I have a single directory containing multiple zip files that contain .jpg files.
I need to unzip all files and save all contents (.jpgs files) into a single folder.
Any suggestions on a unix command that does that?
Please note that some of the contents (jpgs) might exist with same name in multiple zipped files, I need to keep all jpgs.
thanks
unzip '*.zip' -o -B
as by default these utilities are not installed
see http://www.cyberciti.biz/tips/how-can-i-zipping-and-unzipping-files-under-linux.html regarding installation
read about -B flag to realize its limitations.
Related
i'am currently trying to unzip some specific files within a ARR file. This ARR file is within a tar.gz file.
Is it possible to unzip these files without a intermediate step/One liner. Its important that the first tar.gz will not be unpacked.
Thanks!
you can try something like:
gzip -dc input_file.tar.gz|tar xf - path/to/file/you/want/to/extract
This decompress and untar the archive in memory and have advantage of run faster.
I' m trying to zip a folder that contains some .json files plus subfolders with more .json files. I need to zip the parent folder with everything included without containing any of the parent or subfolders paths. Is there any way I can do this?
Thank you
EDIT:
I want this:
pending_provider/722c9cb2-268b-4e4a-9000-f7f65e586011-version/1d296136-ac87-424e-89c4-682a63c7b853.json (deflated 68%)
But not this:
pending_provider/722c9cb2-268b-4e4a-9000-f7f65e586011-version/ (stored 0%)
I want to avoid the "stor" compression type which only saves the folder path. I want only the "defN"
So the -j doesn't help me a lot
Thanks
If you don't want any paths at all you could use the -j option. Below is the man page entry for the option.
-j
--junk-paths
Store just the name of a saved file (junk the path), and do not store
directory names. By default, zip will store the full path (relative to
the current directory).
If you just want to exclude directories
-D
--no-dir-entries
Do not create entries in the zip archive for directories.
I have a logs file at directory cd /opt/app/logs named as
coa.log.1
uoa.log.2
erete-rere.log.1
now my concern is that i am looking for unix command which will zip the files having extension log.1 or log.2 or having log. extension anything
request you to please advise the unix comand to zip these files
Folks please advise for this
You can compress in a lot of formats in unix. The most commom is the tar.gz extension. If you are looking fot .zip specifically, there is a zip command: zip <zipname> <files>
To pass the file list you may use the * wirldcard, indicating any name. For example: *.log.*, as sugested by glen, will match every file that contains .log. in its name.
You probably want something like this:
zip backup_logs.zip /opt/app/logs/*.log.*
This will zip all files in the folder that matched what you asked and create a zip file in your current directory.
The File below:
; Install common files
SetOutPath "${GameDir}\Mopy"
File /r /x "*.bat" /x "*.py*" /x "w9xpopen.exe" /x "Wrye Bash.exe" "Mopy\*.*"
filters out some directories that contain python files but still those directories are created (although empty, or containing empty subdirectories) when I run the installer. Those folders need to be included to the installer (if I get the terminology correct at "compile time") cause the installer has an option to install the python version of the program. I can't come up with a way to not add these empty folders. Is there some wildcard I could use to that purpose or should I go and remove the files on installation (using RMDir ?) ?
I'd say you have two options and one is indeed RMDir if you are OK with it possibly removing empty folders that the user created.
The other option is to not use File /r ... and instead use !system to execute something like a batch file that generates a text file with individual File instructions that you can !include. It would look something like this:
!tempfile files
!system '"mygeneratefilelist.bat" "${files}"'
!include "${files}"
!delfile "${files}"
and the batch file would use FOR and/or DIR to list and ECHO the File commands to %1...
I am attempting to use rsync to copy files, but I want to not copy hidden files and folders, and there is one ordinary file I want excluded from the file transfer. I believe I am eliminating the hidden folders with the --exclude="./" and I believe I am excluding the hidden file with the --exclude file path option. If I eliminate the --exclude file path option, I don't get any errors, but that file is copied, which I do not want. If I eliminate the --excluude="./" the hidden files are copied, which I do not want either. What am I doing wrong?
mbp:~ username $ rsync —-exclude /Users/username/work/java/textsearch/settings/search_config.properties --exclude=".*/" -avz /Users/username/work/java/ root#remote.local:/usr/local/java/ -n
building file list ... rsync: link_stat "/Users/username/?\#200\#224-exclude" failed: No such file or directory (2)
done
sent 9560 bytes received 20 bytes 6386.67 bytes/sec
total size is 17461760 speedup is 1822.73
rsync error: some files could not be transferred (code 23) at /SourceCache/rsync/rsync-42/rsync/main.c(992) [sender=2.6.9]
1) What is /Users/username/?#200#224-exclude and why is rsync looking for it?
2) How do I get rsync to copy everything except the hidden folders/files and the specified file?
If this is an exact copy of the command line, the "--" in front of exclude is not using the correct characters. Delete this and replace with double minus. What happens is, that rsync doesn't recognize the option, instead searching the user directory for the file "—-exclude"