Not getting expected file result using awk - unix

Question

#!/bin/bash
delete_file () {
for file in processor_list.txt currnet_username.txt unique_username.txt
do
if [ -e $file ] ;then
rm $file
fi
done
}
delete_file
ps -elf > processor_list.txt ; chmod 755 processor_list.txt
awk '{print $3}' processor_list.txt > currnet_username.txt ; chmod 755 currnet_username.txt
sort -u currnet_username.txt > unique_username.txt ;chmod 755 unique_username.txt
while read line ; do
if [ -e $line.txt ] ;then
rm $line.txt
fi
grep $line processor_list.txt >$line.sh ;chmod 755 $line.sh
awk '{if($4 == "$line") print $0;}' $line.sh > ${line}1.txt ; #mv ${line}1.txt $line.txt;chmod 755 $line.txt
done < unique_username.txt
I'm a beginner of unix shell scripting. please suggested, i am not getting expected results in ${line}1.txt.
For example, I have two UID like kplus , kplustp. what is my requirement is find "kplus" string from ps -elf command and create a file as same name like kplus.txt and redirect or move the data whatever found data using grep command.
But I am getting kplus and kplustp data in kplus.txt file. I need only kplus value based on UID column from ps –elf in kplus.txt file.

Answer 1

This is wrong way to read variable using awk
awk '{if($4 == "$line") print $0;}' $line.sh
Use:
awk '{if($4 == var) print $0;}' var="$line" $line.sh
Or shorten to
awk '$4==var' var="$line" $line.sh
default action is {print $0} if no action is specified.
If you need to search for the text $line escape the $ in regex
awk '$4==/\$line/' $line.sh
or in text it should work directly
awk '$4=="$line"' $line.sh