I'm about ready to cry!
I've done a lot of Google searches but I can't quite get this piece of coding working the way I want it to.
In Wordpress I have the following taxonomy:
Active
- Open
- In-Progress
- Awaiting Parts
- Pending / On-Hold
- Awaiting Pick-up
Closed
https://dl.dropboxusercontent.com/u/30177707/wo-tax.png
What I would like is for the child to be displayed for the specific post and if there are no children I would like to display just the parent.
Heres a screenshot I've edited so it gives a better picture of what I'm asking.
https://dl.dropboxusercontent.com/u/30177707/stackoverflow.png
This is the code I've been playing with:
$terms = wp_get_post_terms($post->ID, 'pctracker_workorderstatus');
$count = count($terms);
if ( $count > 0 ){
foreach ( $terms as $term ) {
echo $term->name .'<br>';
}
}
At present its displaying the parent and child for the post.
Would be very grateful for some help or direction!
Thanks,
Jase
You'll have to edit column content like this :
This is an example code you could adapt to your needs, basically I look at all terms to get which ones are parents and childs. Then depending of the results I display parents or childs. In your case, there will always be 1 parent and/or 1 child. But the code should work. (not tested)
function MYCUSTOMPOSTTYPE_custom_columns( $column_name, $id ) {
switch ( $column_name ) {
case 'status':
$terms = wp_get_post_terms($id, 'pctracker_workorderstatus');
$count = count($terms);
if ( $count > 0 ) {
$parents = array();
$childs = array();
foreach ( $terms as $term ) {
if(!empty($term->parent)) {
$childs[] = $term;
} else {
$parents[] = $term;
}
}
//display parent if there no child
if(empty($childs)) {
foreach($parents as $p) {
echo $p->name;
}
} elseif(!empty($parents) && !empty($childs)) {
//don't display parent
foreach($childs as $p) {
echo $p->name;
}
}
}
break;
default:
break;
} // end switch
}
add_action( 'manage_MYCUSTOMPOSTTYPE_posts_custom_column', 'MYCUSTOMPOSTTYPE_custom_columns', 10, 2 );
Related
I am using the "custom product options" plugin and created a datepicker for customers to choose a requested ship date. I need to create a column on my orders admin page for their selection so I do not have to go into the order to find the date. I have found a few different threads that are similar but they don't really apply to my exact situation. Would someone be able to provide some help on this? Apologies for a lack of detail that is getting me downvotes, but If I knew what I needed I wouldn't be here asking what to do. I am a novice, cut me a little slack. Datepicker can be seen here.
https://chrish148.sg-host.com/product/butterscotch-oatmeal-copy/
current layout looks like this.
current layout image
This is the code that I used for one of my WooCommerce sites to get order-colors:
add_filter( 'manage_edit-shop_order_columns','shopOrder',10 );
function shopOrder($columns)
{
$columns['custom_color_column'] = "Färger";
return $columns;
}
add_action( 'manage_shop_order_posts_custom_column' , 'populateShopOrder' );
function populateShopOrder( $column ) {
global $the_order, $post;
if( $column == 'custom_color_column' ) {
global $post, $the_order;
if ( empty( $the_order ) || $the_order->get_id() !== $post->ID ) {
$the_order = wc_get_order( $post->ID );
}
if ( empty( $the_order ) ) {
return;
}
$items = $the_order->get_items();
foreach ($items as $item) {
// load meta data - product attributes
foreach ($item->get_meta_data() as $metaData) {
$attribute = $metaData->get_data();
// attribute value
$value = $attribute['value'];
if($value != null && $attribute['key'] == "pa_farg"){
echo "- " . $value;
if(count($items) > 1) echo "<br>";
}
else return;
}
}
}
}
However this might not be the exakt case for you. Since I do not know the exact plugin that you are using I can not know for sure.
However it should be close.
If you can figure out the attribute names then you could switch it from "fa_farg" to that, or you could link the plugin thet you are using and I will take a look at it.
The Challenge
I have been trying to write a filter that applies (prepends a string) to (a) post titles of a certain post type and (b) to that same post type WordPress admin backend for use by an auto social sharing plugin.
I've gotten really close. I've achieved:
1. prepending only to custom post_type post titles
2. prepending to custom_post type titles AND all nav menu items
3. prepending to ALL titles (post, page, nav menu, and backend auto-sharing plugin)
The final, 3rd attempt got me very hopeful, but yet still, no matter the function, conditional statement, or combination I use, I can't get custom_post title AND backend social sharing plugin, but not nav menu items.
