I am new to Julia so sorry if this question is obvious.
I am trying to use Julia to help me run a series of finite element models, which use a text input file to give instructions to the finite element solver. Basically, I would like to use Julia to read in the base input file, edit some parameters on some lines of the file and then write it as a new file. I am getting hung up on a couple things though.
Currently, I am reading in the file like this
mdl = "fullmodelSVTV"; #name of input file
A = readlines(mdl*".inp")
This read each line from the file in as a separate string in a vector which I like because it makes it easier to edit the sections I want but it also makes things more difficult when I try to write to a new file.
I am writing the file like this.
io = open("name.inp","w")
print(io,A)
close(io)
When I try to write to a new file the output ends up look like this
Output from code
which is ["string at index 1","string at index 2","string at index 3"...].
What I would like to do is output this the exact same way is it is read in with string at each index of the vector on its own line. I would also like to remove the brackets and quotation marks from the file, as they might interfere with the finite element solver.
I think I have found a way to concatenate all of the strings at each index and separated them with a new line like shown below.
for i in 1:length(A)
conc = conc*"\n"*lines[i]
end
The issue with this is that it takes a long time to do given the size of the input files I am working with and I feel like there has to achieve my goal.
I also cannot find a way to remove the brackets or quotation marks when writing the file.
So, I'm wondering if anyone has any advice for a better way to write these text files in terms of both concatenating all of the strings from the vector when outputting as well as outputting without the brackets and quotation marks.
Thanks, any advice is appreciated.
The issue with print(io,A) is that it is printing a representation of the vector, but in fact you want to print each element of the vector. To do so, you can simply print each line in a loop:
open("name.inp", "w") do io
for line in A
println(io, line)
end
end
This avoids the overhead of string concatenation.
if you can help with converting a big text:
sample of the text :
X1"II"ID_Sitze.x"II"Produktionsdatum.x"II"Herstellernummer.x"II"Werksnummer.x"II"Fehlerhaft.x"II"Fehlerhaft_Datum.x"II"Fehlerhaft_Fahrleistung.x"II"ID_Sitze.y"II"Produktionsdatum.y"II"Herstellernummer.y"II"Werksnummer.y"II"Fehlerhaft.y"II"Fehlerhaft_Datum.y"II"Fehlerhaft_Fahrleistung.y""1"II1II"K2LE1-109-1091-2"II2008-11-12II"109"II1091II1II2010-10-18II37080IINAIINAIINAIINAIINAIINAIINA"2"II2II"K2LE1-109-1091-1"II2008-11-12II"109"II1091II0IINAII0IINAIINAIINAIINAIINAIINAIINA"3"II3II"K2LE1-109-1091-12"II2008-11-13II"109"II1091II0IINAII0IINAIINAIINAIINAIINAIINAIINA"4"II4II"K2LE1-109-1091-5"II2008-11-13II"109"II1091II0IINAII0IINAIINAIINAIINAIINAIINAIINA"5"II5II"K2LE1-109-1091-40"II2008-11-13II"109"II1091II0IINAII0IINAIINAIINAIINAIINAIINAIINA"6"II6II"K2LE1-109-1091-15"II2008-11-13II"109"II1091II0IINAII0IINAIINAIINAIINAIINAIINAIINA"7"II7II"K2LE1-109-1091-31"II2008-11-13II"109"II1091II0IINAII0IINAIINAIINAIINAIINAIINAIINA"8"II8II"K2LE1-109-1091-6"II2008-11-13II"109"II1091II0IINAII0IINAIINAIINAIINAIINAIINAIINA"9"II9II"K2LE1-109-1091-8"II2008-11-13II"109"II1091II0IINAII0IINAIINAIINAIINAIINAIINAIINA"10"II10II"K2LE1-109-1091-25"II2008-11-13II"109"II1091II0IINAII0IINAIINAIINAIINAIINAIINAIINA"11"II11II"K2LE1-109-1091-24"II2008-11-13II"109"II1091II0IINAII0IINAIINAIINAIINAIINAIINAIINA"12"II12II"K2LE1-109-1091-36"II2008-11-13II"109"II1091II0IINAII0IINAIINAIINAIINAIINAIINAIINA"13"II13II"K2LE1-109-1091-33"II2008-11-13II"109"II1091II0IINAII0IINAIINAIINAIINAIINAIINAIINA"14"II14II"K2LE1-109-1091-42"II2008-11-13II"109"II1091II0IINAII0IINAIINAIINAIINAIINAIINAIINA"15"II15II"K2LE1-109-1091-14"II2008-11-13II"109"II1091II0IINAII0IINAIINAIINAIINAIINAIINAIINA"16"II16II"K2LE1-109-1091-21"II2008-11-13II"109"II1091II0IINAII0IINAIINAIINAIINAIINAIINAIINA"17"II17II"K2LE1-109-1091-43"II2008-11-13II"109"II1091II0IINAII0IINAIINAIINAIINAIINAIINAIINA"18"II18II"K2LE1-109-1091-44"II2008-11-13II"109"II1091II0IINAII0IINAIINAIINAIINAIINAIINAIINA"19"II19II"K2LE1-109-1091-19"II2008-11-13II"109"II1091II1II2010-10-19II37
with separator "II" to a Dataframe.
