I'm using wp_link_pages() to split my post into multiple pages. I want to achieve something like this as shown in the image below. Instead of showing all the page numbers with links, I want it to show only this format (Current Page of Total Page). Please help me with the exact codes. Thank you so much in advance.
PS: I don't want to use plugins.
There is a simple solution to this problem. I've got this inspiration from source file where function wp_link_pages is defined.
function page_pagination( $echo = 1 )
{
global $page, $numpages, $multipage, $more;
if( $multipage ) { //probably you should add && $more to this condition.
$next_text = "next";
$prev_text = "prev";
if( $page < $numpages ) {
$next = _wp_link_page( $i = $page + 1 );
$next_link = $next . $next_text . "</a>";
}
if( $i = ( $page - 1 ) ) {
$prev = _wp_link_page( $i );
$prev_link = $prev . $prev_text . "</a>";
}
$output =
"<div class=\"prev-next-page\">"
. $prev_link
. "<span class=\"page-counter\">{$page} of {$numpages}</span>"
. $next_link
. "</div>";
}
if( $echo ){
echo $output;
}
return $output;
}
If you need more freedom you can always adapt this function to suit your purposes. Include function into wordpress loop! Like this for example:
if ( have_posts( ) ) {
while ( have_posts( ) ) {
the_post( );
//rest of code
the_content();
page_pagination();
}
}
As you can see, there is "private" function _wp_link_page used to solve your problem. I don't like using "private" functions, but it solves our problem.
Related
I am trying to display a line of text if a specific category (in this case: advisories) is empty, but the code I am trying to use does not display anything.
<?php
if ( in_category( 'advisories' )->count > 0 ) {
echo test;
}
?>
Try this one,
Solution
$custom_terms = get_terms();
foreach ($custom_terms as $term) {
if ($term->count != 0 && $term->name == "Uncategorized") {
echo $term->name . " - blank" . '<br>';
}
}
Screenshot
Hope this will helps you.
For more example, please visit
get_terms Wordpress
WordPress to test for an empty term or category
You can try this one
$category = get_category($id);
$count = $category->category_count;
if( $count > $something ) {
// stuff
}
Here is the code for place ads after 1st, 2nd, 3d paragraph. but i want to place ad just before last paragraph of my wordpress post. is there any way to do this ?
<?php
add_filter( 'the_content', 'prefix_insert_post_ads' );
function prefix_insert_post_ads( $content ) {
$ad_code = '<div>Ads code goes here</div>';
if ( is_single() && ! is_admin() ) {
return prefix_insert_after_paragraph( $ad_code, 1, $content );
}
return $content;
}
// Parent Function that makes the magic happen
function prefix_insert_after_paragraph( $insertion, $paragraph_id, $content ) {
$closing_p = '</p>';
$paragraphs = explode( $closing_p, $content );
foreach ($paragraphs as $index => $paragraph) {
if ( trim( $paragraph ) ) {
$paragraphs[$index] .= $closing_p;
}
if ( $paragraph_id == $index + 1 ) {
$paragraphs[$index] .= $insertion;
}
}
return implode( '', $paragraphs );
}
?>
add_filter('the_content', 'ad_signal');
function ad_signal($content)
{
if (!is_single()) return $content;
$tent = get_the_content();
$content = explode("</p>", $content);
$ss = count($content);
$ns = $ss-1; //**before last paragraph in wordpress **
$new_content = '';
for ($i = 0; $i < count($content); $i++) {
if ($i == $ns ) {
$new_content.= ' <div style="text-align:center;">';
$new_content.= '<h1> Your ads Here ! </h1>';
$new_content.= '</div>';
}
$new_content.= $content[$i] . "</p>";
}
return $new_content;
}
I have set Adsense code by this Code in my sites named All BD Results and etunescafe. You just add this code in your sites functions.php N.B. Before adding the code please replace your or add your adsense code. It will be good enough to go through this post. How to Set Adsense Ads Right Before The Last Paragraph
function ads_added_above_last_p($text) {
if( is_single() ) :
$ads_text = '<div class="a" style="text-align: center;">Your Adsense Code</div>';
if($pos1 = strrpos($text, '<p>')){
$text1 = substr($text, 0, $pos1);
$text2 = substr($text, $pos1);
$text = $text1 . $ads_text . $text2;
}
endif;
return $text;
}
add_filter('the_content', 'ads_added_above_last_p');
Hey guys so I ran into the same problem and managed to solve it incorporating your answers into one.
