I have recently started on Drupal (v 7) to create a small company website.
After much reading and watching tutorials, I have started to create my new theme from scratch. I have defined regions and customised the page.tpl.php file to place them into the template (and node.tpl.php etc). All these changes are working and the layout is looking good, and any item I add appears in the main content output.
In my footer region, I have created a block in which I would like links to appear. I have also created a content-type called footer links (with relevant fields) and I have created a couple items of content for it.
The block is showing fine (the title and block body appear). However, despite scouring the documentation, I am not sure what needs to be done to make the items of content (footer links) appear in this block.
Any help appreciated, thanks!
info file snippet for a region
regions[footer_one] = Footer Column One
... and code in page.tpl.php
<div class="one">
<?php if ($page['footer_one']): ?>
<?php print render($page['footer_one']); ?>
<?php endif; ?>
</div>
If you just need simple footer links, no need to create a content type for this, you can simple create a menu and add a menu block in footer.
If you really want to use your own content type for these links, you can create a view (with views module) to display what you want in a block.
About creating a theme from scratch, did you try before to create a sub theme ?
PS: I don't think drupal is a good cms for "small company website".
Views is really powerful and sounds like it will do exactly what you need. Otherwise, you can create a menu for your items and place that menu in your region as well.
Regarding your original code, you'd probably need to grab the information about the nodes from the database in order to construct a list on your own, but views basically does that for you :)
Related
I'm drupal beginner, and can't solve problem with landing page. I create landing page with panels, set custom css code to it but it doesn't look how I want. I see default elements from my theme (header, nav-menu, etc.) on it. I want that layout fill all my page, how can I achieve it?
I have it
I want do like it
well, I found solution for this problem. I use bootstrap 3 sub theme, and there is file who provide page template, it calls node.tpl.php. I just remove string <div class="main-container <?php print $container_class; ?>"> and now it works well.
go to page.tpl.php file, remove the lines that render the header, the logo and the title. They would usually be in an if statement and the varibles are $logo, $site_name, $main_menu, $title.
I am currently developing a website in Drupal. I have a load of news articles which are of content type 'news'. I want to create a widget to show at the bottom of several pages listing the latest articles. I have managed to achieve thus far by creating the view with the fields I want and then making the view available as a block.
The problem is the format in which the articles are being listed in the view. Ideally I would like to customise the HTML. I understand that I can create a custom template to target views/blocks but I haven't quite got a full understanding of it yet, and find the Drupal documentation to be quite dry and therefore hard to find what I need from.
Any pointers would be helpful.
Go to your view edit page and select "table" as your view mode.
Go to "Theme information" and look for the desired (style output) template name.
Copy this name and create a new file in your theme folder using this name. I.e.: views-view-table--view-name-block.tpl.php.
In this file you can use the following structure (as an example) to get the values of the fields:
<?php foreach($rows as $row):?>
<div>
<h2><?php print $row['title'];?></h2>
<p><?php print $row['field_custom'];?></p>
</div>
<?php endforeach;?>
Don't forget press rescan theme files after you saved the file in the view theme section.
You can get as specific as you want. Create a block view next to the default or page view and you will see specific file names in the "Theme information" section.
i'm using the twentytwelve theme and i have to write custom content into my example template.
I want to maintain my header content so the main structure is the following
header = id page, wrapper
ex.page = primary, content
footer = close wrapper, close id page
If i have understood correctly, if i want to insert content into the middle of my page i have to do it into my template page (that is a copy of the main page.php), that is in the middle between my header and my footer
For example i want to insert a div into which insert the loop of such category.
The problem is that it displays me nothing, like i've wrote nothing. I can only see the contents if i erase all the originary div, but it's not what i want to do, just because the only div is the page which is my container.
I can't catch what i have to do.
Can you tell me what i forgot to do?
Thanks,
Alex
page.php is a "master" document. header.php, footer.php and (if it exists) sidebar.php are all imported into page.php. Twenty Twelve also uses atomized content templates. You may need to add your div to content-page.php, which is also imported into page.php. content-page.php is used inside the wordpress loop, and encapsulates the code that pulls in the actual article elements from the wordpress database.
