Is it possible to make only part of div transparent like an amount of space in div.
For example, you select 100px from top of div and the top 100px have an opacity set?
How would I do it?
You can do a couple of things:
Try a background image where half is transparent and the other half is not.
Use a CSS gradient in such a way that half is transparent and the other is not. Ex:
background: -moz-linear-gradient(top, rgba(30,87,153,0) 0%, rgba(41,137,216,0) 50%, rgba(34,125,203,1) 52%, rgba(125,185,232,1) 100%); /* FF3.6+ */
Use multiple divs where one has transparent BG and the other does not. Ex:
<div>
<div id="transparent" style="background: transparent"></div>
<div id="not-transparent" style="background: #000"></div>
</div>
I'm sure there are other ways, but those are the first three that come to mind.
Good luck.
Either you create the right background-image using a semi-transparent PNG (transparent at top, opaque at bottom for example) ; either you use two sub-divs, each having its own background-color (one of which with rgba for the transparent part).
You can use css3 properties along with pseudo elements to create this effect:
The trick is to draw a box with :before or :after pseudo element. We can apply background property for inner semi-transparent background. While for outer background we can use a large box-shadow value.
HTML:
<div class="box"></div>
CSS:
.box {
position: relative;
overflow: hidden;
height: 120px;
width: 250px;
}
.box:before {
background: rgba(0, 0, 0, 0.3);
box-shadow: 0 0 0 1000px #000;
position: absolute;
height: 50px;
width: 50px;
content: '';
left: 0;
top: 0;
}
html,
body {
height: 100%;
}
body {
background: linear-gradient(to top, #ff5a00 0, #ffae00 100%);
margin: 0;
}
.box {
position: relative;
margin: 30px 20px;
overflow: hidden;
height: 120px;
width: 250px;
}
.box:before {
background: rgba(0, 0, 0, 0.3);
box-shadow: 0 0 0 1000px #000;
position: absolute;
height: 50px;
width: 50px;
content: '';
left: 0;
top: 0;
}
<div class="box"></div>
Related
I'm struggling with a bit of CSS, I want a black bar to show every X amount of pixels but I'd want it to increment by about 10px every time it is shown.
E.g first bar appears at 100px, second at 110 and the third at 120.
So far I have used the following background style to achieve the first part (show a bar every X pixels) but it isn't perfect either:
background: repeating-linear-gradient(white, white 1405px, black 210px,black 37.4cm)
Any css warrior out there that knows of a fix?
EDIT
So with a bit of trial and error I have succeeded in placing the line every 1405 pixels with the following code:
background: repeating-linear-gradient(white, white 1405px, black 1405px, black 1415px)
The problem persists however, the elements are in the place they belong, the line needs to appear after every element (hence the + 10px request).
This is what it looks like now: https://imgur.com/a/pokGCTk
It isn't always 1 element though, there might be more like so: https://imgur.com/a/veaVK44
The line still has to be placed behind the elements at a set interval (1405 pixels) but it has to increase by 10 every time. (so 1405 pixels, then after 1415 pixels, then after 1425 pixels etc.)
It's clear that with a simple linear-gradient we cannot have a non-regular pattern. Here is an idea using some transform and perspective to simualte your pattern where the distance between black line will grow:
body {
margin: 0;
perspective: 30px;
perspective-origin: top;
overflow: hidden;
}
.grad {
height: 100vh;
transform: rotateX(10deg);
transform-origin: bottom;
}
.grad:before {
content: "";
position: absolute;
top: 0;
bottom: 0;
left: -1000%;
right: -1000%;
background: repeating-linear-gradient(to bottom, #000 0, #000 10px, #fff 10px, #fff 50px);
]
<div class="grad">
</div>
Or you would need to use multiple gradient and adjust background-position. Something you can easily generate with SASS if you want many lines:
body {
margin: 0;
perspective: 30px;
perspective-origin: top;
overflow: hidden;
}
.grad {
height: 100vh;
background-image:
linear-gradient(#000,#000),
linear-gradient(#000,#000),
linear-gradient(#000,#000),
linear-gradient(#000,#000);
background-size:100% 10px ;
background-repeat:no-repeat;
background-position:
0 0,
0 50px,
0 150px,
0 300px;
}
<div class="grad">
</div>
Here a script provided by #Krypt1 to generate the above using SASS:
https://www.sassmeister.com/gist/15bd039fdd0803ed79d12762ad6da28f
For stripes to work exactly 10px each, you would need to change the repeating-linear-gradient to generate them every 10px from start to end. And then you can use another gradient to hide first 100px with white color, and then change to transparent to show the stripes.