The function that does all the processing is changed so that is counts all the paragraphs created by the explode method. Then another if statement is added to evaluate when you are at the desired location.
function prefix_insert_after_paragraph( $insertion, $paragraph_id, $content ) {
$closing_p = '</p>';
$paragraphs = explode( $closing_p, $content );
$last_paragraph_index = count($paragraphs);
foreach ($paragraphs as $index => $paragraph) {
if ( trim( $paragraph ) ) {
$paragraphs[$index] .= $closing_p;
}
if ( $paragraph_id == $index + 1 ) {
$paragraphs[$index] .= $insertion;
}
else if( $last_paragraph_index + $paragraph_id == $index + 1){
$paragraphs[$index] .= $insertion;
}
}
return implode( '', $paragraphs );
}
in order to use the new functionality you must call it with a negative number.
Think of the function this way, if you want to go from the top of the content you use a positive number, if you want to go from the bottom of the content you use a negative number.
Remember that even though the evaluation is for your decided spot such as before the last paragraph the condition that adds to the array uses the index which we all know is zero based.
This just means that to get after paragraph 1 you must use the number 2 when calling the function and to get to before the last paragraph you have to use -2 and so on.
Here is my example to add the a read the next post if it exists to the article
add_filter( 'the_content', 'prefix_insert_next_article_banner' );
function prefix_insert_next_article_banner( $content ) {
if ( is_single() && ! is_admin() && get_next_post_link() ) {
$next_banner = '<div class="next-banner"> <span> Read Next </span>';
$next_banner .= ' ' . get_the_title(get_adjacent_post(false,'',false)) .' ';
$next_banner .= '</div>';
return prefix_insert_after_paragraph( $next_banner, -2, $content );
}
return $content;
}
Entirely Revised Please Reread
Hello,
The theme I am using displays the page's title as opposed to it's menu label in the breadcrumbs. I am trying to get the breadcrumbs to instead display the associated menu label if it is available and if not then default to the page_title.
I have come up with some code that I think is close. Line 4/// $menu_items = wp_get_nav_menu_items( $slug ); returns null and it should return the nav item that contains $slug of the current post. Obviously, there is something I do not understand.
What I am attempting to do is get the slug of the current post, then using the slug get the nav item post. Then extract the title of the nav item and use that in place of the page title in the breadcrumbs. If the page was not in the nav system then it should default to the page title, as might be the case for a ppc campaign landing page.
if ( is_page() && !$post->post_parent ) {
$title = null;
$slug = mpactMEDIA_get_the_slug( get_the_ID() );
$menu_items = wp_get_nav_menu_items( $slug );
//var_dump((array)$menu_items);
foreach ( (array)$menu_items as $key => $menu_item ) {
$title = $menu_item->post_title;
}
if ( $title ) { echo $delimiter . ' ' . $before . $title . $after; }
else { echo $delimiter . ' ' . $before . get_the_title() . $after; }
}
I'm my functions.php file I have the following function
function mpactMEDIA_get_the_slug( $id=null ){
if( empty($id) ) global $post;
if( empty($post) ) return '';
$id = $post->ID;
endif;
$slug = basename( get_permalink($id) );
return $slug;
}
Thank you in advance,
Tim
I read the question a few times, I got here searching for an answer, ended up making my own.
function get_menu_label_by_post_id($post_id, $menu) {
$menu_title = '';
$nav = wp_get_nav_menu_items($menu);
foreach ( $nav as $item ) {
if ( $post_id == $item->object_id ) {
$menu_title = $item->post_title;
break;
}
}
return ($menu_title !== '') ? $menu_title : get_the_title($post_id);
}
Example usage:
echo get_menu_label_by_post_id($post->ID, 'Primary Nav');
This will return what the menu label is if it finds it, otherwise just the title of the post ID.
Check the documentation for wp_get_nav_menu_items. It doesn't take a page slug as a parameter at all.
