How to find the first focusable component in a container? - apache-flex

I'm trying to programatically set a focus on the first component of a given container. What's the best way to do it?
A couple of notes:
I haven't found any appropriate method on IFocusManager / IFocusManagerContainer interfaces. Ideally, there would be IFocusManagerContainer#getFirstFocusableComponent() but there is no such method.
The "first" component is the one that would receive focus if you were on some component just before the container and pressed TAB. It is not necessarily the first focusable child of the container (tab order plays role here).
I'd like the solution to perform well. I'm not particularly keen on traversing display list, I still hope there is some better way.
Thanks!

Related

Check if QML Item is being drawn

I have a set of QML items distributed all over my UI. They display data from a remote device and their content needs to be updated regularly. The Items are spread on several tabs and hidden in nested ListView instances, so most of them won't be visible to the user all the time.
In order to keep the bandwidth low I want to update only those items that are currently visible to the user.
I am looking for the right hook to get the information which of these Items is currently displayed from within the Item, without relying on information from the parents. If they were all placed in ListView delegates I could use the delegate's Components onCompleted and onDestroyed signals. Since this is not the case I am stuck at finding out how to get this information.
Am I missing something here? Is there an onPaintFinished signal or something similar? My workaround would be to add that logic to the parent containers, but that would be tedious, since there are several kinds of container that can contains these display Items.
Instances that are on delegates of a ListView will not exist until they would be in the visible range or the cache range around the visual area of the list view. If the delegate moves outside of that range, it is destroyed. So, no need to worry about instances hidden there.
Furthermore, items are currently not visible are also not drawn. They are not entered into the scene graph, and hence, not rendered. So, instances of your items appearing on tabs that are currently not current will also not be drawn. However, these items do still exist of course.
Figuring out if an item is effectively visible or not is quite a hard problem though. QML delegates part of that to OpenGL (clipping for instance). There is not feedback on the result of that. You could in theory lift that information out of the renderer, but that would require customizing that and that is very hard. You could take a look at the heuristics that GammaRay uses to warn about items not being visible. Perhaps you can take some inspiration from that.

how to handle WAI ARIA role="listbox"

I have a list of options from which one can be selected. For all intents and purposes HTML's <select> element covers this. Since we need a different visual presentation, I'm looking at using WAI ARIA role="listbox". I'm unclear on how to use aria-activedescendant, aria-selected and aria-checked.
Questions regarding focus/active state:
If I use aria-activedescendant on the listbox to point to the [role="option"] that is currently active (has "virtual focus"), I would use [aria-selected]. How would best I tell the option element itself that it is active (has "virtual focus") to represent that visually? (:focus is on the listbox, after all)
an [role="option"] can have [aria-checked] and [aria-selected]. I guess I need [aria-selected] but don't see what I'd use [aria-checked] for.
Is there a trick to avoid having to put IDs on every option simply so it can be referenced by aria-activedescendant?
Questions regarding keyboard interaction:
"Checkbox - Space toggles checkboxes, if the list items are checkable" - how do I figure out if they are checkable or selectable?
Questions regarding validation:
If the listbox has [aria-required="true"] some sort of validation has to be performed. specifically if an option has been selected (or checked).
when do I trigger the validation? is on blur sufficient?
when invalid, what do I have to do besides setting [aria-invalid="true"] on the listbox?
aria-checked is indeed more something for a list of very closely related options with actual visible checkboxes that can be toggled on or off. This is most common in the Windows world. Explorer can be set to such a pseudo multi-select mode, or some apps use that to activate or deactivate a set of accounts. On the Mac, you can think of the list of accounts in Adium, which can be either checked (active) or not. A selection will always be there, and one or more of their checkboxes can be checked or not.
aria-selected is always the right one to indicate the selected state of an option. E. g. when traversing the list with the arrow keys, aria-selected="true" moves from item to item, while the others must then get aria-selected="false". As Patrick said, you can use this to also generate some nice looking CSS.
As for keyboard interaction: arrows up and down will select an item, and if the items are checkable, too, space will toggle the checked or unchecked state of the currently selected item.
In a true multi-select, like html:select #size>1, and multiselectable being true, the interaction would be:
Arrow keys select a single item.
Ctrl+Arrow keys would move focus from item to item, but not select the item yet.
Ctrl+Space would select the item.
Shift+up and down arrows would select contiguous items.
This is, again, standard Windows paradigm, can be observed in Explorer in Details view, for example.
As for validation: onBlur is sufficient, or you could dynamically do it via changes in selection/focused item, make sure at least one item is selected, or whatever validation you need.
aria-invalid="true" is sufficient for screen readers to know, but an error message and possibly a visual indication would be nice for everyone to know what's wrong.
How would best I tell the option element itself that it is active (has "virtual focus") to represent that visually?
Generally, you'd add aria-selected="true" and then craft some CSS that takes care of it using attribute selectors, e.g. div[role=option][aria-selected=true] { ... }, or add a css class dynamically?
[aria-checked] and [aria-selected]
This is more of a philosophical question I guess. aria-selected more closely matches what you'd have with a select...but then again (particularly for multi-select widgets) you can imagine the listbox actually being a series of checkboxes, and in that case you'd use aria-checked. there's no definitive right or wrong about either one (something you'll find a lot once you dive into more complex ARIA widgets).
Is there a trick to avoid having to put IDs on every option simply so it can be referenced by aria-activedescendant
Hmm...perhaps you could dynamically generate IDs for all options on page load via script? Or - but not tested - you could have something like a "roving" ID that moves around the options depending on which one is active (adding/removing the ID to the relevant option).

