I'm using the ASP.NET RegularExpressionValidator
I need a regular expression to keep users who fill out a form from using all caps.
For example, if they write their name:
Bob JONES or BOB JONES or BOB JOnes or whatever, it will not match.
I am able to match all caps with this regular expression:
[A-Z]{2,10}
But the RegularExpressionValidator requires me to match valid text, not invalid text.
If your goal is to have each word have no more than 1 capital letter in a row at a time, and assuming it's okay to restrict to ASCII letters, try something like this:
^(?:[a-z]|[A-Z](?![A-Z])|['-])+$
In other words, the string must be entirely composed of either lowercase letters, or uppercase letters not followed by another uppercase letter.
This works for single words. For multiple words (like a full name, first and last), simply add a space to the alternation:
^(?:[a-z]|[A-Z](?![A-Z])|[\s'-])+$
(Edited to allow apostrophe and hyphen punctuation)
use this Regex: #"^[^A-Z]*$" It will match anything that not contains upper case characters.
use this regular expression ^[a-z ]+$
if you want catch names like Bob Jones use this one ^([A-Z][a-z ]+)+$
Maybe i'm just stating the obvious, but couldn't you just to myVar.string.toLower before doing the Compare?
Related
I have a document, and I need to find all the words(no spaces) borded with '. (e.g. 'apple', 'hello') What would be the regular expression?
I've tried ^''$ but it didn't work.
If there isn't any solution, it could not be "any word" but also it can be a word from an order(e.g. apple, banana, lemon) but it still must have the (')s.
Thank you so much
Andrew
If you want to capture single-quoted strings, literally any character run except single-quotes but between the single-quotes, use
/'[^']+'/
If you need single words, i.e. alphabetic characters but no spaces, try
/'[a-zA-Z]+'/
I'm asssuming a couple things here:
You're using a language that delimits regexes with slashes. This includes Javascript and Perl to my knowledge, and probably a bunch of others. In some other languages, like C#, you should use double quotes to delimit, e.g. "'[a-zA-Z]+'"
You're using a flavor of regex that does not need to escape the plus sign.
You're trying to capture all such words within a long string. I.e., if the input string is "Here is a 'long' string with 'some' 'words' single-quoted" then you will capture three words: 'long','some', and 'words'.
Right now I need to duplicate a password expression validator for a website. The password is only required to be 8-25 characters (only alphabet characters) long. I thought this was weird and had been using this regex
(?!^[0-9]*$)(?!^[a-zA-Z]*$)^([a-zA-Z0-9]{8,25})
but it has to be optional to have a capital letter, special characters and/or numbers throughout the password. I'm not particularly apt at building regex's where there are optional characters. Any help would be be appreciated.
I am using asp.net's RegularExpressionValidator.
This pattern should work:
^[a-zA-Z]{8,25}$
It matches a string consisting of 8 to 25 Latin letters.
If you want to allow numbers as well, this pattern should work:
^[a-zA-Z0-9]{8,25}$
It matches a string consisting of 8 to 25 Latin letters or decimal digits.
If you want to allow special characters as well, this pattern should work:
^[a-zA-Z0-9$#!]{8,25}$
It matches a string consisting of 8 to 25 Latin letters, decimal digits, or symbols, $, # or ! (of course you can add to this set fairly easily).
Your current regex won't work because it will accept special characters as from 9th character (and anything after the 9th character in fact, even a 26th character because you don't have the end of string anchor) .
You probably want something like this:
^(?=.*[a-z])[A-Za-z0-9]{8,25}$
This first makes sure there are lowercase alphabets (you mentioned that uppercase and digits are optional, so this makes obligatory lowercase) and then allows only uppercase and digits.
EDIT: To allow any special characters, you can use this:
^(?=.*[a-z]).{8,25}$
My understanding of your problem is that the password's first requirement is that it has to contain lowercase alphabet characters. The option now is that it can also contain other characters. If this isn't right, let me know.
regex101 demo
I've a textbox in an ASP.NET application, for which I need to use a regular expression to validate the user input string. Requirements for regex are -
It should allow only one space between words. That is, total number of spaces between words or characters should only be one.
It should ignore leading and trailing spaces.
Matches:
Test
Test abc
Non Matches:
Test abc def
Test abc --> I wanted to include multiple spaces between the 2 words. However the editor ignores these extra spaces while posting a question.
Assuming there must be either one or two 'words' (i.e. sequences of non-space characters)
"\s*\S+(\s\S+)?\s*"
Change \S to [A-Za-z] if you want to allow only letters.
Pretty straightforward:
/^ *(\w+ ?)+ *$/
Fiddle: http://refiddle.com/gls
Maybe this one will do?
\s*\S+?\s?\S*\s*
Edit: Its a server-encoded regex, meaning that you might need to remove one of those escaping slashes.
How about:
^\s*(\w+\s)*\w+\s*$
I am trying to use a regular expression for name field in the asp.net application.
Conditions:name should be minimum 6 characters ?
I tried the following
"^(?=.*\d).{6}$"
I m completely new to the regex.Can any one suggest me what must be the regex for such condition ?
You could use this to match any alphanumeric character in length of 6 or more: ^[a-zA-Z0-9]{6,}$. You can tweak it to allow other characters or go the other route and just put in exclusions. The Regex Coach is a great environment for testing/playing with regular expressions (I wrote a blog post with some links to other tools too).
Look at Expression library and choose user name and/or password regex for you. You can also test your regex in online regex testers like RegexPlanet.
My regex suggestions are:
^[a-zA-Z][a-zA-Z0-9._\-]{5,}$
This regex accepts user names with minimum 6 characters, starting with a letter and containing only letters, numbers and ".","-","_" characters.
Next one:
^[a-zA-Z0-9._\\-]{6,}$
Similar to above, but accepts ".", "-", "_" and 0-9 to be first characters too.
If you want to validate only string length (minimum 6 characters), this simple regex below will be enough:
^.{6,}$
What about
^.{6,}$
What's all the stuff at the start of yours, and did you want to limit yourself to digits?
NRegex is a nice site for testing out regexes.
To just match 6 characters, ".{6}" is enough
In its simplest form, you can use the following:
.{6,}
This will match on 6 or more characters and fail on anything less. This will accept ANY character - unicode, ascii, whatever you are running through. If you have more requirements (i.e. only the latin alphabet, must contain a number, etc), the regex would obviously have to change.
What is the difference between below two regular expressions
(.|[\r\n]){1,1500}
^.{1,1500}$
The first matches up-to-1500 chars, and the second (assuming you haven't set certain regex options) matches a first single line of up-to-1500 chars, with no newlines.
. does not match new lines.
The second one matches the first 1500 characteres of a line IF the line contains 1500 characters or less
First expression matches some <= 1500 characters of the file(or other source).
Second expression matches a entire line with charsNumber <= 1500.
. matches any character except \n newline.
If it's for use in a RegularExpressionValidator, you probably want to use this regex:
^[\s\S]{1,1500}$
This is because the regex may be run on either the server (.NET) or the client (JavaScript). In .NET regexes you can use the RegexOptions.Singleline flag (or its inline equivalent, (?s)) to make the dot match newlines, but JavaScript has no such mechanism.
[\s\S] matches any whitespace character or anything that's not a whitespace character--in other words, anything. It's the most popular idiom for matching anything including a newline in JavaScript; it's much, much more efficient than alternation-based approaches like (.|\n).
Note that you'll still need to use a RequiredFieldValidator if you don't want the user to leave the textbox empty.