If you want to list child pages of a given page, use wp_list_pages and pass a child_of parameter to it.
Also, as a side note, if you know the $post and want the slug, it's just $post->post_name
Hello i have a website and a blog, i want to display my self hosted wordpress blog on my website.
I want to show only 3 post on my website.
I want to automatically check for any new post everytime when i reload my website, so that the recent three gets displayed only.
I want to show the complete title of my wordpress blogpost but specific letters of description.
Also the description should end up with a word not some piece of non-dictionary word ending with "..."
How this can be done, i have heard that it can be done through RSS.
Can somebody help me?
To accomplish this you need to read the RSS of the blog, from RSS you need to read the Title and the description, after reading the whole description and title you need to trim the description to your desired number of letters. After that you need to check weather the description last word has been completed or not and then you need to remove a the last word if not completed and put the "...".
First we will make a script to trim the description and to put "..." in last:-
<?php
global $text, $maxchar, $end;
function substrwords($text, $maxchar, $end='...') {
if (strlen($text) > $maxchar || $text == '') {
$words = preg_split('/\s/', $text);
$output = '';
$i = 0;
while (1) {
$length = strlen($output)+strlen($words[$i]);
if ($length > $maxchar) {
break;
}
else {
$output .= " " . $words[$i];
++$i;
}
}
$output .= $end;
}
else {
$output = $text;
}
return $output;
}
Now we will define the variables in which we store the values:-
$xml=("http://your-blog-path/rss/");
global $item_title, $item_link, $item_description;
$xmlDoc = new DOMDocument();
$xmlDoc->load($xml);
$x=$xmlDoc->getElementsByTagName('item');
Now, we will make an array and store values in it. I am only taking 3 because you have asked it the way. You can change it to anything (The number of post you want to show, put that in the loop)
for ($i=0; $i<3; $i++)
{
$item_title[$i] = $x->item($i)->getElementsByTagName('title')->item(0)->childNodes->item(0)->nodeValue;
$item_link[$i] = $x->item($i)->getElementsByTagName('link')->item(0)->childNodes->item(0)->nodeValue;
$item_description[$i] = $x->item($i)->getElementsByTagName('description')->item(0)->childNodes->item(0)->nodeValue;
}
?>
Now echo all these values, Link is the value where your user will click and he will be taken to your blog:-
FIRST RECENT POST:
<?php echo $item_title[0]; ?>
<?php echo substrwords($item_description[0],70); ?>
SECOND RECENT POST:
<?php echo $item_title[1]; ?>
<?php echo substrwords($item_description[1],70); ?>
THIRD RECENT POST:
<?php echo $item_title[2]; ?>
<?php echo substrwords($item_description[2],70); ?>
Hope this can solve your problem. By the way Nice question.
Click here for the original documentation on displaying RSS feeds with PHP.
Django Anonymous's substrwords function is being used to trim the description and to insert the ... at the end of the description if the it passes the $maxchar value.
Full Code:
blog.php
<?php
global $text, $maxchar, $end;
function substrwords($text, $maxchar, $end='...') {
if (strlen($text) > $maxchar || $text == '') {
$words = preg_split('/\s/', $text);
$output = '';
$i = 0;
while (1) {
$length = strlen($output)+strlen($words[$i]);
if ($length > $maxchar) {
break;
} else {
$output .= " " . $words[$i];
++$i;
}
}
$output .= $end;
} else {
$output = $text;
}
return $output;
}
$rss = new DOMDocument();
$rss->load('http://wordpress.org/news/feed/'); // <-- Change feed to your site
$feed = array();
foreach ($rss->getElementsByTagName('item') as $node) {
$item = array (
'title' => $node->getElementsByTagName('title')->item(0)->nodeValue,
'desc' => $node->getElementsByTagName('description')->item(0)->nodeValue,
'link' => $node->getElementsByTagName('link')->item(0)->nodeValue,
'date' => $node->getElementsByTagName('pubDate')->item(0)->nodeValue,
);
array_push($feed, $item);
}
$limit = 3; // <-- Change the number of posts shown
for ($x=0; $x<$limit; $x++) {
$title = str_replace(' & ', ' & ', $feed[$x]['title']);
$link = $feed[$x]['link'];
$description = $feed[$x]['desc'];
$description = substrwords($description, 100);
$date = date('l F d, Y', strtotime($feed[$x]['date']));
echo '<p><strong>'.$title.'</strong><br />';
echo '<small><em>Posted on '.$date.'</em></small></p>';
echo '<p>'.$description.'</p>';
}
?>
You can easily put this in a separate PHP file (blog.php) and call it inside your actual page.