Here's the snippet:
div {
width: 100%;
height: 200px;
background: linear-gradient(white, white 100px, transparent 100px, transparent),
repeating-linear-gradient(white, white 10px, black 10px, black 20px)
}
<div></div>
A solution which allows you to show background styling from elements behind is to use a pseudoelement positioned behind your div, and make use of rgba within your repeating-lenear-gradient to have transparent colours.
body {
background-color: #e0e0e0;
}
div {
position: relative;
height: 500px;
}
div::after {
content: '';
display: block;
position: absolute;
top: 100px;
right: 0;
bottom: 0;
left: 0;
background-image: repeating-linear-gradient(rgba(0, 0, 0, 0), rgba(0, 0, 0, 0) 10px, #000000 10px, #000000 20px);
z-index: -1;
pointer-events: none;
}
<div></div>
I have an image which covers an entire element using something like #myDiv {background-image: url("../images/background.jpg "); background-repeat: no-repeat; background-size: cover; background-position: center;}
Next, I would like to gray out the left side of the image similar to that shown below.
How can this be accomplished? It doesn't need to look exactly the same, but only similar.
You may use linear-gradients since you use background-image
html {
min-height: 100%;
background:
linear-gradient(to right, rgba(0, 0, 0, 0.75) 60px, transparent 60px), /* the gray, reset opacity to your needs : here 0.75 */
linear-gradient(to right, transparent 60px, red 60px, red 64px, transparent 64px), /* a red line ? */
url(http://lorempixel.com/200/200/fashion) /* and finally, image laying underneath gradients */;
background-size:
auto,
auto,
auto 100%;
}
you could play with a pseudoelement and a RGBA background, e.g.
#mydiv {
background: url(http://www.psdgraphics.com/file/cherry-wood.jpg);
width: 250px;
height: 400px;
position: relative;
}
#mydiv:before {
content: "";
position: absolute;
top: 0;
left: 0;
height: 100%;
width: 30%;
background: rgba(255,255,255, .3);
}
Codepen: http://codepen.io/anon/pen/OyVYwe
Or you could simply add a transparent left border to the element, e.g.
box-sizing: border-box;
background-origin: border-box;
border-left: 50px rgba(255,255,255, .3) solid;
Codepen: http://codepen.io/anon/pen/ZbGNqL
Or you could use an inset box-shadow
box-shadow: 80px 0 0 0px rgba(255, 255, 255, .2) inset;
Codepen: http://codepen.io/anon/pen/avOrXE
Please do not vote for this answer as it was user3791372's comment (yet not yet an answer) and not mine. If you think it is the right approach, please provide a comment why you think so.
http://codepen.io/anon/pen/MaaWMB
<div id="mydiv">
<div id="sidebar"></div>
</div>
#mydiv {
background: url(http://www.psdgraphics.com/file/cherry-wood.jpg) bottom;
width: 230px;
height: 400px;
}
#sidebar {
background-color: white;
opacity: 0.2;
filter: alpha(opacity=20);
width: 50px;
height: 100%;
}
I'm not sure what is specific name for this shape but can I just called it "half Parallelogram" ? I want make this shape purely using CSS/CSS3. Any help? or tutorial?
You can do it using pseudo-elements like below. The approach is to cut out a triangle shape from the left-bottom and top-right of the box. This method can be used with either a solid color an image inside the shape as long as the body background is a solid color. When the body background is a non-solid color this approach will not work because the border hack needs a solid color background.