My Code - what I've tried
I've tried different conditionals, like is_admin() and !is_nav_menu with all nav menu IDs. I've also tried comparing the ID of the post to the ID of the menu. Finally, I've also tried adding the filter only to loop_start and that seems promising if combined with other statements. I will clean up my code for your review but I leave it this way for now in hopes it helps to see what I've tried and maybe where I went wrong with any of those methods.
// , $id = NULL
function append_album_review_to_title( $title ) {
global $post;
global $dont_apply_title_filter;
$text = 'Album Review: ';
$prepended_title = $text . $title;
/*
$nav_menus_obj = wp_get_nav_menus();
$nav_menu_ids = '';
foreach( $nav_menus_obj as $nav_menu ) {
$nav_menu_ids .= $nav_menu->term_id . ',';
}
rtrim($nav_menu_ids, ',');
*/
// if ( get_post_type( $post->ID ) == 'album_review' && in_the_loop() ){
// if ( get_post_type( $post->ID ) == 'album_review' && $id == get_the_ID() ){
// if ( !is_nav_menu( '32057,32058,35135,32054,32056' ) ) {
// if ( get_post_type( $post->ID ) == 'album_review' && is_nav_menu( $id ) ) {
if ( get_post_type( $post->ID ) == 'album_review' && !$dont_apply_title_filter ) {
//print_r( $nav_menu_ids );
//print_r( is_nav_menu( $nav_menu_ids ) );
return $prepended_title;
/*
} elseif ( get_post_type( $post->ID ) == 'album_review' ) {
return $title;
*/
} else {
return $title;
};
}
add_filter('the_title', 'append_album_review_to_title');
//add_action('save_post', 'custom_post_type_title', 100);
/*
function set_custom_title() {
add_filter( 'the_title', 'append_album_review_to_title', 10, 2 );
}
add_action( 'loop_start', 'set_custom_title' );
*/
Solution
function append_album_review_to_title( $title, $id = NULL ) {
if ($id) {
if ( get_post_type( $id ) == 'album_review' ){
return 'Album Review: ' . $title;
} else {
return $title;
}
} else {
return 'Album Review: ' . $title;
};
}
add_filter('the_title', 'append_album_review_to_title', 10, 2);
Explanation
First trying this:
function append_album_review_to_title( $title, $id ) {
if ( get_post_type( $id ) == 'album_review' ){
return 'Album Review: ' . $title;
} else {
return $title;
}
}
add_filter('the_title', 'append_album_review_to_title', 10, 2);
I noticed that on the backend, the social sharing plugin I am using to auto-share posts would return warnings like missing parameter 2 and Notice: Trying to get property of non-object..., and so it occurred to me that unlike the front end (nav menu and the loop), in the backend, apparently an $id is not being passed to the_title and so I can use this as a conditional.
Checking for $id will, for my purposes, tell me that if it is true, we are on front end, if it is false, then we are at backend post view.
This code accomplishes what I need (ie, modify post title in the loop, do NOT modify nav menu items, and modify the_title for use by a backend social sharing plugin):
I was wondering if there is an easy solution to add some php "if" code when my website tries to show the widgets and if it has $_SESSION I set on homepage (based on the source of which they came) not to show one of them?
I think maybe this will answer your question.
You finally could have something like this:
add_filter( 'sidebars_widgets', 'hidemywidget' );
function hidemywidget($all_widgets) {
if( $_SESSION['%your key%'] == '%your value%' ) {
foreach ( $all_widgets['primary-widget-area'] as $i => $inst ) {
$pos = strpos( $inst, '%the widget you want to hide%');
if( $pos !== false ) {
unset( $all_widgets['primary-widget-area'][$i] );
}
}
}
return $all_widgets;
}
Let me tell you the scenario first say the structure of the categories in wordpress is like this
Level 1: Top
Level 2: -Nextme_1
Level 3: --Nextme_2
--Nextme_3
Level 4: ---Nextme_4
---Nextme_5
Now I require to check what is the level of the category? Say I catch a category of level 3 so I have to use different template and if its level 4. Then I need to use another template?
Anybody can give me some hint?
Thanks
Rahul
If you don't have many categories you can try to edit their slug from admin, and then in your page you get the category slug this way:
if (is_category()) {
$cat = get_query_var('cat');
$category = get_category($cat);
echo 'your slug is '. $category->slug;
}
Now, when you're editing the categories slugs try naming them after their level: cat-lvl-1, cat-lvl-2. Then in your page you extract the number from category slug using some php string function, and then you check that number:
if ($category->slug == 1 ) {
//load the template for the category of level 1
}
if ($category->slug == 2 ) {
//load the template for the category of level 2
}
and so on.
