prune feature:
find [directory] \
-name "pattern_to_exclude" -prune \
-o -name "another_pattern_to_exclude" -prune \
-o -name "pattern_to_INCLUDE" -print0 \
| xargs -0 -I FILENAME grep -IR "pattern" FILENAME
On the first line, you specify the directory you want to search. . (current directory) is a valid path, for example.
On the 2nd and 3rd lines, use "*.png", "*.gif", "*.jpg", and so forth. Use as many of these -o -name "..." -prune constructs as you have patterns.
On the 4th line, you need another -o (it specifies "or" to find), the patterns you DO want, and you need either a -print or -print0 at the end of it. If you just want "everything else" that remains after pruning the *.gif, *.png, etc. images, then use
-o -print0 and you're done with the 4th line.
Finally, on the 5th line is the pipe to xargs which takes each of those resulting files and stores them in a variable FILENAME. It then passes grep the -IR flags, the "pattern", and then FILENAME is expanded by xargs to become that list of filenames found by find.
For your particular question, the statement may look something like:
find . \
-name "*.png" -prune \
-o -name "*.gif" -prune \
-o -name "*.svn" -prune \
-o -print0 | xargs -0 -I FILES grep -IR "foo=" FILES
On CentOS 6.6/Grep 2.6.3, I have to use it like this:
grep "term" -Hnir --include \*.php --exclude-dir "*excluded_dir*"
Notice the lack of equal signs "=" (otherwise --include, --exclude, include-dir and --exclude-dir are ignored)
git grep
Use git grep which is optimized for performance and aims to search through certain files.
By default it ignores binary files and it is honoring your .gitignore. If you're not working with Git structure, you can still use it by passing --no-index.
Example syntax:
git grep --no-index "some_pattern"
For more examples, see:
How to exclude certain directories/files from git grep search.
Check if all of multiple strings or regexes exist in a file
I'm a dilettante, granted, but here's how my ~/.bash_profile looks:
export GREP_OPTIONS="-orl --exclude-dir=.svn --exclude-dir=.cache --color=auto" GREP_COLOR='1;32'
Note that to exclude two directories, I had to use --exclude-dir twice.
If you search non-recursively you can use glop patterns to match the filenames.
grep "foo" *.{html,txt}
includes html and txt. It searches in the current directory only.
To search in the subdirectories:
grep "foo" */*.{html,txt}
In the subsubdirectories:
grep "foo" */*/*.{html,txt}
In the directories are also many binary files. I can't search only certain directories (the directory structure is a big mess). Is there's a better way of grepping only in certain files?
ripgrep
This is one of the quickest tools designed to recursively search your current directory. It is written in Rust, built on top of Rust's regex engine for maximum efficiency. Check the detailed analysis here.
So you can just run:
rg "some_pattern"
It respect your .gitignore and automatically skip hidden files/directories and binary files.
You can still customize include or exclude files and directories using -g/--glob. Globbing rules match .gitignore globs. Check man rg for help.
For more examples, see: How to exclude some files not matching certain extensions with grep?
On macOS, you can install via brew install ripgrep.
find and xargs are your friends. Use them to filter the file list rather than grep's --exclude
Try something like
find . -not -name '*.png' -o -type f -print | xargs grep -icl "foo="
The advantage of getting used to this, is that it is expandable to other use cases, for example to count the lines in all non-png files:
find . -not -name '*.png' -o -type f -print | xargs wc -l
To remove all non-png files:
find . -not -name '*.png' -o -type f -print | xargs rm
etc.
As pointed out in the comments, if some files may have spaces in their names, use -print0 and xargs -0 instead.
Try this one:
$ find . -name "*.txt" -type f -print | xargs file | grep "foo=" | cut -d: -f1
Founded here: http://www.unix.com/shell-programming-scripting/42573-search-files-excluding-binary-files.html
those scripts don't accomplish all the problem...Try this better:
du -ha | grep -i -o "\./.*" | grep -v "\.svn\|another_file\|another_folder" | xargs grep -i -n "$1"
this script is so better, because it uses "real" regular expressions to avoid directories from search. just separate folder or file names with "\|" on the grep -v
enjoy it!
found on my linux shell! XD
Look # this one.
grep --exclude="*\.svn*" -rn "foo=" * | grep -v Binary | grep -v tags
The --binary-files=without-match option to GNU grep gets it to skip binary files. (Equivalent to the -I switch mentioned elsewhere.)
(This might require a recent version of grep; 2.5.3 has it, at least.)
suitable for tcsh .alias file:
alias gisrc 'grep -I -r -i --exclude="*\.svn*" --include="*\."{mm,m,h,cc,c} \!* *'
Took me a while to figure out that the {mm,m,h,cc,c} portion should NOT be inside quotes.
~Keith
To ignore all binary results from grep
grep -Ri "pattern" * | awk '{if($1 != "Binary") print $0}'
The awk part will filter out all the Binary file foo matches lines
Try this:
Create a folder named "--F" under currdir ..(or link another folder there renamed to "--F" ie double-minus-F.
#> grep -i --exclude-dir="\-\-F" "pattern" *