i have used :
df_BSt7<-readLines("Komponente_K2LE1.txt")
df_BST7<-str_replace_all(df_BSt7,"II",",")
df_BST7<-read.table(df_BST7,sep = ",")
head(df_BST7)
but I am always getting an Error
could not allocate memory (206 Mb) in C function 'R_AllocStringBuffer'
and when i call head() I am getting
'"X1","ID_Sitze.x","Produktionsdatum.x","Herstellernummer.x","Werksnummer.x","Fehlerhaft.x","Fehlerhaft_Datum.x","Fehlerhaft_Fahrleistung.x","ID_Sitze.y","Produktionsdatum.y","Herstellernummer.y","Werksnummer.y","Fehlerhaft.y","Fehlerhaft_Datum.y","Fehlerhaft_Fahrleistung.y""1",1,"K2LE1-109-1091-2",2008-11-12,"109",1091,1,2010-10-18,37080,NA,NA,NA,NA,NA,NA,NA"2",2,"K2LE1-109-1091-1",2008-11-12,"109",1091,0,NA,0,NA,NA,NA,NA,NA,NA,NA"3",3,"K2LE1-109-1091-12",2008-11-13,"109",1091,0,NA,0,NA,NA,NA,NA,NA,NA,NA"4",4,"K2LE1-109-1091-5",2008-11-13,"109",1091,0,NA,0,NA,NA,NA,NA,NA,NA,NA"5",5,"K2LE1-109-1091-40",2008-11-13,"109",1091,0,NA,0,NA,NA,NA,NA,NA,NA,NA"6",6,"K2LE1-109-1091-15",2008-11-13,"109",1091,0,NA,0,NA,NA,NA,NA,NA,NA,NA"7",7,"K2LE1-109-1091-31",2008-11-13,"109",1091,0,NA,0,NA,NA,NA,NA,NA,NA,NA"8",8,"K2LE1-109-1091-6",2008-11-13,"109",1091,0,NA,0,NA,NA,NA,NA,NA,NA,NA"9",9,"K2LE1-109-1091-8",2008-11-13,"109",1091,0,NA,0,NA,NA,NA,NA,NA,NA,NA"10",10,"K2LE1-109-109 [... abgeschnitten]
So, there are several possible problems, some might be specific to your examples.
Clean example data
First, let's take a look at your example data. In what you provide, there are no newlines, everything is on a single line. Is that the case in the original "Komponente_K2LE1.txt" file? If yes, we might need some more work to find where to add newlines (see below).
The first column name, X1, only has a quote on the right. It can't work without the quote on the left: "X1"IIID_Sitze.
