I have 7 Sqlite tables and i want to join all these into one table or say a new table .Every tables has same number of column names.I am getting error ambiguity with column name.How can join all these tables.
To avoid ambiguity, you should prefix the columns with the table names and use column aliases:
create table tab1(id number, value varchar2(20));
create table tab2(id number, value varchar2(20));
create table tab3(id number, value varchar2(20));
insert into tab1(id, value) values(1, 'a');
insert into tab2(id, value) values(1, 'b');
insert into tab3(id, value) values(1, 'c');
create table t4 as
select tab1.id id, tab1.value value1, tab2.value value2, tab3.value value3
from tab1, tab2, tab3
where tab1.id = tab2.id
and tab1.id = tab3.id;
Related
Assume I have a simple table in Oracle db
CREATE TABLE schema.d_test
(
id_record integer GENERATED AS IDENTITY START WITH 95000 NOT NULL,
DT DATE NOT NULL,
var varchar(50),
num float,
PRIMARY KEY (ID_RECORD)
)
And I have a dataframe in R
dt = c('2022-01-01', '2005-04-01', '2011-10-02')
var = c('sgdsg', 'hjhgjg', 'rurtur')
num = c(165, 1658.5, 8978.12354)
data = data.frame(dt, var, num)%>%
mutate(dt = as.Date(dt))
I'm trying to insert data into Oracle d_test table using the code
data %>%
dbWriteTable(
oracle_con,
value = .,
date = T,
'D_TEST',
append = T,
row.names=F,
overwrite = F
)
But the following error returned
Error in .oci.WriteTable(conn, name, value, row.names = row.names, overwrite = overwrite, :
Error in .oci.GetQuery(con, stmt, data = value) :
ORA-00947: not enough values
What's the problem?
How can I fix it?
Thank you.
This is pure Oracle (I don't know R).
Sample table:
SQL> create table test_so (id number generated always as identity not null, name varchar2(20));
Table created.
SQL> insert into test_so(name) values ('Name 1');
1 row created.
My initial idea was to suggest you to insert any value into the ID column, hoping that Oracle would discard it and generate its own value. However, that won't work.
SQL> insert into test_so (id, name) values (-100, 'Name 2');
insert into test_so (id, name) values (-100, 'Name 2')
*
ERROR at line 1:
ORA-32795: cannot insert into a generated always identity column
But, if you can afford recreating the table so that it doesn't automatically generate the ID column's value but use a "workaround" (we used anyway, as identity columns are relatively new in Oracle) - a sequence and a trigger - you might be able to "fix" it.
SQL> drop table test_so;
Table dropped.
SQL> create table test_so (id number not null, name varchar2(20));
Table created.
SQL> create sequence seq_so;
Sequence created.
SQL> create or replace trigger trg_bi_so
2 before insert on test_so
3 for each row
4 begin
5 :new.id := seq_so.nextval;
6 end;
7 /
Trigger created.
Inserting only name (Oracle will use a trigger to populate ID):
SQL> insert into test_so(name) values ('Name 1');
1 row created.
This is what you'll do in your code - provide dummy ID value, just to avoid
ORA-00947: not enough values
error you have now. Trigger will discard it and use sequence anyway:
SQL> insert into test_so (id, name) values (-100, 'Name 2');
1 row created.
SQL> select * from test_so;
ID NAME
---------- --------------------
1 Name 1
2 Name 2 --> this is a row which was supposed to have ID = -100
SQL>
The way you can handle this problem is to create table with GENERATED BY DEFAULT ON NULL AS IDENTITY like this
CREATE TABLE CM_RISK.d_test
(
id_record integer GENERATED BY DEFAULT ON NULL AS IDENTITY START WITH 5000 NOT NULL ,
DT date NOT NULL,
var varchar(50),
num float,
PRIMARY KEY (ID_RECORD)
)
I have following table structure in SQLite database:
CREATE TABLE A (id integer primary key, name text, room Integer);
CREATE TABLE B (id integer primary key, idA integer not null, code blob, FOREIGN KEY(idA) REFERENCES A(id));
For each record in A there are 1 to n records in B that refers it. Desired table structure is:
CREATE TABLE A (id integer primary key, name text);
CREATE TABLE B (id integer primary key, idA integer not null, code blob, room Integer, FOREIGN KEY(idA) REFERENCES A(id));
So, I would like to transer room column from A to B without data loss: recreate table A without room column, delete duplicates from A, add room column to B, set it depends on what values were in referenced A records room columns (original A table) and reassign idA for B records.