The advantage of this method is that it can support cuts of different angles at each side (like in the question where the hypotenuse of the triangular cut on either side are not parallel to each other).
div {
background: red;
width: 200px;
height: 100px;
position: relative;
}
div:before {
position: absolute;
height: 0;
width: 0;
content: ' ';
border: 20px solid white;
border-color: transparent transparent white white;
border-width: 20px 0px 0px 15px;
left: 0;
top: 80px;
}
div:after {
position: absolute;
height: 0;
width: 0;
content: ' ';
border: 20px solid white;
border-color: white white transparent transparent;
left: 170px;
top: 0px;
}
.with-img {
background: url(http://lorempixel.com/100/100);
}
<div></div>
<br>
<div class="with-img"></div>
Sample 2: You can also achieve a similar effect using gradients. Just 1 gradient is enough to produce a cut of similar angle on both sides. If different angles are required then two gradients should be used. However the multiple gradient approach mentioned here will not work when the body background is a non-solid color.
div {
width: 200px;
height: 100px;
position: relative;
}
.with-single-gradient {
background: linear-gradient(45deg, transparent 5%, yellowgreen 5%, yellowgreen 90%, transparent 90.5%);
}
.with-single-gradient.image {
background: linear-gradient(45deg, white 5%, transparent 5%, transparent 90%, white 90.5%), url(http://lorempixel.com/100/100);
}
.with-multiple-gradient.image {
background: linear-gradient(45deg, transparent 0%, transparent 90%, white 90%), linear-gradient(60deg, white 10%, transparent 5%, transparent 100%), url(http://lorempixel.com/100/100);
}
<div class='with-single-gradient'></div>
<br>
<div class='with-single-gradient image'></div>
<br>
<div class='with-multiple-gradient image'></div>
Sample 3: This can also be created using SVG and is the best method yet. All that it requires is just a single path element which creates the required shape.
<svg viewBox='0 0 100 60' width='200px' height='120px'>
<path d='M0,0 80,0 100,16 100,60 10,60 0,54z' fill='yellowgreen' />
</svg>
Tested on Chrome v24, Firefox v19, Safari v5.1.7 (on Windows) and IE v10. They are older versions but should work in the latest versions also.
Note: IE versions less than 10 do not support gradients as mentioned in this SO thread.
there's no thing as straight radius, but here you have some tutorials. For weird shapes, you need to use a combination of shape and negative space, basically using figures with the same color of the background . The good news is you could use "transparent" as color, so you can "fake" this figures in an easy way. See tutorials Shapes of CSS or yuo can use a generator like CSS Shape Generator or CSS Shape Generator 2 but they will highly depend on your needs. Personally, I'd use a BG image and be a happy camper
to make this shape you have to use pseudo class.
and i hope it will help you
div { display: inline-block; margin: 20px; float: left; }
shape {
width: 208px;
height: 130px;
background: red;
position: relative; }
shape:before {
content: "";
position: absolute;
top: 0;
left: 0;
border-bottom: 29px solid red;
border-right: 29px solid #fff;
width: 179px;
height: 0; }
shape:after {
content: "";
position: absolute;
bottom: 0;
left: 0;
border-top: 29px solid red;
border-left: 29px solid #fff;
width: 42px;
height: 0; }
demo
2 gradients and background-size can be used too :
div {
width: 1440px;
height: 590px;
background:
linear-gradient(45deg, transparent 80px, #FF0000 80px) left no-repeat,
linear-gradient(-135deg, transparent 160px, #FF0000 160px) top right no-repeat;
background-size: 50% 100%;
}
<div>
</div>
1 gradients and calc() can be used too :
div {
width: 1440px;
height: 590px;
background:
linear-gradient(45deg, transparent 80px, #FF0000 80px, #FF0000 calc( 100% - 160px), transparent calc( 100% - 160px) );
}
<div>
</div>
Related to duplicate question https://stackoverflow.com/questions/36932294/how-can-i-create-the-object-in-picture-below-using-css-border-radius :
div {
width:980px;
height:460px;
background:linear-gradient(140deg,transparent 200px, #FFCB05 200px) left no-repeat,
linear-gradient(-40deg,transparent 80px, #FFCB05 80px) top right no-repeat;
background-size:50% 100% ;
}
<div>
div shape
</div>
image
<img src="http://i.stack.imgur.com/M48zP.png" />
For the second shape use this:
border-bottom-left-radius:50px;
border-top-right-radius:50px;
Check JSFiddle Demo
Edit:
Question is edited and second shape has been removed.