Flex: accessing child through navigating the hiererachy

I have a generic function to build rows of controls (each row comprising of sliders, radio buttons, reset buttons, text display) etc, and some functionality to change underlying data based on these
As I didn't want to write specific code for each row, I had code written by which I can detect the row on which there has been a mouseevent, and though the row access each individual control
The hierarchy used is titleWindow (part of popup)->skinnable container->HGroup->control
When I trace for a radiobutton, I get the path as follows Electric_Modify.TitleWindowSkin2620._TitleWindowSkin_Group1.contents.contentGroup.0.RadioButton2645
The '0' before the radioButton stands for the first Hgroup id->named as 0
I tried accessing the radio button as follows- 5th element in the HGroup
((this.contentGroup.getChildAt(row)as Group).getChildAt(4) as RadioButton).enabled=false;
and get a message "Cannot access a property or method of a null object reference" on this line. How should I navigate the hierarchy to reach the element?
You should be using getElementAt(...) and not getChildAt(...).
The get element functions represent a "higher level" element hierarchy which is needed to make skinning easier.
((this.getElementAt(row) as IVisualElementContainer).getElementAt(4) as RadioButton).enabled = false;
It should look something like that, but the exact hierarchy depends on what's in your app.
#drkstr
Thanks for your input... I thought of an alternate approach that worked for me...I mapped out the parent of the HGroup via
parent1=hgrp.parent; and then referenced these buttons as follows
((parent1.getChildAt(row)as Group).getChildAt(4) as RadioButton)
This works like a dream...I presume your suggestion would let me jump across the intermediate layers
#J_A_X/ #Constantiner: Thanks for the suggestion. I have no idea why we didn't think through and go down the DataGroup path. Prima facie seems simpler... we got to creating the UI controls in MXML laying out controls serially,and when it came to making it generic, we literally replicated the MXML approach in AS. Started off easy, till it caused problems like above. We will fix this to a better approach, when we upgrade versions. It works for now

Best way to make elements non-selectable in Flex

All,
As part of requirements for a new feature of "locking" a page, it is desired to have all elements on a locked page be non-selectable. This is not to be confused with disabled. All elements should appear as if the page were active, but not be selectable.
The current thought is to create a clear canvas and place it over the existing elements. With this thought, I have two questions:
if you can think of a better way to make all items non-selectable than applying a clear canvas element over the existing elements could you describe it?
if not, what is the best way to retrofit existing implementations to accept the overlayed canvas item? BTW, all .mxml pages inherit from a custom .as file.
Sorry if this is not very descriptive, however, I am new to Flex and have spent many days trying to figure this out.
Thanks,
Todd
You could also set the mouseChildren property of the page to false so the elements will not receive any mouseEvents
All,
To fully "lock" a screen from user manipulation, one must combine Chris Bos's and www.Flextras.com's answers: disable mouse input (mouseChildren) and disable keyboard focus (focusEnabled).
Todd
Would the focusEnabled property work for you?
Documentation says it only relates to "Tabbing", but my memory says it relates to all sorts of selection.

flex tree custom item renderer children creation

I have created a custom item renderer for the tree, i have added some children in create children function, my problem is that sometimes i need to show these children and sometimes i don't, depending on clicking on a button which also i have added at create children, the problem is that i had to create the item even if i don't want it to be visible, and removed it by making visible false, and this costs a lot of memory, i have tried to create it at buttons click listener but when scrolling the child disappears, and it may appear again if i keep scrolling up and down..
i am trying to add the child just when i need it to be visible, is this possible or i have to create it on child creation method?
Typically you do something like this with states. This way the components within the container (in this case your item renderer) are only created when the container enters the given state. The nice thing about taking this approach is that you can remain oblivious to when components need to be created/removed and let the states model handle that for you. Hope that helps.

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