Is it possible using only SQLite and if it is, how to do this, using only SQLite?
Thank you!
have a look at http://sqlfiddle.com/#!5/e26e2/1 .
creating the databases :
CREATE TABLE A (id integer primary key, name text, room Integer);
CREATE TABLE B (id integer primary key, idA integer not null, code blob, FOREIGN KEY(idA) REFERENCES A(id));
Fill in some test data :
insert into A (id, name, room) values (1, "azerty", 123) ;
insert into A (id, name, room) values (2, "querty", 456) ;
insert into B (id, idA, code) values (10, 1, "code 1") ;
insert into B (id, idA, code) values (15, 1, "code 1b") ;
insert into B (id, idA, code) values (20, 1, "code 1c") ;
insert into B (id, idA, code) values (25, 2, "code 2") ;
insert into B (id, idA, code) values (30, 3, "code 3") ;
copy the wrong table layouts to tables we will later drop :
alter table B rename to old_B ;
alter table A rename to old_A ;
Create tables according the correct layout :
CREATE TABLE A (id integer primary key, name text);
CREATE TABLE B (id integer primary key, idA integer not null, code blob, room Integer, FOREIGN KEY(idA) REFERENCES A(id));
Copy selected data from old_A into A :
INSERT OR REPLACE INTO A ( id, name)
SELECT id, name FROM old_A ;
fill B with an inner join to "line up" room with correct idA :
INSERT OR REPLACE INTO B ( id, idA, code, room)
SELECT old_B.*, old_A.room FROM old_B INNER JOIN old_A ON old_B.idA = old_A.id ;
drop the old tables
DROP TABLE old_A ;
DROP TABLE old_B ;
I have two SQLite tables A and B defined as:
CREATE TABLE A (orig_cat INTEGER, type INTEGER,gv_ID INTEGER);
INSERT INTO A (orig_cat,type) VALUES (1,1);
INSERT INTO A (orig_cat,type) VALUES (2,2);
INSERT INTO A (orig_cat,type) VALUES (3,2);
INSERT INTO A (orig_cat,type) VALUES (4,2);
INSERT INTO A (orig_cat,type) VALUES (1,3);
INSERT INTO A (orig_cat,type) VALUES (2,3);
INSERT INTO A (orig_cat,type) VALUES (3,3);
UPDATE A SET gv_ID=rowid+99;
and
CREATE TABLE B (col_t INTEGER, orig_cat INTEGER, part INTEGER);
INSERT INTO B VALUES (1,1,1);
INSERT INTO B VALUES (3,1,2);
INSERT INTO B VALUES (2,2,1);
INSERT INTO B VALUES (1,2,2);
INSERT INTO B VALUES (3,3,1);
INSERT INTO B VALUES (4,3,2);
I'd like to update and set/replace the values in column col_t of table B where part=2 with selected values of column gv_ID of table A. The selected values I can get with a SELECT command:
SELECT gv_ID
FROM (SELECT * FROM B where part=2) AS B_sub
JOIN (SELECT * FROM A WHERE type=3) AS A_sub
ON B_sub.orig_cat=A_sub.orig_cat;
How can I use that so that the values of col_t in rows 2,3 and 5 (=1,2,3) get replaced with the values 104,105,106 (wich is returned by the selection)?
You can use correlated subquery:
UPDATE B
SET col_t = (SELECT gv_ID FROM A WHERE A.orig_cat = B.orig_cat AND A.type = 3)
WHERE B."part" = 2;
SqlFiddleDemo
I've assumed that pair A.orig_cat and A.type is UNIQUE.