You can add an element with overflow: hidden;
skew transform the parent by desired angle. Unskew the pseudoelement by the negative of that angle.
Using this approach, you can also add images to background.
div {
height: 100px;
width: 220px;
overflow: hidden;
position: relative;
-webkit-transform: skewX(45deg);
-moz-transform: skewX(45deg);
transform: skewX(45deg);
}
div:before {
content: '';
position: absolute;
left: 10px;
height: 100px;
width: 200px;
background: red;
-webkit-transform: skewX(-45deg);
-moz-transform: skewX(-45deg);
transform: skewX(-45deg);
}
<div></div>
FIDDLE
FIDDLE (with image)
I am trying to create a background using css where one side is a solid color and the other is a texture: the two are split by a diagonal line. I would like this to be 2 separate divs since I plan to add some motion with jQuery where if you click on the right, the grey triangle gets smaller and if you click on the left the textured triangle gets smaller (like a curtain effect). Any advice would be greatly appreciated.
I think using a background gradient with a hard transition is a very clean solution:
.diagonal-split-background{
background-color: #013A6B;
background-image: -webkit-linear-gradient(30deg, #013A6B 50%, #004E95 50%);
}
Here are the examples in action: http://jsbin.com/iqemot/1/edit
You can change the placement of the diagonal line with the border pixels. With this approach you would have to position content over the background setup however.
#container {
height: 100px;
width: 100px;
overflow: hidden;
background-image: url(http://www.webdesign.org/img_articles/14881/site-background-pattern-07.jpg);
}
#triangle-topleft {
width: 0;
height: 0;
border-top: 100px solid gray;
border-right: 100px solid transparent;
}
<div id="container">
<div id="triangle-topleft"></div>
</div>
For this sort of thing you could use pseudo selectors such as :before or :after in your CSS to minimize on unnecessary HTML markup.
HTML:
<div id="container"></div>
CSS:
#container {
position: relative;
height: 200px;
width: 200px;
overflow: hidden;
background-color: grey;
}
#container:before {
content: '';
position: absolute;
left: 20%;
width: 100%;
height: 200%;
background-color: rgb(255, 255, 255); /* fallback */
background-color: rgba(255, 255, 255, 0.5);
top: 0;
-webkit-transform: rotate(45deg);
-moz-transform: rotate(45deg);
transform: rotate(45deg);
}
JSFiddle
I then attempted to to make it so that each section could expand depending on where you clicked. This unfortunately requires a little extra jQuery as the position of your click (relative to the the box) needs to be worked out.
A class is then added to the box which changes the :before pseudo object. The upside of using a class is that CSS animations are optimized better for the browser than jQuery ones.
JSFiddle
Resources:
Selecting and manipulating CSS pseudo-elements such as ::before and ::after using jQuery
Using jQuery how to get click coordinates on the target element
This method words on different sized windows and fills the screen. Even works on mobile.
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<title>Diagonal</title>
<style>
*{
margin: 0;
padding: 0;
}
.diagonalimg{
width: 100%;
height: 100vh;
background-image: linear-gradient(to top left, #e394a3 50%, #8dd6a6 50%);
}
</style>
</head>
<body>
<div class="diagonalimg">
</div>
</body>
</html>
This is a full responsive solution. Note the 50.3% on the second stop point, this avoids the pixelating of the line as mentioned in the above comment by #timlg07
.responsive-diagonal {
width: 50vw;
height: 20vh;
background: linear-gradient(to right bottom, #ff0000 50%, #0000ff 50.3%);
}
<div class="responsive-diagonal"></div>
Method 1:
<div class="triangle"></div>
body {
margin: 0;
}
.triangle {
background-image: linear-gradient(to bottom right, LightGray 50%, Salmon 50%);
height: 100vh;
}
https://codepen.io/x-x00102/pen/ZEyEJyM
Method 2:
<div class="triangle"></div>
body {
margin: 0;
}
div {
width: 100vw;
height: 100vh;
}
.triangle::after {
content: '';
position: absolute;
border-top: 100vh solid LightGray;
border-right: 100vw solid Salmon;
}
https://codepen.io/x-x00102/pen/VwWwWGR
Here's a solution to add a diagonal line triangle to the end of a section, it requires one of the two sections to have a flat colour BG, but allows for the other to be a gradient or image.
