i have hyperlink that the color of text will diffrent based on it value, if the value is 0, the color is black, if the value >0 it will red, here the code i have tried
ForeColor='<%#IIf(Eval("exception") = 0, "Black", "Red")%>'
but it give me error"
"The server tag is not well formed."
can anybody help me?
You can change its property in code behind.You just have to assign different CssClass based on values in value change event.
HyperLink1.CssClass = "NewClass"
Try Like below,
ForeColor='<%#(DataBinder.Eval("exception").ToString()=="0") ? "Black" : "Red"%>'
Related
Need to find the button color into human-readable format below code is returning rgba value
Here is my code:
WebElement findbuttonColor = driver.findElement(By.id("color"));
String color = findbuttonColor.getCssValue("background-color");
System.out.println("Button color is :"+color);
I am not sure what human-readable format mean, there are millions of colors which is possible to set for the element. Far not all of them have the names like green, blue, red, etc.
You get the value in rgba because the designer set up the value in rgba. The thing you could do is to define a structure that would map some well-known color codes to rgb (even not considering alpha channel) so that you could pich the "human-readable" format from that map.
Here is the example that might give a clue: Convert RGB values to color name
You can get the element color(Background color of element) by:
element.getCssValue("background-color");
You can get the element text/caption color by:
element.getCssValue("color");
For example if you want to get the background and text color of "Sign in" button for LinkedIn, the code is as follows:
driver.get("https://www.amazon.com/");
String buttonColor = driver.findElement(By.id("searchDropdownBox")).getCssValue("background-color");
String buttonTextColor = driver.findElement(By.id("searchDropdownBox")).getCssValue("color");
System.out.println("Button color: " + buttonColor);
System.out.println("Text color " + buttonTextColor);
When you do getCssValue(), it return rgb value. You can convert it into hex by using below
backgroundColor = element.getCssValue("background-color");
Color.fromString(backgroundColor).asHex();
this returns hex code, something like "#def3ff". You can later compare it with your availbale hexcode in yous css.
Assert.assertEquals(def3ff, ExpectedHexCode);
Note:
You can get hex code of your element by inspecting it > Styles. Refer below screenshot for details
how to get Hexcodefrom
Thank You,
I am using TTTAttributedLabel and need to set background color. I can set text color like this.
[mutableAttributedString addAttribute:NSForegroundColorAttributeName
value:color
range:range];
self.lblContent.attributedText = mutableAttributedString;
But it is not working for background color.
[mutableAttributedString addAttribute:NSBackgroundColorAttributeName
value:color
range:range];
self.lblContent.attributedText = mutableAttributedString;
May I know what is wrong?
You should use kTTTBackgroundFillColorAttributeName. See TTTAttributedLabel.h for details on that constant and several other attribute constants that are specific to TTTAttributedLabel.
Code sample:
var headerRowBackground:RGBColor = new RGBColor(0);
headerRowBackground.b = 58;
headerRowBackground.g = 28;
headerRowBackground.r = 255;
printPDF.beginFill(headerRowBackground);
printPDF.addCell(30, 20, "Room");
The word "Room" is in red, as is the rest of the text in the PDF. I actually want to make the cell background colour red. Anybody know why this doesn't work?
You should look at the API more:
printPDF.addCell(30, 20, 'Room', 0, 0, '1', 0xFF0000);
The documentation is wrong, the fill parameter is described as "Link can be internal to do document level navigation (InternalLink) or external (HTTPLink)".
The code to get this working is:
printPDF.beginFill(new RGBColor(0xFF0718));
printPDF.textStyle(new RGBColor(0x000000));
printPDF.addCell(30, 10, "Room", 0, 0, Align.LEFT, 1);
A couple of things about the code:
The fill parameter should be 0 or 1
rather than the fill value. It just
either switches on or off the fill
value previously set.
The text style
should be set too otherwise the text
and background will use the same
colour
I have a advanced datagrid label function like this:
private function dgFormat(item:Object, column:AdvancedDataGridColumn):String{
var v3:int = item.value1 - item.value2;
return "Total: " + v3;
}
How can I change the text color of v3 dynamically? I want it to be red if it's less than zero & black otherwise.
thanks!
There's a few ways of doing this, but personally if I were you, I'd just create a custom item renderer for the columns that you want the color to change and do something like:
<s:Label text="Total: {data}" color="{data < 0?0xFF0000:0x000000}" />
This way, you bind the difference right off the bat without having to add 'total' in your data, and bind the color change as well.
You'll need a custom item renderer for your AdvancedDataGridColumn. The item renderer will check the value being set, and update the color of the text depending on its content.
This should get you started.
<degrafa:LinearGradientFill id="bluedream">
<degrafa:GradientStop color="#6ab5d0"/>
<degrafa:GradientStop color="#388aae"/>
</degrafa:LinearGradientFill>
<degrafa:GeometryComposition graphicsTarget="{[bgCanvas]}">
<degrafa:RoundedRectangle id="color_preset" fill="{bluedream}"/>
</degrafa:GeometryComposition>
I have issue with degrafa code which I have defined a set of different gradients for color_preset.fill to be dynamic change when user select different color in the combobox.
I replaced fill="{bluedream}" with fill="using_variable" and lead to error compiled message: Initializer for 'fill': values of type com.degrafa.core.IGraphicsFill cannot be represented in text.
Is there a solution to use this code as a color changer?
The fill property in your example is pointing to the LinearGradientFill with id "bluedream". You can either replace the fill with a different gradient (or solid or other fill) or change the colors of the gradient fill itself:
<degrafa:LinearGradientFill id="bluedream">
<degrafa:GradientStop color="{your_combobox.selectedItem}"/>
<degrafa:GradientStop color="{your_other_combobox.selectedItem}"/>
</degrafa:LinearGradientFill>
<degrafa:GeometryComposition graphicsTarget="{[bgCanvas]}">
<degrafa:RoundedRectangle id="color_preset" fill="{bluedream}"/>
</degrafa:GeometryComposition>
I haven't run that code, but it should work. The idea is to change the color of the GradientStop with your dropdown's selectedItem (provided that is a string).
This example does something very similar, but with a color picker instead of a dropdown:
http://degrafa.org/source/CS4IconPreviewer/CS4IconPreviewer.html