I've got two tables already populated with data with the given schemas:
CREATE TABLE objects
(
id BIGINT NOT NULL,
latitude BIGINT NOT NULL,
longitude BIGINT NOT NULL,
PRIMARY KEY (id)
)
CREATE TABLE tags
(
id BIGINT NOT NULL,
tag_key VARCHAR(100) NOT NULL,
tag_value VARCHAR(500),
PRIMARY KEY (id , tag_key)
)
object.id and tags.id refer to the same object
I'd like to populate a third table with the unique combinations of tag_key and tag_value. For example:
INSERT OR REPLACE INTO objects (id) VALUES (0);
INSERT OR REPLACE INTO tags (id, tag_key, tag_value) VALUES (0, 'a', 'x');
INSERT OR REPLACE INTO objects (id) VALUES (1);
INSERT OR REPLACE INTO tags (id, tag_key, tag_value) VALUES (1, 'a', 'y');
INSERT OR REPLACE INTO objects (id) VALUES (2);
INSERT OR REPLACE INTO tags (id, tag_key, tag_value) VALUES (2, 'a', 'x');
INSERT OR REPLACE INTO tags (id, tag_key, tag_value) VALUES (2, 'a', 'y');
INSERT OR REPLACE INTO objects (id) VALUES (3);
INSERT OR REPLACE INTO tags (id, tag_key, tag_value) VALUES (3, 'a', 'x');
INSERT OR REPLACE INTO objects (id) VALUES (4);
INSERT OR REPLACE INTO tags (id, tag_key, tag_value) VALUES (4, 'a', 'y');
Should result in 3 entries of
0: ([a,x])
1: ([a,y])
3: ([a,x][a,y])
Currently I have:
CREATE TABLE tags_combinations
(
id INTEGER PRIMARY KEY,
tag_key VARCHAR(100) NOT NULL,
tag_value VARCHAR(500)
);
The id shouldn't be related to the original id of the object, just something to group unique combinations.
This is the query I have so far:
SELECT
t1.tag_key, t1.tag_value
FROM
tags t1
WHERE
t1.id
IN
(
/* select ids who's every tags entry is not under one id in tags_combinations */
SELECT
t2.id
FROM
tags t2
WHERE
t2.tag_key, t2.tag_value
NOT IN
(
)
);
The part with the comment is what I am not sure about, how would I select every id from tags that does not have all of the corresponding tag_key and tag_value entries already under one id in tags_combinations?
To clarify exactly the result I am after: From the sample data given, it should return 4 rows with:
row id tag_key tag_value
0 0 a x
1 1 a y
2 2 a x
3 2 a y
SQL is a set-based language. If you reformulate your question in the language of set theory, you can directly translate it into SQL:
You want all rows of the tags table, except those from duplicate objects.
Objects are duplicates if they have exactly the same key/value combinations. However, we still want to return one of those objects, so we define duplicates only as those objects where no other duplicate object with a smaller ID exists.
Two objects A and B have exactly the same key/value combinations if
all key/value combinations in A also exist in B, and
all key/value combinations in B also exist in A.
All key/value combinations in A also exist in B if there is no key/value combination in A that does not exist in B (note: double negation).
SELECT id, tag_key, tag_value
FROM tags
WHERE NOT EXISTS (SELECT 1
FROM tags AS dup
WHERE dup.id < tags.id
AND NOT EXISTS (SELECT 1
FROM tags AS A
WHERE A.id = tags.id
AND NOT EXISTS (SELECT 1
FROM tags AS B
WHERE B.id = dup.id
AND B.tag_key = A.tag_key
AND B.tag_value = A.tag_value)
)
AND NOT EXISTS (SELECT 1
FROM tags AS B
WHERE B.id = dup.id
AND NOT EXISTS (SELECT 1
FROM tags AS A
WHERE A.id = tags.id
AND A.tag_key = B.tag_key
AND A.tag_value = B.tag_value)
)
)
ORDER BY id, tag_key;
This is not easy in SQLite. We want to identify groups of tag key/value pairs. So we could group by id and get a string of the associated pairs with group_concat. This would be the way to do it in another DBMS. SQLite, however, cannot order in group_concat, so we might end up with 2: 'a/x,a/y' and 5: 'a/y,a/x'. Two different strings for the same pairs.
