I'm trying to list the max line length for files in the current directory, but I'm having trouble with my command working. I believe it's an issue with escaping the curly brackets {} in my exec command. After googling through a ton of find exec escape answers I wasn't able to locate anything about how to escape brackets {} in the exec command. What am I missing?
find . -iname *.page -exec awk '{if(length($0) > L) { LINE=$0;L = length($0)}}
END {print LINE"|"L}' {}\; | sort
Their are multiple issues with the original command none of which are escaping {}. The first issue is there needs to be a space between {} and \;. The second issue is related to how the shell expands the wildcard in the find iname paramater *.page.
From the Free BSD Forums
"*" is expanded by the shell before the command-line is passed to find(1). If there's only 1 item in the directory, then it works. If
there's more than one item in the directory, then it fails as the
command-line options are no longer correct.
Wrapping the *.page in quotes solves the issue. The final version is
find . -iname '*.page' -exec awk '{if(length($0) > L)
{ LINE=NR;L = length($0)}} END {print L"|"FILENAME":"LINE}' {} \; | sort -n
Which outputs the a sorted list of the longest line for each file with line number
220|./Example1.page:157
206|./Example2.page:203
You want to run awk on each file, right?
create a script: t.sh in your home directory:
awk '{if(length($0) > L) { LINE=$0;L = length($0)}}
END {print LINE"|"L}' "$1"
command line:
find . -iname *.page -exec ~/t.sh {} | sort
I'm not too sure about your awk script but since you think it is what you need let's pass on that for now.
Related
I'm on a UNIX system. Within a directory (and any of its subdirectories), I'm trying to rename all files that match a certain pattern:
change hello (1).pdf
to hello.pdf
Based on the top response from this question, I wrote the following command:
find . -name '* (1)*' -exec rename -ns 's/ (1)//' {} \;
The find works on its own and the rename also works on its own, but the above command only outputs Reading filenames from STDIN and does nothing. How can I make this work?
Figured this out! For whatever reason, it only works when you use the Perl version of rename like this:
find . -name '* (1)*' -exec rename -f -s ' (1)' '' {} \;
I need to select only directories between the periods of 20140729 - 20140921.
The directories look like this.
20140729_154208 20140814_221350 20140829_215623
What is the best method to do this?
Thanks
Using find
In order to find files modified within a range, if the creation time of the last file in the directory matches the directory name, the easiest way is to create files at the boundaries of the range and use the -newer predicate.
touch -t 201407290000 start
touch -t 201409210000 stop
find . -newer start \! -newer stop -type d
(I know not how to work with dates within regex, but I hope I have time to learn)
Using awk
Yeah, why not using awk instead of building a static regex to match the case?
Pass the find or ls result to awk with a little program checking the result is between stop and start (NB: for find I had to substr(3,10) for comparison):
find . |awk -v start=20140729 -v stop=20140921 \
'{ curr=substr($0, 3, 10); if (curr <= stop && curr >= start) { print $0 } }'
(It worked for me on AIX and Linux)
I have a directory customer. I have many customers in customer directory.
Now I want to add two lines in some process_config file within customer directory where it was not available.
For example:
/home/sam/customer/a1/na/process_config.txt
/home/sam/customer/p1/emea/process_config.txt
and so so.
Is this possible by single command like find & sed?
With a simple for loop :
for file in /home/sam/customer/*/*/process_config.txt; do
printf "one line\nanother line\n" >> "$file"
done
find /home/sam/customer -name 'process_config.txt' -exec DoYourAddWithSedAwkEchoOrWhatever {} \;
find give you the possibility to select each wanted (selected) file
option -exec start a subshell with your command on this file.
{} is the file name (full name) in this case.
Use \; as end of command for the iteration (other command couldbe used with the standard behaviour of ; ex -exec echo 'line1' >> {} ; echo "line2" >> {} \;
sed, awk or echo like in sample can modify the file
I'm trying to move file from one place to another directory...So my program will read Log_Deleter, use parameters given in each line to delete the file.
When I execute the file, it seems like it runs fine (no errors) but non of the files are moved... I'm not sure why it's not moving the file nor display any error...
Can someone please identify the error?
my attempt:
#!/bin/ksh
while read -r line ; do
v=$line
set -- $v
cd /
$(find "$1" -type f -name "$2" -mtime +"$3" -exec mv {} "$4" \;)
done < Log_Deleter.txt
Log_Deleter.txt
/usr/IBM/WebSphere/AppServer/profiles/AppSrvSIT1/logs/Server1 'SystemOut_*' 5 /backup/Abackuptest1
/usr/IBM/WebSphere/AppServer/profiles/AppSrvSIT1/logs/Server2 'SystemOut_*' 5 /backup/Abackuptest2
Thanks for your help!
Find is looking for files that have a literal ' in the name. You need to remove the single quotes from $2 before invoking find. Try:
#!/bin/ksh
while read -r path name mtime dest ; do
name=$( echo $name | tr -d "'" )
find "$path" -type f -name "$name" -mtime +"$mtime" -exec mv {} "$dest" \;
done < Log_Deleter.txt
The problem is that you are trying to match a file whose name actually has the single quotes in it.
Barring other problems, I think your script will probably work once you take the quotes out of Log_Deleter.txt.
The quotes are only meaningful when the shell is parsing command input. This is not what the read builtin does. And even when reading command input, once the quotes get into a variable they stay there forever unless reread at the shells CLI layer via eval.
The shell is not exactly a macro processor. It's a complicated hybrid that a little bit CLI, a little bit programming language, and a little bit macro processor.
And, speaking of eval, it's not necessary to wrap the find in an eval-like construct. Simplify your script to run find directly and you will find it easier to debug and understand.
Basically we need to change the end of line characters for a group of files.
Is there a way to accomplish this with a batch file? Is there a freeware utility?
dos2unix
It could be done with somewhat shorter command.
find ./ -type f | xargs -I {} dos2unix {}
You should be able to use tr in combination with xargs to do this.
On the Unix side at least, this should be the simplest way. However, I tried doing it that way once on a Windows box over a decade ago, but discovered that the Windows version of tr was translating my terminators right back to Windows format for me. :-( However, I think in the interveneing decade the tools have gotten smarter.
Combine find with dos2unix/fromdos to convert a directory of files (excluding binary files).
Just add this to your .bashrc:
DOS2UNIX=$(which fromdos || which dos2unix) \
|| echo "*** Please install fromdos or dos2unix"
function finddos2unix {
# Usage: finddos2unix Directory
find $1 -type f -exec file {} \; | grep " text" | cut -d ':' -f1 | xargs $DOS2UNIX
}
First, DOS2UNIX finds whether you have the utility installed, and picks one to use
Find makes a list of all files, then file appends the ": ASCII text" after each text file.
Finally, grep picks the text files, Cut removes all text after ':', and xargs makes this one big command line for DOS2UNIX.