How to Check Which level category it is for wordpress? - wordpress

Question

Let me tell you the scenario first say the structure of the categories in wordpress is like this
Level 1: Top
Level 2: -Nextme_1
Level 3: --Nextme_2
--Nextme_3
Level 4: ---Nextme_4
---Nextme_5
Now I require to check what is the level of the category? Say I catch a category of level 3 so I have to use different template and if its level 4. Then I need to use another template?
Anybody can give me some hint?
Thanks
Rahul

Answer 1

If you don't have many categories you can try to edit their slug from admin, and then in your page you get the category slug this way:
if (is_category()) {
$cat = get_query_var('cat');
$category = get_category($cat);
echo 'your slug is '. $category->slug;
}
Now, when you're editing the categories slugs try naming them after their level: cat-lvl-1, cat-lvl-2. Then in your page you extract the number from category slug using some php string function, and then you check that number:
if ($category->slug == 1 ) {
//load the template for the category of level 1
}
if ($category->slug == 2 ) {
//load the template for the category of level 2
}
and so on.
Later edit:
Try this:
function get_level($category, $level = 0)
{
if ($category->category_parent == 0) {
return $level;
} else {
$level++;
$category = get_category($category->category_parent);
get_level($category, $level);
}
}
if (is_category()) {
$cat = get_query_var('cat');
$yourcat = get_category($cat);
echo get_level($yourcat);
}

Answer 2

You can call the get_ancestors() function to get an array containing the parents of the given object. Then you need to count elements in the result.
function get_the_level($id, $type = 'category') {
return count( get_ancestors($id, $type) );
}
if( is_category() ) {
$level = get_the_level( $cat );
}
elseif( is_product_category() ) {
$level = get_the_level( $wp_query->get_queried_object()->term_id, 'product_cat' );
}

Answer 3

Thanks a lot. This is superb with slight a change the code that you have written is fine but its not returning any value.(i,e the $level) although its calculating correct. A minor change i did and its work fine now with a slight editing of you code given below..
`
function get_level($category, $level = 0)
{
if ($category->category_parent == 0) {
return $level;
} else {
$level++;
$category = get_category($category->category_parent);
return get_level($category, $level);
}
}
if (is_category()) {
$cat = get_query_var('cat');
$yourcat = get_category($cat);
echo get_level($yourcat);
}
`
Thanks #zuzuleinen

Answer 4

I visited this page months back. I came back today, arrow up on the above solution then still went digging. Although it is a good solution, Wordpress often offers better or close.
get_category_parents()
This function does as Rahul has typed basically. It also calls itself which seems the most logical approach and that is why Rahul gets a point from me on this. Do not use $link, return a string of categories, explode() them then count or I suppose we could count the number of times the separator has been used and add 1.
function get_category_parents( $id, $link = false, $separator = '/', $nicename = false, $visited = array() ) {
$chain = '';
$parent = get_term( $id, 'category' );
if ( is_wp_error( $parent ) )
return $parent;
if ( $nicename )
$name = $parent->slug;
else
$name = $parent->name;
if ( $parent->parent && ( $parent->parent != $parent->term_id ) && !in_array( $parent->parent, $visited ) ) {
$visited[] = $parent->parent;
$chain .= get_category_parents( $parent->parent, $link, $separator, $nicename, $visited );
}
if ( $link )
$chain .= ''.$name.'' . $separator;
else
$chain .= $name.$separator;
return $chain;
}