Example:
social.php
<h3>Latest blog post:</h3>
<?php require 'blog.php' ?>
Also, this code is plug-n-play friendly.
Why not use the Wordpress REST API to retrieve posts -
API URL is : https://public-api.wordpress.com/rest/v1/sites/$site/posts/
where $site is the site id of your wordpress blog
or else simply use this plugin -
http://www.codehandling.com/2013/07/wordpress-feeds-on-your-website-with.html
Let me tell you the scenario first say the structure of the categories in wordpress is like this
Level 1: Top
Level 2: -Nextme_1
Level 3: --Nextme_2
--Nextme_3
Level 4: ---Nextme_4
---Nextme_5
Now I require to check what is the level of the category? Say I catch a category of level 3 so I have to use different template and if its level 4. Then I need to use another template?
Anybody can give me some hint?
Thanks
Rahul
If you don't have many categories you can try to edit their slug from admin, and then in your page you get the category slug this way:
if (is_category()) {
$cat = get_query_var('cat');
$category = get_category($cat);
echo 'your slug is '. $category->slug;
}
Now, when you're editing the categories slugs try naming them after their level: cat-lvl-1, cat-lvl-2. Then in your page you extract the number from category slug using some php string function, and then you check that number:
if ($category->slug == 1 ) {
//load the template for the category of level 1
}
if ($category->slug == 2 ) {
//load the template for the category of level 2
}
and so on.
Later edit:
Try this:
function get_level($category, $level = 0)
{
if ($category->category_parent == 0) {
return $level;
} else {
$level++;
$category = get_category($category->category_parent);
get_level($category, $level);
}
}
if (is_category()) {
$cat = get_query_var('cat');
$yourcat = get_category($cat);
echo get_level($yourcat);
}
You can call the get_ancestors() function to get an array containing the parents of the given object. Then you need to count elements in the result.
function get_the_level($id, $type = 'category') {
return count( get_ancestors($id, $type) );
}
if( is_category() ) {
$level = get_the_level( $cat );
}
elseif( is_product_category() ) {
$level = get_the_level( $wp_query->get_queried_object()->term_id, 'product_cat' );
}
Thanks a lot. This is superb with slight a change the code that you have written is fine but its not returning any value.(i,e the $level) although its calculating correct. A minor change i did and its work fine now with a slight editing of you code given below..
`
function get_level($category, $level = 0)
{
if ($category->category_parent == 0) {
return $level;
} else {
$level++;
$category = get_category($category->category_parent);
return get_level($category, $level);
}
}
if (is_category()) {
$cat = get_query_var('cat');
$yourcat = get_category($cat);
echo get_level($yourcat);
}
`
Thanks #zuzuleinen
I visited this page months back. I came back today, arrow up on the above solution then still went digging. Although it is a good solution, Wordpress often offers better or close.
get_category_parents()
This function does as Rahul has typed basically. It also calls itself which seems the most logical approach and that is why Rahul gets a point from me on this. Do not use $link, return a string of categories, explode() them then count or I suppose we could count the number of times the separator has been used and add 1.
function get_category_parents( $id, $link = false, $separator = '/', $nicename = false, $visited = array() ) {
$chain = '';
$parent = get_term( $id, 'category' );
if ( is_wp_error( $parent ) )
return $parent;
if ( $nicename )
$name = $parent->slug;
else
$name = $parent->name;
if ( $parent->parent && ( $parent->parent != $parent->term_id ) && !in_array( $parent->parent, $visited ) ) {
$visited[] = $parent->parent;
$chain .= get_category_parents( $parent->parent, $link, $separator, $nicename, $visited );
}
if ( $link )
$chain .= ''.$name.'' . $separator;
else
$chain .= $name.$separator;
return $chain;
}