The saved dataframe has 16 columns, I expect because there is a row number at the beginning of each row which is not in the header. So we can add an additional column header to have 16 of them:
"row_nb"II"X1"II"ID_Sitze.x"II"Produktionsdatum.x"II"Herstellernummer.x"II"Werksnummer.x"II"Fehlerhaft.x"II"Fehlerhaft_Datum.x"II"
Then we have a small problem with line 19 which is truncated, I assume it comes from your copy/paste and that's not a problem with the full file. So let's forget about it for now. So I have this text:
raw_lines <- '"row_nb"II"X1"II"ID_Sitze.x"II"Produktionsdatum.x"II"Herstellernummer.x"II"Werksnummer.x"II"Fehlerhaft.x"II"Fehlerhaft_Datum.x"II"Fehlerhaft_Fahrleistung.x"II"ID_Sitze.y"II"Produktionsdatum.y"II"Herstellernummer.y"II"Werksnummer.y"II"Fehlerhaft.y"II"Fehlerhaft_Datum.y"II"Fehlerhaft_Fahrleistung.y"
"1"II1II"K2LE1-109-1091-2"II2008-11-12II"109"II1091II1II2010-10-18II37080IINAIINAIINAIINAIINAIINAIINA
"2"II2II"K2LE1-109-1091-1"II2008-11-12II"109"II1091II0IINAII0IINAIINAIINAIINAIINAIINAIINA
"3"II3II"K2LE1-109-1091-12"II2008-11-13II"109"II1091II0IINAII0IINAIINAIINAIINAIINAIINAIINA
"4"II4II"K2LE1-109-1091-5"II2008-11-13II"109"II1091II0IINAII0IINAIINAIINAIINAIINAIINAIINA
"5"II5II"K2LE1-109-1091-40"II2008-11-13II"109"II1091II0IINAII0IINAIINAIINAIINAIINAIINAIINA
"6"II6II"K2LE1-109-1091-15"II2008-11-13II"109"II1091II0IINAII0IINAIINAIINAIINAIINAIINAIINA
"7"II7II"K2LE1-109-1091-31"II2008-11-13II"109"II1091II0IINAII0IINAIINAIINAIINAIINAIINAIINA
"8"II8II"K2LE1-109-1091-6"II2008-11-13II"109"II1091II0IINAII0IINAIINAIINAIINAIINAIINAIINA
"9"II9II"K2LE1-109-1091-8"II2008-11-13II"109"II1091II0IINAII0IINAIINAIINAIINAIINAIINAIINA
"10"II10II"K2LE1-109-1091-25"II2008-11-13II"109"II1091II0IINAII0IINAIINAIINAIINAIINAIINAIINA
"11"II11II"K2LE1-109-1091-24"II2008-11-13II"109"II1091II0IINAII0IINAIINAIINAIINAIINAIINAIINA
"12"II12II"K2LE1-109-1091-36"II2008-11-13II"109"II1091II0IINAII0IINAIINAIINAIINAIINAIINAIINA
"13"II13II"K2LE1-109-1091-33"II2008-11-13II"109"II1091II0IINAII0IINAIINAIINAIINAIINAIINAIINA
"14"II14II"K2LE1-109-1091-42"II2008-11-13II"109"II1091II0IINAII0IINAIINAIINAIINAIINAIINAIINA
"15"II15II"K2LE1-109-1091-14"II2008-11-13II"109"II1091II0IINAII0IINAIINAIINAIINAIINAIINAIINA
"16"II16II"K2LE1-109-1091-21"II2008-11-13II"109"II1091II0IINAII0IINAIINAIINAIINAIINAIINAIINA
"17"II17II"K2LE1-109-1091-43"II2008-11-13II"109"II1091II0IINAII0IINAIINAIINAIINAIINAIINAIINA
"18"II18II"K2LE1-109-1091-44"II2008-11-13II"109"II1091II0IINAII0IINAIINAIINAIINAIINAIINAIINA'
Now you are replacing "II" with "," and reading it with read.table(), which is perfectly correct, except that read.table() would assume you're giving a file name and throw an error as it can't open that connection (that file). To make it work you need this:
df_BST7<-str_replace_all(raw_lines,'II',",")
df_BST7 <- read.table(text = df_BST7,sep = ",")
So now that does run on my computer.
Side note, since you're already using the tidyverse, you could as well use that equivalent code instead:
df_BST7 <- str_replace_all(raw_lines,'II',",")
df_BST7 <- read_csv(df_BST7)
which could help with something later
The error message
Now the error message you get suggests it's a memory problem. I see 2 possibilities: the table is so big it can't fit in your computer's memory, or indeed your whole input table is on a single line, so that makes a very long line, which won't fit in memory.
Whole table too big
I don't think it's the problem here, but just in case, check how big the file on the disk is, and how much memory is free on your computer, and whether you could free up enough memory by just closing a few programs. Possibly you could save your modified text to disk and delete it from R's memory with rm(df_BSt7), then load it directly from disk into df_BST7. Since the raw text fits in memory, that should work. If memory is a challenge, you can replace read_csv() with read_csv_chunked() and process one chunk at a time.
All on one line
I think this is the most likely. Again, there are two possibilities.
Missing carriage return
Actually line breaks can be described in 2 ways, Unix-like systems (MacOS and GNU/Linux) use the symbol newline (\n), whereas Windows uses a pair of carriage return and newline (\r\n). I'm not sure how this could create problems inside R, but if your file was generated on a Unix-like system and you're trying to read it on Windows that's an explanation. Then the goal would become to replace \n with \r\n.