The demo below shows it with the main section having a gradient, and the section below being a solid colour (in this instance, white).
/* Cruft for the demo */
body {
margin: 0;
padding: 0;
}
.gray-block {
background-image: linear-gradient(to bottom right, #000, #ccc);
color: #fff;
}
.gray-block__inner {
padding: 20px;
}
/* The actual solution */
.diagonal-end::after {
content: "";
display: block;
margin-top: -6vw; /* optionally move the diagonal line up half of its height */
border-top: 12vw solid transparent; /* change 12vw to desired angle */
border-bottom: 0px solid transparent;
border-right: 100vw solid #fff;
}
<div class="gray-block diagonal-end">
<div class="gray-block__inner">
<span>Some content</span>
</div>
</div>
Is there any way to limit the length of a border. I have a <div> that has a bottom border, but I want to add a border on the left of the <div> that only stretches half of the way up.
Is there any way to do so without adding extra elements on the page?
CSS generated content can solve this for you:
div {
position: relative;
}
/* Main div for border to extend to 50% from bottom left corner */
div:after {
content: "";
background: black;
position: absolute;
bottom: 0;
left: 0;
height: 50%;
width: 1px;
}
<div>Lorem Ipsum</div>
(note - the content: ""; declaration is necessary in order for the pseudo-element to render)
#mainDiv {
height: 100px;
width: 80px;
position: relative;
border-bottom: 2px solid #f51c40;
background: #3beadc;
}
#borderLeft {
border-left: 2px solid #f51c40;
position: absolute;
top: 50%;
bottom: 0;
}
<div id="mainDiv">
<div id="borderLeft"></div>
</div>
The ::after pseudo-element rocks :)
If you play a bit you can even set your resized border element to appear centered or to appear only if there is another element next to it (like in menus). Here is an example with a menu:
#menu > ul > li {
position: relative;
float: left;
padding: 0 10px;
}
#menu > ul > li + li::after {
content:"";
background: #ccc;
position: absolute;
bottom: 25%;
left: 0;
height: 50%;
width: 1px;
}
#menu > ul > li {
position: relative;
float: left;
padding: 0 10px;
list-style: none;
}
#menu > ul > li + li::after {
content: "";
background: #ccc;
position: absolute;
bottom: 25%;
left: 0;
height: 50%;
width: 1px;
}
<div id="menu">
<ul>
<li>Foo</li>
<li>Bar</li>
<li>Baz</li>
</ul>
</div>
With CSS properties, we can only control the thickness of border; not length.
However we can mimic border effect and control its width and height as we want with some other ways.
With CSS (Linear Gradient):
We can use linear-gradient() to create a background image(s) and control its size and position with CSS so that it looks like a border. As we can apply multiple background images to an element, we can use this feature to create multiple border like images and apply on different sides of element. We can also cover the remaining available area with some solid color, gradient or background image.
Required HTML:
All we need is one element only (possibly having some class).
<div class="box"></div>
Steps:
Create background image(s) with linear-gradient().
Use background-size to adjust the width / height of above created image(s) so that it looks like a border.
Use background-position to adjust position (like left, right, left bottom etc.) of the above created border(s).
Necessary CSS:
.box {
background-image: linear-gradient(purple, purple),
// Above css will create background image that looks like a border.
linear-gradient(steelblue, steelblue);
// This will create background image for the container.
background-repeat: no-repeat;
/* First sizing pair (4px 50%) will define the size of the border i.e border
will be of having 4px width and 50% height. */
/* 2nd pair will define the size of stretched background image. */
background-size: 4px 50%, calc(100% - 4px) 100%;
/* Similar to size, first pair will define the position of the border
and 2nd one for the container background */
background-position: left bottom, 4px 0;
}
Examples:
With linear-gradient() we can create borders of solid color as well as having gradients. Below are some examples of border created with this method.
