Will it be possible to suppress messages such as "Using date format..." when using a function like?
> ymd(vec)
Using date format %Y%m%d
Whilst these are good to see when you are casting a vector, it can be annoying in some circumstances.
Looking at the ymd code, it callse parse_date, which gives those annoying messages via the command message.
Looking at ?message, there is a corresponding suppressMessages:
suppressMessages(ymd(x))
(Note - other similar functions are suppressWarnings, suppressPackageStartupMessages, and capture.output, all of which I have had to use in the past to stop unexpected bits of text turning up (I was outputting some bits to an HTML file and these didn't want these to be in it)).
Manny, suppressMessages() is the only way to go at the moment. But I like your idea of an argument. I've put it on the todo list for lubridate. You could also use strptime() once you have the format for a vector of date-times.
Related
My preceding module in Integromat gives me an expiration date in UNIX time, which is 1640930400.
When I use the FormatDate function to convert this, I'm getting 12/31/1969 when I was expecting to get 12/31/2021. I can't seem to figure out what I'm doing wrong here. Any help would be much appreciated.
Use this instead to first parse the date and then apply the desired formatting to get the results that you want,
{{formatDate(parseDate(1.date; "X"); "MM/DD/YYYY")}}
I want to output today's date without quotes and without line numbers.
How do I get rid of the line number? [1] looks like row 1 of a matrix
R code:
noquote(as.character(Sys.Date()))
[1] 2019-11-21
Sys.Date() Makes the problem a little different than usual.
Unless code is exactly as I am giving in the solution
Sys.Date will be output with a "". I tried using a
semicolon at the end of the line to prevent that from
happening but was not successful.
My cursor is messed up when I use the following suggested command.
Output:
> cat(as.character(Sys.Date()))
2019-11-21>
Thanks. MM
I thought I had tried them all but I hadn't.
I like my work to have identifying information such as name, date, etc.
writeLines function is the answer.
writeLines(noquote(as.character(Sys.Date())))
MM
I have a table like so:
dtab<-data.table(Arr.Dep=c("A","D"),
time=c("2017-05-01 04:50:00","2017-05-01 04:55:00"))
dtab[,time:=parse_date_time(dtab$time, c("%y-%m-%d %H:%M%S"))]
Operations on the date and time column seem successful:
dtab[,time2:=time+2]
But if I try to run an ifelse statement, the POSIXct format goes back to numeric and I seem to be unable to bring it back to date and time.
dtab[,time3:=ifelse(dtab[,Arr.Dep]=="A",dtab[,time]+2,"hello")]
I saw the issue has already been raised:
R- date time variable loses format after ifelse
Unfortunately it's not of great help to me, as when I try to follow the example - adding 2 seconds rather than replacing with NA as in the OP -, I hit an error anyway.
Any help?
Use library(lubridate) and add time dtab$time2 <- dtab$time2 + seconds(2). With this method, the format does not change.
for some reason, I cannot download the r xml package at work. I have an xml file that has contents like this:
x<-read.table("info.xml")
x
</name></content></item><item id="id-123"><content><name>
</name></content></item><item id="id-456"><content><name>
</name></content></item><item id="id-5559"><content><name>
I need to pick values that start with id and - and the numbers like
id-123, id-456 id-5559, etc
tried this:
str_extract_all(x, "id-[0-9]")
but is only printing id-1, I really need help very quick. Any ideas?
str_extract_all(x, "id-[0-9]+")
The regular expression "id-[0-9]" is missing a "+" at the end.
There may be more issues, but that one jumps out.
I am trying to read this file (3.8mb) using its fixed-width structure as described in the following link.
This command:
a <- read.fwf('~/ccsl.txt',c(2,30,6,2,30,8,10,11,6,8))
Produces an error:
line 37 did not have 10 elements
After replicating the issue with different values of the skip option, I figured that the lines causing the problem all contain the "#" symbol.
Is there any way to get around it?
As #jverzani already commented, this problem is probably the fact that the # sign often used as a character to signal a comment. Setting the comment.char input argument of read.fwf to something other than # could fix the problem. I'll leave my answer below as a more general case that you can use on any character that causes problems (e.g. the 's in the Dutch city name 's Gravenhage).
I've had this problem occur with other symbols. The approach I took was to simply replace the # by either nothing, or by a character which does not generate the error. In my case it was no problem to simply replace the character, but this might not be possible in your case.
So my approach would be to delete the symbol that generates the error, or replace by another character. This can be done using a text editor (find and replace), in an R script, or using some linux tools called grep and sed. If you want to do this in an R script, use scan or readLines to read the lines. Once the text is in memory, you can use sub to replace the character.
If you cannot replace the character, I would try the following approach: replace the character by a character that does not generate an error, read it into R using read.fwf, and finally replace the character by the # character.
Following up on the answer above: to get all characters to be read as literals, use both comment.char="" and quote="" (the latter takes care of #PaulHiemstra's problem with single-quotes in Dutch proper nouns) in the call to read.fwf (this is documented in ?read.table).