No line breaks at all
If there is absolutely no line break, neither \r nor \n, then we need to guess where they are. On a Unix system you could try awk or sed, but there are ways to do it in R. The following code should work, except the last column will need some cleaning up afterwards:
raw_lines2 <- str_remove_all(raw_lines2, "\r")
all_fields <- raw_lines2 %>%
str_split("II") %>%
unlist()
nb_lines <- (length(all_fields) - 1)/15
reconstruct_lines <- map_chr(0:(nb_lines-1), ~ paste(all_fields[(2+15*.):(16+15*.)], collapse = ",")) %>%
paste(collapse = "\n")
cat(reconstruct_lines)
I work with knitr() and I wish to transform inline Latex commands like "\label" and "\ref", depending on the output target (Latex or HTML).
In order to do that, I need to (programmatically) generate valid R strings that correctly represent the backslash: for example "\label" should become "\\label". The goal would be to replace all backslashes in a text fragment with double-backslashes.
but it seems that I cannot even read these strings, let alone process them: if I define:
okstr <- function(str) "do something"
then when I call
okstr("\label")
I directly get an error "unrecognized escape sequence"
(of course, as \l is faultly)
So my question is : does anybody know a way to read strings (in R), without using the escaping mechanism ?
Yes, I know I could do it manually, but that's the point: I need to do it programmatically.
There are many questions that are close to this one, and I have spent some time browsing, but I have found none that yields a workable solution for this.
Best regards.
Inside R code, you need to adhere to R’s syntactic conventions. And since \ in strings is used as an escape character, it needs to form a valid escape sequence (and \l isn’t a valid escape sequence in R).
There is simply no way around this.
But if you are reading the string from elsewhere, e.g. using readLines, scan or any of the other file reading functions, you are already getting the correct string, and no handling is necessary.
Alternatively, if you absolutely want to write LaTeX-like commands in literal strings inside R, just use a different character for \; for instance, +. Just make sure that your function correctly handles it everywhere, and that you keep a way of getting a literal + back. Here’s a suggestion:
okstr("+label{1 ++ 2}")
The implementation of okstr then needs to replace single + by \, and double ++ by + (making the above result in \label{1 + 2}). But consider in which order this needs to happen, and how you’d like to treat more complex cases; for instance, what should the following yield: okstr("1 +++label")?
I have a csv, and each line reads as follows:
"http://www.videourl.com/video,video title,video duration,thumbnail,<iframe src=""http://embed.videourl.com/video"" frameborder=0 width=510 height=400 scrolling=no> </iframe>,tag 1,tag 2",,,,,,,,,,,,,,,,,,,,,,,,,,
Is there a program I can use to clean this up? I'm trying to import it to wordpress and map it to current fields, but it isn't functioning properly. Any suggestions?
Just use search and replace in this case. remove the commas at the end and then replace the remaining commas with ",".
Should anyone else have the same issue. Know that this solution will only work with data much like the example giving. If data has a lot of text and there are commas within the text that need kept. Then search replacing comma will not work. Using regex would be the next option and that can be done in Notepad ++
However I think the regex pattern depends on the data so not much point creating an example.
PHP could be used to explode each line also. Remove values that match a regex out of many i.e. URL, money. Then what is left could be (depending on the data again) just a block of text. That approach may not work if there are two or more columns with a lot of text
The text to be checked is in Greek, but I would like to know if it can be done for English words too. My initial idea is described here, and I have already found a way to do it using VBA. But I wonder if there's a way to do it using R. If there isn't a way in R, do you think of something better than Excel-vba?
Alternatively, OpenOffice ships with a dictionary that entries stored in a text file. You can read that and remove the word definitions to create your word list.
This was tested on v3.0; the file location may have shifted, and the filename will change depending on which dictionary you want.
library(stringr)
dict <- readLines("C:/Program Files/OpenOffice.org 3/share/uno_packages/cache/uno_packages/174.tmp_/dict-en.oxt/th_en_US_v2.dat")
is_word <- str_detect(dict, "^[^(]")
words <- str_split_fixed(dict[is_word], "\\|", 2)
words <- words[,1]
This list contains some multi-word phrases. You may prefer to split on the first space, and take unique values. You probably also want to write words to file, to save repeating yourself.
Once this is done, checking a word is as easy as
c("persnickety", "sqwrzib") %in% words # TRUE FALSE
There exists an open source GNU spell checker called Aspell with suppot for various languages. This is a command line program which I basically use for scanning bunches of text files at once (then the output is just given to the console).
But there also exists a C API and perhaps more interesting for you a Pipe mode which accepts streams of texts and outputs to the standard output.
Hope this helps.