Example with border applied on one side only:
.container {
display: flex;
}
.box {
background-image: linear-gradient(purple, purple),
linear-gradient(steelblue, steelblue);
background-repeat: no-repeat;
background-size: 4px 50%, calc(100% - 4px) 100%;
background-position: left bottom, 4px 0;
height: 160px;
width: 160px;
margin: 20px;
}
.gradient-border {
background-image: linear-gradient(red, purple),
linear-gradient(steelblue, steelblue);
}
<div class="container">
<div class="box"></div>
<div class="box gradient-border"></div>
</div>
Example with border applied on two sides:
.container {
display: flex;
}
.box {
background-image: linear-gradient(purple, purple),
linear-gradient(purple, purple),
linear-gradient(steelblue, steelblue);
background-repeat: no-repeat;
background-size: 4px 50%, 4px 50%, calc(100% - 8px) 100%;
background-position: left bottom, right top, 4px 0;
height: 160px;
width: 160px;
margin: 20px;
}
.gradient-border {
background-image: linear-gradient(red, purple),
linear-gradient(purple, red),
linear-gradient(steelblue, steelblue);
}
<div class="container">
<div class="box"></div>
<div class="box gradient-border"></div>
</div>
Example with border applied on all sides:
.container {
display: flex;
}
.box {
background-image: linear-gradient(purple, purple),
linear-gradient(purple, purple),
linear-gradient(purple, purple),
linear-gradient(purple, purple),
linear-gradient(steelblue, steelblue);
background-repeat: no-repeat;
background-size: 4px 50%, 50% 4px, 4px 50%, 50% 4px, calc(100% - 8px) calc(100% - 8px);
background-position: left bottom, left bottom, right top, right top, 4px 4px;
height: 160px;
width: 160px;
margin: 20px;
}
.gradient-border {
background-image: linear-gradient(red, purple),
linear-gradient(to right, purple, red),
linear-gradient(to bottom, purple, red),
linear-gradient(to left, purple, red),
linear-gradient(steelblue, steelblue);
}
<div class="container">
<div class="box"></div>
<div class="box gradient-border"></div>
</div>
Screenshot:
for horizontal lines you can use hr tag:
hr { width: 90%; }
but its not possible to limit border height. only element height.
Another way of doing this is using border-image in combination with a linear-gradient.
div {
width: 100px;
height: 75px;
background-color: green;
background-clip: content-box; /* so that the background color is not below the border */
border-left: 5px solid black;
border-image: linear-gradient(to top, #000 50%, rgba(0,0,0,0) 50%); /* to top - at 50% transparent */
border-image-slice: 1;
}
<div></div>
jsfiddle: https://jsfiddle.net/u7zq0amc/1/
Browser Support:
IE: 11+
Chrome: all
Firefox: 15+
For a better support also add vendor prefixes.
caniuse border-image
Borders are defined per side only, not in fractions of a side. So, no, you can't do that.
Also, a new element wouldn't be a border either, it would only mimic the behaviour you want - but it would still be an element.
This is a CSS trick, not a formal solution. I leave the code with the period black because it helps me position the element. Afterward, color your content (color:white) and (margin-top:-5px or so) to make it as though the period is not there.
div.yourdivname:after {
content: "";
border-bottom: 1px solid grey;
width: 60%;
display: block;
margin: 0 auto;
}
Article about this issue: https://www.steckinsights.com/shorten-length-border-bottom-pure-css/
Another solution is you could use a background image to mimic the look of a left border
Create the border-left style you require as a graphic
Position it to the very left of your div (make it long enough to handle roughly two text size increases for older browsers)
Set the vertical position 50% from the top of your div.
You might need to tweak for IE (as per usual) but it's worth a shot if that's the design you are going for.
I am generally against using images for something that CSS inherently provides, but sometimes if the design needs it, there's no other way round it.
You can define one border per side only. You would have to add an extra element for that!