Consider I have a file abcde.txt which may contain one or more lines of text. I want a script that will DELETE the file if it contains single line.
Something like, if 'wc -l abscde.txt' = 1 then rm abscde.txt
My system : Solaris
Here's a simple bash script:
#!/bin/bash
LINECOUNT=`wc -l abscde.txt | cut -f1 -d' '`
if [[ $LINECOUNT == 1 ]]; then
rm -f abscde.txt
fi
delifsingleline () {
if [ $(cat $1 | wc -l) = "1" ]
then
echo "Deleting $1"
echo "rm $1"
fi
}
Lightly tested on zsh. Should work on bash as well.
This is (mostly) just a reformat of Ben's answer:
wc -l $PATH | grep '^1 ' > /dev/null && rm -f $PATH
Related
I have script which is running in bg(nohup) but it was accidently deleted,but that is continue running now I need to edit the code which is already deleted.
How can I now get that code.I assume somewhere it should be as it is running.
Try this :
#!/bin/bash
if [[ ! $1 || $1 == -h || $1 == --help ]]; then
echo -e "Usage:\n\n\t$0 '[path/]<file name>'"
exit 1
fi
files=(
$(file 2>/dev/null /proc/*/fd/* |
grep "(deleted)'$" |
sed -r 's#(:.*broken\s+symbolic\s+link\s+to\s+.|\(deleted\).$)# #g' |
grep "$1" |
cut -d' ' -f1
)
)
if [[ ${files[#]} ]]; then
for f in ${files[#]}; do
echo "fd $f match... Try to copy this fd to another place quickly!"
done
else
echo >&2 "No matching fd found..."
exit 2
fi
Not tested on non GNU-Linux
I am trying to write a unix command which will write/redirects the output to a file i.e. create a file if there is difference in 2 files else it will not create the file.
I am using the below command but it always creates a file(of 0B if no diff), no matter there is any difference in file or not.
diff -u -w a.txt b.txt > diff.tmp
I am trying to write a single unix command that will create file "diff.tmp" if "a.txt" is not equal to "b.txt" else "diff.tmp" will not be created.
Thanks in advance,
Pritish
In bash you could remove it afterwards:
diff -u -w a.txt b.txt > diff.tmp && if [ -f diff.tmp ] && [ ! -s diff.tmp ]; then rm diff.tmp; fi
Note:
-f: to check if the file exits (-e to check if a file, directory, etc. exists)
-s: to check if the file is non-zero
However can will work for text files ..you can use cmp command as well.
cmp a.txt b.txt > cmp.tmp && if [ -f cmp.tmp ] && [ ! -s cmp.tmp ]; then rm cmp.tmp; fi
you can check return code of diff. From man page:
Exit status is 0 if inputs are the same, 1 if different, 2 if trouble.
So I would write something like:
#!/bin/bash
diff "$1" "$2" 2>/dev/null 1>/dev/null
if [[ $? -eq 0 ]];then
echo "No diff found!"
else
echo "Diff saved in file "$3
diff $1 $2 > $3
fi
And then you call it like
./diff.sh a.txt b.txt diff.tmp
Hope it helps!
Bye
Piero
#!/bin/bash
delete_file () {
for file in processor_list.txt currnet_username.txt unique_username.txt
do
if [ -e $file ] ;then
rm $file
fi
done
}
delete_file
ps -elf > processor_list.txt ; chmod 755 processor_list.txt
awk '{print $3}' processor_list.txt > currnet_username.txt ; chmod 755 currnet_username.txt
sort -u currnet_username.txt > unique_username.txt ;chmod 755 unique_username.txt
while read line ; do
if [ -e $line.txt ] ;then
rm $line.txt
fi
grep $line processor_list.txt >$line.sh ;chmod 755 $line.sh
awk '{if($4 == "$line") print $0;}' $line.sh > ${line}1.txt ; #mv ${line}1.txt $line.txt;chmod 755 $line.txt
done < unique_username.txt
I'm a beginner of unix shell scripting. please suggested, i am not getting expected results in ${line}1.txt.
For example, I have two UID like kplus , kplustp. what is my requirement is find "kplus" string from ps -elf command and create a file as same name like kplus.txt and redirect or move the data whatever found data using grep command.
But I am getting kplus and kplustp data in kplus.txt file. I need only kplus value based on UID column from ps –elf in kplus.txt file.
This is wrong way to read variable using awk
awk '{if($4 == "$line") print $0;}' $line.sh
Use:
awk '{if($4 == var) print $0;}' var="$line" $line.sh
Or shorten to
awk '$4==var' var="$line" $line.sh
default action is {print $0} if no action is specified.
If you need to search for the text $line escape the $ in regex
awk '$4==/\$line/' $line.sh
or in text it should work directly
awk '$4=="$line"' $line.sh
I have a script to remove lower version jars files in a directory.
#!/bin/bash
#Script to remove lower version jar files.
for PREFIX in `ls *.jar|sed 's/-[0-9\.\0-9\.a-zA-Z]*\.jar//g'|uniq -d`; do
for FILE in `ls -r ${PREFIX}*|sed '1d'`; do
echo " $FILE"
rm $FILE
done
done
It has a bug.
I have below list of Duplicate jar files in a directory.
xyz-1.1.jar
xyz-1.1.1.jar
abc-1.6.jar
abc-1.3.jar
abc-xyz-pqr-1.9.6.jar
abc-xyz-pqr-1.9.2.jar
xyz-tom.jar
xyz-tom-20120423.jar
xyz-tom-20120410.jar
abc-toolkit-1.6-runtime-5.2.0.jar
abc-toolkit-1.6-runtime-5.0.0.jar
The bug is with xyz pattern jar files.
BUG:
Script is removing xyz-1.1.1.jar file instead of xyz-1.1.jar
Script is removing xyz-tom-20120423.jar and xyz-tom-20120410.jar files.
#!/bin/bash
if [ $# == 0 ]; then
dir='.'
elif [ $# == 1 ]; then
dir=$1
else
echo "Usage: $0 [dir]";
exit 1;
fi
for lib in `find $dir -name '*.jar'`; do
for class in `unzip -l $lib | egrep -o '[^ ]*.class$'`; do
class=`echo $class | sed s/\\\\.class// | sed s/[-.\\/$]/_/g`
existing=$( eval "echo \$CLS_${class}" )
if [ -n "$existing" ]; then echo "$lib $existing"; fi
eval CLS_${class}="\"${lib} ${existing}\""
done
done | sort | uniq -c | sort -nr
I find this code here
Hi I am struggling to solve this simple program. I am not able to pass the value from the text file to the variable.
I am stuck at this: value=$( sed -n "${line}p" rpt1.txt|awk {$3}
O/P:
1.sh[15]: test: argument expected
CODE:
wc `find /arbor/custom/gur/fold1`|grep -vi "total"| tee rpt1.txt
total1=`wc -l rpt1.txt`
wc `find /arbor/custom/gur/fold2`|grep -vi "total"| tee rpt2.txt
total2=`wc -l rpt2.txt`
line=1
if [ $line -le $total1 ]
then
value=$( sed -n "${line}p" rpt1.txt|awk {$3} )
if [ $value -eq 512 ];
then
sed -n "${line}p" rpt1.txt|awk '{print $4}'| tee direc.txt
fi
line =$line+1
else
echo "loop over"
fi
Shouldn't there be a print in front of $3 in the suspect line?