Your best bet may be to write a program and find the distinct pairs iteratively.
In SQLite you may want to try this:
insert into tags_combinations (id, tag_key, tag_value)
select id, tag_key, tag_value
from tags
where id in
(
select min(id)
from
(
select id, group_concat(tag_key || '/' || tag_value) as tag_pairs
from
(
select id, tag_key, tag_value
from tags
order by id, tag_key, tag_value
) ordered_data
group by id
) aggregated_data
group by tag_pairs
);
Ordering the data before applying group_concat is likely to get the tag pairs ordered, but in no way guaranteed! If this is something you want to do only once, it may be worth a try, though.
To merge multiple rows into one value, you need a function like group_concat().
The ORDER BY is needed to ensure a consistent order of the rows within a group:
SELECT DISTINCT group_concat(tag_key) AS tag_keys,
group_concat(tag_value) AS tag_values
FROM (SELECT id,
tag_key,
tag_value
FROM tags
ORDER BY id,
tag_key,
tag_value)
GROUP BY id;
If you want to have keys and values interleaved, as shown in the question, you need to do more string concatenation:
SELECT DISTINCT group_concat(tag_key || ',' || tag_value, ';') AS keys_and_values
FROM (...
I'm adding an 'index' column to a table in SQLite3 to allow the users to easily reorder the data, by renaming the old database and creating a new one in its place with the extra columns.
The problem I have is that I need to give each row a unique number in the 'index' column when I INSERT...SELECT the old values.
A search I did turned up a useful term in Oracle called ROWNUM, but SQLite3 doesn't have that. Is there something equivalent in SQLite?
You can use one of the special row names ROWID, OID or _ROWID_ to get the rowid of a column. See http://www.sqlite.org/lang_createtable.html#rowid for further details (and that the rows can be hidden by normal columns called ROWID and so on).
Many people here seems to mix up ROWNUM with ROWID. They are not the same concept and Oracle has both.
ROWID is a unique ID of a database ROW. It's almost invariant (changed during import/export but it is the same across different SQL queries).
ROWNUM is a calculated field corresponding to the row number in the query result. It's always 1 for the first row, 2 for the second, and so on. It is absolutely not linked to any table row and the same table row could have very different rownums depending of how it is queried.
Sqlite has a ROWID but no ROWNUM. The only equivalent I found is ROW_NUMBER() function (see http://www.sqlitetutorial.net/sqlite-window-functions/sqlite-row_number/).
You can achieve what you want with a query like this:
insert into new
select *, row_number() over ()
from old;
No SQLite doesn't have a direct equivalent to Oracle's ROWNUM.
If I understand your requirement correctly, you should be able to add a numbered column based on ordering of the old table this way:
create table old (col1, col2);
insert into old values
('d', 3),
('s', 3),
('d', 1),
('w', 45),
('b', 5465),
('w', 3),
('b', 23);
create table new (colPK INTEGER PRIMARY KEY AUTOINCREMENT, col1, col2);
insert into new select NULL, col1, col2 from old order by col1, col2;
The new table contains:
.headers on
.mode column
select * from new;
colPK col1 col2
---------- ---------- ----------
1 b 23
2 b 5465
3 d 1
4 d 3
5 s 3
6 w 3
7 w 45
The AUTOINCREMENT does what its name suggests: each additional row has the previous' value incremented by 1.
I believe you want to use the constrain LIMIT in SQLite.
SELECT * FROM TABLE can return thousands of records.
However, you can constrain this by adding the LIMIT keyword.
SELECT * FROM TABLE LIMIT 5;
Will return the first 5 records from the table returned in you query - if available
use this code For create Row_num 0....count_row
SELECT (SELECT COUNT(*)
FROM main AS t2
WHERE t2.col1 < t1.col1) + (SELECT COUNT(*)
FROM main AS t3
WHERE t3.col1 = t1.col1 AND t3.col1 < t1.col1) AS rowNum, * FROM Table_name t1 WHERE rowNum=0 ORDER BY t1.col1 ASC