Later edit:
Try this:
function get_level($category, $level = 0)
{
if ($category->category_parent == 0) {
return $level;
} else {
$level++;
$category = get_category($category->category_parent);
get_level($category, $level);
}
}
if (is_category()) {
$cat = get_query_var('cat');
$yourcat = get_category($cat);
echo get_level($yourcat);
}
You can call the get_ancestors() function to get an array containing the parents of the given object. Then you need to count elements in the result.
function get_the_level($id, $type = 'category') {
return count( get_ancestors($id, $type) );
}
if( is_category() ) {
$level = get_the_level( $cat );
}
elseif( is_product_category() ) {
$level = get_the_level( $wp_query->get_queried_object()->term_id, 'product_cat' );
}
Thanks a lot. This is superb with slight a change the code that you have written is fine but its not returning any value.(i,e the $level) although its calculating correct. A minor change i did and its work fine now with a slight editing of you code given below..
`
function get_level($category, $level = 0)
{
if ($category->category_parent == 0) {
return $level;
} else {
$level++;
$category = get_category($category->category_parent);
return get_level($category, $level);
}
}
if (is_category()) {
$cat = get_query_var('cat');
$yourcat = get_category($cat);
echo get_level($yourcat);
}
`
Thanks #zuzuleinen
I visited this page months back. I came back today, arrow up on the above solution then still went digging. Although it is a good solution, Wordpress often offers better or close.
get_category_parents()
This function does as Rahul has typed basically. It also calls itself which seems the most logical approach and that is why Rahul gets a point from me on this. Do not use $link, return a string of categories, explode() them then count or I suppose we could count the number of times the separator has been used and add 1.
function get_category_parents( $id, $link = false, $separator = '/', $nicename = false, $visited = array() ) {
$chain = '';
$parent = get_term( $id, 'category' );
if ( is_wp_error( $parent ) )
return $parent;
if ( $nicename )
$name = $parent->slug;
else
$name = $parent->name;
if ( $parent->parent && ( $parent->parent != $parent->term_id ) && !in_array( $parent->parent, $visited ) ) {
$visited[] = $parent->parent;
$chain .= get_category_parents( $parent->parent, $link, $separator, $nicename, $visited );
}
if ( $link )
$chain .= ''.$name.'' . $separator;
else
$chain .= $name.$separator;
return $chain;
}
I want to change the default template hierarchy behavior, and force all subcategory level pages that don't have their own category template file to refer to their parent category template file. In my other post, Richard M. gave an excellent answer that solved the problem for an individual subcategory. Does anyone know how to abstract it?
function myTemplateSelect()
{
if (is_category()) {
if (is_category(get_cat_id('projects')) || cat_is_ancestor_of(get_cat_id('projects'), get_query_var('cat'))) {
load_template(TEMPLATEPATH . '/category-projects.php');
exit;
}
}
}
add_action('template_redirect', 'myTemplateSelect');
Thanks in advance.
/**
* Iterate up current category hierarchy until a template is found.
*
* #link http://stackoverflow.com/a/3120150/247223
*/
function so_3119961_load_cat_parent_template( $template ) {
if ( basename( $template ) === 'category.php' ) { // No custom template for this specific term, let's find it's parent
$term = get_queried_object();
while ( $term->parent ) {
$term = get_category( $term->parent );
if ( ! $term || is_wp_error( $term ) )
break; // No valid parent
if ( $_template = locate_template( "category-{$term->slug}.php" ) ) {
// Found ya! Let's override $template and get outta here
$template = $_template;
break;
}
}
}
return $template;
}
add_filter( 'category_template', 'so_3119961_load_cat_parent_template' );
This loops up the parent hierarchy until an immediate template is found.
i was wondering how to do the same thing for heirarchical taxonomies. TheDeadMedic's answer seems to work in that case too w/ a few tweaks:
function load_tax_parent_template() {
global $wp_query;
if (!$wp_query->is_tax)
return true; // saves a bit of nesting
// get current category object
$tax = $wp_query->get_queried_object();
// trace back the parent hierarchy and locate a template
while ($tax && !is_wp_error($tax)) {
$template = STYLESHEETPATH . "/taxonomy-{$tax->slug}.php";
if (file_exists($template)) {
load_template($template);
exit;
}
$tax = $tax->parent ? get_term($tax->parent, $tax->taxonomy) : false;
}
}
add_action('template_redirect', 'load_tax_parent_template');
The TEMPLATEPATH variable might not work for child themes - looks in parent theme folder.
Use STYLESHEETPATH instead. e.g.
$template = STYLESHEETPATH . "/category-{$cat->slug}.php";