If you are trying to add straight HTML to the templates, ensure that you are not adding code between the php brackets:
<?php // don't add html here ?>
<div>do add html here</div>
Depending upon the type of wordpress page you are trying to display, you may need to consult the Wordpress Template hierarchy to determine the proper Wordpress naming convention for your template file (the copy of page.php).
Technically speaking, everything in content-page.php can be put into page.php replacing the get_template_part function. All the 'content' pages are totally not required and can be combined into one file if you want simplicity.
In my opinion, it's easier to start from scratch when learning Wordpress rather than try and re-work something. The default wordpress themes don't lend themselves to be beginner friendly.
I have a file called page--advertsindex.tpl.php.. Now what i want to do is display that page inside the content region of page.tpl.php..
page--advertsindex.tpl.php contains the HTML which need's to be rendered in the content region of page.tpl but what it does currently when i navigate to my_drupal_site/advertsindex it only show's the html of page--advertsindex, not the page.tpl.php file and the page--advertsindex in the content region..
How can i do this? or is there a different way to achieve my goal?
Any page--<identifier>.tpl.php will be used instead of page.tpl.php for the url /identifier. That is by design and the entire purpose of this system. This can be extended for deeper paths too: page--foo-bar-baz.tpl.php for /foo/bar/baz.
If you want certain content to appear on /identifier, you have two options: Conditionally include the content or copy the content. What to choose depends on your situation.
Conditionally include: inside page.tpl.php:
<div class="footer">
<?php if (arg(0) == "advertsindex"): ?>
<?php print theme("advertsindex_disclaimer"); ?>
<?php endif; ?>
</div>
Overrides: introduce a page--advertsindex.tpl.php:
<div id="content">
<?php print $content ?>
</div>
When to choose what:
Only use conditional includes or conditional rendering when:
The content to be included or excluded is small and shared. Patterns like `[large 20+ line of frontpage HTML][normal HTML] are very bad.
The content to be included needs all sorts of fancy new variables pulled in. Patterns like are really bad. Drupals theme system is push (theme gets variables from modules) and never pull (theme requests parameters at modules).
In all other cases you'd use the overrides. And yes, that will include a lot of duplication, but that is by design and accepted as the default practice in Drupal. To avoid having to modify some HTML in 20+ files, "split" or "copy" them as late as possible.
A rule of thumb is that a conditional should be a few lines only and never require variables that are not available in the parent.
If advertsindex is would be one of your content type then you have to create node--advertsindex.tpl.php file instead of page--advertsindex.tpl.php. Or If you wont to display some content in the page.tpl.php page, then it is better to copy all code of page.tpl.php into YOUR-Custom_page.tpl.php and put your code inside the content section of YOUR-Custom_page.tpl.php.
I think it helps.
Usually I set up pages in Wordpress by putting all the HTML in and the client will edit the content in the WYSIWYG editor
This is great, until they accidentally delete a div or break something.
What is the correct way to go about this making it idiot proof, so that they can change titles, paragraphs etc without potentially deleting parts of the structure?
If your client does not know HTML, and you know this going into the project, the only things he/she should be inputting in the page editor are words, uploaded media, and elements that can be inserted using the visual editor. It's a pain in the butt, but your theme should be the part that's "idiot proof".
Build your theme to wrap the_content(); in a div, and style all the potential elements that can be input accordingly. Only rely on elements that can be added using the CKEditor.
e.g. (within the loop, in a theme template file)
<div id="myContentDiv">
<?php the_content(); ?>
</div>
Then your CSS:
#myContentDiv p {
}
#myContentDiv ul {
}
etc.
There's a few options that comes to me right now:
Use jquery plugins to get columns (which is pretty bad IMHO)
Use a plugin with shortcodes (so you wrap each column with them), which is good but user may screw it up yet
Use custom fields (like one text area "Right column content", then you have another text area "Left column content" and so on)
All these 3 are quite easy to implement! :)
[]'s